<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    jamp
   </journal-id>
   <journal-title-group>
    <journal-title>
     Journal of Applied Mathematics and Physics
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2327-4352
   </issn>
   <issn publication-format="print">
    2327-4379
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/jamp.2025.134072
   </article-id>
   <article-id pub-id-type="publisher-id">
    jamp-142135
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    A Mathematical and Computational Model for Multiple COVID-19 Waves Applied to Kenya
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Wandera
      </surname>
      <given-names>
       Ogana
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff1"> 
      <sup>1</sup>
     </xref> 
     <xref ref-type="aff" rid="aff2"> 
      <sup>2</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Victor Ogesa
      </surname>
      <given-names>
       Juma
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff1"> 
      <sup>1</sup>
     </xref> 
     <xref ref-type="aff" rid="aff3"> 
      <sup>3</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Wallace D.
      </surname>
      <given-names>
       Bulimo
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff4"> 
      <sup>4</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Vincent Nandwa
      </surname>
      <given-names>
       Chiteri
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff1"> 
      <sup>1</sup>
     </xref>
    </contrib>
   </contrib-group> 
   <aff id="aff1">
    <addr-line>
     aDepartment of Mathematics, University of Nairobi, Nairobi, Kenya
    </addr-line> 
   </aff> 
   <aff id="aff2">
    <addr-line>
     aAfrican Mathematics Millennium Science Initiative, Nairobi, Kenya
    </addr-line> 
   </aff> 
   <aff id="aff3">
    <addr-line>
     aMathematics Department, University of British Columbia, Vancouver, Canada
    </addr-line> 
   </aff> 
   <aff id="aff4">
    <addr-line>
     aCentre for Virus Research and the Department of Epidemiology, Statistics and Informatics, Kenya Medical Research Institute, Nairobi, Kenya
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     03
    </day> 
    <month>
     04
    </month>
    <year>
     2025
    </year>
   </pub-date> 
   <volume>
    13
   </volume> 
   <issue>
    04
   </issue>
   <fpage>
    1323
   </fpage>
   <lpage>
    1351
   </lpage>
   <history>
    <date date-type="received">
     <day>
      5,
     </day>
     <month>
      February
     </month>
     <year>
      2025
     </year>
    </date>
    <date date-type="published">
     <day>
      20,
     </day>
     <month>
      February
     </month>
     <year>
      2025
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      20,
     </day>
     <month>
      April
     </month>
     <year>
      2025
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    COVID-19 is a disease caused by the novel coronavirus SARS-CoV-2 that emerged at the end of December 2019 and has since spread globally. In Kenya, the virus was first detected on 13
    <sup>th</sup> March 2020. Soon after, the Kenyan government implemented non-pharmaceutical interventions (NPIs) to slow the spread of the disease. The pandemic continued to spread and it evolved into several waves over the years despite the discovery of vaccines and treatment. Mathematical models have been developed to help analyse, predict and simulate the dynamics of the pandemic. These models have largely been confined to single waves, without ready extension to multiple waves. In this paper, we develop a mathematical and computational model that can be extended to multiple waves using various concepts. Among these is the application of computational techniques that convert infection curves with negative gradients to those with positive gradients, in the neighbourhood of the change point, namely, where transition occurs from one wave to the next. This effectively generates a new wave. We then introduce a jump mechanism for the susceptible fraction, allowing further computation to align itself with the observed infection curve. To commence the process, we solved the system of governing ordinary differential equations for the period the epidemic spread without intervention and obtained values for the transmission, recovery and death rates that yielded the basic reproduction number, 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
        ℛ
       </mi> 
       <mn>
        0
       </mn> 
      </msub> 
      <mo>
       =
      </mo>
      <mn>
       2.76
      </mn>
     </mrow> 
    </math> , which is consistent with other related research. We then applied our model to COVID-19 in Kenya and the computation successfully replicated all the waves and also identified the change points located within the months when COVID-19 variants became dominant. The findings strengthen the proposition that the dominant COVID-19 variants were the major drivers of the waves. The techniques can be extended to new strains of COVID-19, influenza and other respiratory viruses.
   </abstract>
   <kwd-group> 
    <kwd>
     Mathematical Model
    </kwd> 
    <kwd>
      COVID-19 Pandemic
    </kwd> 
    <kwd>
      Non-Pharmaceutical Interventions
    </kwd> 
    <kwd>
      Delay-Functions
    </kwd> 
    <kwd>
      Multiple Waves
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>COVID-19 is a disease caused by the novel coronavirus SARS-CoV-2 that emerged at the end of December 2019 and has since spread globally. The disease has hurt the socioeconomic and health structures of many countries. In Kenya, the virus was first detected on 13<sup>th</sup> March 2020. Soon after, the Kenyan government implemented non-pharmaceutical interventions (NPIs) to slow the spread of the disease <xref ref-type="bibr" rid="scirp.142135-1">
     <a href="#ref1">[1]</a>
    </xref>. Due to low compliance by the public and a rapid rise in infection, the government imposed more stringent measures that remained in effect from 9<sup>th</sup> April 2020 to 8<sup>th</sup> June 2020. Enforcement of the measures adversely affected the country’s economy and people’s livelihoods. Consequently, the government gradually relaxed some of the mitigation measures during the period from 9<sup>th</sup> June 2020 to 8<sup>th</sup> August 2020. Up to this stage, the COVID-19 dynamics was largely influenced by the NPIs imposed by the government <xref ref-type="bibr" rid="scirp.142135-1">
     [1]
    </xref>. The daily infections continued to go down but suddenly they started to increase in September 2020, fuelled primarily by the 2<sup>nd</sup> wave of COVID-19. As in many countries, the pandemic in Kenya continued to oscillate in uneven waves of varying amplitudes that were driven by various factors, such as new variants of concern <xref ref-type="bibr" rid="scirp.142135-2">
     <a href="#ref2">[2]</a>
    </xref>, NPIs <xref ref-type="bibr" rid="scirp.142135-3">
     [3]
    </xref> <xref ref-type="bibr" rid="scirp.142135-4">
     [4]
    </xref>, vaccines and therapy <xref ref-type="bibr" rid="scirp.142135-5">
     [5]
    </xref> <xref ref-type="bibr" rid="scirp.142135-6">
     [6]
    </xref>, human behaviour <xref ref-type="bibr" rid="scirp.142135-7">
     [7]
    </xref>, health system status <xref ref-type="bibr" rid="scirp.142135-8">
     [8]
    </xref>, and host sensitivity to the virus and disease <xref ref-type="bibr" rid="scirp.142135-9">
     <a href="#ref9">[9]</a>
    </xref> <xref ref-type="bibr" rid="scirp.142135-10">
     <a href="#ref10">[10]</a>
    </xref>, among others.</p>
   <p>The pandemic stimulated extensive research by collaborators from many disciplines determined to address the challenges posed by the disease. Mathematical models were developed to analyse, predict and simulate the dynamics of the pandemic, taking into consideration the myriad drivers <xref ref-type="bibr" rid="scirp.142135-11">
     <a href="#ref11">[11]</a>
    </xref> <xref ref-type="bibr" rid="scirp.142135-12">
     [12]
    </xref>. Most widespread are compartmental models in which the human population is traditionally divided into five compartments, namely Susceptible (S), Exposed (E), Infected (I), Recovered (R) and Dead (D) <xref ref-type="bibr" rid="scirp.142135-11">
     [11]
    </xref>-<xref ref-type="bibr" rid="scirp.142135-14">
     <a href="#ref14">[14]</a>
    </xref>. By considering the rate of change of individuals in a compartment, and the contribution of appropriate compartments to this change, we obtain a system of ordinary differential equations, containing parameters that define the rate of flow between adjacent compartments. Models that use all of the compartments are called SEIRD. Various acronyms arise, depending on which compartments are in use. The effects of the COVID-19 drivers may be incorporated by creating additional compartments, for example, asymptomatic spread <xref ref-type="bibr" rid="scirp.142135-9">
     [9]
    </xref> <xref ref-type="bibr" rid="scirp.142135-10">
     [10]
    </xref>, mask-wearing <xref ref-type="bibr" rid="scirp.142135-15">
     [15]
    </xref>, quarantine, vaccination and hospitalization <xref ref-type="bibr" rid="scirp.142135-14">
     [14]
    </xref> <xref ref-type="bibr" rid="scirp.142135-16">
     [16]
    </xref>-<xref ref-type="bibr" rid="scirp.142135-18">
     [18]
    </xref>, asymptomatic and varying symptoms <xref ref-type="bibr" rid="scirp.142135-9">
     [9]
    </xref> <xref ref-type="bibr" rid="scirp.142135-10">
     [10]
    </xref> <xref ref-type="bibr" rid="scirp.142135-19">
     [19]
    </xref>, and social distancing <xref ref-type="bibr" rid="scirp.142135-20">
     [20]
    </xref>. This leads to more complicated systems with more ordinary differential equations and increased numbers of parameters. These models can replicate sub-waves and spikes, due to the NPIs, but they cannot be used to determine how one major wave develops from another.</p>
   <p>The emergence of several COVID-19 waves emphasized the need to investigate how these waves developed and whether it was possible to predict their growth and the emergence of future waves. A few compartmental models have made some attempts in this direction. Perakis et al. <xref ref-type="bibr" rid="scirp.142135-21">
     <a href="#ref21">[21]</a>
    </xref> apply the discrete version of the SEIRD model and identify a time, called the change point, that marks the end of one wave and the beginning of the next. They postulate that the recovery and infection rates have jump values at the change point. The method describes well the spikes in one wave but it is less successful in generating another wave. The approach by Ghosh and Ghosh <xref ref-type="bibr" rid="scirp.142135-22">
     <a href="#ref22">[22]</a>
    </xref> is based on the assumption that the susceptible fraction increases now and again by multiple re-infection of people who have recovered. To achieve this, they add a delay term of the infection, multiplied by a parameter regarded as the rate of re-susceptibility, to the equation involving the Susceptible rate. The same term is subtracted from the equation involving the rate of change of those removed from the system. The results provide a good match for the data from India for a few selected waves. Leonov et al. <xref ref-type="bibr" rid="scirp.142135-23">
     <a href="#ref23">[23]</a>
    </xref> use the SEI model, with the parameters assumed to be piecewise constant. They add an arbitrary function of time to the equation involving the rate of change of infection. This additional term can be considered as a source of infections associated with all other miscellaneous sources. The final solution is obtained from the inverse problem. The method replicates spikes well but it leads to large errors when the gradients of the infection are large, as would be the case involving a new wave. Despite these early efforts, there is still a need for research in this area to come up with reliable and more efficient methods.</p>
   <p>The overall aim of this study is to generate the fore section of the current computed wave, from a previous wave, and to apply appropriate conditions that ensure that the model of the whole wave provides the best fit to the data. We apply the techniques to the SIRD system by using the method in <xref ref-type="bibr" rid="scirp.142135-1">
     [1]
    </xref>, together with new concepts in a version of this manuscript which has previously been published as a preprint <xref ref-type="bibr" rid="scirp.142135-24">
     [24]
    </xref>. To start, we noted that the computed solution of the SIRD system, in the absence of subsequent interventions, has an infection curve that dissipates with time. In addition, a new wave is formed when the observed infection curve diverges from the dissipating computed infection curve. The point of divergence gives us an approximation to the change point, namely the point at which one wave ends and another starts. We then computationally generate the fore section of a new wave by application of a large relaxation force in the neighbourhood of the change point. Some observed infection curves for new waves emanate from a change point in the neighbourhood of which the infection fractions are very low and the susceptible fractions are almost constant. The fore sections of such curves can be approximated by an exponential function. Once the fore section of the current computed wave is generated, we apply a procedure that introduces a jump in the susceptible fraction and perpetuates the growth of a wave in the right direction. Mitigation or relaxation is then undertaken, as appropriate, to yield the rest of the wave. Using these findings, we have simulated all the COVID-19 waves in Kenya.</p>
   <p>We present the paper according to the following outline. In Section 2.1, we describe the SIRD model and present its baseline solution. Section 2.2 contains the derivation of the equations that describe the effects of intervention on the transmission rate. Section 2.3 has a review of the results for the 1<sup>st</sup> wave as obtained in <xref ref-type="bibr" rid="scirp.142135-25">
     <a href="#ref25">[25]</a>
    </xref>. In section 2.4 we present the detailed models of the 2<sup>nd</sup> to 5<sup>th</sup> waves, starting with the generation of a wave through application of a sufficiently large relaxation. In Section 2.5 we present the detailed models of the 6<sup>th</sup> and 7<sup>th</sup> waves, starting with the generation of a wave by assuming exponential infection. In Section 2.6 we introduce error metrics. Section 3.1 contains results and a discussion of the modelled 1<sup>st</sup> wave compared with observation. Section 3.2 contains results and a discussion of the modelled 2<sup>nd</sup> to 5<sup>th</sup> waves compared with observation. Section 3.3 contains results and a discussion of the modelled 6<sup>th</sup> and 7<sup>th</sup> waves compared with observation. Consolidated results for all the waves are presented in Section 3.4. Finally, we give a few concluding remarks and recommendations in Section 4.</p>
  </sec><sec id="s2">
   <title>2. Methods</title>
   <p>In this section, we first present the equations for the SIRD model and their baseline solutions. We then summarize the equations that describe the effects of interventions on the disease transmission rate and indicate their impact on development of the 1<sup>st</sup> wave. We present computational results of the effect of applying large relaxation forces at a point where infection decreases, in the neighbourhood of transition from one wave to another. The results form the basis of generating the 2<sup>nd</sup> to 5<sup>th</sup> COVID-19 waves in Kenya. Finally, we derive the equations for the generation of the 6<sup>th</sup> and 7<sup>th</sup> waves.</p>
   <sec id="s2_1">
    <title>2.1. Baseline Dynamics by SIRD model and present its baseline solution</title>
    <p>From the SEIRD compartmental model, we omit the Exposed (E) compartment and remain with the SIRD model and present its baseline solution, where the population is divided into four basic classes, namely: Susceptible (S), Infected (I), Recovered (R) and Dead (D). We assume homogeneous mixing through the population and that the total population, N, is constant over time. Let β be the infection transmission rate from the susceptible to the infected compartment, γ be the recovery rate from the infected to the recovered compartment, and δ the death rate from the infected to the dead compartment. The governing equations are <xref ref-type="bibr" rid="scirp.142135-1">
