<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">JAMP</journal-id><journal-title-group><journal-title>Journal of Applied Mathematics and Physics</journal-title></journal-title-group><issn pub-type="epub">2327-4352</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/jamp.2022.104086</article-id><article-id pub-id-type="publisher-id">JAMP-116658</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  The Quality Properties of Integral Type Problems for Wave Equations and Applications
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Veli</surname><given-names>B. Shakhmurov</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Rishad</surname><given-names>Shahmurov</given-names></name><xref ref-type="aff" rid="aff2"><sup>2</sup></xref></contrib></contrib-group><aff id="aff1"><addr-line>Department of Industrial Engineering, Antalya Bilim University, Dosemealti, Antalya, Turkey</addr-line></aff><aff id="aff2"><addr-line>University of Alabama, Tuscaloosa, AL, USA</addr-line></aff><pub-date pub-type="epub"><day>02</day><month>04</month><year>2022</year></pub-date><volume>10</volume><issue>04</issue><fpage>1217</fpage><lpage>1239</lpage><history><date date-type="received"><day>19,</day>	<month>February</month>	<year>2022</year></date><date date-type="rev-recd"><day>18,</day>	<month>April</month>	<year>2022</year>	</date><date date-type="accepted"><day>21,</day>	<month>April</month>	<year>2022</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
  In this paper, the integral problem for linear and nonlinear wave equations is studied. The equation involves abstract operator 
  <em>A</em> in Hilbert space 
  <em>H</em>. Here, assuming enough smoothness on the initial data and the operators, the existence, uniqueness, regularity properties of solutions are established. By choosing the space 
  <em>H</em> and 
  <em>A</em>, the regularity properties of solutions of a wide class of wave equations in the field of physics are obtained.
 
</p></abstract><kwd-group><kwd>Abstract Differential Equations</kwd><kwd> Boussinesq Equations</kwd><kwd> Wave Equations</kwd><kwd> Regularity Property of Solutions</kwd><kwd> Fourier Multipliers</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction, Definitions and Background</title><p>The aim here, is to study the existence, uniqueness, regularity properties of solutions of the integral problem (IP) for abstract wave equation (WE)</p><p>u t t − a Δ u + A u = f ( u ) , ( x , t ) ∈ ℝ T n = ℝ n &#215; ( 0 , T ) , (1.1)</p><p>u ( x ,0 ) = φ ( x ) + ∫ 0 T η ( σ ) u ( x , σ ) d σ , (1.2)</p><p>u t ( x ,0 ) = ψ ( x ) + ∫ 0 T β ( σ ) u t ( x , σ ) d σ ,</p><p>where A is a linear and f ( u ) is a nonlinear operator in a Hilbert space H, η ( σ ) , β ( σ ) are measurable functions on ( 0, T ) , a is a complex number, T ∈ ( 0, ∞ ] . Here, Δ denotes the Laplace operator with respect to x ∈ ℝ n , φ ( x ) and ψ ( x ) are the given H-valued initial functions.