<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">JAMP</journal-id><journal-title-group><journal-title>Journal of Applied Mathematics and Physics</journal-title></journal-title-group><issn pub-type="epub">2327-4352</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/jamp.2022.1011222</article-id><article-id pub-id-type="publisher-id">JAMP-121518</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  New Solitary Wave Solutions of the Fisher Equation
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Zidong</surname><given-names>Yang</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Hongyan</surname><given-names>Pan</given-names></name><xref ref-type="aff" rid="aff2"><sup>2</sup></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib></contrib-group><aff id="aff1"><addr-line>Hefei No. 6 High School, Hefei, China</addr-line></aff><aff id="aff2"><addr-line>Institute of Plasma Physics, Hefei Institutes of Physical Science, Chinese Academy of Sciences, Hefei, China</addr-line></aff><pub-date pub-type="epub"><day>09</day><month>11</month><year>2022</year></pub-date><volume>10</volume><issue>11</issue><fpage>3356</fpage><lpage>3368</lpage><history><date date-type="received"><day>30,</day>	<month>October</month>	<year>2022</year></date><date date-type="rev-recd"><day>26,</day>	<month>November</month>	<year>2022</year>	</date><date date-type="accepted"><day>29,</day>	<month>November</month>	<year>2022</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
  In this paper, we use Riccati equation to find new solitary wave solutions of Fisher equation, which describes the process of interaction between diffusion and reaction. It is of great importance to comprehend the equation to solve the problems in chemical kinetics and population dynamics. We resolve the Ricatti equation through diverse function transformation and many types of exact solutions are obtained. Then it is used as an auxiliary equation to solve Fisher equation. In the process, we select different coefficients in the Racatti equation, as a result, abundant solitary wave solutions are obtained, some of which haven’t been found in other documents yet. Moreover, these solutions we got in this paper will be favorable for understanding the Fisher equation.
 
</p></abstract><kwd-group><kwd>Nonlinear Evolution Equations</kwd><kwd> Solitary Wave</kwd><kwd> Soliton</kwd><kwd> Fisher Equation</kwd><kwd> Riccati Equation</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>At present, the study of solitary waves and solitons is a hot topic in nonlinear physics, from chemical kinetics, population dynamics, plasma, optics, and biology, etc [<xref ref-type="bibr" rid="scirp.121518-ref1">1</xref>] - [<xref ref-type="bibr" rid="scirp.121518-ref6">6</xref>]. Through physical mechanisms and facts from experiments, we learned that solitons exist. Under some reasonable conditions, we can establish mathematics models of most physics’ laws, and many of these nonlinear identification studies can give the credit to the nonlinear evolution equations eventually. Hence, finding the exact solutions, such as solitary-wave solutions, is very important for exploring the relevant nonlinear problems and understanding their characteristics, which can help scientists apply them into practical researches and studies to solve the problems in chemical kinetics and population dynamics. A large number of scientists have devoted themselves to the solutions in the latest centuries and as a result, many effective and forceful methods have been put forward in other documents to get the exact solutions of Fisher equation, for example, tanh-sech method and the extended tanh-coth method [<xref ref-type="bibr" rid="scirp.121518-ref7">7</xref>] [<xref