<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">JAMP</journal-id><journal-title-group><journal-title>Journal of Applied Mathematics and Physics</journal-title></journal-title-group><issn pub-type="epub">2327-4352</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/jamp.2023.1112243</article-id><article-id pub-id-type="publisher-id">JAMP-129873</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  Singularity of Two Kinds of Quadcyclic Peacock Graphs
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Xiaojie</surname><given-names>You</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Haicheng</surname><given-names>Ma</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib></contrib-group><aff id="aff1"><addr-line>School of Mathematics and Statistics, Qinghai Minzu University, Xining, China</addr-line></aff><pub-date pub-type="epub"><day>19</day><month>12</month><year>2023</year></pub-date><volume>11</volume><issue>12</issue><fpage>3840</fpage><lpage>3853</lpage><history><date date-type="received"><day>5,</day>	<month>November</month>	<year>2023</year></date><date date-type="rev-recd"><day>17,</day>	<month>December</month>	<year>2023</year>	</date><date date-type="accepted"><day>20,</day>	<month>December</month>	<year>2023</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
  Let 
  G be a graph. 
  G is singular if and only if the adjacency matrix of graph 
  G is singular. The adjacency matrix of graph 
  G is singular if and only if there is at least one zero eigenvalue. The study of the singularity of graphs is of great significance for better characterizing the properties of graphs. The following definitions are given. There are 4 paths, the starting points of the four paths are bonded into one point, and the ending point of each path is bonded to a cycle respectively, so this graph is called a kind of quadcyclic peacock graph. And in this kind of quadcyclic peacock graph assuming the number of points on the four cycles is 
  a
  <sub>1</sub>, 
  a
  <sub>2</sub>, 
  a
  <sub>3</sub>, 
  a
  <sub>4</sub>, and the number of points on the four paths is 
  s
  <sub>1</sub>, 
  s
  <sub>2</sub>, 
  s
  <sub>3</sub>, 
  s
  <sub>4</sub>, respectively. This type of graph is denoted by 
  γ (
  a
  <sub>1</sub>, 
  a
  <sub>2</sub>, 
  a
  <sub>3</sub>, 
  a
  <sub>4</sub>, 
  s
  <sub>1</sub>, 
  s
  <sub>2</sub>, 
  s
  <sub>3</sub>, 
  s
  <sub>4</sub>), called 
  γ graph. And let 
  γ (
  a
  <sub>1</sub>, 
  a
  <sub>2</sub>, 
  a
  <sub>3</sub>, 
  a
  <sub>4</sub>, 1, 1, 1, 1) = 
  δ (
  a
  <sub>1</sub>, 
  a
  <sub>2</sub>, 
  a
  <sub>3</sub>, 
  a
  <sub>4</sub>), this type four cycles peacock graph called 
  δ graph. In this paper, we give the necessary and sufficient conditions for the singularity of 
  γ graph and 
  δ graph.
 
</p></abstract><kwd-group><kwd>Quadcyclic Graphs</kwd><kwd> Singularity</kwd><kwd> Nullity</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>This paper only considers finite and undirected simple graphs. Let G is a graph with n points, its adjacency matrix can be represented by the following matrix: A ( G ) = ( a i j ) n &#215; n</p><p>a i j = ( 1 if   i ~ j , 0 otherwise .</p><p>where i ~ j represents the point i and point j are adjacent. The eigenvalues of any graph G are the eigenvalues of its adjacency matrix A ( G ) , and these n eigenvalues is called the spectrum of graph G. The number of non-zero eigenvalues in the spectrum of G are called the rank of G, denoted by r ( G ) . The number of zero eigenvalues in the spectrum of G are called the the nullity of G, denoted by η ( G ) . Obviously, r ( G ) + η ( G ) = n . G is singular if and only if the adjacency matrix of graph G is singular. And A ( G ) is singular if and only if there is at least one zero eigenvalue.