</p><p>Wave type equations occur in a wide variety of physical systems, such as in the propagation of longitudinal deformation waves in an elastic rod, hydro-dynamical process in plasma, in materials science which describes spinodal decomposition and in the absence of mechanical stresses (see [<xref ref-type="bibr" rid="scirp.116658-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref2">2</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref3">3</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref4">4</xref>] ). The nonlocal theory of elasticity was introduced (see [<xref ref-type="bibr" rid="scirp.116658-ref5">5</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref6">6</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref7">7</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref8">8</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref9">9</xref>] and the references cited therein). The global existence of the Cauchy problem for Boussinesq type equations has been studied by many authors (see [<xref ref-type="bibr" rid="scirp.116658-ref10">10</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref11">11</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref12">12</xref>] ). Note that, the existence and uniqueness of solutions and regularity properties of a wide class of wave equations were considered e.g. in [<xref ref-type="bibr" rid="scirp.116658-ref13">13</xref>] - [<xref ref-type="bibr" rid="scirp.116658-ref22">22</xref>]. The abstract evolution equations were studied e.g. in [<xref ref-type="bibr" rid="scirp.116658-ref23">23</xref>] - [<xref ref-type="bibr" rid="scirp.116658-ref32">32</xref>]. Unlike in these studies, in this paper the abstract wave equation (1.1) is considered. The L p well-posedness of the Cauchy problem (1.1)-(1.2) depends crucially on the presence of the linear operator A and nonlinear operator f ( u ) . Then the question that naturally arises is which of the possible forms of the operator functions and kernel functions are relevant for the global well-posedness of the Cauchy problem (1.1)-(1.2). We find the class of operator A such that provides the existence, uniqueness, regularity properties and blow up of solutions (1.1)-(1.2) in terms of fractional powers of operator A. By choosing the space H, operator A in (1.1)-(1.2), we obtain a wide class of wave equations which occur in application. Let we put H = L 2 ( 0,1 ) and consider the operator A = A 1 defined by</p><p>D ( A 1 ) = W 2 , 2 ( 0 , 1 , L k ) , A 1 u = b 1 u ( 2 ) + b 0 u , (1.3)</p><p>L k u = [ α k u ( m k ) ( 0 ) + β k u ( m k ) ( 1 ) ] = 0 , k = 1 , 2 ,</p><p>where b 1 ( . ) , b 0 ( . ) are VMO functions (see definitions below), m k ∈ { 0,1 } , α k , β k are complex numbers.