<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">JAMP</journal-id><journal-title-group><journal-title>Journal of Applied Mathematics and Physics</journal-title></journal-title-group><issn pub-type="epub">2327-4352</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/jamp.2019.71017</article-id><article-id pub-id-type="publisher-id">JAMP-90187</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  Existence and Uniqueness of Solution to Semilinear Fractional Elliptic Equation
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Shangjian</surname><given-names>Liu</given-names></name><xref ref-type="aff" rid="aff1"><sub>1</sub></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib></contrib-group><aff id="aff1"><label>1</label><addr-line>College of Science, University of Shanghai for Science and Technology, Shanghai, China</addr-line></aff><pub-date pub-type="epub"><day>07</day><month>01</month><year>2019</year></pub-date><volume>07</volume><issue>01</issue><fpage>210</fpage><lpage>217</lpage><history><date date-type="received"><day>10,</day>	<month>January</month>	<year>2019</year></date><date date-type="rev-recd"><day>22,</day>	<month>January</month>	<year>2019</year>	</date><date date-type="accepted"><day>25,</day>	<month>January</month>	<year>2019</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p><html>
 <head></head>
 
  In this work
  ,
   we study the following problem. <img src="Edit_16e75b43-1fee-4fb3-abab-9b55c9c03d49.bmp" alt="" />
  ,
   where <img src="Edit_233d3729-7335-4cac-be24-9f5a90e7d6d7.bmp" alt="" />
  
   is the fractional Laplacian and &amp;#937;
  
   is a bounded domain in R&lt;SUP&gt;N&lt;/SUP&gt;
  
   with Lipschitz boundary. &lt;i&gt;g&lt;/i&gt;: R&amp;#8594;R
   is an increasing locally Lipschitz continuous function. and &lt;I&gt;f&lt;/i&gt;&amp;#8712;L&lt;sup&gt;m&lt;/sup&gt;(&amp;#937;)
  , <img src="Edit_44adeddc-7725-4dc8-83aa-ec923249343d.bmp" alt="" />
  
  . We use Stampacchia’s theorem to study existence of the solution u, and we prove the<b> </b>uniqueness of u by contradiction
  .
 
</html></p></abstract><kwd-group><kwd>Sobolev Embedding Theorem</kwd><kwd> Stampacchia’s Theorem</kwd><kwd> Existence</kwd><kwd> Uniquness</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>In recent years, many people pay attention to the fractional Laplacian. One of the reasons for this comes from the fact that this operator naturally arises in several phenomena like flames propagation and geophysical fluid dynamics, or in mathematical finance. About the Fractional Sobolev space we can refer [<xref ref-type="bibr" rid="scirp.90187-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.90187-ref2">2</xref>] . In this work, we consider the problem</p><p>{ ( − Δ ) s u + g ( u ) = f ( x ) , x ∈ Ω , u = 0 , x ∈ ℝ N \ Ω     . (1.1)</p><p>where s ∈ ( 0 , 1 ) , N &gt; 2 s , Ω ∈ ℝ N is a bounded domain with Lipschitz boundary. ( − Δ ) s as the fractional Laplacian, which defined as</p><p>( − Δ ) s u ( x ) = a N , s P . V . ∫ ℝ N u ( x ) − u ( y ) | x − y | N + 2 s d y , (1.2)</p><p>where</p><p>a N , s = ( ∫ ℝ N 1 − cos ( ξ 1 ) | ξ 1 | N + 2 s ) − 1 = 2 2 s − 1 π − N 2 Γ ( N + 2 s 2 ) | Γ ( − s ) | (1.3)</p><p>It is worthy to point out that</p><p>lim s → 0 a N , s = 0 = lim s → 1 a N , s , (1.4)</p><p>we can refer [<xref ref-type="bibr" rid="scirp.90187-ref3">3</xref>] .</p><p>For s ∈ ( 0 , 1 ) , we can also define the fractional Laplacian ( − Δ ) s as the operator given by the Fourier multiplier | ξ | 2 s ,that is, for u ∈ S (ℝN)</p><p>F ( ( − Δ ) s u ) ( ξ ) = | ξ | 2 s F ( u ) ( ξ ) , (1.5)</p><p>where we denote by S ( ℝ N ) the class of all Schwartz functions in ℝ N .</p><p>We introduce the Sobolev space</p><p>H s ( ℝ N ) = { u ∈ L 2 ( ℝ N ) : | ξ | s F ( u ) ( ξ ) ∈ L 2 ( ℝ N ) } , (1.6)</p><p>and the space H 0 s (Ω)</p><p>H 0 s ( Ω ) = { u ∈ H s ( Ω ) , u = 0 a . e . x ∈ ℝ N \ Ω } , (1.7)</p><p>endowed with the norm</p><p>‖ u ‖ H 0 s ( Ω ) = ( ∬ D Ω | u ( x ) − u ( y ) | 2 | x − y | N + 2 s d x d y ) 1 2 , (1.8)</p><p>where D Ω = ℝ N &#215; ℝ N \ C Ω &#215; C Ω , C Ω = ℝ N \ Ω . This space allows us to deal with the problems proposed in a bounded domain Ω , as we need. The pair ( H 0 s ( Ω ) , ‖ ⋅ ‖ H 0 s ( Ω ) ) yields a Hilbert space [<xref ref-type="bibr" rid="scirp.90187-ref4">4</xref>] . Moreover, it can be seen that</p><p>( − Δ ) s : H 0 s ( Ω ) → H − s ( Ω ) (1.9)</p><p>is a continuous operator.</p><p>Theorem 1.1. Let g : ℝ → ℝ be an increasing locally Lipschitz continuous function. Let f ∈ L m ( Ω ) , m ≥ 2 N N + 2 s . Then (1.1) have a unique solution u ∈ H 0 s ( Ω ) . Moreover,</p><p>g ( u ) ∈ L 1 ( Ω ) .</p></sec><sec id="s2"><title>2. Preliminaries</title><p>In this section, we give some basic results of fractional Sobolev space H 0 s ( Ω ) that will be used in the next section.</p><p>Definition 2.1 We say that u ∈ H 0 s ( Ω ) is a weak solution to (1.1) if we have</p><p>∬ D Ω ( u ( x ) − u ( y ) ) ( φ ( x ) − φ ( y ) ) | x − y | N + 2 s d x d y + ∫ Ω g ( u ) φ d x = ∫ Ω f φ d x , (2.10)</p><p>for any φ ∈ H 0 s ( Ω ) ∩ L ∞ ( Ω ) .</p><p>Lemma 2.1. [<xref ref-type="bibr" rid="scirp.90187-ref5">5</xref>] Let N ≥ 1 and s ∈ ( 0 , 1 ) .Then for all u ∈ H s ( Ω ) we have</p><p>∫ ℝ N | ξ | 2 s | F ( u ) ( ξ ) | 2 d ξ = a N , s ∬ ℝ N &#215; ℝ N | u ( x ) − u ( y ) | 2 | x − y | N + 2 s d x d y , (2.11)</p><p>where a N , s is the constant defined in (1.3).</p><p>Proof. Fixed y we change coordinates z = x − y and apply Plancherel.