      [1]
     </xref> <xref ref-type="bibr" rid="scirp.142135-13">
      [13]
     </xref> <xref ref-type="bibr" rid="scirp.142135-25">
      [25]
     </xref></p>
    <p>
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    <p>where 
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     </math> represent the fractions of individuals in the susceptible, infected, recovered and dead compartments, respectively, at any time t. System (1) is solved subject to the initial conditions</p>
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       <msub> 
        <mi>
          D 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math> are the initial fractions of the susceptible, infected, recovered and dead individuals, respectively. System (1) is also solved subject to the condition of constant total population that can be put in the form</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         + 
       </mo> 
       <mi>
         I 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         + 
       </mo> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         + 
       </mo> 
       <mi>
         D 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         1 
       </mn> 
      </mrow> 
     </math> (3)</p>
    <p>The unknown parameters 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        β 
      </mi> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        γ 
      </mi> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        δ 
      </mi> 
     </math> are determined by model fitting of System (1) to COVID-19 data through optimization.</p>
    <p>COVID-19 was first detected in Kenya on 13<sup>th</sup> March 2020 and it spread till 8<sup>th</sup> April 2020 before any measures were undertaken to control the spread of the disease. This period served as the time during which the disease spread without any intervention and baseline data was being collected. With the death rate, δ = 0.015, approximated from the Case Fatality Rate (CFR), model fitting of System (1) yielded the following values for the remaining parameters during the baseline period <xref ref-type="bibr" rid="scirp.142135-25">
      [25]
     </xref>.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         γ 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         0.0518939 
       </mn> 
       <mo>
         , 
       </mo> 
       <mtext>
           
       </mtext> 
       <mi>
         β 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         0.184618 
       </mn> 
      </mrow> 
     </math> (4)</p>
    <p>From Equation (4) we obtain the reproduction number, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ℛ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math>, and the Recovery Days, given by</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ℛ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mi>
          β 
        </mi> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             γ 
           </mi> 
           <mo>
             + 
           </mo> 
           <mi>
             δ 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         2.76 
       </mn> 
       <mo>
         , 
       </mo> 
       <mtext>
           
       </mtext> 
       <mtext>
           
       </mtext> 
       <mtext>
           
       </mtext> 
       <mtext>
         Recovery Days 
       </mtext> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          / 
        </mo> 
        <mi>
          γ 
        </mi> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         19.3 
       </mn> 
      </mrow> 
     </math> (5)</p>
    <p>The reproduction number gives the approximate number of secondary infections that arise from one infected individual in a population where everyone is susceptible. If we substitute the parameters in Equation (4) into System (1) we can determine the trajectory of the infected fraction, among the other variables.</p>
   </sec>
   <sec id="s2_2">
    <title>2.2. The Effect of Interventions on the Transmission Rate</title>
    <p>We assume that interventions affect only the transmission rate, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         β 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> while the recovery and the death rates remain constant at 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         γ 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         0.0518939 
       </mn> 
      </mrow> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         δ 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         0.015 
       </mn> 
      </mrow> 
     </math>, respectively.</p>
    <p>There exist two types of forces in epidemic interventions: mitigation forces that reduce the rate and extent of infection and relaxation forces that increase the rate and extent. Although mitigation forces are generally perceived as NPIs, arising from the implementation of government policy, we will include among them medical treatment and vaccination, as these actions help to reduce disease spread. Relaxation forces are generally perceived as the lifting of mitigation measures to limit the impact of the disease on society. We will include among them non-compliance with mitigation measures and the emergence of new variants of COVID-19, since both of these dramatically increase the spread of the disease. As noted earlier, some models introduce more compartments to incorporate mitigation and relaxation forces. Our approach is to consider the totality of mitigation and relaxation forces without isolating individual drivers.</p>
    <p>In the rest of this subsection, we summarize the effects of interventions on the transmission rate, with details available in <xref ref-type="bibr" rid="scirp.142135-1">
      [1]
     </xref>. Let an intervention take place on day 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          t 
        </mi> 
        <mi>
          k 
        </mi> 
       </msub> 
      </mrow> 
     </math> and let 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math> be the incoming transmission rate before and up to 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          t 
        </mi> 
        <mi>
          k 
        </mi> 
       </msub> 
      </mrow> 
     </math>. The main objective of intervention is to gradually change the transmission rate from 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math>, by a fraction c, so that the transmission rate at the appropriate future time becomes</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mrow> 
         <mi>
           o 
         </mi> 
         <mi>
           p 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         β 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            t 
          </mi> 
          <mrow> 
           <mi>
             k 
           </mi> 
           <mo>
             + 
           </mo> 
           <mi>
             m 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           − 
         </mo> 
         <mi>
           c 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math> (6)</p>
    <p>where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mrow> 
         <mi>
           o 
         </mi> 
         <mi>
           p 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> denotes the optimum value of the transmission rate that is achieved due to the intervention at the time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          t 
        </mi> 
        <mi>
          k 
        </mi> 
       </msub> 
      </mrow> 
     </math>, c is the intervention ratio which depends on the intensity of the intervention, and m &gt; 0 is the duration, in days, it takes for the transmission rate to achieve the optimum value. Ideally, m should be small so that the effects of the intervention are realized quickly.</p>
    <p>From Equation (6) we note that when 0 &lt; c &lt; 1, then 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         β 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            t 
          </mi> 
          <mrow> 
           <mi>
             k 
           </mi> 
           <mo>
             + 
           </mo> 
           <mi>
             m 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         &lt; 
       </mo> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math> ; this corresponds to the intervention being a mitigation since it yields a smaller future transmission rate which represents a reduction by a fraction c of the incoming transmission rate. We call the quantity 100c the “percent mitigation”. On the other hand when c &lt; 0 then 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         β 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            t 
          </mi> 
          <mrow> 
           <mi>
             k 
           </mi> 
           <mo>
             + 
           </mo> 
           <mi>
             m 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         &gt; 
       </mo> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math>; this corresponds to the intervention being a relaxation since it yields a larger future transmission rate which represents an increase by a fraction 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mo>
          | 
        </mo> 
        <mi>
          c 
        </mi> 
        <mo>
          | 
        </mo> 
       </mrow> 
      </mrow> 
     </math> of the incoming transmission rate. We call 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         100 
       </mn> 
       <mrow> 
        <mo>
          | 
        </mo> 
        <mi>
          c 
        </mi> 
        <mo>
          | 
        </mo> 
       </mrow> 
      </mrow> 
     </math> the “percent relaxation”. If c = 0 then 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         β 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math> for t &gt; t<sub>k</sub>. This implies that no intervention has occurred at t<sub>k</sub>, since the incoming transmission rate remains unchanged after the supposed intervention. If this transmission rate is used in solving System (1), the resulting infection curve, when t &gt; t<sub>k</sub>, is called the non-intervention curve. We shall see later that the non-intervention curve plays a significant role in identifying the type of intervention appropriate for modelling multiple waves.</p>
    <p>If we assume that the intervention at 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          t 
        </mi> 
        <mi>
          k 
        </mi> 
       </msub> 
      </mrow> 
     </math> yields a transmission rate, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         β 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, which changes exponentially then it can be shown that <xref ref-type="bibr" rid="scirp.142135-1">
      [1]
     </xref></p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         β 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          { 
        </mo> 
        <mtable columnalign="left"> 
         <mtr> 
          <mtd> 
           <msub> 
            <mi>
              β 
            </mi> 
            <mi>
              b 
            </mi> 
           </msub> 
           <mo>
             , 
           </mo> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mi>
             t 
           </mi> 
           <mo>
             ≤ 
           </mo> 
           <msub> 
            <mi>
              t 
            </mi> 
            <mi>
              k 
            </mi> 
           </msub> 
          </mtd> 
         </mtr> 
         <mtr> 
          <mtd> 
           <msub> 
            <mi>
              β 
            </mi> 
            <mi>
              b 
            </mi> 
           </msub> 
           <msup> 
            <mtext>
              e 
            </mtext> 
            <mrow> 
             <mi>
               g 
             </mi> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mi>
                t 
              </mi> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </msup> 
           <mo>
             , 
           </mo> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <msub> 
            <mi>
              t 
            </mi> 
            <mi>
              k 
            </mi> 
           </msub> 
           <mo>
             ≤ 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ≤ 
           </mo> 
           <msub> 
            <mi>
              t 
            </mi> 
            <mrow> 
             <mi>
               k 
             </mi> 
             <mo>
               + 
             </mo> 
             <mi>
               m 
             </mi> 
            </mrow> 
           </msub> 
          </mtd> 
         </mtr> 
         <mtr> 
          <mtd> 
           <msub> 
            <mi>
              β 
            </mi> 
            <mrow> 
             <mi>
               o 
             </mi> 
             <mi>
               p 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               1 
             </mn> 
             <mo>
               − 
             </mo> 
             <mi>
               c 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <msub> 
            <mi>
              β 
            </mi> 
            <mi>
              b 
            </mi> 
           </msub> 
           <mo>
             , 
           </mo> 
           <mtext>
               
           </mtext> 
           <mtext>
               
           </mtext> 
           <msub> 
            <mi>
              t 
            </mi> 
            <mrow> 
             <mi>
               k 
             </mi> 
             <mo>
               + 
             </mo> 
             <mi>
               m 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             ≤ 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             &lt; 
           </mo> 
           <mi>
             τ 
           </mi> 
          </mtd> 
         </mtr> 
        </mtable> 
       </mrow> 
      </mrow> 
     </math> (7)</p>
    <p>where</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         g 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               t 
             </mi> 
             <mo>
               − 
             </mo> 
             <msub> 
              <mi>
                t 
              </mi> 
              <mi>
                k 
              </mi> 
             </msub> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mi>
             ln 
           </mi> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               1 
             </mn> 
             <mo>
               − 
             </mo> 
             <mi>
               c 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              t 
            </mi> 
            <mrow> 
             <mi>
               k 
             </mi> 
             <mo>
               + 
             </mo> 
             <mi>
               m 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             − 
           </mo> 
           <msub> 
            <mi>
              t 
            </mi> 
            <mi>
              k 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> (8)</p>
    <p>and τ is the time when the next intervention occurs after the optimum value has been achieved. In solving System (1), we need to take into consideration the value of the transmission rate, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         β 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, according to Equations (7) and (8), depending on the assigned time, t.</p>
   </sec>
   <sec id="s2_3">
    <title>2.3. First Wave</title>
    <p>Ogana et al. <xref ref-type="bibr" rid="scirp.142135-25">
      [25]
     </xref> developed the model of the 1<sup>st</sup> wave in three phases: baseline, mitigation and relaxation. We present a summary of the results here because they are crucial to developing the models of subsequent waves. The baseline phase is covered in Section 2.1. The mitigation phase was from 9<sup>th</sup> April to 8<sup>th</sup> June 2020. The incoming transmission rate was the baseline transmission in Equation (4), namely, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         0.184618 
       </mn> 
      </mrow> 
     </math> The best model was obtained by solving System (1), while using this value, together with m = 15 and c = 0.41 (41% mitigation) in Equations (7) and (8). From Equation (6), we conclude that the optimum transmission rate during mitigation was 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mrow> 
