<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
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 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    jamp
   </journal-id>
   <journal-title-group>
    <journal-title>
     Journal of Applied Mathematics and Physics
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2327-4352
   </issn>
   <issn publication-format="print">
    2327-4379
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/jamp.2025.1310189
   </article-id>
   <article-id pub-id-type="publisher-id">
    jamp-146717
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    Closed Form Solution to the Hubble Tension Based on 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
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    </math> Cosmology for Generalized Cosmological Redshift Scaling of the Form: 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
       z
      </mi>
      <mo>
       =
      </mo>
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          (
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               <mn>
                0
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           <mo>
            /
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         <mo>
          )
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       <mi>
        x
       </mi> 
      </msup> 
      <mo>
       −
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       1
      </mn>
     </mrow> 
    </math> Tested against the Full Distance Ladder of Observed SN Ia Redshift
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Espen Gaarder
      </surname>
      <given-names>
       Haug
      </given-names>
     </name>
    </contrib>
   </contrib-group> 
   <aff id="affnull">
    <addr-line>
     aTempus Graviational Laboratory, Ås, Norway
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     10
    </day> 
    <month>
     10
    </month>
    <year>
     2025
    </year>
   </pub-date> 
   <volume>
    13
   </volume> 
   <issue>
    10
   </issue>
   <fpage>
    3293
   </fpage>
   <lpage>
    3307
   </lpage>
   <history>
    <date date-type="received">
     <day>
      3,
     </day>
     <month>
      September
     </month>
     <year>
      2025
     </year>
    </date>
    <date date-type="published">
     <day>
      25,
     </day>
     <month>
      September
     </month>
     <year>
      2025
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      25,
     </day>
     <month>
      October
     </month>
     <year>
      2025
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    Haug and Tatum have recently outlined a possible path to solving the Hubble tension within 
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     </mrow> 
    </math> cosmology models using a trial-and-error algorithm for redshift scaling, specifically 
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             </mi> 
             <mn>
              0
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            </msub> 
           </mrow> 
          </msub> 
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         <mo>
          /
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        </mrow> 
       </mrow> 
       <mo>
        )
       </mo>
      </mrow>
      <mo>
       −
      </mo>
      <mn>
       1
      </mn>
     </mrow> 
    </math> and 
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         <mo>
          )
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       <mrow> 
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         <mn>
          1
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        </mfrac> 
       </mrow> 
      </msup> 
      <mo>
       −
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     </mrow> 
    </math> . Their algorithm demonstrates that one can start with the measured CMB temperature and a rough estimate of 
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      <msub> 
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       </mi> 
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     </mrow> 
    </math> . Based on this approach, they nearly perfectly match the entire distance ladder of observed supernovae by identifying a single value for 
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      <msub> 
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      </msub> 
     </mrow> 
    </math> . This work replaces a previous numerical approach with a formal, closed-form mathematical solution. Furthermore, we will prove that this solution is valid for a much more general case of any cosmological redshift scaling consistent with: 
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      </mi>
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          (
         </mo> 
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           </mrow>
           <mo>
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           </mo>
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           </mrow>
          </mrow> 
         </mrow> 
         <mo>
          )
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        </mrow>
       </mrow> 
       <mi>
        x
       </mi> 
      </msup> 
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      </mo>
      <mn>
       1
      </mn>
     </mrow> 
    </math> . Haug and Tatum have only considered the most common assumptions of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
       x
      </mi>
      <mo>
       =
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       1
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     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
       x
      </mi>
      <mo>
       =
      </mo>
      <mfrac> 
       <mn>
        1
       </mn> 
       <mn>
        2
       </mn> 
      </mfrac> 
     </mrow> 
    </math> . Our solution involves simply solving an equation to determine the correct value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
        H
       </mi> 
       <mn>
        0
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      </msub> 
     </mrow> 
    </math> . This is possible because an exact mathematical relation between 
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      <msub> 
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        H
       </mi> 
       <mn>
        0
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      </msub> 
     </mrow> 
    </math> and the CMB temperature has recently been established, in combination with the linearity in an 
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    </math> model. We also demonstrate that a thermodynamic form of the Friedmann equation is consistent with a wide range of redshift scalings, namely: 
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     </mrow> 
    </math> .
   </abstract>
   <kwd-group> 
    <kwd>
     Hubble Tension Close Dorm
    </kwd> 
    <kwd>
      Hubble Constant
    </kwd> 
    <kwd>
      Cosmological Redshift
    </kwd> 
    <kwd>
      CMB Temperature
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. 

