<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">AJOR</journal-id><journal-title-group><journal-title>American Journal of Operations Research</journal-title></journal-title-group><issn pub-type="epub">2160-8830</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/ajor.2024.141003</article-id><article-id pub-id-type="publisher-id">AJOR-130601</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  A Note on an Order Level Inventory Model with Varying Two-Phased Demand and Time-Proportional Deterioration
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Sephali</surname><given-names>Mohanty</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Trailokyanath</surname><given-names>Singh</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Sudhansu</surname><given-names>Sekhar Routary</given-names></name><xref ref-type="aff" rid="aff2"><sup>2</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Chinmayee</surname><given-names>Naik</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref></contrib></contrib-group><aff id="aff1"><addr-line>Department of Mathematics, C. V. Raman Global University, Bhubaneswar, India</addr-line></aff><aff id="aff2"><addr-line>Department of Mathematics and Humanities, Odisha University of Technology and Research, Bhubaneswar, India</addr-line></aff><pub-date pub-type="epub"><day>17</day><month>01</month><year>2024</year></pub-date><volume>14</volume><issue>01</issue><fpage>59</fpage><lpage>73</lpage><history><date date-type="received"><day>25,</day>	<month>December</month>	<year>2023</year></date><date date-type="rev-recd"><day>19,</day>	<month>January</month>	<year>2024</year>	</date><date date-type="accepted"><day>22,</day>	<month>January</month>	<year>2024</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
  Th
  e main purpose of this paper is to generalize the effect of two-phased demand and variable deterioration within the EOQ (Economic Order Quantity) framework. The rate of deterioration is a linear function of time. The two-ph
  ased demand function states the constant function for a
   
  certain period and
   the
   quadratic function of time for 
  the
   rest part of the cycle time. No shortages as well as partial backlogging are allowed to occur. The mathematical expressions are derived for determining the optimal cycle time, order quantity and total cost function. An easy-to-use working procedure is provided to calculate the above quantities. A couple of numerical examples are cited to explain the theoretical results and sensitivity analysis of some selected example
  s
   is carried out.
 
</p></abstract><kwd-group><kwd>Deteriorating Items</kwd><kwd> EOQ (Economic Order Quantity)</kwd><kwd> Inventory</kwd><kwd> Time-Proportional Deterioration</kwd><kwd> Two-Phased Demand</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>In recent decades, there has been a spate of interest in analyzing and formulating inventory models for deteriorating items from the point of view of practical applications. The classical EOQ (Economic Order Quantity) models of Harris [<xref ref-type="bibr" rid="scirp.130601-ref1">1</xref>] and Wilson [<xref ref-type="bibr" rid="scirp.130601-ref2">2</xref>] consider the exhaustion of inventory only due to the effect of unchanging demand. But, it has been observed that the depletion of the inventory is due to some demand patterns and some natural phenomena like decay, dryness, evaporation and spoilage. These natural phenomena are directly or indirectly called the process of “deterioration”. Firstly, Ghare and Schrader [<xref ref-type="bibr" rid="scirp.130601-ref3">3</xref>] derived the mathematical expression of the EOQ inventory model with several factors such as inventory level during the cycle time, demand function and instantaneous deterioration rate. They represented these factors with the help of a differential equation d I ( t ) d t + Z ( t ) I ( t ) + D ( t ) = 0 ,   0 ≤ t ≤ T , where I ( t ) , D ( t ) , Z ( t ) and T refer to the inventory level, the demand and the deterioration and time period, respectively. Donaldson [<xref ref-type="bibr" rid="scirp.130601-ref4">4</xref>] examined a complicated analytic solution procedure for the classical no-shortage inventory model for deteriorating items with linear trend in demand over a finite horizon cycle time. An order level no-shortage inventory system with constant demand as well as a constant rate of deterioration was developed by Aggarwal [<xref ref-type="bibr" rid="scirp.130601-ref5">5</xref>] . An inventory model for deteriorating items with linear trends demand, constant deterioration and no-shortages was studied by Dave and Patel [<xref ref-type="bibr" rid="scirp.130601-ref6">6</xref>] . Later, Sachan [<xref ref-type="bibr" rid="scirp.130601-ref7">7</xref>] extended Dave and Patel’s [<xref ref-type="bibr" rid="scirp.130601-ref6">6</xref>] model considering a new factor as shortages. Singh and Pattnayak [<xref ref-type="bibr" rid="scirp.130601-ref8">8</xref>] studied an inventory model for a deteriorating item with varying time-dependent constant demand and Weibull distribution deterioration under permissible delay in payment. Some of the minimization problems on inventory models for deteriorating items under various conditions have been solved by [<xref ref-type="bibr" rid="scirp.130601-ref9">9</xref>] . Reviews of advances in deteriorating inventory policies were presented by Raafat [<xref ref-type="bibr" rid="scirp.130601-ref10">10</xref>] , Goyal and Giri [<xref ref-type="bibr" rid="scirp.130601-ref11">11</xref>] , Li et al. [<xref ref-type="bibr" rid="scirp.130601-ref12">12</xref>] and Janssen et al. [<xref ref-type="bibr" rid="scirp.130601-ref13">13</xref>] .