</p><p>Consider the following mixed problem for WE with discontinuous coefficients</p><p>∂ 2 u ∂ t 2 − a Δ x u + b 1 ∂ 2 u ∂ y 2 + b 0 u = f ( u ) , t ∈ ( 0 , T ) , x ∈ ℝ n , (1.4)</p><p>u ( x , y , 0 ) = φ ( x , y ) + ∫ 0 T η ( σ ) u ( x , y , σ ) d σ ,</p><p>u t ( x , y ,0 ) = ψ ( x , y ) + ∫ 0 T β ( σ ) u t ( x , y , σ ) d σ ,</p><p>α k u ( m k ) ( x , 0 , t ) + β k u ( m k ) ( x , 1 , t ) = 0 , k = 1 , 2 ,</p><p>where a is a complex number. From our results we obtain the existence, uniqueness, regularity properties and blow up of solutions of (1.4) in L p ( ℝ n &#215; ( 0,1 ) ) with terms of fractional powers of the operator A 1 , where p = ( 2, p , p ) and L p ( ℝ n &#215; ( 0,1 ) ) denotes the space of all p -summable complex-valued measurable functions f defined on Ω with the mixed norm</p><p>‖ f ‖ L p ( Ω ) = ( ∫ ℝ n     ∫ 0 T ( ∫ 0 1 | f ( x , y , t ) | p 1 d y ) 2 p 1 d x d t ) 1 2 &lt; ∞ .</p><p>Let E be a Banach space. L p ( Ω ; E ) denotes the space of strongly measurable E-valued functions that are defined on the measurable subset Ω ⊂ ℝ n with the norm</p><p>‖ f ‖ p = ‖ f ‖ L p ( Ω ; E ) = ( ∫ Ω ‖ f ( x ) ‖ E p d x ) 1 p , 1 ≤ p &lt; ∞ ,</p><p>‖ f ‖ L ∞ ( Ω ; E ) = ess sup x ∈ Ω ‖ f ( x ) ‖ E .</p><p>Let E 1 and E 2 be two Banach spaces. ( E 1 , E 2 ) θ , p for θ ∈ ( 0,1 ) , p ∈ [ 1, ∞ ] denotes the real interpolation spaces defined by K-method ( [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 1.3.2). Let E 1 and E 2 be two Banach spaces. B ( E 1 , E 2 ) will denote the space of all bounded linear operators from E 1 to E 2 . For E 1 = E 2 = E it will be denoted by B ( E ) .</p><p>Here,</p><p>S ϕ = { λ ∈ ℂ , λ ≠ 0 , | arg λ | ≤ ϕ , 0 ≤ ϕ &lt; π } .</p><p>A closed linear operator A is said to be sectorial in a Banach space E with bound M &gt; 0 if D ( A ) and R ( A ) are dense on E, N ( A ) = { 0 } and</p><p>‖ ( A + λ I ) − 1 ‖ B ( E ) ≤ M | λ | − 1</p><p>for any λ ∈ S ϕ , 0 ≤ ϕ &lt; π , where I is the identity operator in E, D ( A ) and R ( A ) denote domain and range of the operator A, respectively. It is known that (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 1.15.1) there exist the fractional powers A θ of a sectorial operator A. Let E ( A θ ) denote the space D ( A θ ) with the graphical norm</p><p>‖ u ‖ E ( A θ ) = ( ‖ u ‖ p + ‖ A θ u ‖ p ) 1 p , 1 ≤ p &lt; ∞ , 0 &lt; θ &lt; ∞ .</p><p>A sectorial operator A ( ξ ) is said to be uniformly sectorial in E for ξ ∈ ℝ n , if D ( A ( ξ ) ) is independent of ξ and the following uniform estimate</p><p>‖ ( A + λ I ) − 1 ‖ B ( E ) ≤ M | λ | − 1</p><p>holds for any λ ∈ S ϕ .</p><p>A function Ψ ∈ L ∞ ( ℝ n ) is called a Fourier multiplier from L p ( ℝ n ; E ) to L q ( ℝ n ; E ) if the map P : u → F − 1 Ψ ( ξ ) F u is well defined for u ∈ S ( ℝ n ; E ) and extends to a bounded linear operator.