ref-type="bibr" rid="scirp.121518-ref8">8</xref>], F-expansion method [<xref ref-type="bibr" rid="scirp.121518-ref9">9</xref>] [<xref ref-type="bibr" rid="scirp.121518-ref10">10</xref>], Jacobi elliptic function expansion method [<xref ref-type="bibr" rid="scirp.121518-ref11">11</xref>] [<xref ref-type="bibr" rid="scirp.121518-ref12">12</xref>], auxiliary equation method [<xref ref-type="bibr" rid="scirp.121518-ref13">13</xref>] [<xref ref-type="bibr" rid="scirp.121518-ref14">14</xref>] [<xref ref-type="bibr" rid="scirp.121518-ref15">15</xref>] [<xref ref-type="bibr" rid="scirp.121518-ref16">16</xref>], and so on. However, even some of them are powerful and effective, not all of them can be suitable for exploring the exact solutions of Fisher equation [<xref ref-type="bibr" rid="scirp.121518-ref16">16</xref>], which describes the interaction process between diffusion and reaction. This equation is encountered in chemical kinetics and population dynamics, including problems such as the nonlinear evolution of the population in the one-dimensional conventional neutron population in nuclear reactions. In Ref. [<xref ref-type="bibr" rid="scirp.121518-ref17">17</xref>], Fisher equation is treated with extended tanh method and many new solitary wave solutions were obtained. In this paper, we will use Riccati equation as an auxiliary equation to solve Fisher equation, so that many new results are obtained. The method used in this paper, on the one hand, can simplify the solving process of the nonlinear equation, on the other hand, obtains a new solitary wave solution of the Fisher equation.</p><p>The framework of the paper is as follows: Section 2 introduces the construction of abundant exact solutions of Riccati equation; Section 3 establishes how to operate this method for producing new solitary wave solutions of Fisher equation; Section 4 is the conclusion.</p></sec><sec id="s2"><title>2. Abundant Exact Solutions of Riccati Equation</title><p>The Riccati equation method is very simple but very effective. Hence, it is an ideal method to solve constant coefficient, variable coefficient and high-dimensional nonlinear evolution equations. In the paper, it first comes to our mind that we can use Racatti equation to solve the problems in the following form:</p><p>f ′ ( ξ ) = p 1 f 2 ( ξ ) + q 1 (1)</p><p>where p<sub>1</sub> and q<sub>1</sub> are constants and can be determined later. To find out new exact solutions of Equation (1), a new auxiliary function g ( ξ ) is introduced, which satisfies the following form</p><p>[ g ′ ( ξ ) ] 2 = p 2 g 2 ( ξ ) + q 2 (2)</p><p>where p<sub>2</sub> and q<sub>2</sub> are constants. Equation (2) has the following hyperbolic function solution</p><p>g 1 ( ξ ) = sinh ( ξ ) , ( p 2 = 1 , q 2 = 1 ) (3)</p><p>g 2 ( ξ ) = cosh ( ξ ) , ( p 2 = 1 , q 2 = − 1 ) (4)</p><p>g 3 ( ξ ) = cosh 2 ( ξ ) − 1 2 = sinh 2 ( ξ ) + 1 2 , ( p 2 = 4 , q 2 = − 1 ) (5)</p><p>Then we assume f ( ξ ) and g ( ξ ) have the following formal solution</p><p>f ( ξ ) = g ′ ( ξ ) g ( ξ ) + r (6)</p><p>where r is a constant. Substituting Equation (6) into Equation (1) and using Equation (2), we can obtain</p><p>{ p 1 p 2 + q 1 = 0 , p 2 r = 2 q 1 r , − q 2 = p 1 q 2 + q 1 r 2 . (7)</p><p>Solving this system, we can obtain</p><p>{ r = 0 , p 1 = − 1 , q 1 = p 2 , or { r = &#177; − q 2 p 2 , p 1 = − 1 2 , q 1 = p 2 2 . (8)</p><p>So, we have the following exact solutions of Equation (1)</p><p>f 1 ( ξ ) = cosh ( ξ ) sinh ( ξ ) , ( p 1 = − 1 , q 1 = 1 ) (9)</p><p>f 2 ( ξ ) = sinh ( ξ ) cosh ( ξ ) , ( p 1 = − 1 , q 1 = 1 ) (10)</p><p>f 3 ( ξ ) = 2 sinh ( ξ ) cosh ( ξ ) cosh 2 ( ξ ) − 1 2 , ( p 1 = − 1 , q 1 = 4 ) (11)</p><p>f 4 ( ξ ) = sinh ( ξ ) cosh ( ξ ) + ε , ( p 1 = − 1 2 , q 1 = 1 2 , ε 2 = 1 ) (12)</p><p>f 5 ( ξ ) = cosh ( ξ ) sinh ( ξ ) + ε , ( p 1 = − 1 2 , q 1 = 1 2 , ε 2 = − 1 ) (13)</p><p>Next, we use the following another formal solution to solve Equation (1)</p><p>f ( ξ ) = g ( ξ ) g ′ ( ξ ) g 2 ( ξ ) + r (14)</p><p>where r ≠ 0 . Substituting Equation (14) into Equation (1) and using Equation (2), we can obtain</p><p>{ p 1 p 2 + q 1 = 0 , − q 2 + 2 p 2 r = p 1 q 2 + 2 q 1 r , r q 2 = q 1 r 2 . (15)</p><p>Solving this system, we can obtain</p><p>{ r = q 2 2 p 2 , p 1 = − 2 , q 1 = 2 p 2 . (16)</p><p>So, we can have the following exact solutions</p><p>f 6 ( ξ ) = 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ ) [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8 , ( p 1 = − 2 , q 1 = 8 ) (17)</p><p>It is easy to know that h ( ξ ) = 1 / f ( ξ ) can also satisfy Equation (1) in the condition of p ′ 1 = − q 1 , q ′ 1 = − p 1 . Equations (9) and (10) are a pair of solutions on this condition. Therefore, the following equations are also the solutions of Equation (1)</p><p>f 7 ( ξ ) = cosh 2 ( ξ ) − 1 2 2 sinh ( ξ ) cosh ( ξ ) , ( p 1 = − 4 , q 1 = 1 ) (18)</p><p>f 8 ( ξ ) = cosh ( ξ ) + ε sinh ( ξ ) , ( p 1 = − 1 2 , q 1 = 1 2 , ε 2 = 1 ) (19)</p><p>f 9 ( ξ ) = sinh ( ξ ) + ε cosh ( ξ ) , ( p 1 = − 1 2 , q 1 = 1 2 , ε 2 = − 1 ) (20)</p><p>f 10 ( ξ ) = [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ ) , ( p 1 = − 8 , q 1 = 2 ) (21)</p><p>Equations (6) and (10) are the new types of exact solutions of Equation (1), which are rarely found in the other documents. Then, we use the Equation (1) and its solutions (9)-(13), (17) and (18)-(21) to solve the Fisher equation, and the solving process can be greatly simplified.</p></sec><sec id="s3"><title>3. Application of the Method</title><p>The following Fisher equation [<xref ref-type="bibr" rid="scirp.121518-ref16">16</xref>] [<xref ref-type="bibr" rid="scirp.121518-ref17">17</xref>] is considered</p><p>u t − u x x − u ( 1 − u ) = 0 (22)</p><p>Then suppose Equation (22) has the traveling wave solution</p><p>u ( x , t ) = u ( ξ ) , ξ = μ x + c t (23)</p><p>where μ and c are travelling wave parameters. Substituting the traveling wave equations into Equation (22), the following equation can be obtained</p><p>c u ′ − μ 2 u ″ − u ( 1 − u ) = 0 (24)</p><p>We assume that Equation (24) has the following formal solution</p><p>u ( ξ ) = ∑ i = 1 0 a i f i ( ξ ) + ∑ i = 1 n b i f − i ( ξ ) (25)</p><p>where a i and b i are constants to be determined and f i ( ξ ) is the solutions of Equation (1) and n can be determined by the homogeneous balance method. In the Equation (24), it is easy to know n = 2, so that the solution can be expressed as</p><p>u ( ξ ) = a 0 + a 1 f ( ξ ) + a 2 f 2 ( ξ ) + b 1 f − 1 ( ξ ) + b 2 f − 2 ( ξ ) (26)</p><p>We bring above equation into Equation (24) and use Equation (1), resulting in a series of equations a set of algebraic equations about a<sub>0</sub>, a<sub>1</sub>, a<sub>2</sub>, b<sub>1</sub>, b<sub>2</sub>, μ and c. Then we collect all the terms with the same power of f ( ξ ) , and set each coefficient to zero. Finally, we can obtain</p><p>Case 1 a 0 = 1 4 , a 1 = &#177; 1 2 − p 1 q 1 , a 2 = − p 1 4 q 1 , b 1 = b 2 = 0 , k 2 = − 1 24 p 1 q 1 , c = ∓ 5 12 − p 1 q 1 (27)</p><p>Case 2 a 0 = 1 4 , a 1 = a 2 = 0 , b 1 = &#177; 1 2 − q 1 p 1 , b 2 = − q 1 4 p 1 , k 2 = − 1 24 p 1 q 1 , c = &#177; 5 12 − p 1 q 1 (28)</p><p>Case 3 a 0 = 3 8 , a 1 = &#177; 1 4 − p 1 q 1 , a 2 = − p 1 16 q 1 , b 1 = ∓ 1 4 − q 1 p 1 , b 2 = − q 1 16 p 1 , k 2 = − 1 96 p 1 q 1 , c = ∓ 5 24 − p 1 q 1 (29)</p><p>According to Case 1, we have the following solitary wave solutions of the Fisher equation</p><p>u 1 ( ξ ) = 1 4 &#177; 1 2 coth ( ξ ) + 1 4 coth 2 ( ξ ) (30)</p><p>where ξ = μ x + c t , μ = 1 2 6 ε , c = ∓ 5 12 , ε 2 = 1 . <xref ref-type="fig" rid="fig1">Figure 1</xref>(a) shows the three-dimensional diagrams of Equation (30), which represents the bright solitary wave solution. <xref ref-type="fig" rid="fig1">Figure 1</xref>(b) shows that the amplitude and velocity of this solitary wave remain unchanged during propagation.