         <mi>
           o 
         </mi> 
         <mi>
           p 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0.108925 
       </mn> 
      </mrow> 
     </math>.</p>
    <p>The relaxation phase was from 9<sup>th</sup> June to early September 2020, when the second wave formed. The incoming transmission rate was the optimum transmission rate for mitigation, namely. 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         0.108925 
       </mn> 
      </mrow> 
     </math>. The best model was obtained by solving System (1), while using this value, together with m = 15 and c= −0.24 (24% relaxation) in Equations (7) and (8). From Equation (6), we conclude that the optimum transmission rate during relaxation was</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mrow> 
         <mi>
           o 
         </mi> 
         <mi>
           p 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0.135067 
       </mn> 
      </mrow> 
     </math> (9)</p>
    <p>Consolidation of results from the three phases leads to <xref ref-type="fig" rid="fig1">
      Figure 1
     </xref> in which the modelled percent infection during the 1<sup>st</sup> wave is compared with data <xref ref-type="bibr" rid="scirp.142135-25">
      [25]
     </xref>. <xref ref-type="fig" rid="fig1">
      Figure 1
     </xref> also shows the beginning of the observed 2<sup>nd</sup> wave. Hence the value in Equation (9) serves as the incoming transmission rate for the formation of the second wave.</p>
    <fig id="fig1" position="float">
     <label>Figure 1</label>
     <caption>
      <title>Figure 1. Computed and observed 1<sup>st</sup> wave of COVID-19 in Kenya. The black curve represents the data while the red represents the model. The purple vertical line intersects the data at the boundary of the 1<sup>st</sup> and 2<sup>nd</sup> waves.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId93.jpeg?20250423024404" />
    </fig>
   </sec>
   <sec id="s2_4">
    <title>2.4. Second to Fifth Waves</title>
    <p>The principle behind the modelling of the second to fifth waves is that, under suitable conditions, it is possible to computationally generate a wave by applying a large enough relaxation force, when infection is on the decrease. The generated wave requires some adjustment, however, to make it replicate the observed wave. We illustrate the process by considering what happens between the first and second waves, with the understanding that equivalent results can be obtained between any two adjacent waves.</p>
    <p>From <xref ref-type="fig" rid="fig1">
      Figure 1
     </xref>, the computed first wave dissipates with time; it represents the path the actual infection would take without further interventions, including the formation of the second wave. Through computation, we were able to generate waves emanating from the 1<sup>st</sup> wave by applying relaxation forces of large magnitudes. The waves are influenced by the three factors considered below.</p>
    <p>1) Change point</p>
    <p>We note that the 2<sup>nd</sup> wave forms when its trajectory diverges from the tail of the computed 1<sup>st</sup> wave (<xref ref-type="fig" rid="fig1">
      Figure 1
     </xref>). In the neighbourhood of the formation of the 2<sup>nd</sup> wave, a change occurs in the disease dynamics such that the infection gradient, initially negative, starts to increase and eventually becomes positive once the 2<sup>nd</sup> wave has formed. The point of divergence of the 2<sup>nd</sup> wave from the 1<sup>st</sup> is the same as the time of commencement of the increase in the infection gradient. We use this observation to fix an approximate date for the change point, T<sub>E</sub>, between the 1<sup>st</sup> and 2<sup>nd</sup> waves, namely, the time when the first wave ends and the second starts. The date can be estimated by drawing a line graph through the 2<sup>nd</sup> wave data and noting where the line graph meets the computed 1<sup>st</sup> wave. It may also be obtained by drawing a trendline of the 2<sup>nd</sup> wave data and noting where this trendline meets the computed 1<sup>st</sup> wave. We used both approaches and obtained an initial estimate of the change point to be in early September 2020. In modelling multiple waves, other researchers have used different methods to identify the change points <xref ref-type="bibr" rid="scirp.142135-21">
      [21]
     </xref>-<xref ref-type="bibr" rid="scirp.142135-23">
      [23]
     </xref>.</p>
    <p>As the 2<sup>nd</sup> wave forms, an increase in the infection gradient from negative to positive suggests an increase in the transmission rate. We used this postulation to carry out computational experimentation to determine the effect of relaxation forces in the neighbourhood of the change point. This led to a series of waves. To commence generation of the waves, we chose the change point, T<sub>E</sub>, as 8<sup>th</sup> September 2020 and considered it as an initial estimate of the point at which intervention occurred that yielded the 2<sup>nd</sup> wave from the 1<sup>st</sup>. Consequently, the incoming transmission rate, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math>, was chosen as the optimal transmission rate for the 1<sup>st</sup> wave, as given by Equation (9), so that 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0.135067 
       </mn> 
      </mrow> 
     </math>, We chose the default value m = 15. We substituted these values together with selected relaxation ratios, c, into Equations (7) and (8) and solved System (1) from the change point, T<sub>E</sub>, to stability. This yielded a series of waves which emanated from the change point. We adjusted the change point so that the waves could emanate from a point as close as possible to the point of divergence of the 2<sup>nd</sup> wave from the computed 1<sup>st</sup> wave. This led to 3<sup>rd</sup> September 2020 as the best choice for the change point and the solutions obtained by varying c yielded <xref ref-type="fig" rid="fig2(a)">
      Figure 2(a)
     </xref>.</p>
    <p>2) Wave base</p>
    <p>From <xref ref-type="fig" rid="fig2(a)">
      Figure 2(a)
     </xref>, we note that the computed waves and their apexes are generally above the data and the curvatures of their bases are smaller than that of the observed wave. What we desire are computed waves whose curvatures are as close as possible to that of the observed wave. By adjusting m, we obtain waves whose bases closely match the base of the observed wave. This arose from our observation that varying m, for a fixed c, leads to waves with different curvatures of the bases (<xref ref-type="fig" rid="fig2(b)">
      Figure 2(b)
     </xref>). As m increases the base of the wave becomes broader while the crests of the waves become smaller and they move downwards. We found that m = 30 yielded waves whose bases best matched the second wave (<xref ref-type="fig" rid="fig2(c)">
      Figure 2(c)
     </xref>).</p>
    <p>3) Wave amplitude</p>
    <p>From <xref ref-type="fig" rid="fig2(a)">
      Figure 2(a)
     </xref> and <xref ref-type="fig" rid="fig2(c)">
      Figure 2(c)
     </xref> we notice that, for a fixed m, the waves reach a crest and dissipate thereafter. At low relaxation percentages, there does not appear to be any significant effect but, as the percentages increase, ripples begin to form and eventually turn into sharp waves with large crests which lie approximately on the same vertical line. The objective is to find a c for which the computed wave follows the observed wave as much as possible before reaching the crest. <xref ref-type="fig" rid="fig2(c)">
      Figure 2(c)
     </xref> shows that for m = 30 and T<sub>E</sub> = 3<sup>rd</sup> September 2020, the choice c = −4 (400% relaxation) leads to such a computed wave.</p>
    <fig-group id="fig2" position="float">
     <fig id="fig2" position="float">
      <label>Figure 2</label>
      <caption>
       <title>(a)--(b)--(c)--Figure 2. Effects of the application of relaxation. E is the change point from one wave to another, while TE is the time at E. (a) Relaxations of varying magnitudes, for m = 15, when the infection decreases. (b) Relaxation at the same magnitude, c = −4 (400% relaxation), but varying m when the infection decreases. (c) Relaxations of varying magnitudes, for m = 30, when the infection decreases.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId98.jpeg?20250423024407" />
     </fig>
     <fig id="fig2" position="float">
      <label>Figure 2</label>
      <caption>
       <title>(a)--(b)--(c)--Figure 2. Effects of the application of relaxation. E is the change point from one wave to another, while TE is the time at E. (a) Relaxations of varying magnitudes, for m = 15, when the infection decreases. (b) Relaxation at the same magnitude, c = −4 (400% relaxation), but varying m when the infection decreases. (c) Relaxations of varying magnitudes, for m = 30, when the infection decreases.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId99.jpeg?20250423024407" />
     </fig>
     <fig id="fig2" position="float">
      <label>Figure 2</label>
      <caption>
       <title>(a)--(b)--(c)--Figure 2. Effects of the application of relaxation. E is the change point from one wave to another, while TE is the time at E. (a) Relaxations of varying magnitudes, for m = 15, when the infection decreases. (b) Relaxation at the same magnitude, c = −4 (400% relaxation), but varying m when the infection decreases. (c) Relaxations of varying magnitudes, for m = 30, when the infection decreases.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId100.jpeg?20250423024407" />
     </fig>
    </fig-group>
    <p>The phenomena decribed in this sub-section can be replicated at suitable points in the subsequent waves, with equivalent results to <xref ref-type="fig" rid="fig2">
      Figure 2
     </xref>. They form the foundation of our modelling of the 2<sup>nd</sup> to 5<sup>th</sup> waves. Every wave will be divided into the fore and back sections, each having different mechanisms of development.</p>
    <p>The observed 2<sup>nd</sup> wave starts when the decreasing infection diverges to the right and forms a basin with a concave base, then increases rapidly (<xref ref-type="fig" rid="fig2">
      Figure 2
     </xref>). The portion of the wave from the point of divergence to the point when it starts to increase rapidly is what we identify as the fore section of the wave. Section 2.4.1 shows that the fore section can be modelled by a computed wave generated by the application of a sufficiently large relaxation force. For the model to be successful, the change point and the base geometry should be obtained as accurately as possible. This can be done by the following steps.</p>
    <p>i) a) Choose the initial change point, T<sub>E</sub>, by examining the time when the trajectory of the observed current wave begins to diverge from the modelled tail of the preceding wave.</p>
    <p>b) Choose the default value m = 15.</p>
    <p>ii) Select a grid of negative values of c, preferably from the interval [−10, 0).</p>
    <p>iii) Determine the values at T<sub>E</sub> of the disease variables S, I, R and D, and of the incoming transmission rate, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>iv) Solve System (1) for t &gt; T<sub>E</sub> while applying Equations (7) and (8).</p>
    <p>v) Adjust T<sub>E</sub>, m and c, if necessary, and repeat from step iii, till an infection curve is obtained that best fits the data at the fore section of the wave.</p>
    <p>
     <xref ref-type="bibr" rid="scirp.142135-"></xref>As <xref ref-type="fig" rid="fig2(c)">
      Figure 2(c)
     </xref> shows, the curve obtained in step (v) of Section 2.4.2 will reach a maximum and dissipate at large times. To avoid this fate and force the model to follow the data upwards, we pick a point on this curve, which lies on, or closest to, the data curve, away from the maximum point. Let this point be G, with associated time T<sub>G</sub> and infection I<sub>G</sub> (<xref ref-type="fig" rid="fig3">
      Figure 3
     </xref>). From the preceding wave, or any other suitable previous wave, identify a point B, with associated time T<sub>B</sub> and infection I<sub>B</sub>. Choose B such that I<sub>B</sub> = I<sub>G</sub>, hence the infection at time T<sub>B</sub> equals that at time T<sub>G</sub> (<xref ref-type="fig" rid="fig3">
      Figure 3
     </xref>). Since the infections at the two points are equal and the gradients of the infection curves are in the same direction, we assume the similarity of dynamics at the two points and hence require that the rest of the time-dependent variables should also be equal at the two points. We thus impose the condition</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi mathvariant="script">
         V 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            G 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mi mathvariant="script">
         V 
       </mi> 
       <mrow> 
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          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            B 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (10a)</p>
    <p>where 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mi mathvariant="script">
        V 
      </mi> 
     </math> is S, I, R, D and β. The following will thus hold:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          S 
        </mi> 
        <mi>
          G 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
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        </mi> 
        <mi>
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        </mi> 
       </msub> 
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       </mo> 
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       </mtext> 
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       </mtext> 
       <msub> 
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        </mi> 
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        </mi> 
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       </mo> 
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        </mi> 
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        </mi> 
       </msub> 
       <mo>
         , 
       </mo> 
       <mtext>
           
       </mtext> 
       <mtext>
           
       </mtext> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          G 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          B 
        </mi> 
       </msub> 
       <mo>
         , 
       </mo> 
       <mtext>
           
       </mtext> 
       <mtext>
           
       </mtext> 
       <msub> 
        <mi>
          D 
        </mi> 
        <mi>
          G 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          D 
        </mi> 
        <mi>
          B 
        </mi> 
       </msub> 
       <mtext>
           
       </mtext> 
       <mtext>
           
       </mtext> 
       <mtext>
         and 
       </mtext> 
       <mtext>
           
       </mtext> 
       <mtext>
           
       </mtext> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          G 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          B 
        </mi> 
       </msub> 
      </mrow> 
     </math> (10b)</p>
    <p>where the subscripts denote the values of the quantities at the corresponding points, as shown in <xref ref-type="fig" rid="fig3">
      Figure 3
     </xref>. Equation (10) is known as the delay-function condition, since values at the current time, T<sub>G</sub>, are assigned values at a preceding or previous time, T<sub>B</sub>. The arc E-G is what we call the fore section of the computed wave. Our objective is to make this arc match the observed infection curve as much as possible, by careful choice of the quantities T<sub>E</sub>, m, c, T<sub>G</sub> and I<sub>G</sub>. If the whole of the preceding wave falls below or above I<sub>G</sub>, then it is not possible to obtain the point I<sub>B</sub> in the preceding wave, such that I<sub>G</sub> = I<sub>B</sub>, hence we seek I<sub>B</sub> from a previous wave.</p>
    <fig id="fig3" position="float">
     <label>Figure 3</label>
     <caption>