</p><p>In the detailed survey of review literature on inventory policies, it was observed that the assumption of a constant demand rate is not always suitable for many inventory items (cosmetics, fashion apparel, consumable items and electronics goods) because they experience fluctuations in demand during time of consideration. Thereafter, researches were developed on mainly two types of demand rates such as linear and exponential. The linear and exponential time-varying demands indicate a uniform change and rapid change in demand rates of the item per unit time, respectively those which seldom occur in the real market situation. The optimal replenishment policies for deteriorating items with linear trended demand shortages in all cycles were presented by Goswami and Chaudhuri [<xref ref-type="bibr" rid="scirp.130601-ref14">14</xref>] and Chakrabarti and Chaudhuri [<xref ref-type="bibr" rid="scirp.130601-ref15">15</xref>] . Chung and Ting [<xref ref-type="bibr" rid="scirp.130601-ref16">16</xref>] established an EOQ inventory model for deteriorating items with linear demand, no-shortages and time-proportional deterioration rate. Wee [<xref ref-type="bibr" rid="scirp.130601-ref17">17</xref>] presented an optimal replenishment policy with the assumptions of varying demand patterns and shortages in the declining situation of the market. Hollier and Mak [<xref ref-type="bibr" rid="scirp.130601-ref18">18</xref>] and Ouyang et al. [<xref ref-type="bibr" rid="scirp.130601-ref19">19</xref>] studied the optimal models for deteriorating items with constant deterioration rates and exponential demand rates. Srivastava and Gupta [<xref ref-type="bibr" rid="scirp.130601-ref20">20</xref>] formulated a no-shortage EOQ model for deteriorating items with a constant deterioration rate and both the constant and linearly increasing demand rate. Singh and Pattnayak [<xref ref-type="bibr" rid="scirp.130601-ref21">21</xref>] formulated an optimal two-warehouse inventory model with the incorporation of linear trended demand, constant deterioration and delay in payment conditions. Because of uniform and rapid changes in demand rate, some researchers have not considered the linear and exponential demand patterns for the development of their models. They included a time-dependent quadratic demand pattern in their models as it experiences either accelerated growth or retard growth in demand. The general form of the quadratic demand rate is D ( t ) = a + b t + c t 2 . Here, c = 0 and b = c = 0 refer to the linear and constant demand patterns, respectively. An order level inventory model with no-shortages, time-dependent quadratic demand and constant deterioration was presented by Khanra and Chaudhuri [<xref ref-type="bibr" rid="scirp.130601-ref22">22</xref>] . Ghosh and Chaudhuri [<xref ref-type="bibr" rid="scirp.130601-ref23">23</xref>] established an optimal inventory model by incorporating the two-parameter Weibull distribution deterioration, time-dependent quadratic demand pattern and shortages. Khanra et al. [<xref ref-type="bibr" rid="scirp.130601-ref24">24</xref>] discussed an order-level inventory model for a deteriorating item with time-dependent quadratic demand rate and constant deterioration rate. Singh et al. (2017) formulated an ordering policy for deteriorating items focusing on the time-proportional deterioration rate and both constant and time-dependent linear demand rates and no-shortages.</p><p>Generally, items start deteriorating after a certain period of time on inclusion into the stock. Therefore, the constant deterioration rate is not always suitable for the consideration for formulation of the inventory model. This type of lacking is filled by Weibull distribution deterioration rates because it varies with the passage of time. In this context, Covert and Philip [<xref ref-type="bibr" rid="scirp.130601-ref25">25</xref>] modified Ghare and Schrader’s [<xref ref-type="bibr" rid="scirp.130601-ref3">3</xref>] model by replacing the constant deterioration rate with the two-parameter Weibull distribution deterioration rate. Singh et al. [<xref ref-type="bibr" rid="scirp.130601-ref26">26</xref>] studied an optimal policy for deteriorating items with variable deterioration rates and constant and time-dependent demand rates. Singh et al. [<xref ref-type="bibr" rid="scirp.130601-ref27">27</xref>] presented a three-cased EOQ optimal policy for deteriorating items with the help of trapezoidal type demand, three-parameter Weibull distribution deterioration and shortages. A note on an inventory model for a deteriorating item with varying cubic demand and variable deterioration under permissible delay in payment was studied by Mohanty and Singh [<xref ref-type="bibr" rid="scirp.130601-ref28">28</xref>] .