<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">AJOR</journal-id><journal-title-group><journal-title>American Journal of Operations Research</journal-title></journal-title-group><issn pub-type="epub">2160-8830</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/ajor.2019.95013</article-id><article-id pub-id-type="publisher-id">AJOR-94340</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  An Ordering Policy for Deteriorating Items with Time-Dependent Quadratic Demand and Salvage Value under Permissible Delay in Payment
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Trailokyanath</surname><given-names>Singh</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Madan</surname><given-names>Mohan Muduly</given-names></name><xref ref-type="aff" rid="aff2"><sup>2</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Chittaranjan</surname><given-names>Mallick</given-names></name><xref ref-type="aff" rid="aff3"><sup>3</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Rahul</surname><given-names>Kumar Gupta</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Hadibandhu</surname><given-names>Pattanayak</given-names></name><xref ref-type="aff" rid="aff4"><sup>4</sup></xref></contrib></contrib-group><aff id="aff1"><addr-line>Department of Mathematics, C. V. Raman College of Engineering, Bhubaneswar, India</addr-line></aff><aff id="aff3"><addr-line>Department of Mathematics, Parala Maharaja Engineering College, Berhampur, India</addr-line></aff><aff id="aff2"><addr-line>Department of Mathematics, CET, Techno Campus, Bhubaneswar, India</addr-line></aff><aff id="aff4"><addr-line>Department of Mathematics, Ravenshaw University, Cuttack, India</addr-line></aff><pub-date pub-type="epub"><day>14</day><month>08</month><year>2019</year></pub-date><volume>09</volume><issue>05</issue><fpage>201</fpage><lpage>218</lpage><history><date date-type="received"><day>25,</day>	<month>April</month>	<year>2019</year></date><date date-type="rev-recd"><day>12,</day>	<month>August</month>	<year>2019</year>	</date><date date-type="accepted"><day>15,</day>	<month>August</month>	<year>2019</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
  The article deals with an economic order quantity (EOQ) inventory model for deteriorating items in which the supplier provides the purchaser a permissible delay in payment. This is so when deterioration of units in the inventory is subject to constant deterioration rate, demand rate is quadratic function of time and salvage value is associated with the deteriorated units. Shortages in the system are not allowed to occur. A mathematical formulation is developed when the supplier offers a permissible delay period to the customers under two circumstances: 1) when delay period is less than the cycle of time; and 2) when delay period is greater than the cycle of time. The method is suitable for the items like state-of-the-art aircrafts, super computers, laptops, android mobiles, seasonal items and machines and their spare parts. A solution procedure algorithm is given for finding the optimal order quantity which minimizes the total cost of an inventory system. The article includes numerical examples to support the effectiveness of the developed model. Finally, sensitivity analysis on some parameters on optimal solution is provided.
 
</p></abstract><kwd-group><kwd>Constant Deterioration Rate</kwd><kwd> Deteriorating Items</kwd><kwd> Economic Order Quantity</kwd><kwd> Permissible Delay in Payment</kwd><kwd> Salvage Value</kwd><kwd> Time-Dependent Quadratic Demand Rate</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>It is commonly observed that most of the physical goods in which appreciable deterioration can take place when the item in stock undergoes changes or becomes out of fashion and consequently the loss must be taken into account when analyzing the model. Deterioration is a natural process which is defined as change, decay, evaporation, loss of utility or marginal value of the commodity. Thus, to control and maintain the inventory of deteriorating items to satisfy customer’s demand or retailer’s order is very important in nowadays. Of late, many models have been developed for the control and maintenance of the inventory. Generally, for items like hardware, glassware, steel and toys, the rate of deterioration is too low; and there is little need for considering deterioration of the economic lot-size. But items like seasonal food, vegetables, fruit, blood, fish, meat, radioactive substances, alcohol, chemicals, gasoline, drugs, medicine etc. deteriorate remarkably overtime. In the history, the inventory models for deteriorating items have been continuously modified to become more practicable and realistic. Whitin [<xref ref-type="bibr" rid="scirp.94340-ref1">1</xref>] , the earliest researcher, studied the deterioration of fashion goods at the end of a prescribed storage period. The next earliest work was Ghare and Schrader’s [<xref ref-type="bibr" rid="scirp.94340-ref2">2</xref>] who developed a simple EOQ (Economic Order Quantity) with constant rate of decay. After Ghare and Schrader’s [<xref ref-type="bibr" rid="scirp.94340-ref2">2</xref>] work, many researchers worked on inventory model for deteriorating items assuming the rate of deterioration to be constant and time-dependent. Among the researchers, Covert and Philip [<xref ref-type="bibr" rid="scirp.94340-ref3">3</xref>] and Philip [<xref ref-type="bibr" rid="scirp.94340-ref4">4</xref>] used variable deterioration rate and assumption of constant demand rate and no shortages to formulate the inventory model for deteriorating items. An order-level inventory model for deteriorating items with constant demand rate and constant deterioration rate was presented by Shah and Jaiswal [<xref ref-type="bibr" rid="scirp.94340-ref5">5</xref>] . Donaldson [<xref ref-type="bibr" rid="scirp.94340-ref6">6</xref>] developed the classical EOQ model with time-varying linear demand pattern over a finite horizon of time. Aggarwal [<xref ref-type="bibr" rid="scirp.94340-ref7">7</xref>] presented a note on order-level inventory model for deteriorating items with constant deterioration rate and the constant demand rate. Dave and Patel [<xref ref-type="bibr" rid="scirp.94340-ref8">8</xref>] first presented the inventory model for deteriorating items with a linear increasing demand as time-varying demand and constant deterioration rate with no shortages over a finite horizon. Further, Sachan [<xref ref-type="bibr" rid="scirp.94340-ref9">9</xref>] extended Dave and Patel’s [<xref ref-type="bibr" rid="scirp.94340-ref8">8</xref>] model to allow for shortages. An optimal inventory model for deteriorating items with two-staged demand rate and time-proportional deterioration rate and no shortages is studied by Singh et al. [<xref ref-type="bibr" rid="scirp.94340-ref10">10</xref>] . They determined EOQ and suggested optimal solution by considering demand rate as constant in first part of the cycle and linear increasing in the other part. The literature surveys by Nahmias [<xref ref-type="bibr" rid="scirp.94340-ref11">11</xref>] , Raafat [<xref ref-type="bibr" rid="scirp.94340-ref12">12</xref>] , Goyal and Giri [<xref ref-type="bibr" rid="scirp.94340-ref13">13</xref>] , Li et al. [<xref ref-type="bibr" rid="scirp.94340-ref14">14</xref>] , Bakker et al. [<xref ref-type="bibr" rid="scirp.94340-ref15">15</xref>] and Janssen et al. [<xref ref-type="bibr" rid="scirp.94340-ref16">16</xref>] cite up-to-date review of the advances made in the field of deteriorating inventory.