      <title>Figure 3. Choice of points for application of delay-function at the current and previous waves. m is the optimal duration of change of the transmission rate. G is the point of application of the delay-function condition, while T<sub>G</sub> is the time at G; B is the point in the previous wave where infection at B equals infection at G and T<sub>B</sub> is the time at B.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId109.jpeg?20250423024410" />
    </fig>
    <p>The back section of the computed wave begins at the end of the fore section, namely at T<sub>G</sub> and proceeds for t &gt; T<sub>G</sub>. The fore section of the wave arises mainly from the effects of the new COVID-19 variants. The back section, on the other hand, is influenced by the new variants and NPIs. We can carry out computation for t &gt; T<sub>G</sub> by using the values at T<sub>G</sub> as initial values. There is no guarantee that this will yield results that match the data well, since the transmission rate at T<sub>G</sub> is obtained through delay-function assignment and it could be different from the transmission rate associated with the data. Given the trajectory of the observed infection, it is important to determine what type of intervention, mitigation or relaxation, should be carried out at T<sub>G</sub> or at a suitable subsequent point. The process involves generating a non-intervention curve (see Section 2.2) and comparing it with the data. Since this process will also be required at points other than T<sub>G</sub>, we describe it for an intervention at a general point which we lable T<sub>VN</sub>.</p>
    <p>The process involves the following steps.</p>
    <p>i) Let 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math> be the incoming transmission rate at a general point of intervention, T<sub>VN</sub>. Choose the default value m = 15.</p>
    <p>ii) Choose the values of S, I, R and D at T<sub>VN</sub> as initial values. Generate the non-intervention curve by solving System (1) for t &gt; T<sub>VN</sub>, with 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         β 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math> and c = 0.</p>
    <p>iii) Compare the trajectory of the non-intervention curve with data and one of the following two cases will arise:</p>
    <p>Case 1: After T<sub>VN</sub>, the data is predominantly above the non-intervention curve.</p>
    <p>This means that the transmission rate for the data is larger than the transmission rate of the model, namely 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math>. To obtain a model whose transmission rate is close to that of the data, we apply relaxation by inserting negative values of c into Equations (7, 8), and using the resultant transmission rate to solve System (1) for t &gt; T<sub>VN</sub>. By varying c, and adjusting m, if necessary, we can determine the transmission rate that yields an infection curve that best fits the data. This relaxation stays in effect until another intervention is encountered.</p>
    <p>Case 2: After T<sub>VN</sub>, the data is predominantly below the non-intervention curve.</p>
    <p>This means that the transmission rate for the data is smaller than the transmission rate of the model, namely 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
      </mrow> 
     </math>. To obtain a model whose transmission rate is close to that of the data, we apply mitigation by inserting positive values of c into Equations (7) and (8), and using the resultant transmission rate to solve System (1) for t &gt; T<sub>VN</sub>. By varying c, and adjusting m, if necessary, we can determine the transmission rate that yields an infection curve that best fits the data. This mitigation stays in effect until another intervention is encountered.</p>
    <p>In the modelling of the back section, we may use relaxation, mitigation and the delay-function condition, as convenient, to align the model with the data, if the model departs from the expected trend.</p>
   </sec>
   <sec id="s2_5">
    <title>2.5. Sixth and Seventh Waves</title>
    <p>
     <xref ref-type="bibr" rid="scirp.142135-"></xref>The methods used to generate the fore sections of the 2<sup>nd</sup> to 5<sup>th</sup> waves were applied to the 6<sup>th</sup> and 7<sup>th</sup> waves but they did not succeed, no matter how large a relaxation force was applied. We attributed this to differences in the bases of the two sets of waves. The 2<sup>nd</sup> to 5<sup>th</sup> waves start when a decreasing infection diverges to the right and forms a concave shape, with a base, then increases (<xref ref-type="fig" rid="fig2">
      Figure 2
     </xref>); this geometry allows for sudden and large changes in the gradients of the infection. The 6<sup>th</sup> and 7<sup>th</sup> waves, on the other hand, emerge from very low, almost horizontal, infections that gradually increase before rising sharply (<xref ref-type="fig" rid="fig4">
      Figure 4
     </xref>).</p>
    <fig id="fig4" position="float">
     <label>Figure 4</label>
     <caption>
      <title>Figure 4. Development of the 6<sup>th</sup> wave. E is the change point from 5<sup>th</sup> to 6<sup>th</sup> wave and T<sub>E</sub> the corresponding time. The black curve represents the data corresponding to the 6<sup>th</sup> wave, while the red curve corresponds to the computed tail of the 5<sup>th</sup> wave.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId118.jpeg?20250423024413" />
    </fig>
    <p>The fore sections of the 6<sup>th</sup> and 7<sup>th</sup> waves can be modelled by exponential infection, as shown below. The initial change point, T<sub>E</sub>, between the current and previous waves, is determined as before by noting when the trajectory of the current observed wave diverges from the modelled tail of the previous wave. We observed the following properties of the variables I and S at the beginning of the formation of the 6<sup>th</sup> and 7<sup>th</sup> waves:</p>
    <p>i) Values of I(t) were quite small, &lt; 1%, in the neighbourhood of the change point, and increased slowly away from the change point.</p>
    <p>ii) S(t) was approximately constant for many days after the change point to a point close to where a sharp rise in infection commences, labelled G (<xref ref-type="fig" rid="fig4">
      Figure 4
     </xref>).</p>
    <p>The arc E-G forms the fore section of the wave. Using the 2<sup>nd</sup> property in the preceding paragraph, we assume that S(t) is approximated by the mean value, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mover accent="true"> 
       <mi>
         S 
       </mi> 
       <mo>
         ¯ 
       </mo> 
      </mover> 
     </math>, from T<sub>E</sub> to T<sub>G</sub>. Equation 1(b) can then be written</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mrow> 
         <mtext>
           d 
         </mtext> 
         <mi>
           I 
         </mi> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mtext>
           d 
         </mtext> 
         <mi>
           t 
         </mi> 
        </mrow> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mi>
         r 
       </mi> 
       <mi>
         I 
       </mi> 
      </mrow> 
     </math> (11)</p>
    <p>where</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         r 
       </mi> 
       <mo>
         = 
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        <mi>
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       <mo>
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         </mi> 
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           + 
         </mo> 
         <mi>
           δ 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (12)</p>
    <p>Equation (11) has the solution</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         I 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
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          t 
        </mi> 
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          ) 
        </mo> 
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         = 
       </mo> 
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       </mi> 
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        <mrow> 
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              E 
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          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> (13)</p>
    <p>For the infection to grow we must have r &gt; 0, implying that we must choose a transmission rate β such that</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         β 
       </mi> 
       <mo>
         &gt; 
       </mo> 
       <mrow> 
        <mrow> 
         <mrow> 
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            ( 
          </mo> 
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             γ 
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           </mo> 
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            ) 
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        </mo> 
        <mover accent="true"> 
         <mi>
           S 
         </mi> 
         <mo>
           ¯ 
         </mo> 
        </mover> 
       </mrow> 
      </mrow> 
     </math> (14)</p>
    <p>Although Equation (14) gives a wide range of choices for β, the value must be selected such that the computed infections from Equation (13) agree with the data as well as possible. This is readily done by trying different values of β and fitting the resulting exponential curve to data till a value of β is reached that yields a curve with the best fit. We denote such a value 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mrow> 
         <mi>
           X 
         </mi> 
         <mi>
           P 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math>, to indicate that it is the transmission rate associated with exponential infection. Using Equations (12) and (13), we compute the infected fraction by</p>
    <p>
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         I 
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          t 
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            ] 
          </mo> 
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         <mrow> 
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            [ 
          </mo> 
          <mrow> 
           <mi>
             t 
           </mi> 
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             − 
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            <mi>
              T 
            </mi> 
            <mi>
              E 
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           </msub> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          } 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (15)</p>
    <p>Exponential growth cannot be allowed to proceed indefinitely. Just like in the 2<sup>nd</sup> to 5<sup>th</sup> waves, we terminate the fore sections of the 6<sup>th</sup> and 7<sup>th</sup> waves by enforcing the delay-function condition at the point G, as discussed in Section 2.4.3. Hence Equation (15) is used to determine the infection for t such that 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          E 
        </mi> 
       </msub> 
       <mo>
         ≤ 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ≤ 
       </mo> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          G 
        </mi> 
       </msub> 
      </mrow> 
     </math>. Within this time interval, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mo>
          ( 
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          t 
        </mi> 
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          ) 
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         = 
       </mo> 
       <mover accent="true"> 
        <mi>
          S 
        </mi> 
        <mo>
          ¯ 
        </mo> 
       </mover> 
      </mrow> 
     </math>, a constant, while R(t) and D(t) are estimated from</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         R 
       </mi> 
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            t 
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          ) 
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         R 
       </mi> 
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            t 
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           </mi> 
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             − 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          ) 
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       </mrow> 
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       </mo> 
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       </mi> 
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       </mi> 
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            t 
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            k 
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          ) 
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         D 
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           </mn> 
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          ) 
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          ) 
        </mo> 
       </mrow> 
       <mo>
         , 
       </mo> 
      </mrow> 
     </math> (16)</p>
    <p>through integration of Equations 1(c) and 1(d), respectively.</p>
    <p>The back section of the wave starts at T<sub>G</sub> and its modelling proceeds as described in Section 2.4.4, with the following points to be noted:</p>
   </sec>
   <sec id="s2_6">
    <title>2.6. Error Metrics</title>
    <p>Graphical or visual presentation is usually the first step in assessing how well the numerical simulations fit the data. It should, however, be accompanied by a quantitative value that can be used to determine the closeness of the simulation to data. A popular beginning point involves carrying out the regression of the simulated values against the observed data and computing the coefficient of determination, R<sup>2</sup>. In our case we use the expression</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          R 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mn>
         1 
       </mn> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mrow> 
         <mtext>
           SSR 
         </mtext> 
        </mrow> 
        <mrow> 
         <mtext>
           SST 
         </mtext> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (17)</p>
    <p>where</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
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         SSR 
       </mtext> 
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         = 
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            2 
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         , 
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         SST 
       </mtext> 
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         = 
       </mo> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∑ 
         </mo> 
         <mrow> 
          <mi>
            k 
          </mi> 
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          </mo> 
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            1 
          </mn> 
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           <mi>
             N 
           </mi> 
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             T 
           </mi> 
          </msub> 
         </mrow> 
        </munderover> 
        <mrow> 
         <msup> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                I 
              </mi> 
              <mi>
                k 
              </mi> 
             </msub> 
             <mo>
               − 
             </mo> 
             <mover accent="true"> 
              <mi>
                I 
              </mi> 
              <mo>
                ¯ 
              </mo> 
             </mover> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math> (18)</p>
    <p>in which 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          I 
        </mi> 
        <mi>
          k 
        </mi> 
       </msub> 
      </mrow> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          I 
        </mi> 
        <mi>
          k 
        </mi> 
        <mi>
          c 
        </mi> 
       </msubsup> 
      </mrow> 
     </math> are the observed and simulated infections at node k, respectively, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mover accent="true"> 
       <mi>
         I 
       </mi> 
       <mo>