</p><p>u 2 ( ξ ) = 1 4 &#177; 1 2 tanh ( ξ ) + 1 4 tanh 2 ( ξ ) (31)</p><p>where ξ = μ x + c t , μ = 1 2 6 ε , c = ∓ 5 12 , ε 2 = 1 . <xref ref-type="fig" rid="fig2">Figure 2</xref> shows the</p><p>three-dimensional and two-dimensional plots diagrams of Equation (31), which</p><p>represents the kink solitary wave solution.</p><p>u 3 ( ξ ) = 1 4 &#177; 1 2 sinh ( ξ ) cosh ( ξ ) cosh 2 ( ξ ) − 1 2 + 1 4 [ sinh ( ξ ) cosh ( ξ ) cosh 2 ( ξ ) − 1 2 ] 2 (32)</p><p>where ξ = μ x + c t , μ = 1 4 6 ε , c = ∓ 5 24 , ε 2 = 1 . <xref ref-type="fig" rid="fig3">Figure 3</xref> shows the three-dimensional and two-dimensional plots diagrams of Equation (32), which also represents the kink solitary wave solution.</p><p>u 4 ( ξ ) = 1 4 &#177; 1 2 sinh ( ξ ) cosh ( ξ ) + ε + 1 4 [ sinh ( ξ ) cosh ( ξ ) + ε ] 2 (33)</p><p>where ξ = μ x + c t , μ = 1 6 λ , c = ∓ 5 6 , ε 2 = 1 , λ 2 = 1 . <xref ref-type="fig" rid="fig4">Figure 4</xref> shows the three-dimensional and two-dimensional plots diagrams of Equation (33), which also represents the kink solitary wave solution.</p><p>u 5 ( ξ ) = 1 4 &#177; 1 2 cosh ( ξ ) sinh ( ξ ) + ε + 1 4 [ cosh ( ξ ) sinh ( ξ ) + ε ] 2 (34)</p><p>where ξ = μ x + c t , μ = 1 6 λ , c = ∓ 5 6 , ε 2 = − 1 , λ 2 = 1 . The solution of Equation (34) represents the traveling wave solutions of Equation (24) in complex space.</p><p>u 6 ( ξ ) = 1 4 &#177; 1 4 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ ) [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8     + 1 16 { 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ ) [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8 } 2 (35)</p><p>where ξ = μ x + c t , μ = 1 8 6 ε , c = ∓ 5 48 , ε 2 = 1 . <xref ref-type="fig" rid="fig5">Figure 5</xref> shows the three-dimensional and two-dimensional plots diagrams of Equation (35), which represents the kink solitary wave solution.</p><p>u 7 ( ξ ) = 1 4 &#177; 1 2 cosh 2 ( ξ ) − 1 2 sinh ( ξ ) cosh ( ξ ) + 1 4 [ cosh 2 ( ξ ) − 1 2 sinh ( ξ ) cosh ( ξ ) ] 2 (36)</p><p>where ξ = μ x + c t , μ = 1 4 6 ε , c = ∓ 5 24 , ε 2 = 1 . <xref ref-type="fig" rid="fig6">Figure 6</xref> shows the three-dimensional and two-dimensional plots diagrams of Equation (36), which represents the bright solitary wave solution.</p><p>u 8 ( ξ ) = 1 4 &#177; 1 2 cosh ( ξ ) + ε sinh ( ξ ) + 1 4 [ cosh ( ξ ) + ε sinh ( ξ ) ] 2 (37)</p><p>where ξ = μ x + c t , μ = 1 6 λ , c = ∓ 5 6 , ε 2 = 1 , λ 2 = 1 . <xref ref-type="fig" rid="fig7">Figure 7</xref> shows the three-dimensional and two-dimensional plots diagrams of Equation (37), which represents the bright solitary wave solution.</p><p>u 9 ( ξ ) = 1 4 &#177; 1 2 sinh ( ξ ) + ε cosh ( ξ ) + 1 4 [ sinh ( ξ ) + ε cosh ( ξ ) ] 2 (38)</p><p>where ξ = μ x + c t , μ = 1 6 λ , c = ∓ 5 6 , ε 2 = − 1 , λ 2 = 1 . The solution of Equation (38) represents the traveling wave solutions of Equation (24) in complex space.</p><p>u 10 ( ξ ) = 1 4 &#177; [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ )     + { [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ ) } 2 (39)</p><p>where ξ = μ x + c t , μ = 1 8 6 ε , c = ∓ 5 48 , ε 2 = 1 . <xref ref-type="fig" rid="fig8">Figure 8</xref> shows the three-dimensional and two-dimensional plots diagrams of Equation (39), which represents the bright solitary wave solution.