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    </math> Type Cosmological Models</title>
   <p>A series of interesting papers have been published in recent years <xref ref-type="bibr" rid="scirp.146717-1">
     [1]
    </xref>-<xref ref-type="bibr" rid="scirp.146717-3">
     [3]
    </xref> discussing the Hubble tension. Here, we take a closer look at a proposed solution to the Hubble tension within the Haug-Tatum 
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     </mrow> 
    </math> cosmological model. The Haug-Tatum model <xref ref-type="bibr" rid="scirp.146717-4">
     [4]
    </xref> <xref ref-type="bibr" rid="scirp.146717-5">
     [5]
    </xref> is unique in that it provides an exact mathematical relation between the CMB temperature, the Hubble constant, and the cosmological redshift. The Haug-Tatum cosmological model has evolved over time through multiple stages. It is consistent with the 
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        = 
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     </mrow> 
    </math> principle, which describes a universe expanding at the speed of light without accelerated expansion. Several 
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     </mrow> 
    </math> types of cosmological models exist, and they continue to be actively discussed in the recent literature; see, for example, <xref ref-type="bibr" rid="scirp.146717-6">
     [6]
    </xref>-<xref ref-type="bibr" rid="scirp.146717-9">
     [9]
    </xref>. Melia <xref ref-type="bibr" rid="scirp.146717-10">
     [10]
    </xref> has recently shown that 
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    </math> cosmology appears to be more consistent with observations from the James Webb Space Telescope than the ΛCDM model. The question of which cosmological model best accounts for different observed properties of the universe will undoubtedly remain an ongoing discussion in the years to come. This paper provides additional evidence in support of 
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    </math> cosmology, as it appears that a closed-form mathematical solution can resolve the Hubble tension within this framework.</p>
   <p>Standard cosmology is not able to predict the current CMB temperature, 
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    </math>, despite it being one of the best-determined cosmological parameters, measured with extremely high precision. This limitation, for example, has been clearly pointed out in the review article by Narlikar and Padmanabhan <xref ref-type="bibr" rid="scirp.146717-11">
     [11]
    </xref>: “The present theory is, however, unable to predict the value of 
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       T 
     </mi> 
    </math> at 
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     </mrow> 
    </math>. It is therefore a free parameter in SC (Standard Cosmology)”. Furthermore, they suggest that if one could link 
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    </math> to other physical processes in the universe, this would: “clearly mark an improvement over the standard interpretation”.</p>
   <p>In recent years, we have developed a new model based on Einstein’s general relativity theory that not only predicts 
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    </math> with remarkable precision but also mathematically links 
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    </math> to parameters such as 
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    </math>. This advancement even appears to resolve the Hubble tension, a result we will demonstrate both mathematically and experimentally in this paper.</p>
   <p>In 2015, Tatum et al. <xref ref-type="bibr" rid="scirp.146717-12">
     [12]
    </xref> heuristically presented the following formula for the Cosmic Microwave Background (CMB) temperature, which was later formally derived based on the Stefan-Boltzmann law <xref ref-type="bibr" rid="scirp.146717-13">
     [13]
    </xref> <xref ref-type="bibr" rid="scirp.146717-14">
     [14]
    </xref> by Haug and Wojnow <xref ref-type="bibr" rid="scirp.146717-15">
     [15]
    </xref> <xref ref-type="bibr" rid="scirp.146717-16">
     [16]
    </xref>:</p>
   <p>
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        <msqrt> 
         <mrow> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
          </msub> 
          <mn>
            2 
          </mn> 
          <msub> 
           <mi>
             l 
           </mi> 
           <mi>
             p 
           </mi> 
          </msub> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (1)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         k 
       </mi> 
       <mi>
         b 
       </mi> 
      </msub> 
     </mrow> 
    </math> is the Boltzmann constant and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         m 
       </mi> 
       <mi>
         p 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            ℏ 
          </mi> 
          <mi>
            c 
          </mi> 
         </mrow> 
         <mi>
           G 
         </mi> 
        </mfrac> 
       </mrow> 
      </msqrt> 
     </mrow> 
    </math> is the Planck mass, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         l 
       </mi> 
       <mi>
         p 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            G 
          </mi> 
          <mi>
            ℏ 
          </mi> 
         </mrow> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             3 
           </mn> 
          </msup> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
     </mrow> 
    </math> is the Planck length <xref ref-type="bibr" rid="scirp.146717-17">
     [17]
    </xref> <xref ref-type="bibr" rid="scirp.146717-18">
     [18]
    </xref>, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         c 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> is the Hubble radius and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mi>
         c 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          G 
        </mi> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> is the mass (equivalent) of the critical Friedmann <xref ref-type="bibr" rid="scirp.146717-19">
     [19]
    </xref> universe. The Stefan-Boltzmann law was developed basically for black bodies. The CMB temperature has been described as an almost perfect black body, see, for example, Muller et al. <xref ref-type="bibr" rid="scirp.146717-20">
     [20]
    </xref> state that:</p>
   <p>“Observations with the COBE satellite have demonstrated that the CMB corresponds to a nearly perfect black body characterized by a temperature 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> at 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>, which is measured with very high accuracy, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        2.72548 
      </mn> 
      <mo>
        ± 
      </mo> 
      <mn>
        0.00057 
      </mn> 
      <mi>
        k 
      </mi> 
     </mrow> 
    </math>”.</p>
   <p>Equation (1) has also recently been derived using a geometric mean approach; see <xref ref-type="bibr" rid="scirp.146717-21">
     [21]
    </xref>. Haug <xref ref-type="bibr" rid="scirp.146717-22">
     [22]
    </xref> has demonstrated that the CMB temperature can simply be written as:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mi>
          m 
        </mi> 
        <mi>
          b 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <msub> 
         <mi>
           T 
         </mi> 
         <mrow> 
          <mi>
            m 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            x 
          </mi> 
         </mrow> 
        </msub> 
        <msub> 
         <mi>
           T 
         </mi> 
         <mrow> 
          <mi>
            m 
          </mi> 
          <mi>
            i 
          </mi> 
          <mi>
            n 
          </mi> 
          <mo>
            , 
          </mo> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </msqrt> 
     </mrow> 
    </math> (2)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mrow> 
        <mi>
          m 
        </mi> 
        <mi>
          a 
        </mi> 
        <mi>
          x 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          ℏ 
        </mi> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mrow> 
        <mn>
          8 
        </mn> 
        <mi>
          π 
        </mi> 
        <msub> 
         <mi>
           l 
         </mi> 
         <mi>
           p 
         </mi> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> is the maximum possible Hawking <xref ref-type="bibr" rid="scirp.146717-23">
     [23]
    </xref> temperature, in other words, the temperature for a Planck mass black hole, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mrow> 
        <mi>
          m 
        </mi> 
        <mi>
          i 
        </mi> 
        <mi>
          n 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          ℏ 
        </mi> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mrow> 
        <mn>
          4 
        </mn> 
        <mi>
          π 
        </mi> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <msub> 
           <mi>
             H 
           </mi> 
           <mi>
             t 
           </mi> 
          </msub> 
         </mrow> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> is the Hawking temperature of the Hubble sphere, which is the minimum Hawking temperature. The geometric mean approach is consistent with the Hubble sphere operating as a Carnot <xref ref-type="bibr" rid="scirp.146717-24">
     [24]
    </xref> engine; see Haug <xref ref-type="bibr" rid="scirp.146717-25">
     [25]
    </xref> and also <xref ref-type="bibr" rid="scirp.146717-26">
     [26]
    </xref>-<xref ref-type="bibr" rid="scirp.146717-33">
     [33]
    </xref>.</p>
   <p>Additionally, Haug and Tatum <xref ref-type="bibr" rid="scirp.146717-4">
     [4]
    </xref> have demonstrated that to be consistent with the observed relation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         t 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          + 
        </mo> 
        <mi>
          z 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, see <xref ref-type="bibr" rid="scirp.146717-34">
     [34]
    </xref>-<xref ref-type="bibr" rid="scirp.146717-36">
     [36]
    </xref>, the predicted redshift seems like it must be given by:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mi>
               t 
             </mi> 
            </msub> 
           </mrow> 
          </msub> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> (3)</p>
   <p>However, they also show that one can have the more common 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <msub> 
           <mi>
             H 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
        </msub> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <msub> 
           <mi>
             H 
           </mi> 
           <mi>
             t 
           </mi> 
          </msub> 
         </mrow> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> scaling, but that this leads to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         t 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            + 
          </mo> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mn>
           2 
         </mn> 
        </mfrac> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>, which does not seem to be supported by observational studies. However, we must be careful here, as even in observational studies, there are often assumptions, or hidden assumptions, that need to be carefully revisited before prematurely drawing conclusions. In this paper, we will demonstrate that in a more general model with cosmological redshift scaling of the form:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mi>
                 t 