</p><p>Recently, Khanra et al. [<xref ref-type="bibr" rid="scirp.94340-ref17">17</xref>] established an inventory model for deteriorating items with constant deterioration rate and time-dependent quadratic demand rate when delay in payment is permitted. The motivation behind developing an EOQ model in the present paper is to introduce salvage value into the deteriorated units. Quadratic demand rate depicts different phases of market demand including accelerated rise or fall in demand. Shortages in this system are not allowed to occur. The model is useful for the demand of items such as state-of- the-art aircrafts, super computers, laptops, android mobiles, seasonal items and machines and their spare parts and also newly launched fashion goods, seasonal items, cosmetics etc. for which the demand rate accelerates as they are launched into the market and declines when the season ends. The objective of the proposed model is to minimize the total cost by obtaining the optimal cycle time. In addition, the value of optimal ordering quantity of the inventory system is calculated. The necessary and sufficient conditions for the optimal solutions of the model are provided. It is observed that the optimal solution not only exists but also unique. At the end, numerical examples are given to illustrate the results obtained and sensitivity analysis of the effect of the parameters on the decision variables and the total inventory cost is carried out.</p><p>The remainder of the paper is arranged as follows: In Section 2, the review of literature is presented. In Sections 3 and 4, the notations and fundamental assumptions are used throughout this paper, respectively. Mathematical model with the necessary and sufficient conditions and algorithms of the solution of the model in order to minimize the total relevant inventory costs are given in Sections 5 and 6, respectively. In Sections 7 and 8, numerical examples and the sensitivity analysis of the various parameters are presented to illustrate the model, respectively. Finally, conclusions are drawn and the future research is pointed out in Section 9.</p></sec><sec id="s2"><title>2. Literature Review</title><p>Demand is considered as the driving force of the inventory system. Therefore, its role is important for the development of inventory system of deteriorating items. While developing an inventory model, most of the inventory researchers usually consider the time-dependent demand either linear or exponential for the whole cycle. But in real life situations, the time-varying linear or exponential demand pattern seldom occurs because the linear demand pattern represents the uniform change in demand whereas the other indicates the rapid change in demand. Dash et al. [<xref ref-type="bibr" rid="scirp.94340-ref18">18</xref>] studied a model for deteriorating items considering exponential declining demand and time-varying holding cost. The advantage of time-depen- dent quadratic demand rate is that it shows accelerated growth in demand in mid-season and accelerated decline in demand occurs when the season ends. Accelerated growth and accelerated decline in the demand rate are found to occur in the case of the state-of-the-art aircrafts, supercomputers, laptops, android mobiles and machines and their spare parts and in case of obsolete aircrafts, super computers, laptops, android mobiles and machines and their spare parts, respectively. Demand of items may vary with price or with time or even with the instantaneous state of inventory displayed in the market. So in the recent decades, several inventory models were developed for finding the economic replenishment polices with time-dependent demand pattern. Goswami and Chaudhuri [<xref ref-type="bibr" rid="scirp.94340-ref19">19</xref>] , Chakrabarti and Chaudhuri [<xref ref-type="bibr" rid="scirp.94340-ref20">20</xref>] , Benkherouf [<xref ref-type="bibr" rid="scirp.94340-ref21">21</xref>] etc. have proposed EOQ models for deteriorating items focusing on the time-varying linear demand. The inventory models for deteriorating items with time-varying exponentially demand patterns are also studied by Wee [<xref ref-type="bibr" rid="scirp.94340-ref22">22</xref>] and Jalan and Chaudhuri [<xref ref-type="bibr" rid="scirp.94340-ref23">23</xref>] . But in real life situations, the time-varying linear or exponential demand pattern seldom occurs because the linear demand pattern represents the uniform change in demand whereas the other indicates the rapid change in demand. Khanra and Chaudhuri [<xref ref-type="bibr" rid="scirp.94340-ref24">24</xref>] and Ghosh and Chaudhuri [<xref ref-type="bibr" rid="scirp.94340-ref25">25</xref>] etc. have developed the inventory models taking time-varying quadratic demand rate into consideration. A note on a two-warehouse inventory model for deteriorating items with varying quadratic demand under conditionally permissible delay in payment is proposed by Singh and Pattanayak [<xref ref-type="bibr" rid="scirp.94340-ref26">26</xref>] . Singh and Pattanayak [<xref ref-type="bibr" rid="scirp.94340-ref27">27</xref>] developed an EOQ inventory model for deteriorating items with quadratic demand and partial backlogging with no shortages.</p><p>In the conventional EOQ inventory model, the costs of the items are assumed to be paid at the time of delivery by the supplier. However, this assumption is not always suitable for business practices, as the supplier allows credit facilities to attract more customers for business competition situations. Such an advantage is likely to motivate customer to order more quantities because paying later indirectly reduces the purchase cost. In business competitions, the practical scenario for the supplier to survive in the market is to offer customers some grace period enabling them to pay later. The customer does not have to pay any interest during this fixed period, but if the payment gets delayed, the supplier will charge interest for the period. Generally, the credit period in which the suppliers offer to the retailers with interest is known as the trade credit period or permissible delay period or delay period. During this period, he may sell the goods, accumulate revenues on the sales and earn interest on that revenue. In other words, trade credit period is a powerful promotional tool by which suppliers encourage and attract the retailers. Therefore, trade credit plays an important role in inventory control for both the supplier and the customers. In business market, the unit selling price should be greater than the unit purchasing price. Generally, suppliers offer delay period on purchase of items to the retailer. During this period, the retailer is encouraged to buy more items and accumulate revenues by selling items and earning interest. Initially, Goyal [<xref ref-type="bibr" rid="scirp.94340-ref28">28</xref>] studied the economic order quantity with constant demand rate under conditions of permissible delay in payments. Aggarwal and Jaggi [<xref ref-type="bibr" rid="scirp.94340-ref29">29</xref>] studied the ordering policies of deteriorating items with constant demand rate and constant deterioration rate under permissible delay in payments. Among the deterministic demand rates, quadratic demand rate is the most realistic demand rate considered for the development of inventory models for deteriorating items. Khanra et al. [<xref ref-type="bibr" rid="scirp.94340-ref17">17</xref>] established an inventory model for deteriorating items with constant deterioration rate and time-dependent quadratic demand rate when delay in payment is permitted. Musa and Sani [<xref ref-type="bibr" rid="scirp.94340-ref30">30</xref>] studied the ordering policies for the inventory model of delayed deteriorating items under permissible delay in payments. Now-a-days, inventory researchers try to develop simple and easy solution procedures for implementation in management science. In this regard, Chen et al. [<xref ref-type="bibr" rid="scirp.94340-ref31">31</xref>] proposed a simple arithmetic-geometric method to solve the inventory problem and established some discrimination terms to identify the unique optimal among three alternatives under conditionally permissible delay in payment. Singh et al. [<xref ref-type="bibr" rid="scirp.94340-ref32">32</xref>] studied an EOQ model for a deteriorating item with initial order quantity demand and inventory dependent deterioration under permissible delay in payment scheme.