         ¯ 
       </mo> 
      </mover> 
     </math> is the mean value of the observed infecions during the relevant time period, and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          N 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
      </mrow> 
     </math> is the number of nodes for the relevant time period, and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         0 
       </mn> 
       <mo>
         ≤ 
       </mo> 
       <msup> 
        <mi>
          R 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         ≤ 
       </mo> 
       <mn>
         1 
       </mn> 
      </mrow> 
     </math>.The closer R<sup>2</sup> is to +1 the more accurately the simulation approximates the data.</p>
    <p>In addition to R<sup>2</sup>, we explore other metrics that can be used to determine how close the simulation is to the observed values. We use an error metric, the root mean square error (RMSE), defined thus <xref ref-type="bibr" rid="scirp.142135-26">
      [26]
     </xref>-<xref ref-type="bibr" rid="scirp.142135-28">
      [28]
     </xref>:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         RMSE 
       </mtext> 
       <mo>
         = 
       </mo> 
       <msqrt> 
        <mrow> 
         <mfrac> 
          <mn>
            1 
          </mn> 
          <mrow> 
           <msub> 
            <mi>
              N 
            </mi> 
            <mi>
              T 
            </mi> 
           </msub> 
          </mrow> 
         </mfrac> 
         <mstyle displaystyle="true"> 
          <munderover> 
           <mo>
             ∑ 
           </mo> 
           <mrow> 
            <mi>
              k 
            </mi> 
            <mo>
              = 
            </mo> 
            <mn>
              1 
            </mn> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               N 
             </mi> 
             <mi>
               T 
             </mi> 
            </msub> 
           </mrow> 
          </munderover> 
          <mrow> 
           <msup> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <msubsup> 
                <mi>
                  I 
                </mi> 
                <mi>
                  k 
                </mi> 
                <mi>
                  c 
                </mi> 
               </msubsup> 
               <mo>
                 − 
               </mo> 
               <msub> 
                <mi>
                  I 
                </mi> 
                <mi>
                  k 
                </mi> 
               </msub> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </mstyle> 
        </mrow> 
       </msqrt> 
      </mrow> 
     </math> (19)</p>
    <p>
     <xref ref-type="bibr" rid="scirp.142135-"></xref>where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          I 
        </mi> 
        <mi>
          k 
        </mi> 
       </msub> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          I 
        </mi> 
        <mi>
          k 
        </mi> 
        <mi>
          c 
        </mi> 
       </msubsup> 
      </mrow> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          N 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
      </mrow> 
     </math> are defined immediately after Equation (17). If RMSE = 0 then the simulation perfectly matches the data. This will rarely be the case, hence we use the judgement that the simulation is close to the data if RMSE is close to zero. The actual value of RMSE that is acceptable depends on the dataset and the model; consequently, it is difficult to compare the significance of the RMSE values from different datasets or numerical models. To address these issues, we can obtain the normalized root mean square error, NRMSE, where RMSE is normalized by the mean, range, standard deviation, interquartile range, or square of the data, as convenient <xref ref-type="bibr" rid="scirp.142135-27">
      [27]
     </xref> <xref ref-type="bibr" rid="scirp.142135-28">
      [28]
     </xref>. In this paper we apply normalization by the range to obtain <xref ref-type="bibr" rid="scirp.142135-28">
      [28]
     </xref>.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         NRMSE 
       </mtext> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mtext>
           RMSE 
         </mtext> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            I 
          </mi> 
          <mrow> 
           <mi>
             max 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            I 
          </mi> 
          <mrow> 
           <mi>
             min 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (20)</p>
    <p>where 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          I 
        </mi> 
        <mrow> 
         <mi>
           max 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> and 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          I 
        </mi> 
        <mrow> 
         <mi>
           min 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> are the maximum and minimum values of the observed infection fractions durng the relevant period. If we multiply the right hand side of Equation (20) by 100 then we express NRMSE as the percentage of the data range taken by RMSE. This enables us to interpret the significance of NRMSE as follows: the simulation is deemed very good if 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         NRMSE 
       </mtext> 
       <mo>
         ≤ 
       </mo> 
       <mn>
         10 
       </mn> 
       <mi>
         % 
       </mi> 
      </mrow> 
     </math>, good if 10% &lt; NRMSE &lt; 20%, acceptable if 20% &lt; NRMSE &lt; 30%, and poor if NRSME &gt; 30%. The problem with RMSE and NRMSE is that are biased estimators and the fact that they are close to zero does not guarantee that the simulation fits the data well <xref ref-type="bibr" rid="scirp.142135-27">
      [27]
     </xref>. It is, therefore, advisable to use RMSE and NRMSE in conjunction with other error metrics. Here we will also use the Hanna-Heinold error metric, HH, given by <xref ref-type="bibr" rid="scirp.142135-29">
      [29]
     </xref></p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         HH 
       </mtext> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mstyle displaystyle="true"> 
            <munderover> 
             <mo>
               ∑ 
             </mo> 
             <mrow> 
              <mi>
                k 
              </mi> 
              <mo>
                = 
              </mo> 
              <mn>
                1 
              </mn> 
             </mrow> 
             <mrow> 
              <msub> 
               <mi>
                 N 
               </mi> 
               <mi>
                 T 
               </mi> 
              </msub> 
             </mrow> 
            </munderover> 
            <mrow> 
             <msup> 
              <mrow> 
               <mrow> 
                <mo>
                  ( 
                </mo> 
                <mrow> 
                 <msubsup> 
                  <mi>
                    I 
                  </mi> 
                  <mi>
                    k 
                  </mi> 
                  <mi>
                    c 
                  </mi> 
                 </msubsup> 
                 <mo>
                   − 
                 </mo> 
                 <msub> 
                  <mi>
                    I 
                  </mi> 
                  <mi>
                    k 
                  </mi> 
                 </msub> 
                </mrow> 
                <mo>
                  ) 
                </mo> 
               </mrow> 
              </mrow> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
           </mstyle> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mstyle displaystyle="true"> 
            <munderover> 
             <mo>
               ∑ 
             </mo> 
             <mrow> 
              <mi>
                k 
              </mi> 
              <mo>
                = 
              </mo> 
              <mn>
                1 
              </mn> 
             </mrow> 
             <mrow> 
              <msub> 
               <mi>
                 N 
               </mi> 
               <mi>
                 T 
               </mi> 
              </msub> 
             </mrow> 
            </munderover> 
            <mrow> 
             <msubsup> 
              <mi>
                I 
              </mi> 
              <mi>
                k 
              </mi> 
              <mi>
                c 
              </mi> 
             </msubsup> 
             <msub> 
              <mi>
                I 
              </mi> 
              <mi>
                k 
              </mi> 
             </msub> 
            </mrow> 
           </mstyle> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> (21)</p>
    <p>where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          I 
        </mi> 
        <mi>
          k 
        </mi> 
        <mi>
          c 
        </mi> 
       </msubsup> 
       <mo>
         , 
       </mo> 
       <msub> 
        <mi>
          I 
        </mi> 
        <mi>
          k 
        </mi> 
       </msub> 
      </mrow> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          N 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
      </mrow> 
     </math> are defined immediately after Equation (17). It is shown that HH is an unbiased estimator <xref ref-type="bibr" rid="scirp.142135-27">
      [27]
     </xref>. The closer HH is to zero, the better the fit of the simulation to the data. The HH error metric has been applied in experimental and numerical investigations involving nonlinear waves, for instance <xref ref-type="bibr" rid="scirp.142135-30">
      [30]
     </xref>-<xref ref-type="bibr" rid="scirp.142135-32">
      [32]
     </xref>.</p>
   </sec>
  </sec><sec id="s3">
   <title>3. Results and Discussion</title>
   <p>The presentation of results here will be done one wave at a time; thereafter all the waves will be consolidated into one time series. COVID-19 data was obtained from the Ministry of Health, Kenya <xref ref-type="bibr" rid="scirp.142135-33">
     [33]
    </xref> and Worldometer <xref ref-type="bibr" rid="scirp.142135-34">
     [34]
    </xref>. We obtained information on SARS-CoV-2 lineages and variants from <xref ref-type="bibr" rid="scirp.142135-2">
     [2]
    </xref> <xref ref-type="bibr" rid="scirp.142135-35">
     [35]
    </xref>.</p>
   <sec id="s3_1">
    <title>3.1. First Wave</title>
    <p>The first wave was modelled by Ogana et al. <xref ref-type="bibr" rid="scirp.142135-25">
      [25]
     </xref> and a summary of the results is given in Section 2.3, with the complete wave shown in <xref ref-type="fig" rid="fig1">
      Figure 1
     </xref>. It was driven largely by the global parental SARS-CoV-2 lineage B.1 from March to September 2020 <xref ref-type="bibr" rid="scirp.142135-2">
      [2]
     </xref> <xref ref-type="bibr" rid="scirp.142135-35">
      [35]
     </xref>. The fluctuations in the wave were, however, partly influenced by the mitigation measures imposed on 8th April 2020 and the gradual lifting of some of these measures from 8th June 2020.</p>
    <p>
     <xref ref-type="bibr" rid="scirp.142135-"></xref>Section 2.6 yielded R<sup>2</sup> = 0.711 and the error metrics, RMSE = 0.0413, NRMSE = 12% and HH = 0.328. These values show that the simulation provides a fairly good fit to the data, despite the noise in the observations during the first half of the wave.</p>
   </sec>
   <sec id="s3_2">
    <title>3.2. Second to Fifth Waves</title>
    <p>The procedures are almost identical; the differences are in the dates when major events occur.</p>
    <p>
     <xref ref-type="bibr" rid="scirp.142135-"></xref>Section 2.4.2 yielded the best fit for the fore section (arc E-G in <xref ref-type="fig" rid="fig5">
      Figure 5
     </xref>), obtained using T<sub>E</sub> = 03-Sep-20, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0.13507 
       </mn> 
      </mrow> 
     </math>, m = 30 and c = −4 (400% relaxation). From Section 2.4.3, we identified T<sub>G</sub> = 08-Oct-20 and I<sub>G</sub> = 0.07394. Comparison with previous waves gave T<sub>B</sub> = 17-Jun-20 and I<sub>B</sub> = 0.07394. Equation (10) assigned values to S<sub>G</sub>, I<sub>G</sub>, R<sub>G</sub>, D<sub>G</sub>, and β<sub>G</sub> = 0.67533. Section 2.4.4, applied at T<sub>VN</sub> = T<sub>G</sub> = 08-Oct-20 with c = 0, β<sub>b</sub> = β<sub>G</sub> = 0.67533 and m = 15 led to Case 1 (blue dashed curve in <xref ref-type="fig" rid="fig5">
      Figure 5
     </xref>). Subsequent relaxation for t &gt; T<sub>VN</sub> yielded the best fit for the back section (model curve for t &gt; T<sub>G</sub> in <xref ref-type="fig" rid="fig5">
      Figure 5
     </xref>), using c = −0.26 (26% relaxation) and m = 15. Combination of the fore and back sections resulted in the complete 2<sup>nd</sup> wave (<xref ref-type="fig" rid="fig5">
      Figure 5
     </xref>).</p>
    <p>Section 2.6 yielded R<sup>2</sup> = 0.869 and the error metrics, RMSE = 0.0202, NRMSE = 11%, and HH = 0.0344. These values show that the simulation provides a very good fit to the data.</p>
    <p>Section 2.4.2 yielded the best fit for the fore section (arc E-G in <xref ref-type="fig" rid="fig6">
      Figure 6
     </xref>), obtained using T<sub>E</sub> = 28-Dec-20, β<sub>b</sub> = 0.17018, m = 45 and c = −9 (900% relaxation). From Section 2.4.3, we identified T<sub>G</sub> = 10-Feb-21 and I<sub>G</sub> = 0.04099. Comparison with previous waves gave T<sub>B</sub> = 26-May-20 and I<sub>B</sub> = 0.04099. Equation (10) assigned values to S<sub>G</sub>, I<sub>G</sub>, R<sub>G</sub>, D<sub>G</sub>, and β<sub>G</sub> = 0.10892. An intervention at T<sub>VN</sub> = T<sub>G</sub> = 10-Feb-21 using c = 0, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mi>
          b 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0.10892 
       </mn> 
      </mrow> 
     </math> and m = 15 resulted in a model that followed the data but began to diverge from the data on 21-Feb-21. Hence Section 2.4.4 was applied at T<sub>VN</sub> = 21-Feb-21 with c = 0, β<sub>b</sub> = 0.10892 and m = 15, leading to Case 1 (blue dashed curve in <xref ref-type="fig" rid="fig6">
      Figure 6
     </xref>). Subsequent relaxation for t &gt; T<sub>VN</sub> yielded the best fit for the back section (model curve for t &gt; T<sub>G</sub> in <xref ref-type="fig" rid="fig6">
      Figure 6
     </xref>) using c = −0.5 (50% relaxation) and m = 10. Combination of the fore and back sections resulted in the complete 3<sup>rd</sup> wave (<xref ref-type="fig" rid="fig6">
      Figure 6
     </xref>).</p>
    <fig id="fig5" position="float">
     <label>Figure 5</label>
     <caption>
      <title>Figure 5. Computed and observed 2<sup>nd</sup> wave of COVID-19 in Kenya. The black curve represents the data, the red represents the model and the blue dashed curve is the non-intervention curve. E is the change point from the 1<sup>st</sup> to the 2<sup>nd</sup> wave, at the corresponding time T<sub>E</sub>. G is the point of application of the delay-function condition, at the corresponding time T<sub>G</sub>. T<sub>W</sub> is the end of the 2<sup>nd</sup> wave.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId179.jpeg?20250423024424" />
    </fig>
    <p>
     <xref ref-type="bibr" rid="scirp.142135-"></xref></p>
    <fig id="fig6" position="float">
     <label>Figure 6</label>
     <caption>
      <title>Figure 6. Computed and observed 3<sup>rd</sup> wave of COVID-19 in Kenya. The black curve represents the data, the red represents the model and the blue dashed curve is the non-intervention curve. E is the change point from the 2<sup>nd</sup> to 3<sup>rd</sup> wave, at the corresponding time T<sub>E</sub>. G is the point of application of the delay-function condition, at the corresponding time T<sub>G</sub>. T<sub>W</sub> is the end of the 3<sup>rd</sup> wave.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId180.jpeg?20250423024425" />
    </fig>
    <p>Section 2.6 yielded R<sup>2</sup> = 0.903 and the error metrics, RMSE = 0.0194, NRMSE = 8%, and HH = 0.0335. These values show that the simulation provides a very good fit to the data.</p>