</p><p>Recalling that ( u ( ⋅ + z ) ) ∧ ( ξ ) = e i ξ ⋅ z u ^ ( ξ ) we obtain</p><p>∬ | u ( x ) − u ( y ) | 2 | x − y | N + 2 s d x d y = ∫ ( ∫ | z | − ( N + 2 s ) | e i ξ ⋅ z − 1 | 2 d z ) | u ^ ( ξ ) | 2 d ξ (2.12)</p><p>The integral in brackets is of the form c N , s | ξ | 2 s , with</p><p>c N , s : = ∫ 0 ∞ ∫ S N − 1 | e i r ω ⋅ θ − 1 | 2 d θ r − 2 s − 1 d r = 2 ∫ 0 ∞ ( | S N − 1 | − ( 2π ) N / 2 r − ( N − 2 ) / 2 J ( N − 2 ) / 2 ( r ) ) r − ( 2 s + 1 ) d r (2.13)</p><p>where J ( N − 2 ) / 2 is the Bessel function of the first kind of order ( N − 2 ) / 2 , we can refer [<xref ref-type="bibr" rid="scirp.90187-ref6">6</xref>] .</p><p>Recall that | S N − 1 | = 2 π N / 2 / Γ ( N / 2 ) . The formula (1.3) for c N , s = a N , s − 1 now follows from</p><p>∫ 0 ∞ r − z ( J ( N − 2 ) / 2 ( r ) − 2 − ( N − 2 ) / 2 Γ ( N / 2 ) − 1 r ( N − 2 ) / 2 ) d r = 2 − z Γ ( ( N − 2 z ) / 4 ) Γ ( ( N + 2 z ) / 4 ) , (2.14)</p><p>for N / 2 &lt; Re z &lt; ( N + 4 ) / 2 , we can see [<xref ref-type="bibr" rid="scirp.90187-ref5">5</xref>] .</p><p>Lemma 2.2. [<xref ref-type="bibr" rid="scirp.90187-ref7">7</xref>] For s ∈ ( 0 , 1 ) , N ≥ 2 s , there exists a positive constant C = C ( N , s ) , for any u ∈ D s ( ℝ N ) ,we have</p><p>‖ u ‖ L 2 s ∗ ( ℝ N ) 2 ≤ C ∬ ℝ N &#215; ℝ N | u ( x ) − u ( y ) | 2 | x − y | N + 2 s d x d y , (2.15)</p><p>where 2 s ∗ = 2 N N − 2 s is called fractional critical Sobolev exponent. In particular, if u ∈ H 0 s ( Ω ) then</p><p>‖ u ‖ L 2 s ∗ ( Ω ) 2 ≤ C ∬ D Ω | u ( x ) − u ( y ) | 2 | x − y | N + 2 s d x d y . (2.16)</p><p>Lemma 2.3. (Egorov’s theorem) [<xref ref-type="bibr" rid="scirp.90187-ref8">8</xref>] Let f n be a sequence of functions and f be a function defined on E, with m e a s ( E ) &lt; + ∞ . Assume that f n → f a.e. in E. Then for every ε &gt; 0 there exists a measurable subset A of E such that m e a s ( E \ A ) &lt; ε and f n → f uniformly on A,as n → ∞ .<sup> </sup></p><p>Lemma 2.4. (Vitali) [<xref ref-type="bibr" rid="scirp.90187-ref9">9</xref>] Let f n be a sequence of functions and f be a function in L p ( Ω ) . Assume that</p><p>1) f n → f a.e. in Ω ;</p><p>2) if E is a measurable subset of Ω , and we have</p><p>lim m e a s ( E ) → 0 ∫ E | f n | p = 0 , (2.17)</p><p>uniformly with respect n. Where m e a s ( E ) means measure representing E. Then f n → f in L p ( Ω ) .</p><p>Proof. Fixed ε &gt; 0 , let E ⊂ Ω be a measurable set, we have</p><p>∫ Ω | f n − f | p ≤ ∫ ℝ N \ Ω | f n − f | p + 2 p − 1 ∫ E ( | f n | p + | f | p ) . (2.18)</p><p>Using assumption (2), we know that there exists δ 1 ( ε ) &gt; 0 such that, if m e a s ( E ) &lt; δ 1 ( ε ) , then for any n ∈ ℕ we have</p><p>∫ E | f n | p &lt; ε . (2.19)</p><p>Since f ∈ L p ( Ω ) there exists δ 2 ( ε ) &gt; 0 such that if m e a s ( E ) &lt; δ 2 ( ε ) , then</p><p>∫ E | f | p &lt; ε . (2.20)</p><p>In conclusion the second term of the right-hand side of (2.18) is less than 2 p ε . Let us study the first one. We set δ = min { δ 1 ( ε ) , δ 2 ( ε ) } , and use Egorov’s theorem, there exist v ε ∈ ℕ and a measurable set E 0 ⊂ Ω such that m e a s ( E 0 ) &lt; δ , and</p><p>∫ Ω \ E 0 | f n − f | p &lt; ε , (2.21)</p><p>for any n &gt; v ε .Choosing E = E 0 in(2.18), we get the result.