</p><p>In chemistry, we can use graphs to represent molecular diagrams of molecules, and the application of the nullity (or rank) of graphs is very extensive (see [<xref ref-type="bibr" rid="scirp.129873-ref1">1</xref>] - [<xref ref-type="bibr" rid="scirp.129873-ref6">6</xref>] ). In [<xref ref-type="bibr" rid="scirp.129873-ref6">6</xref>] , it proposes that the nullity of a molecular graphs is a necessary condition for the stability of the molecular chemical properties. In addition, how to characterize all graphs with nullity greater than zero is also a problem that we have been exploring, it was proposed in 1957 (see [<xref ref-type="bibr" rid="scirp.129873-ref2">2</xref>] ). Many scholars have attempted to characterize this type of graph which also known as singular graphs, but this problem is very difficult and still unresolved. So far, there are only some results for special graphs (see [<xref ref-type="bibr" rid="scirp.129873-ref7">7</xref>] - [<xref ref-type="bibr" rid="scirp.129873-ref16">16</xref>] ). In order to better characterize this type of graph, some mathematical scholars attempt to explore the mutual influence between the nullity of the graph and the structure of the graph by studying the structural characteristics of singular graphs (see [<xref ref-type="bibr" rid="scirp.129873-ref17">17</xref>] [<xref ref-type="bibr" rid="scirp.129873-ref18">18</xref>] [<xref ref-type="bibr" rid="scirp.129873-ref19">19</xref>] [<xref ref-type="bibr" rid="scirp.129873-ref20">20</xref>] [<xref ref-type="bibr" rid="scirp.129873-ref21">21</xref>] ). Some works by researchers have shown significant connections between singular graphs and other fields of mathematics (see [<xref ref-type="bibr" rid="scirp.129873-ref22">22</xref>] [<xref ref-type="bibr" rid="scirp.129873-ref23">23</xref>] [<xref ref-type="bibr" rid="scirp.129873-ref24">24</xref>] [<xref ref-type="bibr" rid="scirp.129873-ref25">25</xref>] ). Recently, we give the necessity and sufficiency of the singular of some classes tricycle graphs and probability of the occurence of these singular graphs [<xref ref-type="bibr" rid="scirp.129873-ref26">26</xref>] [<xref ref-type="bibr" rid="scirp.129873-ref27">27</xref>] .</p><p>The subgraph of graph G where each branch is an isolated edge or cycle is called the basic Sachs subgraph of graph G. The basic subgraph containing all points of G is called a basic spanning subgraph or a spanning Sachs subgraph. A basic spanning subgraph only composed of isolated edges is called a perfect matching of graph G. Of course, if a graph has a perfect matching, the number of points on the graph must be even. Let P<sub>n</sub>, C<sub>n</sub> and K<sub>n</sub> denote the path, cycle and complete graph with n vertices, respectively. Let G ∪ H be the union of two graphs G and H. For the notations and terms which are not defined above, please refer to [<xref ref-type="bibr" rid="scirp.129873-ref1">1</xref>] .</p><p>There are 4 paths, the starting points of the four paths are bonded into one point, and the ending point of each path is bonded to a cycle respectively, so this graph is called a kind of quadcyclic peacock graph. And in this kind of quadcyclic peacock graph assuming the number of points on the four cycles is a 1 , a 2 , a 3 , a 4 , and the number of points on the four paths is s 1 , s 2 , s 3 , s 4 . This type of graph is denoted by γ ( a 1 , a 2 , a 3 , a 4 , s 1 , s 2 , s 3 , s 4 ) , called γ graph (see <xref ref-type="fig" rid="fig1">Figure 1</xref>). And let γ ( a 1 , a 2 , a 3 , a 4 ,1,1,1,1 ) = δ ( a 1 , a 2 , a 3 , a 4 ) , this type four cycles peacock graph called δ graph (see <xref ref-type="fig" rid="fig2">Figure 2</xref>). In this paper, we give the necessary and sufficient conditions for the singularity of γ graph and δ graph. This paper is a generalization of [<xref ref-type="bibr" rid="scirp.129873-ref26">26</xref>] [<xref ref-type="bibr" rid="scirp.129873-ref27">27</xref>] , and has a certain promotion effect on the better characterization of singular graphs, and is also an application of nullity in graph theory.</p><p>In this paper, a 1 , a 2 , a 3 , a 4 collectively referred to as four a. s 1 , s 2 , s 3 , s 4 collectively referred to as four s. A path with the odd number of points is called a odd path, and a path with the even same as above is called even path.