</p><p>In practice, the assumptions of the constant deterioration rate and the constant demand pattern are debatable. A common practical situation is when the demand is constant for a certain period and then it varies with time for the rest part of the inventory cycle time. Recently, Srivastava and Gupta [<xref ref-type="bibr" rid="scirp.130601-ref20">20</xref>] studied a no-shortages inventory model for deteriorating items with a constant deterioration rate and both the constant and linear demand patterns. In this work, an optimal EOQ inventory policy is developed with the inclusion of a two-phased demand pattern, variable deterioration and no shortages. The two-phase demand describes the constant demand for the first part and time-dependent quadric demand for the rest part of the inventory cycle time. This pattern of demand rate shows the demand for items such as newly launched mobiles, automobiles, fashion apparels, cosmetics etc. as they experience constant demand in the first part and time-dependent quadric quadratic in the rest part of the cycle time. In addition, the deterioration rate is considered as a linear function of time for the second part of the inventory cycle. We think such type of two-phase demand pattern and time-proportional deterioration is quite realistic for developing no-shortage inventory model for deteriorating items. The objective of the proposed work is to optimize the average total cost and ordered quantity with respect to the cycle time. Finally, the model is illustrated with a couple of numerical examples and a sensitivity analysis of a selected example is presented.</p><p>The rest portion of the paper is arranged as follows: In Section 2, the notations and the fundamental assumptions involved in this problem are described. The mathematical formulation of the model and its working procedure are given in Section 3. Section 4 addresses a couple of numerical examples followed by sensitivity analysis of all system parameters in Section 5. Finally, a summary and some suggestions for future work are provided in Section 6.</p></sec><sec id="s2"><title>2. Notations and Assumptions</title><p>The mathematical analysis of the EOQ inventory model is based on the following notations and assumptions:</p><sec id="s2_1"><title>2.1. Notations</title><p>The notations used in this paper are given below:</p><p>θ ( t ) : The linear deterioration function, i.e., θ ( t ) = θ t , where 0 &lt; θ ≪ 1 and t &gt; 0 . For t = 1 , the variable deterioration rate reduces to a constant deterioration rate.</p><p>D ( t ) : The demand rate, i.e., D ( t ) = { a ,                                                                                                                       0 ≤ t ≤ η a + b ( t − η ) + c ( t − η ) 2 ,                           η ≤ t ≤ T .</p><p>During the first interval [ 0 , η ] , the demand is constant at the rate of a units per unit time, i.e., it does not vary with time and during the second interval [ η , T ] , the demand rate is a quadratic function of time.</p><p>I ( t ) : The inventory level at any time t.</p><p>T: The length of the cycle.</p><p>I s : The number of items received at the starting of the inventory system.</p><p>c o : The ordering cost per order.</p><p>h c : The inventory holding cost per unit per unit of time.</p><p>d c : The unit cost of the item per unit per unit of time.</p><p>η : The time point at which the demand increases with time as well as the deterioration starts.</p><p>T C ( T ) : The average total cost per unit per unit time.</p><p>T * : The optimal value of time T.</p><p>I s * : The optimal value of I s .</p><p>T C ( T * ) : The optimal average total cost per unit per unit time.</p></sec><sec id="s2_2"><title>2.2. Assumptions</title><p>The following assumptions are considered in this paper:</p><p>1) The inventory system involves only one type of item.</p><p>2) There is no deterioration for the first part and the varying deterioration rate in the rest part of the cycle.</p><p>3) The demand is of two-phase pattern, i.e., it is constant for the first part and quadratic function of time in the rest part of the cycle.</p><p>4) No shortages and backlogging are allowed to occur.</p><p>5) The occurrence of replenishment is instantaneous and the delivery lead time is zero.</p><p>6) Only a typical planning schedule of the length of the planning horizon is considered and all the remaining cycles are identical.</p><p>7) Deteriorated units are not replaced or repaired during the prescribed cycle period.</p><p>8) All types of costs such as ordering cost, holding cost and unit cost remain fixed over time.</p></sec></sec><sec id="s3"><title>3. Mathematical Formulation of the Model and Its Solution Procedure</title><p>The following model as well as its solution procedure is started below:</p><sec id="s3_1"><title>3.1. Model Development</title><p>Initially, the order quantity brings the level of the system up to I s units. Because of the constant demand, the level of the inventory declines, say, a units per unit time in the interval [ 0 , η ] . Due to time-dependent quadratic demand and time-varying deterioration, the inventory level gradually depletes over time t = T . The nature of the inventory system is shown in <xref ref-type="fig" rid="fig1">Figure 1</xref>.