</p><p>Most of the inventory models developed assumed that the deterioration of a unit is a complete loss and that these deteriorated units have no sale value. They are considered as lost. But, in real life situations, the supplier can offer a fixed reduced unit cost to his retailer for the deteriorated stock in order to reduce the total inventory cost. In other words, inclusion of salvage value into the deteriorated stock benefits both the supplier and retailer. The proposed strategy can be implemented in inventory control model of selling seasonal items, fashion items, automobiles, smart phones and machines and their spare parts. In the several articles, the models assumed that deteriorated units have salvage values. So they are considered as lost in business. To overcome such loss, supplier can offer to his retailer reduced unit cost for the deteriorated stocks. In this respect, Jaggi and Aggarwal [<xref ref-type="bibr" rid="scirp.94340-ref33">33</xref>] proposed the concept of inclusion of salvage value into deteriorated units in the inventory model. Later, Mishra and Shah [<xref ref-type="bibr" rid="scirp.94340-ref34">34</xref>] developed the inventory model for time dependent deteriorating items with salvage values. In their paper, the salvage value is associated into the deteriorated units. An optimal policy for deteriorating items with constant demand rate, constant deterioration rate, incorporation of salvage value into the deteriorated items and shortages is studied by Annadurai [<xref ref-type="bibr" rid="scirp.94340-ref35">35</xref>] . Mishra and Tripathy [<xref ref-type="bibr" rid="scirp.94340-ref36">36</xref>] presented an inventory model with constant demand rate and the three-parameter weibull distribution deterioration rate by introducing the salvage value into deteriorated units for the calculation of minimization of total cost.</p></sec><sec id="s3"><title>3. Fundamental Assumptions</title><p>The following assumptions are needed for developing the mathematical model:</p><p>1) The deterioration rate is constant for the period, which is practically very small.</p><p>2) A single type of item is considered over a prescribed period.</p><p>3) The delivery lead time (i.e., the length of time between making a decision to replenish an item and its actual addition to stock) is zero.</p><p>4) Replacement rate occurs instantaneously.</p><p>5) The demand rate is known and is a quadratic increasing function of time.</p><p>6) The planning horizon of the inventory system is infinite.</p><p>7) No shortages in inventory are allowed.</p><p>8) The supplier offers the purchaser a delay period in paying for purchasing cost and the purchaser can accumulate revenues by selling items and by earning interest.</p></sec><sec id="s4"><title>4. Model Development</title><p>The paper is developed considering the replenishment problem of a single deteriorating item. The inventory system starts at time t = 0 when a lot size of a certain number of units enters the system and ends with zero inventory at time t = T . The depletion of inventory occurs due to combined effect of the time- dependent quadratic demand rate and constant deterioration rate in time period 0 ≤ t ≤ T . Thus, the governing differential equation of the instantaneous state of inventory level I ( t ) at any time t is given by</p><p>d I ( t ) d t + θ I ( t ) = − R ( t ) ,               0 ≤ t ≤ T , (1)</p><p>with the boundary conditions I ( 0 ) = I o (1a)</p><p>and</p><p>I ( T ) = 0 , (1b)</p><p>where R ( t ) = a + b t + c t 2 .</p><p>The solution of Equation (1) is given by</p><p>I ( t ) = ( a + b T + c T 2 θ − b + 2 c T θ 2 + 2 c θ 3 ) e θ ( T − t )                   − a + b t + c t 2 θ + b + 2 c t θ 2 − 2 c θ 3 ,               0 ≤ t ≤ T (2)</p><p>and the order quantity is</p><p>I o = I ( 0 ) = ( a + b T + c T 2 θ − b + 2 c T θ 2 + 2 c θ 3 ) e θ T − a θ + b θ 2 − 2 c θ 3 (3)</p><p>Now, the model is analyzed under three possibilities depending upon the relationship between delay period and cycle time.</p><p>Case A: t p &lt; T . (Delay period is less than the cycle time).</p><p>The total variable cost comprises the sum of the ordering cost, holding cost, deterioration cost and interest chargeable minus the sum of the salvage value of the deteriorated items and interest earned. They are grouped together after evaluating the above costs individually.</p><p>1) The ordering cost ( O C ) is</p><p>O C = C 3 (4)</p><p>2) The deterioration cost ( D C ):</p><p>The total demand during the time period [ 0 , T ] is</p><p>∫ 0 T R ( t ) d t = a T + b T 2 2 + c T 3 3 (5)</p><p>The total number of deteriorated units is given by</p><p>I 0 − ∫ 0 T R ( t ) d t = ( a + b T + c T 2 θ − b + 2 c T θ 2 + 2 c θ 3 ) e θ T     − a θ + b θ 2 − 2 c θ 3 − a T − b T 2 2 − c T 3 3 (6)</p><p>Thus, the deterioration cost ( D C ) for the period [ 0 , T ] is</p><p>D C = C 2 [ ( a + b T + c T 2 θ − b + 2 c T θ 2 + 2 c θ 3 ) e θ T     − a θ + b θ 2 − 2 c θ 3 − a T − b T 2 2 − c T 3 3 ] (7)</p><p>3) The salvage value ( C S V ) for deteriorated items for the period [ 0 , T ] is</p><p>C S V = χ [ ( a + b T + c T 2 θ − b + 2 c T θ 2 + 2 c θ 3 ) e θ T     − a θ + b θ 2 − 2 c θ 3 − a T − b T 2 2 − c T 3 3 ] (8)</p><p>4) The holding cost ( H C ) for the period [ 0 , T ] is</p><p>H C = C 1 ( e θ T − 1 ) θ 2 ( a + b T + c T 2 − b + 2 c T θ + 2 c θ 2 )     − C 1 T θ [ a + b T 2 + c T 2 3 − b + c T θ + 2 c θ 2 ] (9)</p><p>5) The interest payable ( P I A ) for the period [ 0 , T ] is</p><p>P I A = C 2 I c θ 2 ( e θ ( T − t p ) − 1 ) ( a + b T + c T 2 − b + 2 c T θ + 2 c θ 2 ) − C 2 I c ( T − t p ) θ [ a + b ( T + t p ) 2 + c ( T 2 + T t p + t p 2 ) 3 − b + c ( T + t p ) θ + 2 c θ 2 ] (10)</p><p>where C 1 = h 1 C 2 .</p><p>6) The interest earned ( E I A ) for the period [ 0 , T ] is</p><p>E I A = p I e ∫ 0 T t R ( t ) d t = p I e T 2 ( a 2 + b T 3 + c T 2 4 ) . (11)</p><p>The total cost function for the period [ 0 , T ] is defined as</p><p>T C A ( T ) = O C + H C + ( D C − C S V ) + P I A − E I A . (12)</p><p>The total variable cost per unit time ( T V C A ( T ) ) for the period [ 0 , T ] is</p><p>T V C A ( T ) = 1 T [ O C + H C + ( D C − C S V ) + P I A − E I A ] = C 3 T + C 1 θ T [ ( a + b T + c T 2 − b + 2 c T θ + 2 c θ 2 ) ( e θ T − 1 θ )     − a T − b T 2 2 − c T 3 3 + b T + c T 2 θ − 2 c T θ 2 ]     + ( C 2 − χ ) T [ ( a + b T + c T 2 θ − b + 2 c T θ 2 + 2 c θ 3 ) e θ T     − a θ + b θ 2 − 2 c θ 3 − a T − b T 2 2 − c T 3 3 ]</p><p>  + C 2 I c θ T ( a + b T + c T 2 − b + 2 c T θ + 2 c θ 2 ) ( e θ ( T − t p ) − 1 θ )   − C 2 I e T ( a 2 + b T 3 + c T 2 4 ) − C 2 I c ( T − t p ) θ T [ a + b ( T + t p ) 2   + c ( T 2 + T t p + t p 2 ) 3 − b + c ( T + t p ) θ + 2 c θ 2 ] (13)</p><p>The objective of the problem is to determine the optimal value of T so that T V C ( T ) is minimized. The necessary condition to minimize T V C A ( T ) for a given value of t p is</p><p>d [ T V C A ( T ) ] d T = 0 (14)</p><p>provided it satisfies the condition d 2 [ T V C A ( T ) ] d T 2 &gt; 0 .