</p><p>The main conclusions are the following theorem and corollary.</p><p>Theorem 1. G = γ ( a 1 , a 2 , a 3 , a 4 , s 1 , s 2 , s 3 , s 4 ) is singular if and only if one of the following holds:</p><p>(i) At least the length of one cycle is a multiple of 4.</p><p>(ii) If there are four even cycles, at most two s are even or four s are even.</p><p>(iii) If there are three even cycles, at least two s which connected to even cycles are odd.</p><p>(iv) If there are two even cycles, (1) s which connected to even cycles are odd, (2) s which connected to even cycles are even and the s which connected to odd cycles have same parity and the length of the two odd cycles is different with respect module 4.</p><p>(v) If there is no even cycle, (1) the parity of the four s is same and four a is exactly two module 4 remainder 1 and two module 4 remainder 3, (2) exactly two s are odd and two s are even and the a which connected to the s with the same parity is different with respect module 4.</p><p>By theorem 1, the following corollary 1 is obvious.</p><p>Corollary 1. G = δ ( a 1 , a 2 , a 3 , a 4 ) is singular if and only if one of the following holds:</p><p>(i) At least the length of one cycle is a multiple of 4.</p><p>(ii) There are four even cycles or three even cycles or two even cycles.</p></sec><sec id="s2"><title>2. Some Lemmas</title><p>Lemma 2. [<xref ref-type="bibr" rid="scirp.129873-ref1">1</xref>] Suppose G = G 1 ∪ G 2 ∪ ⋯ ∪ G t , where G i ( i = 1,2, ⋯ , t ) are connected components of G. Then η ( G ) = ∑ i = 1 t     η ( G i ) . Equivalently, G is non-singular if and only if each G i ( i = 1,2, ⋯ , t ) is non-singular.</p><p>Lemma 3. [<xref ref-type="bibr" rid="scirp.129873-ref1">1</xref>] If G is a graph with n vertices and adjacency matrix is A ( G ) , then</p><p>d e t ( A ( G ) ) = ( − 1 ) n ∑ H ∈ H ( − 1 ) p ( H ) 2 c ( H ) ,</p><p>H is the set of spanning Sachs subgraph of G, p ( H ) is the number of the components in H, c ( H ) is the number of cycles in H.</p></sec><sec id="s3"><title>3. Proof of the Theorem</title><p>Proof. | V ( G ) | = a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 . Combine the parity of the a<sub>1</sub>, a<sub>2</sub>, a<sub>3</sub>, a<sub>4</sub>, s<sub>1</sub>, s<sub>2</sub>, s<sub>3</sub>, s<sub>4</sub> and the symmetry of graph γ, we will discuss as follows.</p><p>1 Four a are even.</p><p>1.1 Four s are even. G has no spanning Sachs subgraph, G is singular.</p><p>1.2 Three s are even. We can assume that s<sub>1</sub>, s<sub>2</sub>, s<sub>3</sub> are even, s<sub>4</sub> is odd.</p><p>The spanning Sachs subgraphs of graph G with four cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ C a 4 ∪ s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>The spanning Sachs subgraphs of graph G with three cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 1 ∪ C a 2 ∪ C a 4 ∪ a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 1 ∪ C a 3 ∪ C a 4 ∪ a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 2 ∪ C a 3 ∪ C a 4 ∪ a 1 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two).</p><p>The spanning Sachs subgraphs of graph G with two cycles have:</p><p>C a 1 ∪ C a 2 ∪ a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (four),</p><p>C a 1 ∪ C a 3 ∪ a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (four),</p><p>C a 1 ∪ C a 4 ∪ a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (four),</p><p>C a 2 ∪ C a 3 ∪ a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (four),</p><p>C a 2 ∪ C a 4 ∪ a 1 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (four),</p><p>C a 3 ∪ C a 4 ∪ a 1 + a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (four).</p><p>The spanning Sachs subgraphs of graph G with one cycle have:</p><p>C a 1 ∪ a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (eight),</p><p>C a 2 ∪ a 1 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (eight),</p><p>C a 3 ∪ a 1 + a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (eight),</p><p>C a 4 ∪ a 1 + a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (eight).