</p><p>Definition 1.1. Let U be an open set in a Banach space X, let Y be a Banach space. A function f : U → Y is called (Frechet) differentiable at x ∈ U if there is a bounded linear operator D f ( x ) : X → Y , called the derivative of f at a, such that</p><p>lim h → 0 ‖ f ( x + h ) − f ( x ) − D f ( x ) h ‖ Y ‖ h ‖ X = 0</p><p>If f is differentiable at each x ∈ U , then f is called differentiable. This function may also have a derivative, the second order derivative of f, which, by the definition of derivative, will be a map</p><p>D 2 f : U → L ( X , L ( X , Y ) ) .</p><p>Let E be a Banach space. S = S ( ℝ n ; E ) denotes E-valued Schwartz class, i.e. the space of all E-valued rapidly decreasing smooth functions on ℝ n equipped with its usual topology generated by seminorms. S ( ℝ n ; ℂ ) denoted by S. Let S ′ ( ℝ n ; E ) denote the space of all continuous linear functions from S into E, equipped with the bounded convergence topology. Recall S ( ℝ n ; E ) is norm dense in L p ( ℝ n ; E ) when 1 ≤ p &lt; ∞ . Let m be a positive integer. W m , p ( Ω ; E ) denotes an E-valued Sobolev space of all functions u ∈ L p ( Ω ; E ) that have the generalized derivatives ∂ m u ∂ x k m ∈ L p ( Ω ; E ) with the norm</p><p>‖ u ‖ W m , p ( Ω ; E ) = ‖ u ‖ L p ( Ω ; E ) + ∑ k = 1 n ‖ ∂ m u ∂ x k m ‖ L p ( Ω ; E ) &lt; ∞ .</p><p>Let W s , p ( ℝ n ; E ) denotes the fractional Sobolev space of order s ∈ ℝ , that is defined as:</p><p>W s , p ( E ) = W s , p ( ℝ n ; E ) = { u ∈ S ′ ( ℝ n ; E ) , ‖ u ‖ W s , p ( E ) = ‖ F − 1 ( I + | ξ | 2 ) s 2 u ^ ‖ L p ( ℝ n ; E ) &lt; ∞ } .</p><p>It is clear that W 0, p ( ℝ n ; E ) = L p ( ℝ n ; E ) . Let E 0 and E be two Banach spaces and E 0 is continuously and densely embedded into E. Here, W s , p ( ℝ n ; E 0 , E ) denote the Sobolev-Lions type space i.e.,</p><p>W s , p ( ℝ n ; E 0 , E ) = { u ∈ W s , p ( ℝ n ; E ) ∩ L p ( ℝ n ; E 0 ) , ‖ u ‖ W s , p ( ℝ n ; E 0 , E ) = ‖ u ‖ L p ( ℝ n ; E 0 ) + ‖ u ‖ W s , p ( ℝ n ; E ) &lt; ∞ } .</p><p>In a similar way, we define the following Sobolev-Lions type space:</p><p>W 2, s , p ( ℝ T n ; E 0 , E ) = { u ∈ L p ( ℝ T n ; E 0 ) , ∂ t 2 u ∈ L p ( ℝ T n ; E ) ,       F x − 1 ( I + | ξ | 2 ) s 2 u ^ ∈ L p ( ℝ T n ; E ) , ‖ u ‖ W 2, s , p ( ℝ T n ; E 0 , E ) = ‖ u ‖ L p ( ℝ T n ; E 0 ) + ‖ ∂ t 2 u ‖ L p ( ℝ T n ; E ) + ‖ F x − 1 ( I + | ξ | 2 ) s 2 u ^ ‖ L p ( ℝ T n ; E ) &lt; ∞ } .</p><p>Let L q ∗ ( E ) denote the space of all E-valued function space such that</p><p>‖ u ‖ L q ∗ ( E ) = ( ∫ 0 ∞ ‖ u ( t ) ‖ E q d t t ) 1 q &lt; ∞ , 1 ≤ q &lt; ∞ , ‖ u ‖ L ∞ ∗ ( E ) = sup 0 &lt; t &lt; ∞ ‖ u ( t ) ‖ E .</p><p>Let s &gt; 0 . Fourier-analytic representation of E-valued Besov space on ℝ n is defined as:</p><p>B p , q s ( ℝ n ; E ) = { u ∈ S ′ ( ℝ n ; E ) , ‖ u ‖ B p , q s ( ℝ n ; E ) = ‖ F − 1 ∑ k = 1 n     t ϰ − s ( 1 + | ξ | 2 ) ϰ 2 e − t | ξ | 2 F u ‖ L q ∗ ( L p ( ℝ n ; E ) ) , p ∈ ( 1 , ∞ ) , q ∈ [ 1 , ∞ ] , ϰ &gt; s } .</p><p>It should be noted that, the norm of Besov space does not depend on ϰ (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 2.3 for E = ℂ ).