               </mi> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> (4)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> is what we can call the scaling factor, it is still possible to resolve the Hubble tension. The 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> is decided by assumption based on observations and logic, for example if one decide the cosmological scaling should be 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <msub> 
           <mi>
             H 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
        </msub> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <msub> 
           <mi>
             H 
           </mi> 
           <mi>
             t 
           </mi> 
          </msub> 
         </mrow> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> (a scaling used in multiple 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> models such as the Melia model) one simply set 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> or if one want 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mi>
               t 
             </mi> 
            </msub> 
           </mrow> 
          </msub> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> scaling one set 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math>, but one can also set 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> to any other value and still one will by solving an equation we soon will look at get the one and the same value for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> that seems to solves the Hubble tension. Technically, one could even make 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> time dependent 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>.</p>
   <p>It is important to be aware that we only claim to solve the Hubble tension inside a class of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmological models this way and not at all inside the Λ-CDM model. The 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> model of Haug and Tatum has many advantages over the Λ-CDM model, some of them listed in the recent paper <xref ref-type="bibr" rid="scirp.146717-37">
     [37]
    </xref>.</p>
   <p>For example, the Melia 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> model has a cosmological redshift corresponding to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> in our suggested general redshift scaling formula. Melia has however no equation for the relation between the CMB temperature now and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>. Haug and Tatum model B in <xref ref-type="bibr" rid="scirp.146717-4">
     [4]
    </xref> given above corresponds then to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math>, the Haug and Tatum model A <xref ref-type="bibr" rid="scirp.146717-4">
     [4]
    </xref> that has the same redshift scaling as the Melia model corresponds to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>, but this model is still different than the Melia model, as we in this have a tight mathematical relation between CMB temperature and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> that Melia does not have in his model.</p>
   <p>For the general redshift scaling Equation (4) to be consistent with the CMB temperature formula derived from the Stefan-Boltzmann law, we get the following relation for the CMB temperature now and in past cosmological epochs:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mi>
                 t 
               </mi> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> (5)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msubsup> 
             <mi>
               T 
             </mi> 
             <mi>
               t 
             </mi> 
             <mn>
               2 
             </mn> 
            </msubsup> 
           </mrow> 
           <mrow> 
            <msubsup> 
             <mi>
               T 
             </mi> 
             <mn>
               0 
             </mn> 
             <mn>
               2 
             </mn> 
            </msubsup> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> (6)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            z 
          </mi> 
          <mo>
            + 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            x 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           T 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           T 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (7)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         t 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            + 
          </mo> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            x 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> (8)</p>
   <p>Observations seem to favor a 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        ≈ 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math>, even if the exact value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> not yet is experimentally fully settled. We will not in this paper strongly conclude on the optimal scaling factor 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math>. The important point in this paper is that the Hubble tension itself seems to be solved for any scaling factor 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> in the closed-form solution we will soon present.</p>
   <p>Haug and Tatum demonstrate that the predicted redshift in one of their two models must satisfy:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          p 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          e 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mi>
               t 
             </mi> 
            </msub> 
           </mrow> 
          </msub> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mfrac> 
           <mi>
             c 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mrow> 
          <msup> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <mfrac> 
               <mrow> 
                <mi>
                  ℏ 
                </mi> 
                <mi>
                  c 
                </mi> 
               </mrow> 
               <mrow> 
                <msub> 
                 <mi>
                   T 
                 </mi> 
                 <mn>
                   0 
                 </mn> 
                </msub> 
                <mrow> 
                 <mo>
                   ( 
                 </mo> 
                 <mrow> 
                  <mn>
                    1 
                  </mn> 
                  <mo>
                    + 
                  </mo> 
                  <msub> 
                   <mi>
                     z 
                   </mi> 
                   <mrow> 
                    <mi>
                      o 
                    </mi> 
                    <mi>
                      b 
                    </mi> 
                    <mi>
                      s 
                    </mi> 
                    <mo>
                      , 
                    </mo> 
                    <mi>
                      i 
                    </mi> 
                   </mrow> 
                  </msub> 
                 </mrow> 
                 <mo>
                   ) 
                 </mo> 
                </mrow> 
                <msub> 
                 <mi>
                   k 
                 </mi> 
                 <mi>
                   b 
                 </mi> 
                </msub> 
                <mn>
                  4 
                </mn> 
                <mi>
                  π 
                </mi> 
               </mrow> 
              </mfrac> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <msub> 
             <mi>
               l 
             </mi> 
             <mi>
               p 
             </mi> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
      <mo>
        − 
      </mo> 
      <mn>
        1. 
      </mn> 
     </mrow> 
    </math> (9)</p>
   <p>Be aware that they do similar for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          p 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          e 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <msub> 
           <mi>
             H 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
        </msub> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <msub> 
           <mi>
             H 
           </mi> 
           <mi>
             t 
           </mi> 
          </msub> 
         </mrow> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> redshift scaling.</p>
   <p>They then use a smart trial-and-error algorithm, such as the Newton-Raphson method or the bisection method, to find the value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> that minimizes the sum of the prediction errors 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle displaystyle="true"> 
       <msubsup> 
        <mo>
          ∑ 
        </mo> 
        <mrow> 
         <mi>
           i 
         </mi> 
         <mo>
           = 
         </mo> 
         <mn>
           1 
         </mn> 
        </mrow> 
        <mi>
          n 
        </mi> 
       </msubsup> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             z 
           </mi> 
           <mrow> 
            <mi>
              p 
            </mi> 
            <mi>
              r 
            </mi> 
            <mi>
              e 
            </mi> 
            <mo>
              , 
            </mo> 
            <mi>
              i 
            </mi> 
           </mrow> 
          </msub> 
          <mo>
            − 
          </mo> 
          <msub> 
           <mi>
             z 
           </mi> 
           <mrow> 
            <mi>
              o 
            </mi> 
            <mi>
              b 
            </mi> 
            <mi>
              s 
            </mi> 
            <mo>
              , 
            </mo> 
            <mi>
              i 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             z 
           </mi> 
           <mrow> 
            <mi>
              o 
            </mi> 
            <mi>
              b 
            </mi> 
            <mi>
              s 
            </mi> 
            <mo>
              , 
            </mo> 
            <mi>
              i 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </mstyle> 
     </mrow> 
    </math>. They demonstrate that this approach leads to a single 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> value that perfectly matches the model with the full observed distance ladder, something that seems to solve the Hubble tension.</p>
   <p>However, here we simply solve Equation (9) for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>, which yields:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msubsup> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           k 
         </mi> 
         <mi>
           b 
         </mi> 
         <mn>
           2 
         </mn> 
        </msubsup> 
        <mn>
          32 
        </mn> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msub> 
         <mi>
           l 
         </mi> 
         <mi>
           p 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                o 
              </mi> 
              <mi>
                b 
              </mi> 
              <mi>
                s 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                p 
              </mi> 
              <mi>
                r 
              </mi> 
              <mi>
                e 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (10)</p>
   <p>In the case where the predicted redshift 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          p 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          e 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          i 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> is exactly equal to the observed redshift 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          o 
        </mi> 
        <mi>
          b 
        </mi> 
        <mi>
          s 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          i 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>, we must have 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                o 