</p><p>It contains 16 perfect matchings.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) s 1 + s 2 + s 3 + s 4 − 7 2 + 4 &#215; 2 4 + ( − 1 ) a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 2 + ( − 1 ) a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 2 + ( − 1 ) a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 2 + ( − 1 ) a 1 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 2 + ( − 1 ) a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 4 + ( − 1 ) a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 4 + ( − 1 ) a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 4</p><p>+ ( − 1 ) a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 4 + ( − 1 ) a 1 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 4 + ( − 1 ) a 1 + a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 4 + ( − 1 ) a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 8 + ( − 1 ) a 1 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 8 + ( − 1 ) a 1 + a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 8 + ( − 1 ) a 1 + a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 8 + ( − 1 ) a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 &#215; 16 = 0 ,</p><p>multiply both sides by ( − 1 ) a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 , if and only if</p><p>( − 1 ) a 1 + a 2 + a 3 + a 4 2 − ( − 1 ) a 1 + a 2 + a 3 2 − ( − 1 ) a 1 + a 2 + a 4 2 − ( − 1 ) a 1 + a 3 + a 4 2 − ( − 1 ) a 2 + a 3 + a 4 2 + ( − 1 ) a 1 + a 2 2 + ( − 1 ) a 1 + a 3 2 + ( − 1 ) a 1 + a 4 2 + ( − 1 ) a 2 + a 3 2 + ( − 1 ) a 2 + a 4 2 + ( − 1 ) a 3 + a 4 2 − ( − 1 ) a 1 2 − ( − 1 ) a 2 2 − ( − 1 ) a 3 2 − ( − 1 ) a 4 2 + 1 = 0 ,</p><p>if and only if</p><p>( ( − 1 ) a 1 2 − 1 ) ( ( − 1 ) a 2 2 − 1 ) ( ( − 1 ) a 3 2 − 1 ) ( ( − 1 ) a 4 2 − 1 ) = 0,</p><p>if and only if 4 | a 1 , 4 | a 2 , 4 | a 3 or 4 | a 4 , if and only if the length of any cycle is a multiple of 4.</p><p>1.3 Two s or one s or no s is even. In these cases, G has no spanning Sachs subgraph, G is singular.</p><p>2 Three a are even. We can assume that a<sub>1</sub>, a<sub>2</sub>, a<sub>3</sub> are even, a<sub>4</sub> is odd.</p><p>2.1 Four s or three s are even. Similar to case 1.2, in these cases we can get that G is singular if and only if the length of any cycle is a multiple of 4.</p><p>2.2 Two s are even.</p><p>2.2.1 If s<sub>4</sub> is contained in two s. Let’s assume that s<sub>3</sub>, s<sub>4</sub> are even, s<sub>1</sub>, s<sub>2</sub> are odd. G has no spanning Sachs subgraph, G is singular.</p><p>2.2.2 If s<sub>4</sub> is not contained in two s. Let’s assume that s<sub>1</sub>, s<sub>2</sub> are even, s<sub>3</sub>, s<sub>4</sub> are odd. Similar to case 1.2, we can get that G is singular if and only if the length of any cycle is a multiple of 4.</p><p>2.3 One s or no s is even. In these cases, G has no spanning Sachs subgraph, G is singular.</p><p>3 Two a are even. We can assume that a<sub>1</sub>, a<sub>2</sub> are even, a<sub>3</sub>, a<sub>4</sub> are odd.</p><p>3.1 Four s are even. There is no the spanning Sachs subgraph with four cycles. The spanning Sachs subgraphs of graph G with three cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 2 ∪ C a 4 ∪ a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>The spanning Sachs subgraphs of graph G with two cycles have:</p><p>C a 1 ∪ C a 3 ∪ a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 1 ∪ C a 4 ∪ a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 2 ∪ C a 3 ∪ a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 2 ∪ C a 4 ∪ a 1 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two).</p><p>The spanning Sachs subgraphs of graph G with one cycle have:</p><p>C a 3 ∪ a 1 + a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (four),</p><p>C a 4 ∪ a 1 + a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (four).</p><p>There is no perfect matching.