</p><p>Let A be a sectorial operator in H. Here,</p><p>X p = L p ( ℝ n ; H ) , X p ( A γ ) = L p ( ℝ n ; H ( A γ ) ) , 1 ≤ p , q ≤ ∞ ,</p><p>Y s , p = Y s , p ( H ) = W s , p ( ℝ n ; H ) , Y q s , p ( H ) = Y s , p ( H ) ∩ X q ,</p><p>‖ u ‖ Y q s , p = ‖ u ‖ W s , p ( ℝ n ; H ) + ‖ u ‖ X q &lt; ∞ ,</p><p>W s , p ( A γ ) = W s , p ( ℝ n ; H ( A γ ) ) , 0 &lt; γ ≤ 1 ,</p><p>Y s , p = Y s , p ( A , H ) = W s , p ( ℝ n ; H ( A ) , H ) ,</p><p>Y 2 , s , p = Y 2 , s , p ( A , H ) = W 2 , s , p ( ℝ T n ; H ( A ) , H ) ,</p><p>Y q s , p ( A ; H ) = Y s , p ( H ) ∩ X q ( A ) ,</p><p>‖ u ‖ Y q s , p ( A , H ) = ‖ u ‖ Y s , p ( H ) + ‖ u ‖ X q ( A ) &lt; ∞ ,</p><p>E 0 p = ( Y s , p ( A , H ) , X p ) 1 2 p , p , E 1 p = ( Y s , p ( A , H ) , X p ) 1 + p 2 p , p ,</p><p>where ( Y s , p , X p ) θ , p denotes the real interpolation space between Y s , p and X p for θ ∈ ( 0,1 ) , p ∈ [ 1, ∞ ] (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 1.3).</p><p>Remark 1.1. By Fubini’s theorem we get</p><p>L p ( ℝ T n ; H ) = L p ( 0, T ; X p )     for   X p = L , p ( ℝ n ; H ) .</p><p>Then by definition of spaces Y 2, s , p , Y s , p = H s , p ( ℝ n ; H ( A ) , H ) and X p we have</p><p>Y 2 , s , p = { u : u ∈ W 2 , p ( 0 , T ; Y s , p , X p ) , ‖ u ‖ W 2 , p ( 0 , T ; Y s , p , X p )                             = ‖ u ‖ L p ( 0 , T ; Y s , p ) + ‖ u ( 2 ) ‖ L p ( 0 , T ; X p ) } .</p><p>By J. lions-J. Peetre result (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 1.8.2) for u ∈ W 2, p ( 0, T ; Y s , p , X p ) the trace operator u → d i u d t i ( t 0 ) = ∂ i u ∂ t i ( ., t 0 ) is bounded from Y 2, s , p into</p><p>C ( 0 , T ; ( Y s , p , X p ) θ j , p ) , θ j = 1 + j p 2 p , j = 0 , 1.</p><p>Moreover, if u ( x ,. ) ∈ ( Y s , p , X p ) θ j , p , then under some assumptions that will be stated in Section 3, f ( u ) ∈ H for all x, t ∈ ℝ T n and the map u → f ( u ) is bounded from ( Y s , p , X p , ) 1 2 p , p into E. Hence, the nonlinear Equation (1.1) is satisfied in the Banach space H. Here, H ( A ) denotes a domain of A equipped with graphical norm.</p><p>Sometimes we use one and the same symbol C without distinction in order to denote positive constants which may differ from each other even in a single context. When we want to specify the dependence of such a constant on a parameter, say α , we write C α . Moreover, for u , υ &gt; 0 the relations u ≲ υ , u ≈ υ means that there exist positive constants C , C 1 , C 2 independent on u and υ such that, respectively</p><p>u ≤ C υ , C 1 υ ≤ u ≤ C 2 υ .</p><p>The paper is organized as follows: In Section 1, some definitions and background are given. In Section 2, we obtain the existence of unique solution and a priory estimates for solution of the linearized problem (1.1)-(1.2). In Section 3, we show the existence and uniqueness of local strong solution of the problem (1.1)-(1.2). In Section 4, the existence and uniqueness of global strong solution of the problem (1.1)-(1.2) is derived. Section 5 is devoted to blow up property of the solution of (1.1)-(1.2). In Section 6, we show some applications of the problem (1.1)-(1.2).