              </mi> 
              <mi>
                b 
              </mi> 
              <mi>
                s 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                p 
              </mi> 
              <mi>
                r 
              </mi> 
              <mi>
                e 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>. Substituting 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                o 
              </mi> 
              <mi>
                b 
              </mi> 
              <mi>
                s 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                p 
              </mi> 
              <mi>
                r 
              </mi> 
              <mi>
                e 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> back into Equation (10) gives:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msubsup> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           k 
         </mi> 
         <mi>
           b 
         </mi> 
         <mn>
           2 
         </mn> 
        </msubsup> 
        <mn>
          32 
        </mn> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msub> 
         <mi>
           l 
         </mi> 
         <mi>
           p 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <msubsup> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mi>
        ℧ 
      </mi> 
     </mrow> 
    </math> (11)</p>
   <p>The last part, the Latin upsilon: 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ℧ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           k 
         </mi> 
         <mi>
           b 
         </mi> 
         <mn>
           2 
         </mn> 
        </msubsup> 
        <mn>
          32 
        </mn> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msub> 
         <mi>
           l 
         </mi> 
         <mi>
           p 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           k 
         </mi> 
         <mi>
           b 
         </mi> 
         <mn>
           2 
         </mn> 
        </msubsup> 
        <mn>
          32 
        </mn> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msqrt> 
         <mi>
           G 
         </mi> 
        </msqrt> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mrow> 
          <mrow> 
           <mn>
             3 
           </mn> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
        </msup> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mrow> 
          <mrow> 
           <mn>
             5 
           </mn> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>, is a composite constant made up of well-known constants (which we <xref ref-type="bibr" rid="scirp.146717-38">
     [38]
    </xref> <xref ref-type="bibr" rid="scirp.146717-39">
     [39]
    </xref> have coined 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℧ 
     </mi> 
    </math>). This is the same formula as given by <xref ref-type="bibr" rid="scirp.146717-38">
     [38]
    </xref>, but here we have for the first time just demonstrated that this formula is strictly valid only when the predicted redshift exactly matches the observed redshift, or as we soon will see we can use Equation (13) to match the full distance ladder of observed supernova redshifts by simply finding this one 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> value directly from the current measured CMB temperature.</p>
   <p>This means that we only need to know 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> and this Hubble constant to closely match all observed cosmological redshifts. The reason we say “close to perfect” rather than “perfect” is due to small measurement errors in both the measured CMB temperature and in 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       G 
     </mi> 
    </math>, and that is the only uncertainty in this method. The Boltzmann constant, the speed of light, and the reduced Planck constant have no uncertainty, as they have been exactly defined since the 2019 NIST CODATA standard.</p>
   <p>We can generalize this to any redshift scaling assumption 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          p 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          e 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mi>
                 t 
               </mi> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mi>
                 t 
               </mi> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> inside 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology, as long as we assume Equation (1), which has been derived from the Stefan-Boltzmann law, is correct, we then get:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          p 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          e 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mi>
                 t 
               </mi> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mfrac> 
             <mi>
               c 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mrow> 
            <msup> 
             <mrow> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <mfrac> 
                 <mrow> 
                  <mi>
                    ℏ 
                  </mi> 
                  <mi>
                    c 
                  </mi> 
                 </mrow> 
                 <mrow> 
                  <msub> 
                   <mi>
                     T 
                   </mi> 
                   <mn>
                     0 
                   </mn> 
                  </msub> 
                  <msup> 
                   <mrow> 
                    <mrow> 
                     <mo>
                       ( 
                     </mo> 
                     <mrow> 
                      <mn>
                        1 
                      </mn> 
                      <mo>
                        + 
                      </mo> 
                      <msub> 
                       <mi>
                         z 
                       </mi> 
                       <mrow> 
                        <mi>
                          o 
                        </mi> 
                        <mi>
                          b 
                        </mi> 
                        <mi>
                          s 
                        </mi> 
                        <mo>
                          , 
                        </mo> 
                        <mi>
                          i 
                        </mi> 
                       </mrow> 
                      </msub> 
                     </mrow> 
                     <mo>
                       ) 
                     </mo> 
                    </mrow> 
                   </mrow> 
                   <mrow> 
                    <mfrac> 
                     <mn>
                       1 
                     </mn> 
                     <mrow> 
                      <mn>
                        2 
                      </mn> 
                      <mi>
                        x 
                      </mi> 
                     </mrow> 
                    </mfrac> 
                   </mrow> 
                  </msup> 
                  <msub> 
                   <mi>
                     k 
                   </mi> 
                   <mi>
                     b 
                   </mi> 
                  </msub> 
                  <mn>
                    4 
                  </mn> 
                  <mi>
                    π 
                  </mi> 
                 </mrow> 
                </mfrac> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
             <mn>
               2 
             </mn> 
            </msup> 
            <mfrac> 
             <mn>
               1 
             </mn> 
             <mrow> 
              <mn>
                2 
              </mn> 
              <msub> 
               <mi>
                 l 
               </mi> 
               <mi>
                 p 
               </mi> 
              </msub> 
             </mrow> 
            </mfrac> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1. 
      </mn> 
     </mrow> 
    </math> (12)</p>
   <p>Solved for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> we get:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msubsup> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           k 
         </mi> 
         <mi>
           b 
         </mi> 
         <mn>
           2 
         </mn> 
        </msubsup> 
        <mn>
          32 
        </mn> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msub> 
         <mi>
           l 
         </mi> 
         <mi>
           p 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                o 
              </mi> 
              <mi>
                b 
              </mi> 
              <mi>
                s 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mi>
             x 
           </mi> 
          </mfrac> 
         </mrow> 
        </msup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                p 
              </mi> 
              <mi>
                r 
              </mi> 
              <mi>
                e 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mi>
             x 
           </mi> 
          </mfrac> 
         </mrow> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (13)</p>
   <p>when we have (or want) perfect prediction of redshift, we must have 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          p 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          e 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          i 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          o 
        </mi> 
        <mi>
          b 
        </mi> 
        <mi>
          s 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          i 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> and then we end up with 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                o 
              </mi> 
              <mi>
                b 
              </mi> 
              <mi>
                s 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mi>
             x 
           </mi> 
          </mfrac> 
         </mrow> 
        </msup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                p 
              </mi> 
              <mi>
                r 
              </mi> 
              <mi>
                e 
              </mi> 
              <mo>
                , 
              </mo> 
              <mi>
                i 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mi>
             x 
           </mi> 
          </mfrac> 
         </mrow> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> and therefore we must have:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msubsup> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           k 
         </mi> 
         <mi>
           b 
         </mi> 
         <mn>
           2 
         </mn> 
        </msubsup> 
        <mn>
          32 
        </mn> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msub> 
         <mi>
           l 
         </mi> 
         <mi>
           p 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (14)</p>
   <p>That is, for any scaling factor, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> one gets exactly the same 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> dependent on only the CMB temperature measured now, the Boltzmann constant, the Planck length, the speed of light and the Planck constant. The only variable is the CMB temperature that has been measured very precisely.</p>
  </sec><sec id="s2">
   <title>
    <xref ref-type="bibr" rid="scirp.146717-"></xref>2. Distance, Hubble Constant and Redshift</title>
   <p>If we solve the general redshift formula for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>, we get:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mi>
                 t 
               </mi> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math></p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         c 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <mi>
              z 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mi>
             x 
           </mi> 
          </mfrac> 
         </mrow> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        . 
      </mo> 
     </mrow> 
    </math> (15)</p>
   <p>This means the predicted distance to the observed redshift must be:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        − 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mi>
         c 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <mi>
              z 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mi>
             x 
           </mi> 
          </mfrac> 
         </mrow> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        − 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         c 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mi>
         c 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <mi>
              z 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mi>
             x 
           </mi> 
          </mfrac> 
         </mrow> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        − 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         c 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <msup> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <mn>
                1 
              </mn> 
              <mo>
                + 
              </mo> 
              <mi>
                z 
              </mi> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
           <mrow> 
            <mfrac> 
             <mn>
               1 
             </mn> 
             <mi>
               x 
             </mi> 
            </mfrac> 
           </mrow> 
          </msup> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (16)</p>
   <p>further if we solve this for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>, we get:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         c 
       </mi> 
       <mi>
         d 
       </mi> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <msup> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <mn>
                1 
              </mn> 
              <mo>
                + 
              </mo> 
              <mi>
                z 
              </mi> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
           <mrow> 
            <mfrac> 
             <mn>
               1 
             </mn> 
             <mi>
               x 
             </mi> 
            </mfrac> 
           </mrow> 
          </msup> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (17)</p>
   <p>Here, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        d 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        − 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> will be the estimated distance to the object emitting the photons. For very low redshift, we have 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        ≪ 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> and we can use the first term of the Taylor expansion to get:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        d 
      </mi> 
      <mo>
        ≈ 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mi>
          z 
        </mi> 
       </mrow> 
       <mrow> 
        <mi>
          x 
        </mi> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (18)</p>
   <p>and now solved for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       z 
     </mi> 
    </math>, we get:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        ≈ 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          x 
        </mi> 
        <mi>
          d 
        </mi> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
     </mrow> 
    </math> (19)</p>
   <p>In the case 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>, this is identical to the standard Λ-CDM cosmological redshift prediction formula approximation when used for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        ≪ 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>. Haug and Tatum examine both the special case of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>, where one obtains the standard distance formula when 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        ≪ 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>, and a model corresponding to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math>, which predicts twice the distance of Λ-CDM for low 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       z 
     </mi> 
    </math>. However, as we will soon demonstrate, any value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> can be used in the redshift scaling and still resolve the Hubble tension. The choice of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> therefore depends on other observations beyond predictions of the Hubble constant versus redshift. It is influenced by factors such as determining the optimal 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       β 
     </mi> 
    </math> in 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         t 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            + 
          </mo> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mi>
            β 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msup> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            + 
          </mo> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            x 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> in comparison with observed data; see, for example, <xref ref-type="bibr" rid="scirp.146717-40">
     [40]
    </xref>, which suggests that 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       β 
     </mi> 
    </math> should be close to 0. However, it is crucial to carefully examine the assumptions and methods used in any observational study to arrive at its results.</p>
   <p>Nevertheless, this is not the primary focus of this paper. The main discussion, as we will see in the next section, is that within the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology model presented here, any choice of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> can be used while still allowing us to match all observed SN Ia redshifts with a single 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> value. Most values of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math>, and likely all except one, should be ruled out based on other types of observations, such as the observed 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         t 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            + 
          </mo> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mi>
            β 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> scaling.</p>
   <p>In the Λ-CDM model, at least three different distances are considered for a given cosmological redshift: the comoving distance, the angular diameter distance, and the luminosity distance. These three distances differ from each other in the Λ-CDM model, which is fully consistent within the model and necessarily accounts for phenomena such as accelerated expansion. In 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmological models, however, there is no accelerated expansion, and in the Haug-Tatum cosmological model ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math>), the comoving, luminosity, and angular diameter distances are identical, see <xref ref-type="bibr" rid="scirp.146717-41">
     [41]
    </xref> for in detailed discussion on this point. We believe this is not a coincidence. Only the redshift scaling 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math> is consistent with 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         t 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          + 
        </mo> 
        <mi>
          z 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, and it is the only redshift scaling where the three distances—comoving, luminosity distance, and angular diameter distance—are identical. For any other 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math>, the three distances are not the same.</p>
   <p>Importantly, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math> is also consistent with the well-known Etherington equation <xref ref-type="bibr" rid="scirp.146717-42">
     [42]
    </xref>, which is based on purely geometrical principles linked to general relativity. Both the Λ-CDM model and the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> model used here are consistent with the Etherington equation: 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         D 
       </mi> 
       <mi>
         L 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            + 
          </mo> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
      <msub> 
       <mi>
         D 
       </mi> 
       <mi>
         A 
       </mi> 
      </msub> 
     </mrow> 
    </math>, where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         D 
       </mi> 
       <mi>
         L 
       </mi> 
      </msub> 
     </mrow> 
    </math> is the luminosity distance and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         D 
       </mi> 
       <mi>
         A 
       </mi> 
      </msub> 
     </mrow> 
    </math> is the angular diameter distance. In the next section, we will see how our model can match one of the largest databases of supernovae of type SN Ia while simultaneously predicting their distances. We suspect that the Λ-CDM model has become overly complex due to its three different distances for each observed 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mi>
         i 
       </mi> 
      </msub> 
     </mrow> 
    </math>. In 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology, things appear to be much simpler, and we are even able to match all the SN Ia with a single 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> parameter value, as we will explore next. The distance to cosmological redshifts is not the main topic of this article.</p>
  </sec><sec id="s3">
   <title>
    <xref ref-type="bibr" rid="scirp.146717-"></xref>3. Predictions Relative to the Observations Using the Full Distance Ladder from the PantheonPlus Compilation</title>
   <p>Here, we will see if our model can match all the observed cosmological redshifts by simply determining the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> constant from Equations (13) and (17). However, to demonstrate the superiority of Equations (13) and (17), we will first instead use the predicted value for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> by for example Riess <xref ref-type="bibr" rid="scirp.146717-43">
     [43]
    </xref> of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        73.04 
      </mn> 
      <mo>
        ± 
      </mo> 
      <mn>
        1.04 
      </mn> 
     </mrow> 
    </math> km/s/Mpc. We plot the Riess value, accounting for 2 Standard Deviations (STDs), and from this, we get <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>. The blue line represents the predicted redshift from 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        73.04 
      </mn> 
     </mrow> 
    </math> km/s/Mpc, while the green lines represent the 2 STD confidence interval, i.e., ±2 × 1.04 km/s/Mpc. We can see that even the 95% confidence interval falls outside the observations, meaning that any 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> value within this interval does not come close to matching the observed redshifts in our cosmological model.</p>
   <fig id="fig1" position="float">
    <label>Figure 1</label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.146717-"></xref>Figure 1. This figure shows observed redshift values from 2287 type Ia supernovae from PantheonPlusSH0ES, sorted by redshift (blue line). Based on the measured CMB temperature by Dhal et al. (2023) <xref ref-type="bibr" rid="scirp.146717-44">
       [44]
      </xref> of 2.725007 K, the blue line represents our predictions based on 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mi>
          