</p><p>From Equation (14), the respective non-linear equation is</p><p>d [ T V C A ( T ) ] d T = ( a + b T + c T 2 ) [ ( C 1 θ + C 2 − χ ) ( e θ T − 1 ) + C 2 I c θ ( e θ ( T − t p ) − 1 ) − C 2 I e T ]       − [ T V C A ( T ) ] = 0 (15)</p><p>The second order of T V C A ( T ) with respect to T is as follows:</p><p>d 2 [ T V C A ( T ) ] d T 2 = ( a + b T + c T 2 ) T [ ( C 1 θ + C 2 − χ ) θ e θ T + C 2 I c e θ ( T − t p ) − C 2 I e ]       − ( 2 a + b T ) T 2 [ ( C 1 θ + C 2 − χ ) ( e θ T − 1 ) + C 2 I c θ ( e θ ( T − t p ) − 1 ) − C 2 I e T ]       + 2 T 2 [ T V C A ( T ) ] (16)</p><p>Case B: t p &gt; T . (Delay period is greater than the cycle time)</p><p>Here, total variable cost comprises the sum of the ordering cost, holding cost and deterioration cost interest chargeable minus the sum of the salvage value of the deteriorated items and interest earned as interest chargeable is zero. The ordering cost, holding cost, deterioration cost and the salvage value of the deteriorated items are same as Case A.</p><p>Now, the total interest earned ( E I B ) during the cycle time is given by the sum of the interest earned during the period [ 0 , T ] and the interest earned during the delay period [ T , t p ] . Thus,</p><p>E I B = C 2 I e ∫ 0 T t R ( t ) d t + C 2 I e ( t p − T ) ∫ 0 T R ( t ) d t = C 2 I e T [ ( a + b T 2 + c T 2 3 ) t p − a T 2 − b T 2 6 − c T 3 12 ] (17)</p><p>Here, the total cost function in this case is defined as</p><p>T C B ( T ) = O C + H C + ( D C − C S V ) − E I B (18)</p><p>The total variable cost per unit time ( T V C B ( T ) ) in this case is</p><p>T V C B ( T ) = 1 T [ O C + H C + ( D C − C S V ) − E I B ] = C 3 T + C 1 θ T [ ( a + b T + c T 2 − b + 2 c T θ + 2 c θ 2 ) ( e θ T − 1 θ ) − a T     − b T 2 2 − c T 3 3 + b T + c T 2 θ − 2 c T θ 2 ]     + ( C 2 − χ ) T [ ( a + b T + c T 2 θ − b + 2 c T θ 2 + 2 c θ 3 ) e θ T     − a θ + b θ 2 − 2 c θ 3 − a T − b T 2 2 − c T 3 3 ]     − C 2 I e [ ( a + b T 2 + c T 2 3 ) t p − a T 2 − b T 2 6 − c T 3 12 ] (19)</p><p>The necessary condition to minimize T V C B ( T ) for a given value of t p is</p><p>d [ T V C B ( T ) ] d T = 0 (20)</p><p>provided it satisfies the condition d 2 [ T V C B ( T ) ] d T 2 &gt; 0 .</p><p>From (20), the respective non-linear equation is</p><p>d [ T V C B ( T ) ] d T = ( a + b T + c T 2 ) ( e θ T − 1 ) ( C 1 θ + C 2 − χ )         − C 2 I e [ t p ( a + b T + c T 2 ) − a T − b T 2 2 − c T 3 3 ] − [ T V C B ( T ) ] = 0 (21)</p><p>The second order derivative of T V C B ( T ) with respect to T is as follows:</p><p>d 2 [ T V C B ( T ) ] d T 2 = ( a + b T + c T 2 ) T [ ( C 1 θ + C 2 − χ ) θ e θ T + C 2 I c e θ ( T − t p ) − C 2 I e ]       − ( 2 a + b T ) T 2 [ ( C 1 θ + C 2 − χ ) ( e θ T − 1 ) + C 2 I c θ ( e θ ( T − t p ) − 1 ) − C 2 I e ]       + 2 T 2 [ T V C B ( T ) ] (22)</p><p>Case C: t p = T . (Delay period is equal to the cycle time).</p><p>The respective cost function is obtained from either Equation (13) or Equation (19) by substituting T = t p because of both of ( T V C A ( T ) ) and ( T V C B ( T ) ) are identical.</p><p>Based on the results above, a procedure is derived to locate the optimal cycle time for the two cases.</p></sec><sec id="s5"><title>5. Solution Procedure</title><p>The following Solution procedure is recommended for the calculation of EOQ and optimal solution.</p><p>Step I: Perform (1)-(9).</p><p>1) Assign values to the parameters.</p><p>2) Solve equation (15) for T 1 * .</p><p>3) Test the respective sufficient condition.</p><p>4) Compare T 1 * with t p .</p><p>5) If T 1 * &gt; t p , then substitute the value of T 1 * in Equation (13) to get T V C A ( T 1 * ) .</p><p>6) Solve Equation (21) for T 2 * .</p><p>7) Test the respective sufficient condition.</p><p>8) Compare T 2 * with t p .</p><p>9) If T 2 * &lt; t p , then substitute the value of T 2 * in Equation (19) to get T V C B ( T 2 * ) .</p><p>Then the following decision will be held.</p><p>Decision I. If T 1 * &gt; t p &gt; T 2 * is satisfied, then the optimal cost T V C ( T * ) , i.e., the minimum cost is obtained by comparing both T V C A ( T 1 * ) and T V C B ( T 2 * ) and evaluate the corresponding optimal order quantity I o * from Equation (3).</p><p>Step II: Decision II. If T 1 * &gt; t p and T 2 * &gt; t p are satisfied, then the optimal cost T V C ( T * ) is T V C A ( T 1 * ) and evaluate the corresponding optimal order quantity I o * from Equation (3).</p><p>Decision III. If T 1 * &lt; t p and T 2 * &lt; t p are satisfied, then the optimal cost T V C ( T * ) is T V C B ( T 2 * ) and evaluate the corresponding optimal order quantity I o * from Equation (3).</p><p>The following numerical examples are presented in order to demonstrate the above solution procedure which can be applied to determine the optimal solution.</p></sec><sec id="s6"><title>6. Numerical Examples</title><p>Example 1. (Case A and Case B): Minimum average cost is T V C A ( T 1 * ) .</p><p>Let a = 1000 , b = 150 , c = 15 , θ = 0.20 , C 1 = 0.12 , C 2 = 20 , C 3 = 200 , χ = 0.02 , I c = 0.15 , I e = 0.13 , and t p = 0.25 in appropriate units. Solving Equation (13), we get T 1 * = 0.351257 year and putting T 1 * = 0.351257 year in Equation (13), the corresponding average cost is T V C A ( T 1 * ) = $ 939.98 which</p><p>satisfies the sufficient condition (16), i.e., d 2 [ T V C A ( T 1 * ) ] d T 2 = 15048.8 &gt; 0 .</p><p>Similarly, solving Equation (21), we get T 2 * = 0.238718 year and putting T 2 * = 0.238718 year in Equation (19), the corresponding average cost is</p><p>T V C B ( T 2 * ) = $ 1001.42 which satisfies the sufficient condition (22), i.e.,</p><p>d 2 [ T V C B ( T 2 * ) ] d T 2 = 30273.846 &gt; 0 .</p><p>In this case, by Step I, the optimal average cost is T V C A ( T 1 * ) = $ 939.98 and the corresponding cycle length is T 1 * = 0.351257 year and the corresponding EOQ is I o * ( T 1 * ) = 373.846 .</p><p>Example 2. (Case A and B): Minimum average cost is T V C B ( T 2 * ) .</p><p>Let a = 1000 , b = 150 , c = 15 , θ = 0.20 , C 1 = 0.12 , C 2 = 20 , C 3 = 200 , χ = 0.02 , I c = 0.15 , I e = 0.13 and t p = 0.35 in appropriate units. Solving Equation (15), we get T 1 * = 0.401514 year and putting T 1 * = 0.401514 year in Equation (13), the corresponding average cost is T V C A ( T 1 * ) = $ 884.336 which</p><p>satisfies the sufficient condition (16), i.e., d 2 [ T V C A ( T 1 * ) ] d T 2 = 13280.9 &gt; 0 .</p><p>Similarly, solving Equation (21), we get T 2 * = 0.239385 year and putting T 2 * = 0.239385 year in Equation (19), the corresponding average cost is T V C B ( T 2 * ) = $ 736.681 which satisfies the sufficient condition (22), i.e.,</p><p>d 2 [ T V C B ( T 2 * ) ] d T 2 = 30026.2 &gt; 0 .</p><p>In this case, by Step I, the optimal average cost is T V C B ( T 2 * ) = $ 736.681 and the corresponding cycle length is T 2 * = 0.239385 year and the corresponding EOQ is I o * ( T 2 * ) = 249.717 .</p></sec><sec id="s7"><title>7. Sensitivity Analysis</title><p>The effect of changing of the several parameters on the optimal cycle time and the optimal total cost is studied. The sensitivity analysis of the parameters present in this model is also performed. The optimal values of the total average cost T V C ( T * ) change significantly with changes (−50%, −25%, −10%, +10%, +25%, +50%) of different parameters value in <xref ref-type="table" rid="table1">Table 1</xref> based on Example 1.