</p><p>Sometimes we use one and the same symbol C without distinction in order to denote positive constants which may differ from each other even in a single context. When we want to specify the dependence of such a constant on a parameter, say h, we write C h .</p></sec><sec id="s2"><title>2. Estimates for Linearized Equation</title><p>In this section, we make the necessary estimates for solutions of the integral problem for linear WE</p><p>u t t − a Δ u + A u = g ( x , t ) , x ∈ ℝ n , t ∈ ( 0 , T ) , T ∈ ( 0 , ∞ ] , (2.1)</p><p>u ( x , 0 ) = φ ( x ) + ∫ 0 T η ( σ ) u ( x , σ ) d σ , (2.2)</p><p>u t ( x ,0 ) = ψ ( x ) + ∫ 0 T β ( σ ) u t ( x , σ ) d σ ,</p><p>where A is a linear operator in a Banach space E, a is a complex number and η ( s ) , β ( s ) are measurable functions on ( 0, T ) .</p><p>Remark 2.1. By properties of real interpolation of Banach spaces and interpolation of the intersection of the spaces (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 1.3) we obtain</p><p>E 0 p = ( Y s , p ( A , H ) ∩ X p , X p ) 1 2 p , p = ( Y s , p ( H ) , X p ) 1 2 p , p ∩ ( X p ( A ) , X p ) 1 2 p , p</p><p>= W s ( 1 − 1 2 p ) , p ( ℝ n ; H ) ∩ L p ( ℝ n ; ( H ( A ) , H ) 1 2 p , p ) = W s ( 1 − 1 2 p ) , p ( ℝ n ; ( H ( A ) , H ) 1 2 p , p , H ) .</p><p>In a similar way, we have</p><p>E 1 p = ( Y s , p ( A , H ) ∩ X p , X p ) 1 + p 2 p , p = W s ( p − 1 ) 2 p , p ( ℝ n ; ( H ( A ) , H ) 1 + p 2 p , p , H ) .</p><p>Remark 2.2. Let A be a sectorial operator in a Banach space E. In view of interpolation of sectorial operators (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 1.8.2) we have the following relation</p><p>E ( A 1 − θ − ε ) ⊂ ( E ( A ) , E ) θ , p ⊂ E ( A 1 − θ + ε )</p><p>for 0 &lt; θ &lt; 1 and 0 &lt; ε &lt; 1 − θ .</p><p>Note that from J. lions-J. Peetre result (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 1.8.2) we obtain the following result.</p><p>Lemma A<sub>1</sub>. The trace operator u → ∂ i u ∂ t i ( x , t ) is bounded from Y 2, s , p ( A , H ) into</p><p>C ( ℝ n ; ( Y s , p ( A , H ) , X p ) θ j , p ) , θ j = 1 + j p 2 p , j = 0 , 1.</p><p>We assume that A is a sectorial operator in a Hilbert space H. Let A be a generator of a strongly continuous cosine operator function in a Banach space E defined by formula</p><p>C ( t ) = C A ( t ) = 1 2 ( e i t A 1 2 + e − i t A 1 2 )</p><p>(see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref25">25</xref>], Section 11 or [<xref ref-type="bibr" rid="scirp.116658-ref23">23</xref>], Section 3). Then, from the definition of sine operator-function S ( t ) we have</p><p>S ( t ) = S A ( t ) = ∫ 0 t C ( σ ) d σ ,   i . e .   S ( t ) = 1 2 i A − 1 2 ( e i t A 1 2 − e − i t A 1 2 ) .