</p><p>The objective of the proposed problem is to optimize the cycle length T so that the present value of the average total cost T C ( T ) is minimized.</p><p>Initially, during the interval [ 0 , η ] , the system demand rate (SDR) per unit time and the total demand (TDR) are given by</p><p>S D R = a , (3.1)</p><p>and</p><p>T D R = a η , (3.2)</p><p>respectively.</p><p>Therefore, the inventory level is decreased by the portion a η and thus, the remaining portion of the inventory (SRI) during the interval [ η , T ] is given by</p><p>S R I = I s − a η . (3.3)</p><p>In order to make the calculation easier, the interval [ η , T ] can be taken as</p><p>t 1 = T − η . (3.4)</p><p>Consequently, the instantaneous inventory level I ( t ) at any time t during the time interval 0 ≤ t ≤ t 1 satisfies the following differential equation:</p><p>d I ( t ) d t + θ ( t ) I ( t ) = − [ a + b ( t − η ) + c ( t − η ) 2 ] ,           0 ≤ t ≤ t 1 (3.5)</p><p>where θ ( t ) = θ t ,   ( 0 &lt; θ ≪ 1 ) and I ( 0 ) = I s − a η .</p><p>Here the integrating factor (IF) and the solution of the differential equation are</p><p>I F = e θ t 2 2 , (3.6)</p><p>and</p><p>I ( t ) ⋅ e θ t 2 2 = − ∫ [ a + b ( t − η ) + c ( t − η ) 2 ] ⋅ e θ t 2 2 d t + k , (3.7)</p><p>where k is a constant of integration, respectively.</p><p>Solving the differential Equation (3.5), we have</p><p>I ( t ) = [ I s − a η − a ( t + θ t 3 6 ) − b ( − 2 η + t 2 − η θ t 3 6 + η t 4 8 )                             − c [ η 2 t − η t 2 + ( 2 + θ η 2 6 ) t 3 − η θ t 4 4 + θ t 5 10 ] ] ⋅ e − θ t 2 2 ,             0 ≤ t ≤ t 1 (3.8)</p><p>by ignoring the terms containing the powers like θ 2 , θ 3 , θ 4 , ⋯ 0 &lt; θ ≪ 1 .</p><p>The Equation (3.8) at I ( t 1 ) = 0 is given by</p><p>I s = a η + a ( t 1 + θ t 1 3 6 ) + b ( − η t 1 + t 1 2 2 − η θ t 1 3 6 + η t 1 4 8 )     + c [ η 2 t 1 − η t 1 2 + ( 2 + θ η 2 6 ) t 1 3 − η θ t 1 4 4 + θ t 1 5 10 ] (3.9)</p><p>Using the relation t 1 = T − η , Equation (3.9) is equivalent to</p><p>I s = a [ T + θ ( T − η ) 3 6 ] + b [ − η ( T − η ) + ( T − η ) 2 2 − η θ ( T − η ) 3 6 + η ( T − η ) 4 8 ]     + c [ η 2 ( T − η ) − η ( T − η ) 2 + ( 2 + θ η 2 6 ) ( T − η ) 3 − η θ ( T − η ) 4 4 + θ ( T − η ) 5 10 ] (3.10)</p><p>In order to obtain the optimum total average cost, following cost components are needed:</p><p>1) Ordering cost (SSC):</p><p>S S C = c o . (3.11)</p><p>2) Holding cost (SCC) during the period [ 0 , T ] is the sum of the holding cost during the period [ 0 , η ] and the holding cost during the period [ η , T ] , i.e.,</p><p>S C C = h c &#215; [ areaoftrapeziumPQSO + areaoftriangleQRS ] = h c [ 1 2 ⋅ ( I s + ( I s − a η ) ) ⋅ η + 1 2 ⋅ t 1 ⋅ ( I s − a η ) ] = h c [ a η 2 2 + ( I s − a η ) ( η + t 1 2 ) ] (3.12)</p><p>3) The deterioration cost (SDC) during the period [ 0 , T ] is</p><p>S D C = d c [ I s − a η − ∫ 0 t 1 [ a + b ( t − η ) + c ( t − η ) 2 ] d t ] = d c [ I s − a ( t 1 + η ) − b ( t 1 − η ) 2 2 − c ( t 1 − η ) 3 3 − b η 2 2 + c η 3 3 ] (3.13)</p><p>Hence, using the previous results, the average total cost per unit time ( T C ( T ) ) of the system during the period [ 0 , T ] :</p><p>T C ( T ) = 1 T [ S S C + S C C + S D C ] = 1 T [ c o + h c [ a η 2 2 + ( I s − a η ) ( η + t 1 2 ) ]   + d c [ I s − a ( t 1 + η ) − b ( t 1 − η ) 2 2 − c ( t 1 − η ) 3 3 − b η 2 2 + c η 3 3 ] ]</p><p>= c o T + h c a η 2 2 T − d c T [ a ( T − η ) + b ( T − 2 η ) 2 2 + c ( T − 2 η ) 3 3 + b η 2 2 − c η 3 3 ]   + T − η T [ a ( 1 + θ ( T − η ) 2 6 ) + b ( − η + T − η 2 − η θ ( T − η ) 2 6 + θ ( T − η ) 3 8 )   + c ( η 2 − η ( T − η ) + ( 2 + θ η 2 6 ) ( T − η ) 2 − η θ ( T − η ) 3 4 + θ ( T − η ) 4 10 ) ]   ⋅ [ h c ( T + η 2 ) + d c ] (3.14)</p><p>by using the Equations (3.2) and (3.7).</p><p>In order to determine the optimum value of ( T C ( T ) ), the necessary condition is</p><p>d ( T C ( T ) ) d T = 0 , (3.15)</p><p>provided it satisfies the sufficient condition</p><p>d 2 ( T C ( T ) ) d T 2 = 0 . (3.16)</p><p>From the Equation (3.15), we have</p><p>d ( T C ( T ) ) d T = 1 T [ a ( 1 + θ ( T − η ) 2 6 ) + b ( − η + T − η 2 − η θ ( T − η ) 2 6 + θ ( T − η ) 3 8 )   + c ( η 2 − η ( T − η ) + ( 2 + θ η 2 6 ) ( T − η ) 2 − η θ ( T − η ) 3 4 + θ ( T − η ) 4 10 ) ]   ⋅ [ h c T + d c ] + T − η T [ a θ ( T − η ) 3 + b ( 1 2 − η θ ( T − η ) 3 + 3 θ ( T − η ) 2 2 )   + c ( − η + ( 2 + θ η 2 3 ) ( T − η ) − 3 η θ ( T − η ) 2 4 + 2 θ ( T − η ) 3 5 ) ]   ⋅ [ h c ( T + η 2 ) + d c ] − d c T [ a + b ( T − 2 η ) + c ( T − 2 η ) 2 ] − T C ( T ) T = 0 (3.17)</p><p>provided the sufficient condition d 2 ( T C ( T ) ) d T 2 &gt; 0 (see Appendix).</p><p>Special cases: 1) Putting c = 0 in the demand pattern D ( t ) = { a ,                                                                                                                 0 ≤ t ≤ η a + b ( t − η ) + c ( t − η ) 2 ,             η ≤ t ≤ T , the model reduces to that of Srivastava and Gupta [<xref ref-type="bibr" rid="scirp.130601-ref20">20</xref>] .</p><p>2) Putting t = 1 in the deterioration rate θ ( t ) = θ t , the model also reduces to that of Srivastava and Gupta [<xref ref-type="bibr" rid="scirp.130601-ref20">20</xref>] .</p><p>A step by step solution procedure for above problem is given below.