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 2 + ( − 1 ) a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 2 + ( − 1 ) a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 2 + ( − 1 ) a 1 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 2 + ( − 1 ) a 1 + a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 4 + ( − 1 ) a 1 + a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 4 = 0 ,</p><p>multiply both sides by ( − 1 ) s 1 + s 2 + s 3 + s 4 − 6 2 , if and only if</p><p>− ( − 1 ) a 4 − 1 2 − ( − 1 ) a 3 − 1 2 + ( − 1 ) a 2 + ( a 4 − 1 ) 2 + ( − 1 ) a 2 + ( a 3 − 1 ) 2 + ( − 1 ) a 1 + ( a 4 − 1 ) 2 + ( − 1 ) a 1 + ( a 3 − 1 ) 2 − ( − 1 ) a 1 + a 2 + ( a 4 − 1 ) 2 − ( − 1 ) a 1 + a 2 + ( a 3 − 1 ) 2 = 0,</p><p>if and only if</p><p>− ( ( − 1 ) a 4 − 1 2 + ( − 1 ) a 3 − 1 2 ) ( ( − 1 ) a 1 2 − 1 ) ( ( − 1 ) a 2 2 − 1 ) = 0,</p><p>if and only if 4 | a 1 , 4 | a 2 or ( − 1 ) a 4 − 1 2 + ( − 1 ) a 3 − 1 2 = 0 , if and only if the length of any cycle is a multiple of 4 or the length of the two odd cycles is module 4 with different remainder.</p><p>3.2 Three s are even.</p><p>3.2.1 If s<sub>1</sub> and s<sub>2</sub> are all contained in three s. Let’s assume that s<sub>1</sub>, s<sub>2</sub>, s<sub>3</sub> are even, s<sub>4</sub> is odd. The spanning Sachs subgraphs of graph G with four cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ C a 4 ∪ s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>The spanning Sachs subgraphs of graph G with three cycles have:</p><p>C a 1 ∪ C a 3 ∪ C a 4 ∪ a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 2 ∪ C a 3 ∪ C a 4 ∪ a 1 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two).</p><p>The spanning Sachs subgraphs of graph G with two cycles have:</p><p>C a 3 ∪ C a 4 ∪ a 1 + a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (four),</p><p>C a 1 ∪ C a 2 ∪ a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>The spanning Sachs subgraphs of graph G with one cycle have:</p><p>C a 1 ∪ a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 2 ∪ a 1 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two).</p><p>It contains 4 perfect matchings.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) s 1 + s 2 + s 3 + s 4 − 7 2 + 4 &#215; 2 4 + ( − 1 ) a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 2 + ( − 1 ) a 1 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 2 + ( − 1 ) a 1 + a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 4 + ( − 1 ) a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 1 + ( − 1 ) a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 2 + ( − 1 ) a 1 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 2 + ( − 1 ) a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 &#215; 4 = 0 ,</p><p>multiply both sides by ( − 1 ) a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 , if and only if</p><p>2 2 &#215; ( ( − 1 ) a 1 + a 2 + a 3 + a 4 2 − ( − 1 ) a 1 + a 3 + a 4 2 − ( − 1 ) a 2 + a 3 + a 4 2 + ( − 1 ) a 3 + a 4 2 ) + ( − 1 ) a 1 + a 2 2 − ( − 1 ) a 1 2 − ( − 1 ) a 2 2 + 1 = 0 ,</p><p>if and only if</p><p>( 4 ( − 1 ) a 3 + a 4 2 + 1 ) ( ( − 1 ) a 1 2 − 1 ) ( ( − 1 ) a 2 2 − 1 ) = 0,</p><p>obviously, the first equation is equal to 0 without a solution, if and only if 4 | a 1 or 4 | a 2 , if and only if the length of any cycle is a multiple of 4.</p><p>3.2.2 If s<sub>1</sub> and s<sub>2</sub> are not all contained in three s. Let’s assume that s<sub>1</sub>, s<sub>3</sub>, s<sub>4</sub> are even, s<sub>2</sub> is odd. Similar to case 1.2, we can get that G is singular if and only if the length of any cycle is a multiple of 4.</p><p>3.3 Two s are even.</p><p>3.3.1 If s<sub>1</sub>, s<sub>2</sub> are contained in two s exactly. Let’s assume that s<sub>1</sub>, s<sub>2</sub> are even, s<sub>3</sub>, s<sub>4</sub> are odd. Similar to subcase 3.1, it is obtained that G is singular if and only if the length of any cycle is a multiple of 4 or the length of the two odd cycles is module 4 with different remainder.