</p><p>On the basis of sensitivity analysis of the parameters, the following features</p><table-wrap-group id="1"><label><xref ref-type="table" rid="table1">Table 1</xref></label><caption><title> Effect of changes in the parameters of the inventory</title></caption><table-wrap id="1_1"><table><tbody><thead><tr><th align="center" valign="middle" >Changing parameters</th><th align="center" valign="middle" >Change in parameters</th><th align="center" valign="middle" >Cycle length ( T 1 * )</th><th align="center" valign="middle" >Total cost ( T V C A ( T 1 * ) )</th><th align="center" valign="middle" >Cycle length ( T 2 * )</th><th align="center" valign="middle" >Total cost ( T V C B ( T 2 * ) )</th><th align="center" valign="middle" >Optimal cycle length ( T * )</th><th align="center" valign="middle" >Optimal total cost ( T V C ( T * ) )</th></tr></thead><tr><td align="center" valign="middle"  rowspan="6"  >a</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.311248</td><td align="center" valign="middle" >1079.73</td><td align="center" valign="middle" >0.196504</td><td align="center" valign="middle" >1041.62</td><td align="center" valign="middle" >0.196504</td><td align="center" valign="middle" >1041.62</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.328076</td><td align="center" valign="middle" >1012.97</td><td align="center" valign="middle" >0.214591</td><td align="center" valign="middle" >1030.43</td><td align="center" valign="middle" >0.214591</td><td align="center" valign="middle" >1030.43</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.341003</td><td align="center" valign="middle" >970.087</td><td align="center" valign="middle" >0.228140</td><td align="center" valign="middle" >1015.52</td><td align="center" valign="middle" >0.228140</td><td align="center" valign="middle" >1015.52</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.363206</td><td align="center" valign="middle" >908.398</td><td align="center" valign="middle" >0.250887</td><td align="center" valign="middle" >983.430</td><td align="center" valign="middle" >0.363206</td><td align="center" valign="middle" >908.398</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.385391</td><td align="center" valign="middle" >857.595</td><td align="center" valign="middle" >0.273124</td><td align="center" valign="middle" >947.763</td><td align="center" valign="middle" >0.385391</td><td align="center" valign="middle" >857.595</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.441043</td><td align="center" valign="middle" >759.892</td><td align="center" valign="middle" >0.327654</td><td align="center" valign="middle" >856.993</td><td align="center" valign="middle" >0.441043</td><td align="center" valign="middle" >759.892</td></tr><tr><td align="center" valign="middle"  rowspan="6"  >b</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.347954</td><td align="center" valign="middle" >945.380</td><td align="center" valign="middle" >0.237367</td><td align="center" valign="middle" >1003.39</td><td align="center" valign="middle" >0.347954</td><td align="center" valign="middle" >945.380</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.349579</td><td align="center" valign="middle" >942.696</td><td align="center" valign="middle" >0.238036</td><td align="center" valign="middle" >1002.41</td><td align="center" valign="middle" >0.349579</td><td align="center" valign="middle" >942.696</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.350579</td><td align="center" valign="middle" >941.070</td><td align="center" valign="middle" >0.238444</td><td align="center" valign="middle" >1001.82</td><td align="center" valign="middle" >0.350579</td><td align="center" valign="middle" >941.070</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.351943</td><td align="center" valign="middle" >938.885</td><td align="center" valign="middle" >0.238994</td><td align="center" valign="middle" >1001.01</td><td align="center" valign="middle" >0.351943</td><td align="center" valign="middle" >938.885</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.352989</td><td align="center" valign="middle" >937.232</td><td align="center" valign="middle" >0.239411</td><td align="center" valign="middle" >1000.41</td><td align="center" valign="middle" >0.352989</td><td align="center" valign="middle" >937.232</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.354780</td><td align="center" valign="middle" >934.451</td><td align="center" valign="middle" >0.240117</td><td align="center" valign="middle" >999.384</td><td align="center" valign="middle" >0.354780</td><td align="center" valign="middle" >934.451</td></tr><tr><td align="center" valign="middle"  rowspan="6"  >c</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.354369</td><td align="center" valign="middle" >957.299</td><td align="center" valign="middle" >0.238689</td><td align="center" valign="middle" >1001.45</td><td align="center" valign="middle" >0.354369</td><td align="center" valign="middle" >957.299</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.352804</td><td align="center" valign="middle" >948.581</td><td align="center" valign="middle" >0.238704</td><td align="center" valign="middle" >1001.43</td><td align="center" valign="middle" >0.352804</td><td align="center" valign="middle" >948.581</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.351873</td><td align="center" valign="middle" >943.406</td><td align="center" valign="middle" >0.238712</td><td align="center" valign="middle" >1001.42</td><td align="center" valign="middle" >0.351873</td><td align="center" valign="middle" >943.406</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.350643</td><td align="center" valign="middle" >936.572</td><td align="center" valign="middle" >0.238723</td><td align="center" valign="middle" >1001.41</td><td align="center" valign="middle" >0.350643</td><td align="center" valign="middle" >936.572</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.349727</td><td align="center" valign="middle" >931.494</td><td align="center" valign="middle" >0.238732</td><td align="center" valign="middle" >1001.40</td><td align="center" valign="middle" >0.349727</td><td align="center" valign="middle" >931.494</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.348215</td><td align="center" valign="middle" >923.120</td><td align="center" valign="middle" >0.238746</td><td align="center" valign="middle" >1001.38</td><td align="center" valign="middle" >0.348215</td><td align="center" valign="middle" >923.120</td></tr><tr><td align="center" valign="middle"  rowspan="6"  >θ</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.288355</td><td align="center" valign="middle" >1261.25</td><td align="center" valign="middle" >0.208512</td><td align="center" valign="middle" >1237.54</td><td align="center" valign="middle" >0.288355</td><td align="center" valign="middle" >1261.25</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.314936</td><td align="center" valign="middle" >1104.92</td><td align="center" valign="middle" >0.222126</td><td align="center" valign="middle" >1123.26</td><td align="center" valign="middle" >0.314936</td><td align="center" valign="middle" >1104.92</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.335154</td><td align="center" valign="middle" >1006.81</td><td align="center" valign="middle" >0.231656</td><td align="center" valign="middle" >1051.16</td><td align="center" valign="middle" >0.335154</td><td align="center" valign="middle" >1006.81</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.370299</td><td align="center" valign="middle" >872.666</td><td align="center" valign="middle" >0.246449</td><td align="center" valign="middle" >950.183</td><td align="center" valign="middle" >0.370299</td><td align="center" valign="middle" >872.666</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.407349</td><td align="center" valign="middle" >774.140</td><td align="center" valign="middle" >0.259560</td><td align="center" valign="middle" >870.214</td><td