    H
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
  
        <mo>
         
   =
  
        </mo>
  
        <mn>
         
   73.04
  
        </mn>
 
       </mrow>

      </math> km/s/Mpc, and the green lines represent the 2 STD confidence interval ±2 × 1.04 km/s/Mpc. We find that the Riess 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mi>
          
    H
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
 
       </mrow>

      </math> value cannot match the observed redshifts in this 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mi>
          
    R
   
         </mi> 
   
         <mrow> 
    
          <msub> 
     
           <mi>
             H 
           </mi> 
     
           <mi>
             t 
           </mi> 
    
          </msub> 
   
         </mrow> 
  
        </msub> 
  
        <mo>
         
   =
  
        </mo>
  
        <mi>
         
   c
  
        </mi>
  
        <mi>
         
   t
  
        </mi>
 
       </mrow>

      </math> model.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724333-rId311.jpeg?20251030114157" />
   </fig>
   <p>
    <xref ref-type="fig" rid="fig2">
     Figure 2
    </xref> demonstrates the results we get when we instead calculate 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> based on Equation (11) when using the Dhal et al. <xref ref-type="bibr" rid="scirp.146717-44">
     [44]
    </xref> measured CMB value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        2.725007 
      </mn> 
      <mo>
        ± 
      </mo> 
      <mn>
        0.000024 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        K 
      </mtext> 
     </mrow> 
    </math>. According to our theory, this should provide a perfect match between the observed and predicted values, and as we can see, the observed and predicted values lie on top of each other. The confidence interval is now so narrow that even if we plotted it, it would appear to overlap with the observed values. The predicted 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        66.8712 
      </mn> 
      <mo>
        ± 
      </mo> 
      <mn>
        0.0019 
      </mn> 
     </mrow> 
    </math> km/s/Mpc when using this measured CMB temperature.</p>
   <fig id="fig2" position="float">
    <label>Figure 2</label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.146717-"></xref>Figure 2. This figure shows observed redshift values from 2287 type Ia supernovae, sorted by redshift (blue line). Based upon the measured CMB temperature by Dhal et al. (2023) <xref ref-type="bibr" rid="scirp.146717-44">
       [44]
      </xref> of 2.725007 K, the red line represents our predictions based on 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mi>
          