</p><p>Remark 2.3. Let A be a densely defined operator in H. By virtue of ( [<xref ref-type="bibr" rid="scirp.116658-ref23">23</xref>], Theorem 3.15.3) if A be the generator of a cosine function C ( t ) , i.e.</p><p>R ( λ 2 , A ) = 1 λ ∫ 0 ∞ e − λ t C ( t ) d t     for   λ &gt; ω .</p><p>Let</p><p>A &#177; ( ξ ) = e i t A ( ξ ) &#177; e − i t A ( ξ ) , C ( t ) = C ( ξ , t ) = A + ( ξ ) 2 , (2.3)</p><p>S ( t ) = S ( ξ , t ) = S ( ξ , t , A ) = 1 2 i A − 1 ( ξ ) A − ( ξ ) .</p><p>Condition 2.1. Assume: 1)</p><p>| 1 + ∫ 0 T η ( σ ) β ( σ ) d σ | &gt; ∫ 0 T ( | η ( σ ) | + | β ( σ ) | ) d σ ; (2.0)</p><p>2) A is a ϕ -sectorial operator in the Hilbert space H and A is a generator of a cosine function; 3) a ∈ S ϕ 1 for 0 ≤ ϕ 1 &lt; π , ϕ 1 &lt; π − ϕ ; 4) φ ∈ E 0 p and ψ ∈ E 1 p .</p><p>Definition 1.1. Let T &gt; 0 , φ ∈ E 0 p and ψ ∈ E 1 p . The function u ∈ C 2 ( Y 1 s , p ( A ) ) satisfies of the problem (1.1)-(1.2) is called the continuous solution or the strong solution of (1.1)-(1.2). If T &lt; ∞ , then u ( x , t ) is called the local strong solution of (1.1)-(1.2). If T = ∞ , then u ( x , t ) is called the global strong solution of (1.1)-(1.2).</p><p>First we need the following lemmas:</p><p>Lemma 2.1. Let the Condition 2.1 holds. Then, problem (2.1)-(2.2) has a solution.</p><p>Proof. By using of the Fourier transform, we get from (2.1)-(2.2):</p><p>u ^ t t ( ξ , t ) + A ξ 2 u ^ ( ξ , t ) = g ^ ( ξ , t ) , (2.4)</p><p>u ^ ( ξ ,0 ) = φ ^ ( ξ ) + ∫ 0 T η ( σ ) u ^ ( ξ , σ ) d σ , (2.5)</p><p>u ^ t ( ξ ,0 ) = ψ ^ ( ξ ) + ∫ 0 T β ( σ ) u ^ t ( ξ , σ ) d σ ,</p><p>where u ^ ( ξ , t ) is a Fourier transform of u ( x , t ) in x and φ ^ ( ξ ) , ψ ^ ( ξ ) are Fourier transform of φ and ψ , respectively and</p><p>A ξ = [ a | ξ | 2 + A ] 1 2 .</p><p>Consider first, the Cauchy problem</p><p>u ^ t t ( ξ , t ) + A ξ 2 u ^ ( ξ , t ) = g ^ ( ξ , t ) , (2.6)</p><p>u ^ ( ξ , 0 ) = u 0 ( ξ ) , u ^ t ( ξ , 0 ) = u 1 ( ξ ) , ξ ∈ ℝ n , t ∈ [ 0 , T ] ,</p><p>where u 0 ( ξ ) , u 1 ( ξ ) ∈ D ( A ) for ξ ∈ ℝ n . By virtue of ( [<xref ref-type="bibr" rid="scirp.116658-ref25">25</xref>], Section 11.2, 11.4) we obtain that A ξ is a generator of a strongly continuous cosine operator function and the Cauchy problem (2.6) has a unique solution for all ξ ∈ ℝ n . Moreover, the solution of (2.6) can be expressed as</p><p>u ^ ( ξ , t ) = C ( t ) u 0 ( ξ ) + S ( t ) u 1 ( ξ ) + ∫ 0 T S ( t − τ , ξ , A ) g ^ ( ξ , τ ) d τ , t ∈ ( 0 , T ) , (2.7)</p><p>where C ( t ) is a cosine and S ( t ) is a sine operator-functions generated by A ξ , i.e.</p><p>C ( t ) = C ( t , ξ , A ) = 1 2 ( e t A ξ + e − t A ξ ) ,</p><p>S ( t ) = S ( t , ξ , A ) = 1 2 A ξ − 1 ( e t A ξ − e − t A ξ ) .