</p></sec><sec id="s3_2"><title>3.2. Solution Procedure: Algorithms</title><p>To obtain the values of ( T C ( T ) ) and I s , the following steps are required.</p><p>Step I. Input the appropriate value of the parameters.</p><p>Step II. Obtain the value of T from the Equation (3.15) by Numerical method.</p><p>Step III. Compare T with η .</p><p>1) If T &gt; η , then T is a feasible solution, say T * . Go to Step IV.</p><p>2) If T &lt; η , then T is infeasible.</p><p>Step IV. Substitute T * in the Equations (3.14) and (3.10) to get ( T C ( T * ) ) and I s * , respectively.</p></sec></sec><sec id="s4"><title>4. Numerical Examples</title><p>To illustrate the results obtained from the inventory problem with two-phased demand and time-proportional deterioration, the following numerical examples are cited.</p><p>Example 1: Let us take the parametric values of the inventory model of deteriorating items in their units as follows: a = 20   units , b = 0.2 , c = 100 , θ = 0.02 , η = 0.4   days , c o = $ 80 , h c = $ 0.5 / unit / day and d c = $ 18 / unit .</p><p>Solving the Equation (3.15), the optimal cycle time is T * = 1.75651 days which satisfies the sufficient condition, i.e., d 2 ( T C ( T ) ) d T 2 = 157.701 &gt; 0 . Substituting the value of T * = 1.75651 in the Equations (3.14) and (3.10), the optimal value of the average total cost and the optimal order quantity are T C ( T * ) = 113.074 and I s * = 67.0517 units, respectively.</p><p>Example 2: Let us take the parametric values of the inventory model of deteriorating items in their units as follows: a = 20   units , b = 0.2 , c = 160 , θ = 0.02 , η = 0.4   days , c o = $ 80 , h c = $ 0.5 / unit / day and d c = $ 18 / unit .</p><p>Solving the Equation (3.15), the optimal cycle time is T * = 1.71125 days which satisfies the sufficient condition, i.e., d 2 ( T C ( T ) ) d T 2 = 229.733 &gt; 0 . Substituting the value of T * = 1.71125 in the equations (3.14) and (3.10), the optimal value of the average total cost and the optimal order quantity are T C ( T * ) = 174.205 and I s * = 78.6997 units, respectively.</p></sec><sec id="s5"><title>5. Sensitivity Analysis</title><p>The effect of changes in the values of various parameters a, b, c, θ , η , c o , h c and d c for the optimum cost and optimum order quantity is studied with the help of sensitivity analysis. It works by changing the each of the parameters by +50%, +20%, +10%, −10%, −20% and −50% at a time and keeping remaining parameters unchanged. The analysis is developed on the basis of Example-2 and the results are displayed in <xref ref-type="table" rid="table1">Table 1</xref>. The following points are noted.</p><p>1) T * decreases while T C ( T * ) and I s * increase with the increase in the value of the parameter a. Here T * , T C ( T * ) and I s * are insensitive to changes in a.</p><p>2) T * , T C ( T * ) and I s * decrease with the increase in the value of the parameter b. Here T * , T C ( T * ) and I s * are insensitive to changes in b.</p><p>3) T * decreases while T C ( T * ) and I s * increase with the increase in the value of the parameter c. Here T * , T C ( T * ) and I s * are moderately sensitive to changes in c.</p><p>4) T * and I s * decrease while T C ( T * ) increases with the increase in the value of the parameter θ and h c . Here T * , T C ( T * ) and I s * are moderately sensitive to changes in θ and h c .</p><p>5) T * , T C ( T * ) and I s * increase with the increase in the value of the parameter η . Here T * , T C ( T * ) and I s * are highly sensitive to changes in η .</p><p>6) T * , T C ( T * ) and I s * increase with the increase in the value of the parameter c o and d c . Here T * , T C ( T * ) and I s * are moderately sensitive to changes in c o and d c .</p><table-wrap id="table1" ><label><xref ref-type="table" rid="table1">Table 1</xref></label><caption><title> Sensitivity analysis</title></caption><table><tbody><thead><tr><th align="center" valign="middle" >Parameter</th><th align="center" valign="middle" >% change in parameter</th><th align="center" valign="middle" >T *</th><th align="center" valign="middle" >% change in T *</th><th align="center" valign="middle" >T C ( T * )</th><th align="center" valign="middle" >% change in T C ( T * )</th><th align="center" valign="middle" >I s *</th><th align="center" valign="middle" >% change in I s *</th></tr></thead><tr><td align="center" valign="middle" >a</td><td align="center" valign="middle" >+50 +20 +10 −10 −20 −50</td><td align="center" valign="middle" >1.69458 1.70457 1.70791 1.71459 1.71794 1.72799</td><td align="center" valign="middle" >−0.97414 −0.39035 −0.19517 +0.19517 +0.39094 +0.97823</td><td align="center" valign="middle" >152.264 149.236 148.222 146.185 145.163 142.080</td><td align="center" valign="middle" >+3.43670 +1.37971 +0.69087 −0.69291 −1.38718 −2.48154</td><td align="center" valign="middle" >93.1643 84.5144 81.6121 75.7770 72.8456 63.9901</td><td align="center" valign="middle" >+18.3795 +7.38847 +3.70065 −3.71374 −7.43853 −18.6908</td></tr><tr><td align="center" valign="middle" >b</td><td align="center" valign="middle" >+50 +20 +10 −10 −20 −50</td><td align="center" valign="middle" >1.71065 1.71101 1.71113 1.71137 1.71149 1.71184</td><td align="center" valign="middle" >−0.03506 −0.01402 −0.00701 +0.00701 +0.01402 +0.03447</td><td