    H
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
  
        <mo>
         
   =
  
        </mo>
  
        <mn>
         
   66.8712
  
        </mn>
 
       </mrow>

      </math> km/s/Mpc, which we extracted from the data using Equation (11).</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724333-rId324.jpeg?20251030114157" />
   </fig>
   <p>
    <xref ref-type="fig" rid="fig3">
     Figure 3
    </xref> demonstrates the results we get when we calculate 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> based on Equation (14) when the measured CMB value of Fixsen <xref ref-type="bibr" rid="scirp.146717-45">
     [45]
    </xref>: 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        2.72548 
      </mn> 
      <mo>
        ± 
      </mo> 
      <mn>
        0.00057 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        K 
      </mtext> 
     </mrow> 
    </math>, this leads to a basically perfect match between predicted and observed SN Ia redshifts with a predicted 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        66.8943 
      </mn> 
      <mo>
        ± 
      </mo> 
      <mn>
        0.0287 
      </mn> 
     </mrow> 
    </math> km/s/Mpc.</p>
   <fig id="fig3" position="float">
    <label>Figure 3</label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.146717-"></xref>Figure 3. This figure shows observed redshift values from 2287 type Ia supernovae, sorted by redshift (blue line). Based upon the measured CMB temperature by Fixen (2009) <xref ref-type="bibr" rid="scirp.146717-45">
       [45]
      </xref> of 2.72548 K, the red line represents our predictions based on 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mi>
          
    H
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
  
        <mo>
         
   =
  
        </mo>
  
        <mn>
         
   66.8943
  
        </mn>
 
       </mrow>

      </math> km/s/Mpc calculated from Equation (11).</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724333-rId333.jpeg?20251030114157" />
   </fig>
   <p>It is important to understand that the results in this section are independent of the value selected for the scaling factor 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> in 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
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        <mrow> 
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           ( 
         </mo> 
         <mrow> 
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           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mi>
                 t 
               </mi> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> in our 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology.</p>
  </sec><sec id="s4">
   <title>
    <xref ref-type="bibr" rid="scirp.146717-"></xref>4. The New Thermodynamic Friedmann Equation Consistent with the General Redshift Scaling of the Form 

    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
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   z
  
      </mi>
  
      <mo>
       
   =
  
      </mo>
  
      <msup> 
   
       <mrow> 
    
        <mrow>
     
         <mo>
           ( 
         </mo> 
     
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mn>
                 0 
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              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
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              <msub> 
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                 H 
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                 t 
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          </mfrac> 
         </mrow> 
     