</p><p>3.3.2 If one of s<sub>1</sub>, s<sub>2</sub> is contained in two s. Let’s assume that s<sub>1</sub>, s<sub>3</sub> are even, s<sub>2</sub>, s<sub>4</sub> are odd. Similar to case 1.2, we can get that G is singular if and only if the length of any cycle is a multiple of 4.</p><p>3.3.3 If s<sub>1</sub>, s<sub>2</sub> are not contained in two s exactly. Let’s assume that s<sub>3</sub>, s<sub>4</sub> are even, s<sub>1</sub>, s<sub>2</sub> are odd. G has no spanning Sachs subgraph, G is singular.</p><p>3.4 One s is even.</p><p>3.4.1 If s<sub>1</sub> or s<sub>2</sub> is contained in one s. Let’s assume that s<sub>1</sub> is even, s<sub>2</sub>, s<sub>3</sub>, s<sub>4</sub> are odd. Similar to case 1.2, we can get that G is singular if and only if the length of any cycle is a multiple of 4.</p><p>3.4.2 If s<sub>1</sub> or s<sub>2</sub> is not contained in one s. Let’s assume that s<sub>3</sub> is even, s<sub>1</sub>, s<sub>2</sub>, s<sub>4</sub> are odd. G has no spanning Sachs subgraph, G is singular.</p><p>3.5 Four s are odd. G has no spanning Sachs subgraph, G is singular.</p><p>4 One a is even. We can assume that a<sub>1</sub> is even, a<sub>2</sub>, a<sub>3</sub>, a<sub>4</sub> are odd.</p><p>4.1 Four s are even. There is no the spanning Sachs subgraph with four cycles. The spanning Sachs subgraphs of graph G with three cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 2 ∪ C a 4 ∪ a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 3 ∪ C a 4 ∪ a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>The spanning Sachs subgraphs of graph G with two cycles have:</p><p>C a 2 ∪ C a 3 ∪ a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 2 ∪ C a 4 ∪ a 1 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 3 ∪ C a 4 ∪ a 1 + a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two).</p><p>There is no the spanning Sachs subgraph with one cycle. There is no perfect matching.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 2 + ( − 1 ) a 1 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 2 + ( − 1 ) a 1 + a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 2 = 0 ,</p><p>multiply both sides by ( − 1 ) a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 , if and only if</p><p>− ( − 1 ) a 1 + a 2 + a 3 2 − ( − 1 ) a 1 + a 2 + a 4 2 − ( − 1 ) a 1 + a 3 + a 4 2 + ( − 1 ) a 2 + a 3 2 + ( − 1 ) a 2 + a 4 2 + ( − 1 ) a 3 + a 4 2 = 0 ,</p><p>if and only if</p><p>( − ( − 1 ) a 1 2 + 1 ) ( ( − 1 ) a 2 + a 3 2 + ( − 1 ) a 2 + a 4 2 + ( − 1 ) a 3 + a 4 2 ) = 0,</p><p>due to ( − 1 ) a 2 + a 3 2 + ( − 1 ) a 2 + a 4 2 + ( − 1 ) a 3 + a 4 2 ≠ 0 , the above equation holds if and only if 4 | a 1 , if and only if the length of any cycle is a multiple of 4.</p><p>4.2 Three s are even.</p><p>4.2.1 If s<sub>1</sub> is contained in three s. Let’s assume that s<sub>1</sub>, s<sub>2</sub>, s<sub>3</sub> are even, s<sub>4</sub> is odd. The spanning Sachs subgraphs of graph G with four cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ C a 4 ∪ s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>The spanning Sachs subgraphs of graph G with three cycles have:</p><p>C a 2 ∪ C a 3 ∪ C a 4 ∪ a 1 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two).</p><p>The spanning Sachs subgraphs of graph G with two cycles have:</p><p>C a 1 ∪ C a 2 ∪ a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 3 ∪ a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>The spanning Sachs subgraphs of graph G with one cycle have:</p><p>C a 2 ∪ a 1 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 3 ∪ a 1 + a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two).</p><p>There is no perfect matching.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) s 1 + s 2 + s 3 + s 4 − 7 2 + 4 &#215; 2 4 + ( − 1 ) a 1 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 2 + ( − 1 ) a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 1 + ( − 1 ) a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 1 + ( − 1 ) a 1 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 2 + ( − 1 ) a 1 + a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 &#215; 2 = 0 ,</p><p>multiply both sides by ( − 1 ) s 1 + s 2 + s 3 + s 4 − 7 2 , if and only if</p><p>4 − 4 ( − 1 ) a 1 2 + ( − 1 ) a 3 + a 4 2 + ( − 1 ) a 2 + a 4 2 − ( − 1 ) a 1 + a 3 + a 4 2 − ( − 1 ) a 1 + a 2 + a 4 2 = 0,</p><p>if and only if</p><p>( 1 − ( − 1 ) a 1 2 ) ( 4 + ( − 1 ) a 3 + a 4 2 + ( − 1 ) a 2 + a 4 2 ) = 0,</p><p>if and only if 4 | a 1 , if and only if the length of any cycle is a multiple of 4.