align="center" valign="middle" >0.407349</td><td align="center" valign="middle" >774.140</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.528423</td><td align="center" valign="middle" >674.344</td><td align="center" valign="middle" >0.286847</td><td align="center" valign="middle" >727.005</td><td align="center" valign="middle" >0.528423</td><td align="center" valign="middle" >674.344</td></tr><tr><td align="center" valign="middle"  rowspan="6"  >C 1</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.351931</td><td align="center" valign="middle" >966.618</td><td align="center" valign="middle" >0.237652</td><td align="center" valign="middle" >1008.85</td><td align="center" valign="middle" >0.351931</td><td align="center" valign="middle" >966.618</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.351593</td><td align="center" valign="middle" >953.285</td><td align="center" valign="middle" >0.238183</td><td align="center" valign="middle" >1005.14</td><td align="center" valign="middle" >0.351593</td><td align="center" valign="middle" >953.285</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.351391</td><td align="center" valign="middle" >945.299</td><td align="center" valign="middle" >0.238503</td><td align="center" valign="middle" >1002.91</td><td align="center" valign="middle" >0.351391</td><td align="center" valign="middle" >945.299</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.351122</td><td align="center" valign="middle" >934.666</td><td align="center" valign="middle" >0.238933</td><td align="center" valign="middle" >999.925</td><td align="center" valign="middle" >0.351122</td><td align="center" valign="middle" >934.666</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.350902</td><td align="center" valign="middle" >926.703</td><td align="center" valign="middle" >0.239256</td><td align="center" valign="middle" >997.685</td><td align="center" valign="middle" >0.350902</td><td align="center" valign="middle" >926.703</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.350585</td><td align="center" valign="middle" >913.455</td><td align="center" valign="middle" >0.239798</td><td align="center" valign="middle" >993.945</td><td align="center" valign="middle" >0.350585</td><td align="center" valign="middle" >913.455</td></tr><tr><td align="center" valign="middle"  rowspan="6"  >C 2</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.310932</td><td align="center" valign="middle" >1047.57</td><td align="center" valign="middle" >0.196518</td><td align="center" valign="middle" >1036.24</td><td align="center" valign="middle" >0.196518</td><td align="center" valign="middle" >1036.24</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.327754</td><td align="center" valign="middle" >1010.45</td><td align="center" valign="middle" >0.214539</td><td align="center" valign="middle" >1027.76</td><td align="center" valign="middle" >0.327754</td><td align="center" valign="middle" >1010.45</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.340807</td><td align="center" valign="middle" >969.102</td><td align="center" valign="middle" >0.228094</td><td align="center" valign="middle" >1014.46</td><td align="center" valign="middle" >0.340807</td><td align="center" valign="middle" >969.102</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.363554</td><td align="center" valign="middle" >909.325</td><td align="center" valign="middle" >0.250998</td><td align="center" valign="middle" >984.432</td><td align="center" valign="middle" >0.363554</td><td align="center" valign="middle" >909.325</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.386787</td><td align="center" valign="middle" >859.717</td><td align="center" valign="middle" >0.273639</td><td align="center" valign="middle" >950.069</td><td align="center" valign="middle" >0.386787</td><td align="center" valign="middle" >859.717</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.448166</td><td align="center" valign="middle" >762.779</td><td align="center" valign="middle" >0.330790</td><td align="center" valign="middle" >859.988</td><td align="center" valign="middle" >0.448166</td><td align="center" valign="middle" >762.779</td></tr></tbody></table></table-wrap><table-wrap id="1_2"><table><tbody><thead><tr><th align="center" valign="middle"  rowspan="6"  >C 3</th><th align="center" valign="middle" >+50</th><th align="center" valign="middle" >0.402373</th><th align="center" valign="middle" >1214.36</th><th align="center" valign="middle" >0.290496</th><th align="center" valign="middle" >1379.22</th><th align="center" valign="middle" >0.402373</th><th align="center" valign="middle" >1214.36</th></tr></thead><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.377880</td><td align="center" valign="middle" >1081.84</td><td align="center" valign="middle" >0.265993</td><td align="center" valign="middle" >1199.53</td><td align="center" valign="middle" >0.377880</td><td align="center" valign="middle" >1081.84</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.362194</td><td align="center" valign="middle" >997.984</td><td align="center" valign="middle" >0.250019</td><td align="center" valign="middle" >1083.26</td><td align="center" valign="middle" >0.362194</td><td align="center" valign="middle" >997.984</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.339889</td><td align="center" valign="middle" >880.094</td><td align="center" valign="middle" >0.226802</td><td align="center" valign="middle" >915.493</td><td align="center" valign="middle" >0.339889</td><td align="center" valign="middle" >880.094</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.321920</td><td align="center" valign="middle" >786.265</td><td align="center" valign="middle" >0.207535</td><td align="center" valign="middle" >777.356</td><td align="center" valign="middle" >0.207535</td><td align="center" valign="middle" >777.356</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.288966</td><td align="center" valign="middle" >616.802</td><td align="center" valign="middle" >0.170235</td><td align="center" valign="middle" >512.707</td><td align="center" valign="middle" >0.170235</td><td align="center" valign="middle" >512.707</td></tr><tr><td align="center" valign="middle"  rowspan="6"  >χ</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.351334</td><td align="center" valign="middle" >939.621</td><td align="center" valign="middle" >0.238753</td><td align="center" valign="middle" >1001.17</td><td align="center" valign="middle" >0.351334</td><td align="center" valign="middle" >939.621</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.351215</td><td align="center" valign="middle" >939.801</td><td align="center" valign="middle" >0.238736</td><td align="center" valign="middle" >1001.29</td><td align="center" valign="middle" >0.351215</td><td align="center" valign="middle" >939.801</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.351272</td><td align="center" valign="middle" >939.908</td><td align="center" valign="middle" >0.238725</td><td align="center" valign="middle" >1001.37</td><td align="center" valign="middle" >0.351272</td><td align="center" valign="middle" >939.908</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.351241</td><td align="center" valign="middle" >940.052</td><td align="center" valign="middle" >0.238711</td><td align="center" valign="middle" >1001.47</td><td align="center" valign="middle" >0.351241</td><td align="center" valign="middle" >940.052</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.351218</td><td align="center" valign="middle" >940.160</td><td align="center" valign="middle" >0.238700</td><td align="center" valign="middle" >1001.54</td><td