         <mo>
           ) 
         </mo>
    
        </mrow>
   
       </mrow> 
   
       <mi>
        
    x
   
       </mi> 
  
      </msup> 
  
      <mo>
       
   −
  
      </mo>
  
      <mn>
       
   1
  
      </mn>
 
     </mrow>

    </math></title>
   <p>Haug and Tatum <xref ref-type="bibr" rid="scirp.146717-46">
     [46]
    </xref> have recently demonstrated that the critical Friedmann <xref ref-type="bibr" rid="scirp.146717-19">
     [19]
    </xref> equation:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          8 
        </mn> 
        <mi>
          π 
        </mi> 
        <mi>
          G 
        </mi> 
        <mi>
          ρ 
        </mi> 
       </mrow> 
       <mn>
         3 
       </mn> 
      </mfrac> 
     </mrow> 
    </math> (20)</p>
   <p>can be rewritten in thermodynamical form:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
       <mn>
         4 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           4 
         </mn> 
        </msup> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          G 
        </mi> 
        <mi>
          ρ 
        </mi> 
       </mrow> 
       <mrow> 
        <mn>
          384 
        </mn> 
        <msubsup> 
         <mi>
           k 
         </mi> 
         <mi>
           b 
         </mi> 
         <mn>
           4 
         </mn> 
        </msubsup> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
        <msubsup> 
         <mi>
           l 
         </mi> 
         <mi>
           p 
         </mi> 
         <mn>
           2 
         </mn> 
        </msubsup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           5 
         </mn> 
        </msup> 
        <mi>
          ρ 
        </mi> 
       </mrow> 
       <mrow> 
        <mn>
          384 
        </mn> 
        <msubsup> 
         <mi>
           k 
         </mi> 
         <mi>
           b 
         </mi> 
         <mn>
           4 
         </mn> 
        </msubsup> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (21)</p>
   <p>Keep in mind that when doing the caculations that 
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      <mi>
        G 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           l 
         </mi> 
         <mi>
           p 
         </mi> 
         <mn>
           2 
         </mn> 
        </msubsup> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
       <mi>
         ℏ 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>, something we get by simply solving the Planck length formula 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         l 
       </mi> 
       <mi>
         p 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            G 
          </mi> 
          <mi>
            ℏ 
          </mi> 
         </mrow> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             3 
           </mn> 
          </msup> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
     </mrow> 
    </math>, see also <xref ref-type="bibr" rid="scirp.146717-47">
     [47]
    </xref>.</p>
   <p>Here, we will generalize this to</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
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         4 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
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         <mn>
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           5 
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        </msup> 
        <mi>
          ρ 
        </mi> 
       </mrow> 
       <mrow> 
        <mn>
          384 
        </mn> 
        <msubsup> 
         <mi>
           k 
         </mi> 
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         </mi> 
         <mn>
           4 
         </mn> 
        </msubsup> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           3 
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        </msup> 
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      </mfrac> 
      <mfrac> 
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              1 
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              + 
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            <msub> 
             <mi>
               z 
             </mi> 
             <mrow> 
              <mi>
                p 
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              <mo>
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              </mo> 
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             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             ) 
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         </mrow> 
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              1 
            </mn> 
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              + 
            </mo> 
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               z 
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              </mi> 
              <mi>
                b 
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           </mi> 
          </mfrac> 
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     </mrow> 
    </math> (22)</p>
   <p>and when 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
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       <mi>
         z 
       </mi> 
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          , 
        </mo> 
        <mi>
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        </mi> 
       </mrow> 
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    </math> this will simply reduce to (21). We have simply replaced 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
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       <mn>
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    </math> with 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
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       </mn> 
      </msubsup> 
      <mfrac> 
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         <mi>
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        </msubsup> 
        <mn>
          32 
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           2 
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         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </mfrac> 
      <mfrac> 
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        </msup> 
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      </mfrac> 
     </mrow> 
    </math>. However, when 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          p 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          e 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          i 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          o 
        </mi> 
        <mi>
          b 
        </mi> 
        <mi>
          s 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          i 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> we end up getting Equation (21), which demonstrates that the thermodynamic form of the Haug and Tatum equation is very general and robust, it is valid for a wide range of redshift scaling choices (the choice of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math>) inside 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology.</p>
   <p>From the sections above, it is clear that this thermodynamic Friedmann equation is valid and identical for any 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> scaling factors in 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mi>
                 t 
               </mi> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>, as they all lead to the exactly same 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> when 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          p 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          e 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        → 
      </mo> 
      <msub> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mi>
          o 
        </mi> 
        <mi>
          b 
        </mi> 
        <mi>
          s 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>.</p>
   <p>More importantly, the thermodynamic Friedmann equation, when carefully studied in relation to our empirical and theoretical work, clearly seems to present a solution to the Hubble tension. However, further discussions and testing by many other researchers are needed before a consensus can be reached. We hope the research community is open-minded enough to carefully consider this possibility and not simply ignore it due to biases based on the current consensus model, where the Hubble tension has yet to be solved.</p>
  </sec><sec id="s5">
   <title>
    <xref ref-type="bibr" rid="scirp.146717-"></xref>5. The Preferred Value for x Based on Other Observations</title>
   <p>Even if we can essentially perfectly match all SN Ia in our model for “any” value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math> with the same single value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        66.8712 
      </mn> 
      <mo>
        ± 
      </mo> 
      <mn>
        0.0019 
      </mn> 
     </mrow> 
    </math> km/s/Mpc, there are other important aspects that a good cosmological model must also fit. Only when we have 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math> in our model that is fully consistent with the observationally confirmed relation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         t 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          + 
        </mo> 
        <mi>
          z 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>. At the moment, it seems that 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math> is favored. However, this should be investigated further, as many other aspects of the observed cosmos must also fit the model.</p>
   <p>We also have to remember that this solution is only valid within the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> principle. More research also needs to be done to compare 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology with the Λ-CDM model and other alternatives. We have already compared a series of properties in the two models, where the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> appears to outperform the Λ-CDM model; see Haug and Tatum <xref ref-type="bibr" rid="scirp.146717-37">
     [37]
    </xref>.</p>
  </sec><sec id="s6">
   <title>
    <xref ref-type="bibr" rid="scirp.146717-"></xref>6. Conclusions</title>
   <p>Haug and Tatum have outlined a way to solve the Hubble tension inside 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology based on new exact relations between the CMB temperature, the Hubble constant and redshift, they however use a numerical search algorithm to do so and have only considered 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mrow> 
            <msub> 
             <mi>
               H 
             </mi> 
             <mi>
               t 
             </mi> 
            </msub> 
           </mrow> 
          </msub> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <mi>
            H 
          </mi> 
          <mn>
            0 
          </mn> 
         </mrow> 
        </msub> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <mi>
            H 
          </mi> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> cosmological redshift scaling. Even if their method is intuitive and powerful, we here demonstrate that one can simply solve one of their equations and further based on logic, get to the one single 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> value that makes their model match all observed SN Ia. In other words, this leads to a closed-form mathematical solution of the Hubble tension inside 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology. We get a 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        66.8712 
      </mn> 
      <mo>
        ± 
      </mo> 
      <mn>
        0.0019 
      </mn> 
     </mrow> 
    </math> km/s/Mpc when relying on the very precise. Dhal et al. <xref ref-type="bibr" rid="scirp.146717-44">
     [44]
    </xref> measured CMB value matching, leading to matching all the observed SN Ia redshifts across the full distance ladder in the PantheonPlusSH0ES compilation. This is the same value Haug and Tatum got from their numerical search algorithm solution when solving the Hubble tension. It is basically the same solution; one is using numerical search algorithm while the latter uses closed-form solution. The closed form solution is naturally more elegant as no numerical search routine with many calculations are needed to find the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> that matches all the supernovas. Further, the solution in this paper is generalized for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               R 
             </mi> 
             <mrow> 
              <msub> 
               <mi>
                 H 
               </mi> 
               <mi>
                 t 
               </mi> 
              </msub> 
             </mrow> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         x 
       </mi> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> cosmological scaling, while Haug and Tatum have only considered the case equivalent to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math>.</p>
   <p>So, it looks like we have a path to solving the Hubble tension in 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology, but this does not solve the Hubble tension inside Λ-CDM cosmology. Further investigation between 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           H 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> cosmology and Λ-CDM cosmology is therefore warranted.</p>
  </sec><sec id="s7">
   <title>Data Availability Statements</title>
   <p>The supernova PantheonPlusSH0ES database that we have used can be found here: <xref ref-type="bibr" rid="scirp.146717-https://github.com/PantheonPlusSH0ES/DataRelease/blob/main/Pantheon%2B_Data/1_DATA/all_redshifts_PVs.csv">
     https://github.com/PantheonPlusSH0ES/DataRelease/blob/main/Pantheon%2B_Data/1_DATA/all_redshifts_PVs.csv
    </xref>.</p>
  </sec>
 </body><back>
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