</p><p>Lemma 2.5. (Stampacchia) [<xref ref-type="bibr" rid="scirp.90187-ref10">10</xref>] Let H be a Hilbert space, a : H &#215; H → ℝ is a continuous and linear form in the second variable such that</p><p>1) for β ∈ ℝ + ,any ψ 1 , ψ 2 , w ∈ H , we have</p><p>| a ( ψ 1 , w ) − a ( ψ 2 , w ) | ≤ β ‖ ψ 1 − ψ 2 ‖ ‖ w ‖ , (2.22)</p><p>2) for a positive constant C, any ψ 1 , ψ 2 ∈ H we have</p><p>a ( ψ 1 , ψ 1 − ψ 2 ) − a ( ψ 2 , ψ 1 − ψ 2 ) ≥ C ‖ ψ 1 − ψ 2 ‖ 2 . (2.23)</p><p>Lemma 2.6. (H&#246;lder inequality) [<xref ref-type="bibr" rid="scirp.90187-ref11">11</xref>] Let p and q are dual indicators, stisfies</p><p>1 / p + 1 / q = 1 ,</p><p>where 1 ≤ p ≤ ∞ , if f ∈ L p ( Ω ) , and g ∈ L q ( Ω ) , then the product of ( f g ) ( x ) = f ( x ) g ( x ) the defined function belongs to L 1 ( Ω ) , and we have</p><p>| ∫ Ω f g d x | ≤ ∫ Ω | f | | g | d x ≤ ‖ f ‖ p ‖ g ‖ q . (2.24)</p><p>If and only if there is a real constant m that makes the following formula hold</p><p>f g = e i m | f | | g | . (2.25)</p><p>The first unequal sign of (2.24) is established. If f not constant equals 0,then the second unequal sign of (2.24) is established, if and only if there exists a constant η ∈ ℝ , such that</p><p>1) if 1 &lt; p &lt; ∞ , then | g ( x ) | = η | f ( x ) | p − 1 μ a .e . ∈ Ω .</p><p>2) if p = 1 , then | g ( x ) | ≤ η μ a .e . ∈ Ω , and when f ( x ) ≠ 0 , we have | g ( x ) | = η .</p><p>3) if p = ∞ , then | f ( x ) | ≤ η μ a .e . ∈ Ω , and when g ( x ) ≠ 0 , we have | f ( x ) | = η .</p></sec><sec id="s3"><title>3. Proof of Theorem 1.1</title><p>Theorem 3.1. Let g : ℝ → ℝ be an increasing function, and g is Lipschitz continuous, that is, there exists a positive constant μ such that for any s , t ∈ ℝ we have</p><p>| g ( s ) − g ( t ) | ≤ μ | s − t | , (3.1)</p><p>Let f ∈ L m ( Ω ) , m ≥ 2 N N + 2 s . Then (1.1) exists a unique solution u ∈ H 0 s ( Ω ) .</p><p>Proof. We define the following form on H 0 s ( Ω ) &#215; H 0 s ( Ω ) :</p><p>a ( u , w ) = ∬ D Ω ( u ( x ) − u ( y ) ) ( w ( x ) − w ( y ) ) | x − y | N + 2 s d x d y + ∫ Ω g ( u ) w d x . (3.2)</p><p>Using H&#246;lder inequality and (3.1) we have</p><p>| a ( u , w ) | ≤ ∬ D Ω u ( x ) − u ( y ) | x − y | N + 2 s 2 ⋅ w ( x ) − w ( y ) | x − y | N + 2 s 2 d x d y + ∫ Ω [ μ | u | + g ( 0 ) ] | w | d x , (3.3)</p><p>that is, a is well defined. By the definition of a, we know that a is continuous and linear in the second variable. If w n → w in H 0 s ( Ω ) , then</p><p>∬ D Ω ( u ( x ) − u ( y ) ) ( w n ( x ) − w n ( y ) ) | x − y | N + 2 s d x d y → ∬ D Ω ( u ( x ) − u ( y ) ) ( w ( x ) − w ( y ) ) | x − y | N + 2 s d x d y , (3.4)</p><p>∫ Ω g ( u ) w n d x → ∫ Ω g ( u ) w d x . (3.5)</p><p>Since</p><p>| a ( u 1 , w ) − a ( u 2 , w ) | = | ∬ D Ω ( u 1 ( x ) − u 1 ( y ) ) ( w ( x ) − w ( y ) ) | x − y | N + 2 s d x d y − ∬ D Ω ( u 2 ( x ) − u 2 ( y ) ) ( w ( x ) − w ( y ) ) | x − y | N + 2 s d x d y | + | ∫ Ω [ g ( u 1 ) − g ( u 2 ) ] w d x | = | ∬ D Ω ( u 1 − u 2 ) ( x ) − ( u 1 − u 2 ) ( y ) | x − y | N + 2 s 2 ⋅ ( w 1 ) ( x ) − ( w 2 ) ( y ) | x − y | N + 2 s 2 | + | ∫ Ω [ g ( u 1 ) − g ( u 2 ) ] w d x | ≤ ‖ u 1 − u 2 ‖ H 0 s ( Ω ) ‖ w ‖ H 0 s ( Ω ) + μ ‖ u 1 − u 2 ‖ L 2 ( Ω ) ‖ w ‖ L 2 ( Ω ) , (3.6)</p><p>the last inequality following from H&#246;lder inequality and (3.1), by lemma 2.2</p><p>| a ( u 1 , w ) − a ( u 2 , w ) | ≤ ( 1 + μ C 2 ) ‖ u 1 − u 2 ‖ H 0 s ( Ω ) ‖ w ‖ H 0 s ( Ω ) . (3.7)</p><p>Since</p><p>a ( u 1 , u 1 − u 2 ) − a ( u 2 , u 1 − u 2 ) = ∬ D Ω | ( u 1 − u 2 ) ( x ) − ( u 1 − u 2 ) ( y ) | 2 | x − y | N + 2 s d x d y + ∫ Ω [ g ( u 1 ) − g ( u 2 ) ] ( u 1 − u 2 ) d x (3.8)</p><p>by (3.1)</p><p>∫ Ω [ g ( u 1 ) − g ( u 2 ) ] ( u 1 − u 2 ) d x ≥ 0 , (3.9)</p><p>then</p><p>a ( u 1 , u 1 − u 2 ) − a ( u 2 , u 1 − u 2 ) ≥ ‖ u 1 − u 2 ‖ H 0 s ( Ω ) 2 . (3.10)</p><p>We know that a satisfies lemma 2.4 from (3.2) and (3.10), the result follows from lemma 2.4.</p><p>We define the following function, for k &gt; 0 :</p><p>T k ( s ) = { − k ,   s ≤ − k , s , | s | ≤ k , k , s ≥ k . (3.11)</p><p>Proof of theorem 1.1: First, we proof the existence of a solution by approximation. Let g n ( t ) = T n ( g ( t ) ) , By theorem 3.1 we know that there exists u n ∈ H 0 s ( Ω ) be the solution to problems</p><p>{ ( − Δ ) s u n + g n ( u n ) = f ( x ) , x ∈ Ω , u n = 0 , x ∈ ℝ N \ Ω     . (3.12)</p><p>We use u n as a test function in (3.12), we get</p><p>‖ u n ‖ H 0 s ( Ω ) 2 + ∫ Ω u n g n ( u n ) d x = ∫ Ω f u n d x . (3.13)</p><p>Then use H&#246;lder inequality on the right-hand side implies</p><p>‖ u n ‖ H 0 s ( Ω ) 2 + ∫ Ω u n g n ( u n ) d x ≤ ( ∫ Ω f 2 N N + 2 s d x ) N + 2 s 2 N ( ∫ Ω u n 2 s ∗ d x ) 1 2 s ∗ = ‖ f ‖ L 2 N N + 2 s ( Ω ) ‖ u n ‖ L 2 s ∗ ( Ω ) . (3.14)</p><p>Because g is increasing, then ‖ u n ‖ H 0 s ( Ω ) 2 ≤ ‖ f ‖ L 2 N N + 2 s ( Ω ) ‖ u n ‖ L 2 s ∗ ( Ω ) . This means ‖ u n ‖ H 0 s ( Ω ) is uniformly bounded. We can deduce there exists u n → u weakly in H 0 s ( Ω ) and a.e., since ‖ u n ‖ H 0 s ( Ω ) 2 ≥ 0 , by (3.13) there exists a positive constant C such that</p><p>∫ Ω u n g n ( u n ) d x ≤ C , (3.14)</p><p>for every n.