</p><p>4.2.2 If s<sub>1</sub> is not contained in three s. Let’s assume that s<sub>2</sub>, s<sub>3</sub>, s<sub>4</sub> are even, s<sub>1</sub> is odd. Similar to case 1.2, we can get that G is singular if and only if the length of any cycle is a multiple of 4.</p><p>4.3 Two s are even.</p><p>4.3.1 If s<sub>1</sub> is contained in two s. Let’s assume that s<sub>1</sub>, s<sub>2</sub> are even, s<sub>3</sub>, s<sub>4</sub> are odd. There is no the spanning Sachs subgraph with four cycles. The spanning Sachs subgraphs of graph G with three cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 2 ∪ C a 4 ∪ a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>The spanning Sachs subgraphs of graph G with two cycles have:</p><p>C a 2 ∪ C a 3 ∪ a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two),</p><p>C a 2 ∪ C a 4 ∪ a 1 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (two).</p><p>The spanning Sachs subgraphs of graph G with one cycle have:</p><p>C a 1 ∪ a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>It contains 2 perfect matchings.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 2 + ( − 1 ) a 1 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 &#215; 2 + ( − 1 ) a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 + ( − 1 ) a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 &#215; 2 = 0 ,</p><p>multiply both sides by ( − 1 ) a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 , if and only if</p><p>4 ( − ( − 1 ) a 1 + a 2 + a 3 2 − ( − 1 ) a 1 + a 2 + a 4 2 + ( − 1 ) a 2 + a 3 2 + ( − 1 ) a 2 + a 4 2 ) − ( − 1 ) a 1 2 + 1 = 0,</p><p>if and only if</p><p>( − ( − 1 ) a 1 2 + 1 ) ( 4 ( − 1 ) a 2 + a 3 2 + 4 ( − 1 ) a 2 + a 4 2 + 1 ) = 0,</p><p>if and only if 4 | a 1 , if and only if the length of any cycle is a multiple of 4.</p><p>4.3.2 If s<sub>1</sub> is not contained in two s. Let’s assume that s<sub>3</sub>, s<sub>4</sub> are even, s<sub>1</sub>, s<sub>2</sub> are odd. Similar to case 1.2, we can get that G is singular if and only if the length of any cycle is a multiple of 4.</p><p>4.4 One s or no s is even. Similar to case 4.1, in these cases we can get that G is singular if and only if the length of any cycle is a multiple of 4.</p><p>5 Four a are odd.</p><p>5.1 Four s are even. There is no the spanning Sachs subgraph with four cycles. The spanning Sachs subgraphs of graph G with three cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 2 ∪ C a 4 ∪ a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 3 ∪ C a 4 ∪ a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 2 ∪ C a 3 ∪ C a 4 ∪ a 1 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>There is no the spanning Sachs subgraph with one or two cycles. There is no perfect matching.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 2 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 + ( − 1 ) a 1 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 &#215; 1 = 0 ,</p><p>multiply both sides by ( − 1 ) s 1 + s 2 + s 3 + s 4 − 6 2 , if and only if</p><p>( − 1 ) a 1 − 1 2 + ( − 1 ) a 2 − 1 2 + ( − 1 ) a 3 − 1 2 + ( − 1 ) a 4 − 1 2 = 0 ,</p><p>if and only if four a is exactly two module 4 remainder 1 and two module 4 remainder 3.</p><p>5.2 Three s are even. We can assume that s<sub>1</sub>, s<sub>2</sub>, s<sub>3</sub> are even, s<sub>4</sub> is odd. The spanning Sachs subgraphs of graph G with four cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ C a 4 ∪ s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>There is no the spanning Sachs subgraph with three cycles. The spanning Sachs subgraphs of graph G with two cycles have:</p><p>C a 1 ∪ C a 2 ∪ a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 3 ∪ a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 2 ∪ C a 3 ∪ a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>There is no the spanning Sachs subgraph with one cycle. There is no perfect matching.