align="center" valign="middle" >0.351218</td><td align="center" valign="middle" >940.160</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.351179</td><td align="center" valign="middle" >940.339</td><td align="center" valign="middle" >0.238682</td><td align="center" valign="middle" >1001.66</td><td align="center" valign="middle" >0.351179</td><td align="center" valign="middle" >940.339</td></tr><tr><td align="center" valign="middle"  rowspan="6"  >I c</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.329930</td><td align="center" valign="middle" >955.000</td><td align="center" valign="middle" >0.238718</td><td align="center" valign="middle" >1001.42</td><td align="center" valign="middle" >0.329930</td><td align="center" valign="middle" >955.000</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.339316</td><td align="center" valign="middle" >948.231</td><td align="center" valign="middle" >0.238718</td><td align="center" valign="middle" >1001.42</td><td align="center" valign="middle" >0.339316</td><td align="center" valign="middle" >948.231</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.346109</td><td align="center" valign="middle" >943.489</td><td align="center" valign="middle" >0.238718</td><td align="center" valign="middle" >1001.42</td><td align="center" valign="middle" >0.346109</td><td align="center" valign="middle" >943.489</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.357000</td><td align="center" valign="middle" >936.148</td><td align="center" valign="middle" >0.238718</td><td align="center" valign="middle" >1001.42</td><td align="center" valign="middle" >0.357000</td><td align="center" valign="middle" >936.148</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.366988</td><td align="center" valign="middle" >929.687</td><td align="center" valign="middle" >0.238718</td><td align="center" valign="middle" >1001.42</td><td align="center" valign="middle" >0.366988</td><td align="center" valign="middle" >929.687</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.388717</td><td align="center" valign="middle" >916.463</td><td align="center" valign="middle" >0.238718</td><td align="center" valign="middle" >1001.42</td><td align="center" valign="middle" >0.388717</td><td align="center" valign="middle" >916.463</td></tr><tr><td align="center" valign="middle"  rowspan="6"  >I e</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.411444</td><td align="center" valign="middle" >694.678</td><td align="center" valign="middle" >0.219984</td><td align="center" valign="middle" >821.307</td><td align="center" valign="middle" >0.411444</td><td align="center" valign="middle" >694.678</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.377918</td><td align="center" valign="middle" >821.947</td><td align="center" valign="middle" >0.228784</td><td align="center" valign="middle" >921.857</td><td align="center" valign="middle" >0.377918</td><td align="center" valign="middle" >821.947</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.361248</td><td align="center" valign="middle" >893.754</td><td align="center" valign="middle" >0.234593</td><td align="center" valign="middle" >966.376</td><td align="center" valign="middle" >0.361248</td><td align="center" valign="middle" >893.754</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.342033</td><td align="center" valign="middle" >985.006</td><td align="center" valign="middle" >0.243064</td><td align="center" valign="middle" >1035.91</td><td align="center" valign="middle" >0.342033</td><td align="center" valign="middle" >985.006</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.329441</td><td align="center" valign="middle" >1050.48</td><td align="center" valign="middle" >0.250046</td><td align="center" valign="middle" >1086.58</td><td align="center" valign="middle" >0.329441</td><td align="center" valign="middle" >1050.48</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.311183</td><td align="center" valign="middle" >1154.69</td><td align="center" valign="middle" >0.263125</td><td align="center" valign="middle" >1167.84</td><td align="center" valign="middle" >0.311183</td><td align="center" valign="middle" >1154.69</td></tr><tr><td align="center" valign="middle"  rowspan="6"  >t p</td><td align="center" valign="middle" >+50</td><td align="center" valign="middle" >0.415372</td><td align="center" valign="middle" >877.827</td><td align="center" valign="middle" >0.239553</td><td align="center" valign="middle" >670.495</td><td align="center" valign="middle" >0.239553</td><td align="center" valign="middle" >670.495</td></tr><tr><td align="center" valign="middle" >+25</td><td align="center" valign="middle" >0.381666</td><td align="center" valign="middle" >899.200</td><td align="center" valign="middle" >0.239134</td><td align="center" valign="middle" >835.958</td><td align="center" valign="middle" >0.239134</td><td align="center" valign="middle" >835.958</td></tr><tr><td align="center" valign="middle" >+10</td><td align="center" valign="middle" >0.362924</td><td align="center" valign="middle" >921.031</td><td align="center" valign="middle" >0.238884</td><td align="center" valign="middle" >935.234</td><td align="center" valign="middle" >0.362924</td><td align="center" valign="middle" >921.031</td></tr><tr><td align="center" valign="middle" >−10</td><td align="center" valign="middle" >0.340300</td><td align="center" valign="middle" >962.853</td><td align="center" valign="middle" >0.238552</td><td align="center" valign="middle" >1067.60</td><td align="center" valign="middle" >0.340300</td><td align="center" valign="middle" >962.853</td></tr><tr><td align="center" valign="middle" >−25</td><td align="center" valign="middle" >0.325361</td><td align="center" valign="middle" >1005.35</td><td align="center" valign="middle" >0.238303</td><td align="center" valign="middle" >1166.87</td><td align="center" valign="middle" >0.325361</td><td align="center" valign="middle" >1005.35</td></tr><tr><td align="center" valign="middle" >−50</td><td align="center" valign="middle" >0.305092</td><td align="center" valign="middle" >1101.34</td><td align="center" valign="middle" >0.237891</td><td align="center" valign="middle" >1332.32</td><td align="center" valign="middle" >0.305092</td><td align="center" valign="middle" >1101.34</td></tr></tbody></table></table-wrap></table-wrap-group><p>are observed.</p><p>1) If the initial rate of demand (a) increases, then the optimal cycle length ( T * ) decreases and the optimal average cost ( T V C ( T * ) ) increases. Here T * and T V C ( T * ) are moderately sensitive to change in a.</p><p>2) If the rate of increasing demand (b) increases, then the optimal cycle length ( T * ) decreases and the optimal average cost ( T V C ( T * ) ) increases. Here T * and T V C ( T * ) are lowly sensitive to change in b.</p><p>3) If the rate of changing demand (c) increases, then both the optimal cycle length ( T * ) and the optimal average cost ( T V C ( T * ) ) increase. Here T * and T V C ( T * ) are lowly sensitive to change in c.</p><p>4) If the rate of deterioration ( θ ) increases, then the optimal cycle length ( T * ) decreases and the optimal average cost ( T V C ( T * ) ) increases. Here T * and T V C ( T * ) are highly sensitive to change in θ .</p><p>5) If the holding cost per unit time ( C 1 ) increases, then both the optimal cycle length ( T * ) and the optimal average cost ( T V C ( T * ) ) increase. Here T * and T V C ( T * ) are lowly sensitive to change in C 1 .</p><p>6) If the unit purchase cost ( C 2 ) increases, then the optimal cycle length ( T * ) decreases and the optimal average cost ( T V C ( T * ) ) increases. Here T * and T V C ( T * ) are highly sensitive to change in C 2 .