</p><p>Now we prove g n ( u n ) → g ( u ) in L 1 ( Ω ) . Since g is continuous in Ω then it is clear that g n ( u n ) → g ( u ) a.e. in Ω . If E is a subset of Ω , for t ∈ ℝ + have</p><p>∫ E | g n ( u n ) | = ∫ { x ∈ E : | u n ( x ) ≤ t | } | g n ( u n ) | + ∫ { x ∈ E : | u n ( x ) &gt; t | } | g n ( u n ) |   ≤ ∫ E | g n ( t ) | + 1 t ∫ { x ∈ E : | u n ( x ) &gt; t | } u n g ( u n )   ≤ | g ( t ) | m e a s ( E ) + C t , (3.15)</p><p>combining (3.14), for t ∈ ℝ + we have</p><p>lim m e a s ( E ) → 0 ∫ E | g n ( u n ) | ≤ C t . (3.16)</p><p>Using lemma 2.4, we know that g n ( u n ) → g ( u ) in L 1 ( Ω ) . Then for any ϕ ∈ H 0 s ( Ω ) ∩ L ∞ (Ω)</p><p>we from</p><p>∬ D Ω ( u n ( x ) − u n ( y ) ) ( ϕ ( x ) − ϕ ( y ) ) | x − y | N + 2 s d x d y + ∫ Ω g n ( u n ) ϕ d x = ∫ Ω f ϕ d x (3.17)</p><p>get</p><p>∬ D Ω ( u ( x ) − u ( y ) ) ( ϕ ( x ) − ϕ ( y ) ) | x − y | N + 2 s d x d y + ∫ Ω g ( u ) ϕ d x = ∫ Ω f ϕ d x . (3.18)</p><p>Finally we prove the solution of problem (1.1) is unique. We assume u 1 and u 2 are two solutions, u 1 ≠ u 2 , we take u 1 − u 2 as a test function</p><p>∬ D Ω ( u 1 ( x ) − u 1 ( y ) ) [ ( u 1 − u 2 ) ( x ) − ( u 1 − u 2 ) ( y ) ] | x − y | N + 2 s d x d y + ∫ Ω g ( u 1 ) ( u 1 − u 2 ) d x = ∫ Ω f ( u 1 − u 2 ) d x , (3.19)</p><p>∬ D Ω ( u 2 ( x ) − u 2 ( y ) ) [ ( u 1 − u 2 ) ( x ) − ( u 1 − u 2 ) ( y ) ] | x − y | N + 2 s d x d y + ∫ Ω g ( u 2 ) ( u 1 − u 2 ) d x = ∫ Ω f ( u 1 − u 2 ) d x . (3.20)</p><p>We can deduce from (3.19) and (3.20)</p><p>∬ D Ω [ u 1 ( x ) − u 1 ( y ) − u 2 ( x ) + u 2 ( y ) ] [ ( u 1 − u 2 ) ( x ) − ( u 1 − u 2 ) ( y ) ] | x − y | N + 2 s d x d y = ∫ Ω ( g ( u 1 ) − g ( u 2 ) ) ( u 1 − u 2 ) d x . (3.21)</p><p>This means</p><p>‖ u 1 − u 2 ‖ H 0 s ( Ω ) 2 = ∫ Ω ( g ( u 1 ) − g ( u 2 ) ) ( u 1 − u 2 ) d x . (3.22)</p><p>By the monotonicity of g we know</p><p>∫ Ω ( g ( u 1 ) − g ( u 2 ) ) ( u 1 − u 2 ) d x ≤ 0 . (3.23)</p><p>Combining (3.22) and (3.23) we know u 1 = u 2 a.e. in Ω .</p></sec><sec id="s4"><title>Conflicts of Interest</title><p>The author declares no conflicts of interest regarding the publication of this paper.</p></sec><sec id="s5"><title>Cite this paper</title><p>Liu, S.J. (2019) Existence and Uniqueness of Solution to Semilinear Fractional Elliptic Equation. Journal of Applied Mathematics and Physics, 7, 210-217. https://doi.org/10.4236/jamp.2019.71017</p></sec></body><back><ref-list><title>References</title><ref id="scirp.90187-ref1"><label>1</label><mixed-citation publication-type="other" xlink:type="simple">Tommaso, L., Ireneo, P., Ana, P. and Fernando, S. (2015) Basic Estimates for Solutions of a Class of Nonlocal Elliptic and Parabolic Equations. Discrete and Continuous Dynamical System, 35, 6031-6068.</mixed-citation></ref><ref id="scirp.90187-ref2"><label>2</label><mixed-citation publication-type="other" xlink:type="simple">Begona, B., Bonis, I.D. and Medina, M. 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