align="center" valign="middle" >147.052 147.144 147.174 147.236 147.266 147.358</td><td align="center" valign="middle" >−0.10393 −0.04143 −0.02105 +0.02105 +0.04143 +0.10393</td><td align="center" valign="middle" >78.6402 78.6759 78.6878 78.7116 78.7235 78.7576</td><td align="center" valign="middle" >−0.07560 −0.03024 −0.01512 +0.01512 +0.03024 +0.07357</td></tr><tr><td align="center" valign="middle" >c</td><td align="center" valign="middle" >+50 +20 +10 −10 −20 −50</td><td align="center" valign="middle" >1.68215 1.69711 1.70363 1.72025 1.73108 1.78280</td><td align="center" valign="middle" >−1.70051 −0.82629 −0.44528 +0.52593 +1.15880 +4.18115</td><td align="center" valign="middle" >192.354 165.293 156.255 138.138 129.051 101.571</td><td align="center" valign="middle" >+30.6708 +12.2876 +6.14789 −6.15944 −12.3325 −31.0003</td><td align="center" valign="middle" >94.5202 85.0034 81.8457 75.5645 72.4471 63.2716</td><td align="center" valign="middle" >+20.1024 +8.00981 +3.99747 −3.98375 −7.94488 −19.6038</td></tr><tr><td align="center" valign="middle" >θ</td><td align="center" valign="middle" >+50 +20 +10 −10 −20 −50</td><td align="center" valign="middle" >1.66492 1.69131 1.70101 1.72208 1.73357 1.77295</td><td align="center" valign="middle" >−2.70738 −1.16523 −0.59839 +0.63287 +1.30431 +3.60555</td><td align="center" valign="middle" >150.376 148.538 147.883 146.501 145.768 143.372</td><td align="center" valign="middle" >+2.15414 +0.90554 +0.45990 −0.47824 −0.97619 −2.60385</td><td align="center" valign="middle" >72.0672 75.7724 77.1824 80.3366 82.1101 88.4816</td><td align="center" valign="middle" >−8.42751 −3.71958 −1.92796 +2.07993 +4.33343 +12.4294</td></tr><tr><td align="center" valign="middle" >η</td><td align="center" valign="middle" >+50 +20 +10 −10 −20 −50</td><td align="center" valign="middle" >2.24873 1.92160 1.81516 1.61093 1.51549 1.27237</td><td align="center" valign="middle" >+31.4086 +12.7012 +6.07217 −5.86238 −11.4396 −25.6467</td><td align="center" valign="middle" >266.410 186.730 165.599 131.567 118.703 96.6536</td><td align="center" valign="middle" >+80.9789 +26.8503 +12.4357 −10.6233 −19.3621 −34.5446</td><td align="center" valign="middle" >119.598 92.7249 85.2893 73.0312 68.3794 61.7054</td><td align="center" valign="middle" >+51.9675 +17.8212 +8.37309 −7.20270 −13.1135 −21.5939</td></tr><tr><td align="center" valign="middle" >c o</td><td align="center" valign="middle" >+50 +20 +10 −10 −20 −50</td><td align="center" valign="middle" >1.76569 1.73397 1.72278 1.69935 1.68705 1.64746</td><td align="center" valign="middle" >+3.18130 +1.32768 +0.67377 −0.69539 −1.41417 −3.74522</td><td align="center" valign="middle" >170.207 156.493 151.864 142.514 137.789 123.396</td><td align="center" valign="middle" >+15.6258 +6.30957 +3.16497 −3.18671 −6.39651 −16.1740</td><td align="center" valign="middle" >87.6296 82.3149 80.5147 76.8684 75.0197 69.3665</td><td align="center" valign="middle" >+11.3468 +4.59366 +2.30623 −2.32695 −4.67600 −11.8593</td></tr><tr><td align="center" valign="middle" >h c</td><td align="center" valign="middle" >+50 +20 +10 −10 −20 −50</td><td align="center" valign="middle" >1.62771 1.67479 1.69244 1.73135 1.75290 1.82823</td><td align="center" valign="middle" >−4.88181 −2.13061 −1.09920 +1.17458 +2.43389 +6.83594</td><td align="center" valign="middle" >157.400 151.495 149.390 144.932 142.561 134.731</td><td align="center" valign="middle" >+6.92572 +2.91430 +1.48432 −1.54411 −3.15478 −8.47390</td><td align="center" valign="middle" >66.7111 73.2210 75.8243 81.8900 85.4486 99.0608</td><td align="center" valign="middle" >−15.2333 −6.96153 −3.65364 +4.05376 +8.57551 +25.8719</td></tr><tr><td align="center" valign="middle" >d c</td><td align="center" valign="middle" >+50 +20 +10 −10 −20 −50</td><td align="center" valign="middle" >1.74198 1.72525 1.71859 1.70311 1.69405 1.65948</td><td align="center" valign="middle" >+1.79576 +0.81811 +0.42892 −0.47563 −1.00511 −3.02527</td><td align="center" valign="middle" >186.157 162.816 155.016 139.379 131.538 107.882</td><td align="center" valign="middle" >+26.4611 +10.6049 +5.30621 −5.31640 −10.6430 −26.7131</td><td align="center" valign="middle" >83.6274 80.9088 79.9073 77.4424 76.0663 71.0356</td><td align="center" valign="middle" >+6.26140 +2.80700 +1.53444 −1.59759 −3.34614 −9.73841</td></tr></tbody></table></table-wrap><table-wrap id="table2" ><label><xref ref-type="table" rid="table2">Table 2</xref></label><caption><title> Effect of η on the optimal solution</title></caption><table><tbody><thead><tr><th align="center" valign="middle" >η</th><th align="center" valign="middle" >Change (%) in η</th><th align="center" valign="middle" >T *</th><th align="center" valign="middle" >Comparison between η and T *</th><th align="center" valign="middle" >T C ( T * )</th><th align="center" valign="middle" >I s *</th></tr></thead><tr><td align="center" valign="middle" >0.500</td><td align="center" valign="middle" >+25.0000</td><td align="center" valign="middle" >1.97551 (+1544.25)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >198.317 (+34.7216)</td><td align="center" valign="middle" >96.7430 (+22.9268)</td></tr><tr><td align="center" valign="middle" >1.000</td><td align="center" valign="middle" >+150.000</td><td