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) s 1 + s 2 + s 3 + s 4 − 7 2 + 4 &#215; 2 4 + ( − 1 ) a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 + ( − 1 ) a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 + ( − 1 ) a 1 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 = 0 ,</p><p>multiply both sides by ( − 1 ) s 1 + s 2 + s 3 + s 4 − 7 2 , if and only if</p><p>4 + ( − 1 ) a 3 + a 4 2 + ( − 1 ) a 2 + a 4 2 + ( − 1 ) a 1 + a 4 2 = 0,</p><p>it is impossible to establish.</p><p>5.3 Two s are even. We can assume that s<sub>1</sub>, s<sub>2</sub> are even, s<sub>3</sub>, s<sub>4</sub> are odd. There is no the spanning Sachs subgraph with four cycles. The spanning Sachs subgraphs of graph G with three cycles have:</p><p>C a 1 ∪ C a 2 ∪ C a 3 ∪ a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 2 ∪ C a 4 ∪ a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>There is no the spanning Sachs subgraph with two cycles. The spanning Sachs subgraphs of graph G with one cycle have:</p><p>C a 1 ∪ a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 2 ∪ a 1 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>There is no perfect matching.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 + ( − 1 ) a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 3 &#215; 2 3 + ( − 1 ) a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 + ( − 1 ) a 1 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 1 &#215; 2 = 0 ,</p><p>multiply both sides by ( − 1 ) s 1 + s 2 + s 3 + s 4 − 6 2 , if and only if</p><p>4 ( ( − 1 ) a 4 − 1 2 + ( − 1 ) a 3 − 1 2 ) + ( − 1 ) a 2 + a 3 + a 4 − 1 2 + ( − 1 ) a 1 + a 3 + a 4 − 1 2 = 0,</p><p>if and only if a 1 , a 2 is module 4 with different remainder and a 3 , a 4 is module 4 with different remainder.</p><p>5.4 One s is even. We can assume that s<sub>1</sub> is even, s<sub>2</sub>, s<sub>3</sub>, s<sub>4</sub> are odd. There is no the spanning Sachs subgraph with four or three cycles. The spanning Sachs subgraphs of graph G with two cycles have:</p><p>C a 1 ∪ C a 2 ∪ a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 3 ∪ a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one),</p><p>C a 1 ∪ C a 4 ∪ a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 P 2 (one).</p><p>There is no the spanning Sachs subgraph with one cycle. It contains 1 perfect matching.</p><p>By Lemma 2.2, G is singular if and only if</p><p>( − 1 ) a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 + ( − 1 ) a 2 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 + ( − 1 ) a 2 + a 3 + s 1 + s 2 + s 3 + s 4 − 7 2 + 2 &#215; 2 2 + ( − 1 ) a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 = 0 ,</p><p>multiply both sides by ( − 1 ) a 1 + a 2 + a 3 + a 4 + s 1 + s 2 + s 3 + s 4 − 7 2 , if and only if</p><p>4 ( ( − 1 ) a 1 + a 2 2 + ( − 1 ) a 1 + a 3 2 + ( − 1 ) a 1 + a 4 2 ) + 1 = 0,</p><p>it is impossible to establish.</p><p>5.5 Four s is odd. Similar to case 5.1, we can get G is singular if and only if four a is exactly two module 4 remainder 1 and two module 4 remainder 3.</p><p>The Theorem 1.1 is proved by summarizing the above cases.</p></sec><sec id="s4"><title>Acknowledgements</title><p>Supported by National Natural Science Foundation of China (11561056), National Natural Science Foundation of Qinghai Provence (2022-ZJ-924), and Innovation Project of Qinghai Minzu University (07M2022002).</p></sec><sec id="s5"><title>Conflicts of Interest</title><p>The authors declare no conflicts of interest regarding the publication of this paper.</p></sec><sec id="s6"><title>Cite this paper</title><p>You, X.J. and Ma, H.C. (2023) Singularity of Two Kinds of Quadcyclic Peacock Graphs. 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