    <p>The 4<sup>th</sup> COVID-19 wave in Kenya appeared in two spikes of different amplitudes. We modelled each spike separately before combining them to form the complete 4<sup>th</sup> wave. For convenience of presentation, we will adopt some notations as follows. There is a change point from the 3<sup>rd</sup> wave to the 1<sup>st</sup> spike which we label E1; there is another change point from the 1<sup>st</sup> spike to the 2<sup>nd</sup> and we label this E2. We let G1 and G2 be the delay-function points in the 1<sup>st</sup> and 2<sup>nd</sup> spikes, respectively, and B1 and B2 be the points for application of Equation (10) for values at G1 and G2, respectively.</p>
    <p>First spike: Section 2.4.2 yielded the best fit for the fore section (arc E1-G1 in <xref ref-type="fig" rid="fig7">
      Figure 7
     </xref>) obtained using T<sub>E</sub><sub>1</sub> = 02-May-21, β<sub>b</sub> = 0.16339, m = 30 and c = −7 (700% relaxation). From Section 2.4.3, we identified T<sub>G</sub><sub>1</sub> = 01-Jun-21 and I<sub>G</sub><sub>1 </sub>= 0.0724. Comparison with previous waves led to T<sub>B</sub><sub>1</sub> = 28-Feb-21 and I<sub>B1</sub> = 0.0724. Equation (10) assigned values to S<sub>G</sub><sub>1</sub>, I<sub>G</sub><sub>1</sub>, R<sub>G</sub><sub>1</sub>, D<sub>G</sub><sub>1</sub>, and β<sub>G</sub><sub>1</sub> = 1.3071. Section 2.4.4, applied at T<sub>VN</sub> = T<sub>G</sub><sub>1</sub> = 01-Jun-21 with c = 0, β<sub>b</sub> = β<sub>G</sub><sub>1</sub> = 1.3071 and m = 15 led to Case 2 (blue dashed curve in <xref ref-type="fig" rid="fig7">
      Figure 7
     </xref>). Subsequent mitigation for t &gt; T<sub>VN</sub> led to the best fit for the back section (model curve from G1 to E2 in <xref ref-type="fig" rid="fig7">
      Figure 7
     </xref>) using c = 0.5 (50% mitigation) and m = 30. Combination of the fore and back sections resulted in the complete 1<sup>st</sup> spike (arc E1-E2 in <xref ref-type="fig" rid="fig7">
      Figure 7
     </xref>).</p>
    <fig id="fig7" position="float">
     <label>Figure 7</label>
     <caption>
      <title>Figure 7. Computed and observed 4<sup>th</sup> wave of COVID-19 in Kenya. The black curve represents the data and the red represents the model. The blue dashed curve is the non-intervention curve in the 1<sup>st</sup> spike while the blue dotted curve is the non-intervention curve in the 2<sup>nd</sup> spike. E1 is the change point from the 3<sup>rd</sup> wave to the 1<sup>st</sup> spike of the 4<sup>th</sup> wave at the corresponding time T<sub>E</sub><sub>1</sub>; G1 is the point of application of delay-function condition in the 1<sup>st</sup> spike at the corresponding time T<sub>G1</sub>. E2 is the change point from the 1<sup>st</sup> to 2<sup>nd</sup> spike at the corresponding time T<sub>E</sub><sub>2</sub>. G2 is the point of application of the delay-function condition in the 2<sup>nd</sup> spike at the corresponding time T<sub>G</sub><sub>2</sub>. T<sub>W</sub> is the end of the 4<sup>th</sup> wave.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId181.jpeg?20250423024427" />
    </fig>
    <p>Second spike: Section 2.4.2 yielded the best fit for the fore section (arc E2-G2 in <xref ref-type="fig" rid="fig7">
      Figure 7
     </xref>) obtained using T<sub>E</sub><sub>2</sub> = 27-Jun-21, β<sub>b</sub> = 0.079341, m = 30 and c = −2.9 (290% relaxation). From Section 2.4.3, we identified T<sub>G</sub><sub>2</sub> = 26-Jul-21 and I<sub>G</sub><sub>2</sub> = 0.143. Comparison with previous waves led to T<sub>B</sub><sub>2</sub> = 14-Mar-21 and I<sub>B</sub><sub>2</sub> = 0.143. Equation (10) assigned values to S<sub>G</sub><sub>2</sub>, I<sub>G</sub><sub>2</sub>, R<sub>G</sub><sub>2</sub>, D<sub>G</sub><sub>2</sub>, and β<sub>G</sub><sub>2</sub> = 0.29571. Section 2.4.4, applied at T<sub>VN</sub> = T<sub>G2</sub> = 26-Jul-21 with c = 0, β<sub>b</sub> = β<sub>G</sub><sub>2</sub> = 0.29572 and m = 15 led to Case 2 (blue dotted curve in <xref ref-type="fig" rid="fig7">
      Figure 7
     </xref>). Subsequent mitigation for t &gt; T<sub>VN</sub> led to the best fit for the back section (model curve for t &gt; T<sub>G</sub><sub>2</sub> in <xref ref-type="fig" rid="fig7">
      Figure 7
     </xref>), using c = 0.2 (20% mitigation) and m = 15. Combination of the fore and back sections resulted in the complete 2<sup>nd</sup> spike (model curve for t &gt; T<sub>E</sub><sub>2</sub> in <xref ref-type="fig" rid="fig7">
      Figure 7
     </xref>). The 1<sup>st</sup> and 2<sup>nd</sup> spikes were combined to yield the complete 4<sup>th</sup> wave (<xref ref-type="fig" rid="fig7">
      Figure 7
     </xref>).</p>
    <p>
     <xref ref-type="bibr" rid="scirp.142135-"></xref>Section 2.6 yielded R<sup>2</sup> = 0.81 and the error metrics, RMSE = 0.0190, NRMSE = 8%, and HH = 0.0389. These values show that the simulation provides a very good fit to the data.</p>
    <p>For convenience of presentation, we will adopt some notations as follows. There will be two delay-function points which we label G1 and G2. We let B1 and B2 be the points for application of Equation (10) for values at G1 and G2, respectively.</p>
    <p>Section 2.4.2 yielded the best fit for the fore section (arc E-G1 in <xref ref-type="fig" rid="fig8">
      Figure 8
     </xref>) obtained using T<sub>E</sub> = 21-Oct-21, β<sub>b</sub> = 0.13071, m = 60 and c = −10 (1000% relaxation). From Section 2.4.3, we identified T<sub>G</sub><sub>1</sub> = 02-Dec-21 and I<sub>G</sub><sub>1</sub> = 0.0147. Comparison with previous waves led to T<sub>B</sub><sub>1</sub> = 27-Apr-20 and I<sub>B</sub><sub>1</sub> = 0.0147. Equation (10) assigned values to S<sub>G</sub><sub>1</sub>, I<sub>G</sub><sub>1</sub>, R<sub>G</sub><sub>1</sub>, D<sub>G</sub><sub>1</sub>, and β<sub>G</sub><sub>1</sub> = 0.67286. Section 2.4.4, applied at T<sub>VN</sub> = T<sub>G</sub><sub>1</sub> = 02-Dec-21with c = 0, β<sub>b</sub> = β<sub>G</sub><sub>1</sub> = 0.67286 and m = 15 led to Case 1 (blue dashed curve in <xref ref-type="fig" rid="fig8">
      Figure 8
     </xref>). Relaxation was undertaken for t &gt; T<sub>VN</sub> using β<sub>b</sub> = 0.67286, c = −4 (400% relaxation) and m = 15. The resulting model followed data but began to diverge from the data on 14-Dec-21 (model solution in arc G1-G2). Consequently, we chose a 2<sup>nd</sup> delay-function point at T<sub>G</sub><sub>2</sub> = 14-Dec-21 with I<sub>G</sub><sub>2</sub> = 0.0988. Comparison with previous waves led to T<sub>B</sub><sub>2</sub> = 16-Jul-21 and I<sub>B</sub><sub>2</sub> = 0.0985. Equation (10) assigned values to S<sub>G</sub><sub>2</sub>, I<sub>G</sub><sub>2</sub>, R<sub>G</sub><sub>2</sub>, D<sub>G</sub><sub>2</sub>, and β<sub>G</sub><sub>2</sub> = 0.39473. Section 2.4.4, applied at T<sub>VN</sub> = T<sub>G</sub><sub>2</sub> = 14-Dec-21 with c = 0, β<sub>b</sub> = β<sub>G</sub><sub>2</sub> = 0.39473 and m = 15 led to Case 1 (blue dotted curve in <xref ref-type="fig" rid="fig8">
      Figure 8
     </xref>). Subsequent relaxation for t &gt; T<sub>VN</sub> led to the best fit for the rest of the back section (model curve for t &gt; T<sub>G</sub><sub>2</sub> in <xref ref-type="fig" rid="fig8">
      Figure 8
     </xref>), using β<sub>b</sub> = β<sub>G</sub><sub>2</sub> = 0.394736, c = −3.5 (350% relaxation) and m = 5. Combination of the fore and back sections resulted in the complete 5<sup>th</sup> wave (<xref ref-type="fig" rid="fig8">
      Figure 8
     </xref>).</p>
    <p>
     <xref ref-type="bibr" rid="scirp.142135-"></xref>Section 2.6 yielded R<sup>2</sup> = 0.966 and the error metrics, RMSE = 0.0211, NRMSE = 6%, and HH = 0.0315. These values show that the simulation provides a very good fit to the data.</p>
    <p>a) Attempts to generate waves from points upstream or downstream of the identified change points led to weak waves which eventually disappeared.</p>
    <p>b) When choosing the initial values for the relaxation ratio, c, in Section 2.4.2, it is advisable to start with c = 0, −2, −4, −6, −8, −10, representing 0%, 200%, 400%, 600%, 800%, 1000% relaxation, respectively. Once the suitable change point, T<sub>E</sub>, and m have been identified, it will be easy to see the c-curves that immediately enclose the data. Hence a finer grid of c values can be applied to identify the c-value that yields the curve that best fits the data. This procedure helps to minimize computation time.</p>
    <p>c) A summary of the computation procedure for the 2<sup>nd</sup> to 5<sup>th</sup> waves is provided in the supplement, <xref ref-type="table" rid="tableS1">
      Table S1
     </xref>.</p>
    <fig id="fig8" position="float">
     <label>Figure 8</label>
     <caption>
      <title>Figure 8. Computed and observed 5<sup>th</sup> wave of COVID-19 in Kenya. The black curve represents the data while the red represents the model. The blue dashed curve is the non-intervention curve from G1 while the dotted blue curve is the non-intervention curve from G2. E is the change point from the 4<sup>th</sup> to the 5<sup>th</sup> wave, at the corresponding time T<sub>E</sub>. G1 is the first point of application of the delay-function condition at the time T<sub>G</sub><sub>1</sub>, and G2 is the second point of application of the delay-function condition at the time T<sub>G</sub><sub>2</sub>. T<sub>W</sub> is the end of 5<sup>th</sup> wave.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId182.jpeg?20250423024428" />
    </fig>
   </sec>
   <sec id="s3_3">
    <title>3.3. Sixth and Seventh Waves</title>
    <p>The fore sections of the 6<sup>th</sup> and 7<sup>th</sup> waves were generated by exponential approximation, rather than by relaxation, as was the case with the previous waves. The results are, therefore, presented separately in this section.</p>
    <p>Section 2.4.2 yielded the best fit for the fore section (arc E-G in <xref ref-type="fig" rid="fig9">
      Figure 9
     </xref>) obtained using T<sub>E</sub> = 13-Mar-22, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mover accent="true"> 
        <mi>
          S 
        </mi> 
        <mo>
          ¯ 
        </mo> 
       </mover> 
       <mo>
         = 
       </mo> 
       <mn>
         0.00036 
       </mn> 
      </mrow> 
     </math>, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mrow> 
         <mi>
           X 
         </mi> 
         <mi>
           P 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         238 
       </mn> 
      </mrow> 
     </math> and T<sub>G</sub> = 14-May-22. Equations (15) and (16) yielded disease variables from T<sub>E</sub> to T<sub>G</sub> such that I<sub>G</sub> = 0.00817. Comparison with previous waves gave T<sub>B</sub> = 16-Apr-20 and I<sub>B</sub> = 0.00827. Equation (10) assigned values to S<sub>G</sub>, I<sub>G</sub>, R<sub>G</sub>, D<sub>G</sub>, and β<sub>G</sub> = 0.84538. Section 2.4.4, applied at T<sub>VN</sub> = T<sub>G</sub> = 14-May-22 with c = 0, β<sub>b</sub> = β<sub>G</sub> = 0.84538 and m = 15 led to Case 1 (blue dashed curve in <xref ref-type="fig" rid="fig9">
      Figure 9
     </xref>). Subsequent relaxation for t &gt; T<sub>VN</sub> led to the best fit for the left side of the back section of the wave (model solution from T<sub>G</sub> to T<sub>MT</sub> in <xref ref-type="fig" rid="fig9">
      Figure 9
     </xref>), using c = −0.15 (15% relaxation) and m = 15. We effected another intervention at T<sub>VN</sub> = T<sub>MT</sub> = 17-Jun-22, near the apex of the wave. Section 2.4.4, applied at T<sub>VN</sub> = T<sub>MT</sub> = 17-Jun-22 with c = 0, β<sub>b</sub> = 0.169597 and m = 15 led to Case 2 (blue dotted curve in <xref ref-type="fig" rid="fig9">
      Figure 9
     </xref>). Subsequent mitigation for t &gt; T<sub>VN</sub> = T<sub>MT</sub> led to the best fit for the right side of the back section of the wave (model solution for t &gt; T<sub>MT</sub> in <xref ref-type="fig" rid="fig9">
      Figure 9
     </xref>), using c = 0.82 (82% mitigation) and m = 15. Combination of the fore and back sections of the wave yielded the complete 6<sup>th</sup> wave (<xref ref-type="fig" rid="fig9">
      Figure 9
     </xref>).</p>
    <p>
     <xref ref-type="bibr" rid="scirp.142135-"></xref>Section 2.6 yielded R<sup>2</sup> = 0.947 and the error metrics, RMSE = 0.0093, NRMSE = 6%, and HH = 0.0309. These values show that the simulation provides a very good fit to the data.</p>
    <fig id="fig9" position="float">
     <label>Figure 9</label>
     <caption>
      <title>Figure 9. Computed and observed 6<sup>th</sup> wave of COVID-19 in Kenya. The black curve represents the data while the red represents the model. E is the change point from the 5<sup>th</sup> to the 6<sup>th</sup> wave, at the corresponding time T<sub>E</sub>. G is the end of the fore section of the wave, where exponential growth terminates and T<sub>G</sub> is the corresponding time. The blue dashed curve is the non-intervention curve from T<sub>G</sub>. T<sub>MT</sub> is a point near the apex of the wave where mitigation is applied. The dotted blue curve is the non-intervention curve from T<sub>MT</sub>.T<sub>W</sub> is the end of the 6<sup>th</sup> wave.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId187.jpeg?20250423024432" />
    </fig>
    <p>Section 2.4.2 yielded the best fit for the fore section (arc E-G in <xref ref-type="fig" rid="fig10">
      Figure 10
     </xref>), obtained using T<sub>E</sub> = 22-Aug-22, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mover accent="true"> 
        <mi>
          S 
        </mi> 
        <mo>
          ¯ 
        </mo> 
       </mover> 
       <mo>
         = 
       </mo> 
       <mn>
         0.63 
       </mn> 
      </mrow> 
     </math>, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          β 
        </mi> 
        <mrow> 
         <mi>
           X 
         </mi> 
         <mi>
           P 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0.11 
       </mn> 
      </mrow> 
     </math> and T<sub>G</sub> = 10-Oct-22. Equations (15) and (16) yielded disease variables from T<sub>E</sub> to T<sub>G</sub> such that I<sub>G</sub> = 0.0101. Comparison with previous waves gave T<sub>B</sub> = 17-May-22 and I<sub>B</sub> = 0.0105. Equation (10) assigned values to S<sub>G</sub>, I<sub>G</sub>, R<sub>G</sub>, D<sub>G</sub>, and β<sub>G</sub> = 0.029875. Section 2.4.4, applied at T<sub>VN</sub> = T<sub>G</sub> = 10-Oct-22 with c = 0, β<sub>b</sub> = β<sub>G</sub> = 0.029875 and m = 15 led to Case 1 (blue dashed curve in <xref ref-type="fig" rid="fig10">
      Figure 10
     </xref>). Subsequent relaxation for t &gt; T<sub>VN</sub> led to the best fit for the left side of the back section of the wave (model solution from T<sub>G</sub> to T<sub>MT</sub> in <xref ref-type="fig" rid="fig10">
      Figure 10
     </xref>), using c = −0.2 (20% relaxation) and m = 15. We effected another intervention at T<sub>VN</sub> = T<sub>MT</sub> = 05-Nov-22, near the apex of the wave. Section 2.4.4, applied at T<sub>VN</sub> = T<sub>MT</sub> = 05-Nov-22 with c = 0, β<sub>b</sub> = 0.1781 and m = 15 led to Case 2 (blue dotted curve in <xref ref-type="fig" rid="fig10">
      Figure 10
     </xref>). Subsequent mitigation for t &gt; T<sub>VN</sub> = T<sub>MT</sub> led to the best fit for the right side of the back section of the wave (model solution for t &gt; T<sub>MT</sub> in <xref ref-type="fig" rid="fig10">
      Figure 10
     </xref>), using c = 0.68 (68% mitigation) and m = 10. Combination of the fore and back sections of the wave yielded the complete 7<sup>th</sup> wave (<xref ref-type="fig" rid="fig10">
      Figure 10
     </xref>). We noticed some noise in the data from mid-December 2022 before it stopped being posted in the public portal of the Ministry of Health site on 26 January 2023 <xref ref-type="bibr" rid="scirp.142135-33">
      [33]
     </xref>.</p>
    <p>Section 2.6 yielded R<sup>2</sup> = 0.82 and the error metrics, RMSE = 0.0186, NRMSE = 11%, and HH = 0.1118. These values show that the simulation provides a good fit to the data, despite the noise in the data towards the end of the wave.</p>
    <fig id="fig10" position="float">
     <label>Figure 10</label>
     <caption>
      <title>Figure 10. Computed and observed 7<sup>th</sup> wave of COVID-19 in Kenya. The black curve represents the data while the red represents the model. E is the change point from the 6<sup>th</sup> to the 7<sup>th</sup> wave, at the corresponding time T<sub>E</sub>. G is the end of the fore section of the wave, where exponential growth terminates, and T<sub>G</sub> is the corresponding time. The blue dashed curve is the non-intervention curve from T<sub>G</sub>. T<sub>MT</sub> is a point near the apex of the wave where mitigation is applied. The dotted blue curve is the non-intervention curve from T<sub>MT</sub>. T<sub>W</sub> is the end of the 7<sup>th</sup> wave.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId192.jpeg?20250423024434" />