align="center" valign="middle" >3.33619 (+94.9563)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >708.653 (+381.406)</td><td align="center" valign="middle" >253.465 (+222.066)</td></tr><tr><td align="center" valign="middle" >2.000</td><td align="center" valign="middle" >+400.000</td><td align="center" valign="middle" >5.86408 (+242.678)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >3075.06 (+1988.96)</td><td align="center" valign="middle" >935.278 (+1088.41)</td></tr><tr><td align="center" valign="middle" >5.000</td><td align="center" valign="middle" >+1150.00</td><td align="center" valign="middle" >12.6870 (+641.388)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >22916.5 (+15467.7)</td><td align="center" valign="middle" >22916.5 (+15467.7)</td></tr><tr><td align="center" valign="middle" >6.000</td><td align="center" valign="middle" >+1400.00</td><td align="center" valign="middle" >14.8515 (+767.874)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >34479.0 (+23322.4)</td><td align="center" valign="middle" >14334.9 (+18114.7)</td></tr><tr><td align="center" valign="middle" >6.100</td><td align="center" valign="middle" >+1425.00</td><td align="center" valign="middle" >15.0663 (+780.427)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >35787.8 (+24211.5)</td><td align="center" valign="middle" >15017.4 (+18981.9)</td></tr><tr><td align="center" valign="middle" >6.200</td><td align="center" valign="middle" >+1450.00</td><td align="center" valign="middle" >15.2808 (+792.961)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >37125.3 (+25120.1)</td><td align="center" valign="middle" >15722.6 (+19878.0)</td></tr><tr><td align="center" valign="middle" >6.300</td><td align="center" valign="middle" >+1475.00</td><td align="center" valign="middle" >15.4950 (+805.478)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >38491.7 (+26048.4)</td><td align="center" valign="middle" >16450.8 (+20803.3)</td></tr><tr><td align="center" valign="middle" >6.400</td><td align="center" valign="middle" >+1500.00</td><td align="center" valign="middle" >15.7089 (+817.978)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >39887.4 (+26996.5)</td><td align="center" valign="middle" >17202.4 (+21758.3)</td></tr><tr><td align="center" valign="middle" >6.500</td><td align="center" valign="middle" >+1525.00</td><td align="center" valign="middle" >15.9226 (+830.466)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >41312.4 (+27964.5)</td><td align="center" valign="middle" >17978.2 (+22744.1)</td></tr><tr><td align="center" valign="middle" >6.510</td><td align="center" valign="middle" >+1527.50</td><td align="center" valign="middle" >15.9439 (+831.711)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >41456.5 (+28062.4)</td><td align="center" valign="middle" >41456.5 (+28062.4)</td></tr><tr><td align="center" valign="middle" >6.550</td><td align="center" valign="middle" >+1537.50</td><td align="center" valign="middle" >16.0293 (+836.701)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >42036.0 (+28456.1)</td><td align="center" valign="middle" >16596.0 (+20987.8)</td></tr><tr><td align="center" valign="middle" >6.560</td><td align="center" valign="middle" >+1540.00</td><td align="center" valign="middle" >16.0507 (+837.952)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >42181.6 (+28555.0)</td><td align="center" valign="middle" >18455.4 (+23350.4)</td></tr><tr><td align="center" valign="middle" >6.570</td><td align="center" valign="middle" >+1542.50</td><td align="center" valign="middle" >16.0720 (+839.1960)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >42327.5 (+28654.1)</td><td align="center" valign="middle" >18535.7 (+23452.4)</td></tr><tr><td align="center" valign="middle" >6.571</td><td align="center" valign="middle" >+1542.75</td><td align="center" valign="middle" >16.0740 (839.31300)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >42342.2 (+28664.1)</td><td align="center" valign="middle" >18543.3 (+23462.1)</td></tr><tr><td align="center" valign="middle" >6.572</td><td align="center" valign="middle" >+1543.00</td><td align="center" valign="middle" >16.0763 (+839.4480)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >42356.8 (+28674.0)</td><td align="center" valign="middle" >18551.8 (+23472.9)</td></tr><tr><td align="center" valign="middle" >6.573</td><td align="center" valign="middle" >+1543.25</td><td align="center" valign="middle" >16.0784 (+839.5700)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >42371.4 (+28683.9)</td><td align="center" valign="middle" >18559.8 (+23483.1)</td></tr><tr><td align="center" valign="middle" >6.574</td><td align="center" valign="middle" >+1543.50</td><td align="center" valign="middle" >16.0806 (+839.6990)</td><td align="center" valign="middle" >η &lt; T *</td><td align="center" valign="middle" >42386.0 (+28693.9)</td><td align="center" valign="middle" >18568.0 (+23493.5)</td></tr><tr><td align="center" valign="middle" >6.575</td><td align="center" valign="middle" >+1543.75</td><td align="center" valign="middle" >0.843227 (−50.7245)</td><td align="center" valign="middle" >η &gt; T *</td><td align="center" valign="middle" >…</td><td align="center" valign="middle" >…</td></tr><tr><td align="center" valign="middle" >6.576</td><td align="center" valign="middle" >+1544.00</td><td align="center" valign="middle" >0.845722 (−50.5758)</td><td align="center" valign="middle" >η &gt; T *</td><td align="center" valign="middle" >…</td><td align="center" valign="middle" >…</td></tr><tr><td align="center" valign="middle" >7.000</td><td align="center" valign="middle" >+1650.00</td><td align="center" valign="middle" >1.67175 (−2.308250)</td><td align="center" valign="middle" >η &gt; T *</td><td align="center" valign="middle" >…</td><td align="center" valign="middle" >…</td></tr></tbody></table></table-wrap><p>The effects of η on the basis of Example-2 are also discussed in <xref ref-type="table" rid="table2">Table 2</xref>.