</p><p>Because the solutions f 1 ( ξ ) − f 10 ( ξ ) of Equation (1) contain that corresponding to h ( ξ ) = 1 / f ( ξ ) , the solitary wave solutions of the Fisher equation in Case 2 are the same as in Case1. Corresponding to case 3, we express the solitary wave solution of Fisher equation as</p><p>u 11 ( ξ ) = 3 8 &#177; 1 4 coth ( ξ ) + 1 16 coth 2 ( ξ ) ∓ 1 4 tanh ( ξ ) + 1 16 tanh 2 ( ξ ) (40)</p><p>where ξ = μ x + c t , μ = 1 4 6 ε , c = ∓ 5 24 , ε 2 = 1 . <xref ref-type="fig" rid="fig9">Figure 9</xref> shows the three-dimensional and two-dimensional plots diagrams of Equation (40), which represents the bright solitary wave solution.</p><p>u 12 ( ξ ) = 3 8 &#177; 1 4 sinh ( ξ ) cosh ( ξ ) cosh 2 ( ξ ) − 1 2 + 1 16 [ sinh ( ξ ) cosh ( ξ ) cosh 2 ( ξ ) − 1 2 ] 2     ∓ 1 4 cosh 2 ( ξ ) − 1 2 sinh ( ξ ) cosh ( ξ ) + 1 16 [ cosh 2 ( ξ ) − 1 2 sinh ( ξ ) cosh ( ξ ) ] 2 (41)</p><p>where ξ = μ x + c t , μ = 1 8 6 ε , c = ∓ 5 48 , ε 2 = 1 . <xref ref-type="fig" rid="fig1">Figure 1</xref>0 shows the</p><p>three-dimensional and two-dimensional plots diagrams of Equation (41), which represents the bright solitary wave solution.</p><p>u 13 ( ξ ) = 3 8 &#177; 1 4 cosh ( ξ ) + ε sinh ( ξ ) + 1 16 [ cosh ( ξ ) + ε sinh ( ξ ) ] 2     ∓ 1 4 sinh ( ξ ) cosh ( ξ ) + ε + 1 16 [ sinh ( ξ ) cosh ( ξ ) + ε ] 2 (42)</p><p>where ξ = μ x + c t , μ = 1 2 6 λ , c = ∓ 5 12 , ε 2 = 1 , λ 2 = 1 . <xref ref-type="fig" rid="fig1">Figure 1</xref>1 shows the three-dimensional and two-dimensional plots diagrams of Equation (42), which represents the bright solitary wave solution.</p><p>u 14 ( ξ ) = 3 8 &#177; 1 4 cosh ( ξ ) sinh ( ξ ) + ε + 1 16 [ cosh ( ξ ) sinh ( ξ ) + ε ] 2     ∓ 1 4 sinh ( ξ ) + ε cosh ( ξ ) + 1 16 [ sinh ( ξ ) + ε cosh ( ξ ) ] 2 (43)</p><p>where ξ = μ x + c t , μ = 1 2 6 ε , c = ∓ 5 12 , ε 2 = − 1 . The solution of Equation (43)</p><p>represents the traveling wave solutions of Equation (24) in complex space.</p><p>u 15 ( ξ ) = 3 8 &#177; 1 2 [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ )     + 1 4 [ [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ ) ] 2     ∓ 1 8 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ ) [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8     + 1 64 [ 2 sinh ( ξ ) cosh 3 ( ξ ) − sinh ( ξ ) cosh ( ξ ) [ cosh 2 ( ξ ) − 1 2 ] 2 − 1 8 ] 2 (44)</p><p>where ξ = μ x + c t , μ = 1 16 6 ε , c = ∓ 5 96 , ε 2 = − 1 . <xref ref-type="fig" rid="fig1">Figure 1</xref>2 shows the three-dimensional and two-dimensional plots diagrams of Equation (44), which represents the bright solitary wave solution.</p></sec><sec id="s4"><title>4. Conclusion</title><p>In this paper, we use Riccati equation to find new solitary wave solutions of Fisher equation. Riccati equation is solved by using of two types of function transformation Equation (6) and Equation (14), so that many new exact solutions are obtained. With the formal solution of Equation (25), we have constructed abundant and new solitary wave solutions for the Fisher equation. The solitary wave solutions expressed by Equations (39), (41)-(44) are rarely found in other documents. The numerical images show that although the new expressions of many solutions are different, the solitary waves represented by them, including amplitude, wave velocity and space-time width, are the same. This method can greatly simplify the calculation process, especially suitable for solving more complex nonlinear systems.</p></sec><sec id="s5"><title>Conflicts of Interest</title><p>The authors declare no conflicts of interest regarding the publication of this paper.</p></sec><sec id="s6"><title>Cite this paper</title><p>Yang, Z.D. and Pan, H.Y. (2022) New Solitary Wave Solutions of the Fisher Equation. 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