    </fig>
    <p>a) When estimating the interval [T<sub>E</sub>, T<sub>G</sub>} within which the susceptible fraction, S, is taken to be constant, in <xref ref-type="fig" rid="fig4">
      Figure 4
     </xref>, it is sufficient to choose the values of S that agree to one or two significant figures, unless values that agree to more significant figures are available.</p>
    <p>b) A summary of the computation procedure for the 6<sup>th</sup> and 7<sup>th</sup> waves is provided in the supplement, <xref ref-type="table" rid="tableS2">
      Table S2
     </xref>.</p>
   </sec>
   <sec id="s3_4">
    <title>3.4. Consolidated Results</title>
    <p>Consolidation of <xref ref-type="fig" rid="fig1">
      Figure 1
     </xref> and <xref ref-type="fig" rid="figFigures 5-10">
      Figures 5-10
     </xref>, without the non-intervention curves, yields the complete COVID-19 waves in Kenya, as shown in <xref ref-type="fig" rid="fig11">
      Figure 11
     </xref>, where the model results are compared with data. The simulation and data are very close graphically.</p>
    <p>Section 2.6 yielded R<sup>2</sup> = 0.882 and the error metrics, RMSE = 0.02360, NRMSE = 6%, and HH = 0.0711. These values show that the simulation provides a very good fit to the data.</p>
    <fig id="fig11" position="float">
     <label>Figure 11</label>
     <caption>
      <title>Figure 11. Computed and observed complete COVID-19 Waves in Kenya. The black curve represents the data while the red represents the model.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724054-rId193.jpeg?20250423024438" />
    </fig>
    <p>In <xref ref-type="table" rid="table1">
      Table 1
     </xref>, we present the amplitudes and durations of the waves. The durations are based on the times between identified change points and they differ slightly from those arrived at from clinical considerations <xref ref-type="bibr" rid="scirp.142135-35">
      [35]
     </xref>. The strongest wave was the 5<sup>th</sup> at 33.6% infected and the weakest was the 7<sup>th</sup> wave at 13.0% infected. The longest lasting was the 1<sup>st</sup> wave, with a duration of 174 days while the shortest was the 2<sup>nd</sup> with a duration of 116 days.</p>
    <table-wrap id="table1">
     <label>
      <xref ref-type="table" rid="table1">
       Table 1
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.142135-"></xref>Table 1. Kenya COVID-19 wave amplitudes in 7-day averaged percent infected and durations in days.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td custom-top-td acenter" width="17.50%"><p style="text-align:center"></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="11.77%"><p style="text-align:center">Wave 1</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="11.79%"><p style="text-align:center">Wave 2</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="11.79%"><p style="text-align:center">Wave 3</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="11.79%"><p style="text-align:center">Wave 4</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="11.79%"><p style="text-align:center">Wave 5</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="11.79%"><p style="text-align:center">Wave 6</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="11.79%"><p style="text-align:center">Wave 7</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="17.50%"><p style="text-align:center">Amplitude</p><p style="text-align:center">(% infected)</p></td> 
       <td class="custom-top-td acenter" width="11.77%"><p style="text-align:center">13.1</p></td> 
       <td class="custom-top-td acenter" width="11.79%"><p style="text-align:center">18.0</p></td> 
       <td class="custom-top-td acenter" width="11.79%"><p style="text-align:center">18.6</p></td> 
       <td class="custom-top-td acenter" width="11.79%"><p style="text-align:center">17.1</p></td> 
       <td class="custom-top-td acenter" width="11.79%"><p style="text-align:center">33.6</p></td> 
       <td class="custom-top-td acenter" width="11.79%"><p style="text-align:center">13.6</p></td> 
       <td class="custom-top-td acenter" width="11.79%"><p style="text-align:center">13.0</p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td acenter" width="17.50%"><p style="text-align:center">Duration</p><p style="text-align:center">(Days)</p></td> 
       <td class="custom-bottom-td acenter" width="11.77%"><p style="text-align:center">174</p></td> 
       <td class="custom-bottom-td acenter" width="11.79%"><p style="text-align:center">116</p></td> 
       <td class="custom-bottom-td acenter" width="11.79%"><p style="text-align:center">125</p></td> 
       <td class="custom-bottom-td acenter" width="11.79%"><p style="text-align:center">172</p></td> 
       <td class="custom-bottom-td acenter" width="11.79%"><p style="text-align:center">143</p></td> 
       <td class="custom-bottom-td acenter" width="11.79%"><p style="text-align:center">161</p></td> 
       <td class="custom-bottom-td acenter" width="11.79%"><p style="text-align:center">157</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>In <xref ref-type="table" rid="table2">
      Table 2
     </xref>, we present the SARS-CoV-2 variants of concern and the periods when they were dominant, as determined from genomic analysis <xref ref-type="bibr" rid="scirp.142135-2">
      [2]
     </xref> <xref ref-type="bibr" rid="scirp.142135-35">
      [35]
     </xref>. We have also indicated the change points at which new waves were computationally generated by the application of large relaxation forces or through exponential approximation. We note that the change points fall in the months when the variants of SARS-CoV-2 started to be dominant. This makes us conclude that the dominant variants of SARS-CoV-2 were the most likely sources of the large relaxation forces that could turn infections with negative gradients to those with positive gradients, thus leading to new COVID-19 waves. Hence the SARS-CoV-2 variants of concern were, most likely, the main drivers of the COVID-19 waves. There were indeed other relaxation forces arising from the lifting of, or noncompliance to, mitigation measures. In our view such forces were not, on their own, sufficiently large to generate new waves of the epidemic.</p>
    <table-wrap id="table2">
     <label>
      <xref ref-type="table" rid="table2">
       Table 2
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.142135-"></xref>Table 2. Dominant SARS-CoV-2 variants and change points.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td custom-top-td acenter" width="19.07%"><p style="text-align:center">Wave Number</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="36.54%"><p style="text-align:center">Dominant SARS-CoV-2 Variant</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="29.28%"><p style="text-align:center">Period</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="15.12%"><p style="text-align:center">Change Point</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="19.07%"><p style="text-align:center">WAVE 1</p></td> 
       <td class="custom-top-td acenter" width="36.54%"><p style="text-align:center">B.1</p></td> 
       <td class="custom-top-td acenter" width="29.28%"><p style="text-align:center">MAR-2020 to SEP-2020</p></td> 
       <td class="custom-top-td acenter" width="15.12%"><p style="text-align:center">13-MAR-20</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="19.07%"><p style="text-align:center">WAVE 2</p></td> 
       <td class="acenter" width="36.54%"><p style="text-align:center">Beta</p></td> 
       <td class="acenter" width="29.28%"><p style="text-align:center">SEP-2020 to NOV-2020</p></td> 
       <td class="acenter" width="15.12%"><p style="text-align:center">03-SEP-20</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="19.07%"><p style="text-align:center">WAVE 3</p></td> 
       <td class="acenter" width="36.54%"><p style="text-align:center">Alpha</p></td> 
       <td class="acenter" width="29.28%"><p style="text-align:center">DEC-2020 to APR-2021</p></td> 
       <td class="acenter" width="15.12%"><p style="text-align:center">28-DEC-20</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="19.07%"><p style="text-align:center">WAVE 4</p></td> 
       <td class="acenter" width="36.54%"><p style="text-align:center">Delta</p></td> 
       <td class="acenter" width="29.28%"><p style="text-align:center">MAY-2021 to OCT-2021</p></td> 
       <td class="acenter" width="15.12%"><p style="text-align:center">02-MAY-21</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="19.07%"><p style="text-align:center">WAVE 5</p></td> 
       <td class="acenter" width="36.54%"><p style="text-align:center">Omicron</p></td> 
       <td class="acenter" width="29.28%"><p style="text-align:center">OCT-2021 to FEB-2022</p></td> 
       <td class="acenter" width="15.12%"><p style="text-align:center">21-OCT-21</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="19.07%"><p style="text-align:center">WAVE 6</p></td> 
       <td class="acenter" width="36.54%"><p style="text-align:center">Omicron, sub-variants BA.4 &amp; BA.5</p></td> 
       <td class="acenter" width="29.28%"><p style="text-align:center">MAR-2022 to AUG-2022</p></td> 
       <td class="acenter" width="15.12%"><p style="text-align:center">13-MAR-22</p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td acenter" width="19.07%"><p style="text-align:center">WAVE 7</p></td> 
       <td class="custom-bottom-td acenter" width="36.54%"><p style="text-align:center">Omicron BQ1 and BQ1.1</p></td> 
       <td class="custom-bottom-td acenter" width="29.28%"><p style="text-align:center">AUG-2022 to JAN-2023</p></td> 
       <td class="custom-bottom-td acenter" width="15.12%"><p style="text-align:center">22-AUG-22</p></td> 
      </tr> 
     </table>
    </table-wrap>
   </sec>
  </sec><sec id="s4">
   <title>4. Conclusions</title>
   <p>In this study, we have formulated, analysed and computed a COVID-19 model that is based on the generation of two types of new waves. The first type is a wave generated from a vertically decreasing infection that diverges to the right, and forms a concave shape before increasing upwards; such a wave is modelled by generating a wave using large relaxation ratios ranging from c = −2.9 (290% relaxation) to c = −10 (1000% relaxation). The second type is a wave that emerges from very low infections with a trajectory that is almost horizontal; such a wave is modelled by an exponential infection. The models were implemented taking into consideration the characteristics of each wave. The simulations provide good to very good fit to the data. No other comparable results, based on compartmental models, are available for modelling the complete COVID-19 waves in Kenya or elsewhere. The closest to this work are results for a few waves in India <xref ref-type="bibr" rid="scirp.142135-22">
     [22]
    </xref>.</p>
   <p>The change point that determines the transition from one wave to the next is obtained by noting the tail end of the modelled preceding wave and where the trajectory of the newly observed infection begins to diverge from this tail. After identifying the change point, the transition from one wave to the next has so far been determined empirically, or computationally. Mathematical analysis should be carried out to unravel the theory behind this transition. With increased attention being paid to AI, we should, however, be prepared for the possibility that computational experimentation could yield some exciting results before theoretical justification becomes available.</p>
   <p>We have introduced a robust mathematical and computational model that adeptly captures the dynamics of multiple COVID-19 waves and is successfully applied to Kenya. The model was developed after analysis of the wave formation patterns in Kenya. Since such patterns are not unique to Kenya, and the methods section presents descriptions in general parameter terms, it is possible to adapt this model to investigate multiple COVID-19 waves outside Kenya.</p>
   <p>Further research is imperative to expand the model’s capabilities and enhance its practical application. Future efforts should focus on incorporating real-time data integration to refine predictive accuracy, improving computational algorithms for faster real-time processing, and broadening the model’s applicability to include new strains of COVID-19, influenza and other respiratory viruses. Additionally, creating user-friendly interfaces will make this tool accessible to a broader range of policymakers and health professionals, enabling informed decision-making in public health management.</p>
  </sec><sec id="s5">
   <title>Author Contributions</title>
   <p>W.O. conceptualized the study, developed the theory, designed the computation procedures and wrote the initial draft, with input from all the authors. V.O.J. contributed to improvement of the theory, verified analytical methods and carried out the numerical simulations. W.D.B. provided the biological and biochemical interpretation of the model; also provided information on the COVID-19 variants. V.N.C. collected information on mitigation and relaxation forces due to NPIs. All authors discussed the results and contributed to the final manuscript.</p>
  </sec><sec id="s6">
   <title>Acknowledgements</title>
   <p>We acknowledge Lucy Nyanchama for her assistance with data collection.</p>
  </sec><sec id="s7">
   <title>Data Sources</title>
   <p>All the data used is in the public domain <xref ref-type="bibr" rid="scirp.142135-33">
     [33]
    </xref> <xref ref-type="bibr" rid="scirp.142135-34">
     [34]
    </xref>.</p>
  </sec><sec id="s8">
   <title>Supplement</title>
   <table-wrap id="table3">
    <label>
     <xref ref-type="table" rid="table3">
      Table 3
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.142135-"></xref>Table S1. A summary of the computation procedure for the 2<sup>nd</sup> to 5<sup>th</sup> COVID-19 Waves in Kenya.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td custom-top-td acenter" width="51.48%" colspan="2"><p style="text-align:center">Variables and Parameters</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="8.50%"><p style="text-align:center">2<sup>nd</sup> Wave</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="8.50%"><p style="text-align:center">3<sup>rd</sup> Wave</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="12.42%"><p style="text-align:center">4<sup>th</sup> wave 1<sup>st</sup> Spike</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="11.76%"><p style="text-align:center">4<sup>th</sup> wave 2<sup>nd</sup> Spike</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="7.35%"><p style="text-align:center">5<sup>th</sup> Wave</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td aleft" width="45.60%"><p style="text-align:left">A. FORE SECTION OF THE WAVE</p></td> 