</p><p>Here “...” denotes the infeasible solution.</p><p>It reveals that if the parameter η is increased by 1543.5%, then the value of the optimal cycle time is increased by 839.699%, the optimal average total cost is increased by 28693.9% and the optimal order quantity is increased by 23493.5%. Further, if the parameter η is increased by 1543.75%, then the value of the optimal cycle time is decreased by −50.7245%.</p><p>The notable point is that the increase in the value of the parameter η after 6.574 gives an infeasible solution as η &gt; T * .</p></sec><sec id="s6"><title>6. Conclusions</title><p>This study develops an EOQ inventory model for deteriorating items with a variable deterioration rate and a two-phased demand rate. The two-phased demand rate experiences constant and quadratic demand functions in its first and second phases, respectively. The deterioration rate is a linear function of time. The reason for assuming two-phased demand is due to the newly launched items like mobiles, automobiles, cosmetics, fashion apparels, etc. The demand for such items remains constant for some period of time and then varies with the quadratic function of time. Any types of shortages like partially backlogged and complete backlogged are not allowed to occur. The article concludes with a couple of numerical examples and a sensitivity analysis of various parameters to support the theoretical results. The objective of the proposed model is to generalize the demand rate involved in the model of Srivastava and Gupta (2007). The general form of the quadratic demand is considered as D ( t ) = a + b t + c t 2 where a &gt; 0 , b ≠ 0 and c ≠ 0 . Here c = 0 and b = c = 0 refer the time-dependent linear demand pattern and constant demand, respectively. The variable deterioration of the system is of the form θ ( t ) = θ t , ( 0 &lt; θ ≪ 1 ) . If t = 1 , then the variable deterioration rate becomes a constant deterioration rate. To be more precise, the proposed model has been studied for the computation of the cycle time, order quantity and total average cost under the factors of time-dependent two-phased demand and variable deterioration.</p><p>A future study will further include the proposed model into several realistic approaches like stochastic demand, generalized demand pattern, stock and price dependent demand. We could extend the work to several variable deteriorations like the two-parameter Weibull distribution deterioration and Gamma distribution deterioration. Finally, this work can be extended by incorporating the concept of shortages or partial backlogging.</p></sec><sec id="s7"><title>Conflicts of Interest</title><p>The authors declare no conflicts of interest regarding the publication of this paper.</p></sec><sec id="s8"><title>Cite this paper</title><p>Mohanty, S., Singh, T., Routary, S.S. and Naik, C. (2024) A Note on an Order Level Inventory Model with Varying Two-Phased Demand and Time-Proportional Deterioration. American Journal of Operations Research, 14, 59-73. https://doi.org/10.4236/ajor.2024.141003</p></sec><sec id="s9"><title>Appendix</title><p>d 2 ( T C ( T ) ) d T 2 = h c T [ a ( 1 + θ ( T − η ) 2 6 ) + b ( − η + T − η 2 − η θ ( T − η ) 2 6 + θ ( T − η ) 3 8 )       + c ( η 2 − η ( T − η ) + ( 2 + θ η 2 6 ) ( T − η ) 2 − η θ ( T − η ) 3 4 + θ ( T − η ) 4 10 ) ]       + 1 T [ a θ ( T − η ) 3 + b ( 1 2 − η θ ( T − η ) 3 + 3 θ ( T − η ) 2 8 )       + c ( − η + ( 2 + θ η 2 3 ) ( T − η ) − 3 η θ ( T − η ) 2 4 + 2 θ ( T − η ) 3 5 ) ]</p><p>⋅ [ h c ( 3 T + η + 1 2 ) + 2 d c ] + T − η T [ a θ 3 + b ( − η θ 3 + 3 θ ( T − η ) 4 ) + c ( 2 + θ η 2 3 − 3 η θ 2 ( T − η ) + 6 θ ( T − η ) 2 5 ) ] ⋅ [ h c ( T + η 2 ) + d c ] − d c T [ a + 2 b ( T − 2 η ) ] − 2 T 2 [ a ( 1 + θ ( T − η ) 2 6 ) + b ( − η + T − η 2 − η θ ( T − η ) 2 6 + θ ( T − η ) 3 8 ) + c ( η 2 − η ( T − η ) + ( 2 + θ η 2 6 ) ( T − η ) 2 − η θ ( T − η ) 3 4 + θ ( T − η ) 4 10 ) ] ⋅ [ h c T + d c ]</p><p>− 2 ( T − η ) T 2 [ a θ ( T − η ) 3 + b ( 1 2 − η θ ( T − η ) 3 + 3 θ ( T − η ) 2 2 ) + c ( − η + ( 2 + θ η 2 6 ) ( T − η ) − 3 η θ ( T − η ) 2 4 + 2 θ ( T − η ) 3 5 ) ] ⋅ [ h c ( T + η 2 ) + d c ] + 2 d c T 2 [ a + b ( T − 2 η ) + c ( T − 2 η ) 2 ] + 2 T 2 ( T C ( T ) )</p></sec></body><back><ref-list><title>References</title><ref id="scirp.130601-ref1"><label>1</label><mixed-citation publication-type="journal" xlink:type="simple"><name name-style="western"><surname>Harris</surname><given-names> F.W. </given-names></name>,<etal>et al</etal>. 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