</p><p>7) If the ordering cost ( C 3 ) increases, then both the optimal cycle length ( T * ) and the optimal average cost ( T V C ( T * ) ) increase. Here T * and T V C ( T * ) are highly sensitive to change in C 3 .</p><p>8) If the salvage value ( χ ) increases, then the optimal cycle length ( T * ) increases and the optimal average cost ( T V C ( T * ) ) decreases. Here T * and T V C ( T * ) are lowly sensitive to change in χ .</p><p>9) If the interest charged per unit ( I c ) increases, then the optimal cycle length ( T * ) decreases and the optimal average cost ( T V C ( T * ) ) increases. Here T * and T V C ( T * ) are lowly sensitive to change in I c .</p><p>10) If the interest earned per unit ( I e ) increases, then the optimal cycle length ( T * ) increases and the optimal average cost ( T V C ( T * ) ) decreases. Here T * and <inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x208.png" xlink:type="simple"/></inline-formula> are highly sensitive to change in<inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x209.png" xlink:type="simple"/></inline-formula>.</p><p>11) If the permissible delay period (<inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x210.png" xlink:type="simple"/></inline-formula>) increases, then both the optimal cycle length (<inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x211.png" xlink:type="simple"/></inline-formula>) and the optimal average cost (<inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x212.png" xlink:type="simple"/></inline-formula>) decrease. Here <inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x213.png" xlink:type="simple"/></inline-formula> and <inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x214.png" xlink:type="simple"/></inline-formula> are highly sensitive to change in<inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x215.png" xlink:type="simple"/></inline-formula>.</p></sec><sec id="s8"><title>8. Conclusions</title><p>The proposed model assumes an EOQ model for deteriorating items with the time-dependent quadratic increasing demand under permissible delay in payment. The reason for considering quadratic demand rate is that it depicts different phases of market demand including accelerated rise or fall in demand. Shortages are not permitted in this inventory system. Salvage value is included in the deteriorated units. The model is suitable for the demand of items such as state-of-the-art aircrafts, super computers, laptops, android mobiles, seasonal items and machines and their spare parts and also newly launched fashion goods, seasonal items, cosmetics etc. for which the demand rate accelerates as they are launched into the market and declines when the season ends. The objective of the model is to optimize the cycle time, ordering cost and the total system costs. Further, several numerical examples and sensitivity analysis with respect to various parameters are presented to validate the theoretical results.</p><p>In the future study, it is hoped to extend and incorporate the proposed model into several situations, such as, varying deterioration rate like Weibull distribution and Gamma distribution. Also, we could generalize the model to incorporate quantity discounts, inflation rates and allow for shortages and partial backlogging and other things. The present idea can be extended to consider the parameter as fuzzy or stochastic fuzzy. In addition, we could extend the deterministic demand to stochastic fluctuating demand patterns.</p></sec><sec id="s9"><title>Acknowledgements</title><p>The authors would like to express deep felt gratitude to the Editor-in-Chief and the referees for their invaluable suggestions and guidance.</p></sec><sec id="s10"><title>Conflicts of Interest</title><p>The authors declare no conflicts of interest regarding the publication of this paper.</p></sec><sec id="s11"><title>Cite this paper</title><p>Singh, T., Muduly, M.M., Mallick, C., Gupta, R.K. and Pattanayak, H. (2019) An Ordering Policy for Deteriorating Items with Time-Dependent Quadratic Demand and Salvage Value under Permissible Delay in Payment. American Journal of Operations Research, 9, 201-218. https://doi.org/10.4236/ajor.2019.95013</p></sec><sec id="s12"><title>Notations</title><p>The following symbols are needed for developing the mathematical model:</p><p><inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x216.png" xlink:type="simple"/></inline-formula>: Instantaneous inventory level at any time<inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x217.png" xlink:type="simple"/></inline-formula>.</p><p><inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x218.png" xlink:type="simple"/></inline-formula>: Time-varying quadratic demand rate, where <inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x219.png" xlink:type="simple"/></inline-formula> where<inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x220.png" xlink:type="simple"/></inline-formula>, <inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x221.png" xlink:type="simple"/></inline-formula>and<inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x222.png" xlink:type="simple"/></inline-formula>.</p><p><inline-formula><inline-graphic xlink:href="/html.scirp.org/file/1-1040693x223.png" xlink:type="simple"/></inline-formula>: Constant deterioration rate.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x224.png" xlink:type="simple"/></inline-formula>: Inventory holding cost excluding interest charges, $/unit/year.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x225.png" xlink:type="simple"/></inline-formula>: Unit purchase cost, $/unit.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x226.png" xlink:type="simple"/></inline-formula>: Ordering cost of the inventory per cycle, $/order.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x227.png" xlink:type="simple"/></inline-formula>: Interest charged, $/year.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x228.png" xlink:type="simple"/></inline-formula>: Interest earned, $/year.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x229.png" xlink:type="simple"/></inline-formula>: Purchaser’s permissible delay period offered by the supplier for settling the account.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x230.png" xlink:type="simple"/></inline-formula>: Size of the initial inventory.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x231.png" xlink:type="simple"/></inline-formula>: Optimal quantity.</p><p>T: Length of the cycle time (decision variable).</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x232.png" xlink:type="simple"/></inline-formula>: Optimal value of T.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x233.png" xlink:type="simple"/></inline-formula>: Total inventory cost per unit time for<inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x233.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x234.png" xlink:type="simple"/></inline-formula>.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x235.png" xlink:type="simple"/></inline-formula>: Total inventory cost per unit time for<inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x235.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x236.png" xlink:type="simple"/></inline-formula>.</p><p><inline-formula><inline-graphic xlink:href="//html.scirp.org/file/1-1040693x237.png" xlink:type="simple"/></inline-formula>: Optimal cost, which is a function of time.</p></sec></body><back><ref-list><title>References</title><ref id="scirp.94340-ref1"><label>1</label><mixed-citation publication-type="other" xlink:type="simple">Whitin, T.M. 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