      <td class="custom-top-td acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">A1. Generation of new wave by relaxation</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Change point</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">T<sub>E</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">03-09-20</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">28-12-20</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">02-05-21</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">27-06-21</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">21-10-21</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Transmission rate preceding relaxation at T<sub>E</sub>; [=β(T<sub>E</sub>)]</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">β<sub>b</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">0.13507</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">0.17018</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">0.16339</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">0.079341</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">0.13071</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Relaxation ratio for wave generation</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">c</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">−4</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">−9</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">−7</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">−2.9</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">−10</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Duration of optimal change of transmission rate</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">m</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">30</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">45</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">30</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">30</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">60</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Use values of S, I, R, D and β at T<sub>E</sub> to solve the system till the time for enforcing the delay-function as indicated below.</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">A2. Application of delay-function</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Time in current wave at which delay-function is enforced</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">T<sub>G</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">08-10-20</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">10-02-21</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">01-06-21</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">26-07-21</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">02-12-21</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Approximate infected ratio at T<sub>G</sub></p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">I<sub>G</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">0.07394</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">0.04099</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">0.0724</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">0.143</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">0.0147</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Infection in previous wave that approximates I<sub>G</sub></p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">I<sub>B</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">0.07394</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">0.04099</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">0.0724</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">0.143</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">0.014699</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Time at which I<sub>B</sub> occurs.</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">T<sub>B</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">17-06-20</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">26-05-20</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">28-02-21</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">14-03-21</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">27-04-20</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Apply delay-function at T<sub>G</sub> to, I, R, D and β</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">B. BACK SECTION OF THE WAVE</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">B1. Intervention (Relaxation/Mitigation)</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">From T<sub>G</sub> solve the system for L days then apply intervention</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Number of days for solution after T<sub>G</sub></p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">L</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">11</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Time at which intervention is enforced</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">T<sub>VN</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">08-10-20</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">21-02-21</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">01-06-21</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">26-07-21</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">02-12-21</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Transmission rate preceding intervention at T<sub>VN</sub>; [=β(T<sub>VN</sub>)]</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">β<sub>b</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">0.67533</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">0.10892</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">1.3071</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">0.29571</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">0.67286</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Apply Relaxation/Mitigation from non-intervention curve</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">c</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">−0.26</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">−0.5</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">0.5</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">0.2</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">−4</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Duration of optimal change of transmission rate</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">m</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">15</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">10</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">30</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">15</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">15</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">B2. Application of the 2nd delay-function</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">L days from previous relaxation, apply a 2<sup>nd</sup> delay-function</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Number of days to follow previous relaxation</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">L</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">12</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Time at which the 2<sup>nd</sup> delay-function is enforced</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">T<sub>G</sub><sub>2</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">14-12-21</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Approximate infected fraction at T<sub>G</sub><sub>2</sub></p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">I<sub>G</sub><sub>2</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">0.0988</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Infection in previous wave that approximates I<sub>G</sub><sub>2</sub></p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">I<sub>B</sub><sub>2</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">0.0985</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Time in previous wave where I<sub>B</sub><sub>2</sub> occurs.</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">T<sub>B</sub><sub>2</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">16-07-21</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Apply delay-function at T<sub>B</sub><sub>2</sub>; Follow by relaxation at T<sub>B</sub><sub>2</sub>.</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">B3. Application of the 2nd relaxation</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Time for 2<sup>nd</sup> relaxation (=T<sub>G</sub><sub>2</sub>)</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">T<sub>VN</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">14-12-21</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Transmission rate preceding 2nd relaxation; [=β(T<sub>VN</sub>)]</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">β<sub>b</sub></p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">0.39473</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Relaxation ratio</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">c</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">−3.5</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="45.60%"><p style="text-align:left">Duration of optimal change of transmission rate</p></td> 
      <td class="acenter" width="5.88%"><p style="text-align:center">m</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="8.50%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="12.42%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="11.76%"><p style="text-align:center">-</p></td> 
      <td class="acenter" width="7.35%"><p style="text-align:center">5</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td aleft" width="45.60%"><p style="text-align:left">Use the values of S, I, R, D and β, and the associated Relaxation/Mitigation parameters, at the last intervention point, T<sub>VN</sub>, and solve the system of ODEs for t &gt; TVN to obtain the rest of the wave</p></td> 
      <td class="custom-bottom-td acenter" width="5.88%"><p style="text-align:center"></p></td> 
      <td class="custom-bottom-td acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="custom-bottom-td acenter" width="8.50%"><p style="text-align:center"></p></td> 
      <td class="custom-bottom-td acenter" width="12.42%"><p style="text-align:center"></p></td> 
      <td class="custom-bottom-td acenter" width="11.76%"><p style="text-align:center"></p></td> 
      <td class="custom-bottom-td acenter" width="7.35%"><p style="text-align:center"></p></td> 
     </tr> 
    </table>
   </table-wrap>
   <table-wrap id="table4">
    <label>
     <xref ref-type="table" rid="table4">
      Table 4
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.142135-"></xref>Table S2. A summary of the computation procedure for the 6<sup>th</sup> to 7<sup>th</sup> COVID-19 Waves in Kenya.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td custom-top-td acenter" width="75.18%" colspan="2"><p style="text-align:center">Variables and Parameters</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="12.41%"><p style="text-align:center">6<sup>th</sup> Wave</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="12.41%"><p style="text-align:center">7<sup>th</sup> Wave</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td aleft" width="66.59%"><p style="text-align:left">A. FRONT SECTION OF COMPUTED WAVE</p></td> 
      <td class="custom-top-td acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">A1. Generation of new wave by exponential infection</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Change point</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">T<sub>E</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">13-03-22</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">22-08-22</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Infected fraction at Change Point</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">I<sub>E</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.00255</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.00899</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Constant Susceptible fraction for exponential infection</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"> 
        <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mover accent="true"> 
          <mi>
            S 
          </mi> 
          <mo>
            ¯ 
          </mo> 
         </mover> 
        </math></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.00036</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.63</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Transmission rate for exponential infection</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">β<sub>XP</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">238</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.11</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Use values of S, I, R, and D at T<sub>E</sub> as initial values and solve the system till the time for enforcing delay-function as below.</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">A2. Application of delay-function</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Time in current wave at which delay-function is enforced</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">T<sub>G</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">14-05-22</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">10-10-22</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Approximate infected ratio at T<sub>G</sub></p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">I<sub>G</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.00817</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.0101</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Infection in previous wave that approximates I<sub>G</sub></p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">I<sub>B</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.00827</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.0105</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Time at which I<sub>B</sub> occurs</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">T<sub>B</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">16-04-20</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">17-05-22</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Apply delay-function: Let V(I<sub>G</sub>) = V(I<sub>B</sub>), where V is S, I, R, D and β</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">B. BACK SECTION OF THE WAVES</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">B1. Relaxation</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Apply relaxation at the point of delay-function</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Time of at which relaxation is enforced; [=T<sub>G</sub>]</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">T<sub>VN</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">14-05-22</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">10-10-22</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Transmission rate preceding relaxation at T<sub>VN</sub>; [=β(T<sub>VN</sub>)]</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">β<sub>b</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.84538</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.029875</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Relaxation ratio</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">c</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">−0.15</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">−0.2</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Duration of optimal change of transmission rate</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">m</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">15</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">15</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">B2. Mitigation</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">After following the relaxation curve, determine when to apply mitigation</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Time at which mitigation is applied; [=T<sub>MT</sub>]</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">T<sub>VN</sub> <sup>= </sup>T<sub>MT</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">17-06-22</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">05-11-22</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Transmission rate preceding mitigation at T<sub>VN</sub> = T<sub>MT</sub>; [=β(T<sub>VN</sub>)]</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">β<sub>b</sub></p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.169597</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.1781</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Mitigation ratio</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">c</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.82</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">0.68</p></td> 
     </tr> 
     <tr> 
      <td class="aleft" width="66.59%"><p style="text-align:left">Duration of optimal change of transmission rate</p></td> 
      <td class="acenter" width="8.59%"><p style="text-align:center">m</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">15</p></td> 
      <td class="acenter" width="12.41%"><p style="text-align:center">10</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td aleft" width="66.59%"><p style="text-align:left">Use the values of S, I, R, D and β, and the associated Mitigation parameters, at the last intervention point, T<sub>MT</sub>, and solve the system of ODEs for t &gt; T<sub>MT</sub> to obtain the rest of the wave</p></td> 
      <td class="custom-bottom-td acenter" width="8.59%"><p style="text-align:center"></p></td> 
      <td class="custom-bottom-td acenter" width="12.41%"><p style="text-align:center"></p></td> 
      <td class="custom-bottom-td acenter" width="12.41%"><p style="text-align:center"></p></td> 
     </tr> 
    </table>
   </table-wrap>
  </sec>
 </body><back>
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