</p><p>Using the formula (2.7) and the first integral condition (2.5) we get</p><p>u 0 ( ξ ) = φ ^ ( ξ ) + ∫ 0 T η ( σ ) [ u 0 ( ξ ) + 1 2 i A − 1 ( ξ ) u 1 ( ξ ) ] d σ                       + ∫ 0 T η ( σ ) [ C ( σ ) u 0 ( ξ ) + S ( σ ) u 1 ( ξ ) ] d σ                       + ∫ 0 T ∫ 0 T η ( σ ) S ( σ − τ , ξ , A ) g ^ ( σ , ξ ) d τ d σ , τ ∈ ( 0 , T ) ,</p><p>i.e. we obtain the first equation with respect to u 0 ( ξ ) , u 1 ( ξ ) :</p><p>b 10 ( ξ ) u 0 ( ξ ) + b 11 ( ξ ) u 1 ( ξ ) = g 10 ( ξ ) , (2.8)</p><p>where</p><p>b 10 ( ξ ) = [ 1 − ∫ 0 T η ( σ ) [ 1 + C ( σ ) ] d σ ] ,</p><p>b 11 ( ξ ) = − 1 2 i A ξ − 1 ∫ 0 T η ( σ ) C ( σ ) d σ − ∫ 0 T η ( σ ) S ( σ ) d σ ,</p><p>g 10 ( ξ ) = φ ^ ( ξ ) + ∫ 0 T ∫ 0 T η ( σ ) S ( σ − τ , ξ , A ) g ^ ( σ , ξ ) d τ d σ</p><p>Differentiating both sides of formula (2.7) and using the seconf integral condition (2.5), we have</p><p>u 1 ( ξ ) = ψ ^ ( ξ ) + ∫ 0 T β ( σ ) [ 1 2 i u 0 ( ξ ) + u 1 ( ξ ) ] d σ     + ∫ 0 T ∫ 0 T β ( σ ) C ( σ − τ , ξ , A ) g ^ ( ξ , σ ) d τ d σ ,</p><p>i.e. we get the second equation with respect to u 0 ( ξ ) , u 1 ( ξ ) :</p><p>b 20 ( ξ ) u 0 ( ξ ) + b 21 ( ξ ) u 1 ( ξ ) = g 20 ( ξ ) , (2.9)</p><p>where</p><p>b 20 ( ξ ) = − 1 2 i ∫ 0 T β ( σ ) d σ , b 21 ( ξ ) = 1 − ∫ 0 T β ( σ ) d σ ,</p><p>g 20 ( ξ ) = ψ ^ ( ξ ) + ∫ 0 T ∫ 0 T β ( σ ) C ( σ − τ , ξ , A ) g ^ ( ξ , σ ) d τ d σ .</p><p>Now, we consider the system of Equations (2.8)-(2.9) in u 0 ( ξ ) and u 1 ( ξ ) . By assumption (2.0) and due to uniformly boundedness of A ξ − 1 , the main determinant of this system</p><p>D ( ξ ) = | b 10 ( ξ ) b 11 ( ξ ) b 20 ( ξ ) b 21 ( ξ ) | = [ 1 − ∫ 0 T η ( σ ) [ 1 + C ( σ ) ] d σ ] [ 1 − ∫ 0 T β ( σ ) d σ ] − [ − 1 2 i ∫ 0 T β ( σ ) d σ ] [ − 1 2 i A ξ − 1 ∫ 0 T η ( σ ) C ( σ ) d σ − ∫ 0 T η ( σ ) S ( σ ) d σ ] = 1 − ∫ 0 T β ( σ ) d σ − ∫ 0 T η ( σ ) [ 1 + C ( σ ) ] d σ + ( ∫ 0 T β ( σ ) d σ ) ∫ 0 T η ( σ ) [ 1 + C ( σ ) ] d σ   + − 1 4 A ξ − 1 ( ∫ 0 T β ( σ ) d σ ) ( ∫ 0 T η ( σ ) C ( σ ) d σ ) − 1 2 i ( ∫ 0 T β ( σ ) d σ ) [ ∫ 0 T η ( σ ) S ( σ ) d σ ]</p><p>= 1 − ∫ 0 T β ( σ ) d σ + [ ∫ 0 T η ( σ ) [ 1 + C ( σ ) ] d σ ] [ ∫ 0 T β ( σ ) d σ − 1 ]   − ( ∫ 0 T β ( σ ) d σ ) [ 1 4 A ξ − 1 ∫ 0 T η ( σ ) C ( σ ) d σ + 1 2 i ∫ 0 T η ( σ ) S ( σ ) d σ ] ≠ 0</p><p>for all ξ ∈ ℝ n . By solving the system (2.8)-(2.9) we get</p><p>u 0 ( ξ ) = D 1 ( ξ ) D − 1 ( ξ ) , u 1 ( ξ ) = D 2 ( ξ ) D − 1 ( ξ ) , (2.10)</p><p>D 1 ( ξ ) = b 21 ( ξ ) g 10 ( ξ ) − b 11 ( ξ ) g 20 ( ξ ) , D 2 ( ξ ) = b 10 ( ξ ) g 20 ( ξ ) − b 20 ( ξ ) g 10 ( ξ ) .</p><p>By substituting the values u 0 ( ξ ) and u 1 ( ξ ) in (2.7), we obtain</p><p>u ^ ( ξ , t ) = C ( ξ , t ) D 1 ( ξ ) D − 1 ( ξ ) + S ( ξ , t ) D 2 ( ξ ) D − 1 ( ξ )     + ∫ 0 t S ( ξ , t − τ ) g ^ ( ξ , τ ) d τ , (2.11)</p><p>i.e. problem (2.1)-(2.2) has a unique solution</p><p>u ( x , t ) = C 1 ( t ) φ + S 1 ( t ) ψ + Q g , (2.12)</p><p>where C 1 ( t ) , S 1 ( t ) , Q are linear operator functions defined by</p><p>C 1 ( t ) φ = F − 1 [ C ( ξ , t ) D 1 ( ξ ) ] , S 1 ( t ) ψ = F − 1 [ S ( ξ , t ) D 2 ( ξ ) ] ,</p><p>Q g = F − 1 Q ˜ ( ξ , t ) , Q ˜ ( ξ , t ) = ∫ 0 t F − 1 [ S ( ξ , t − τ ) g ^ ( ξ , τ ) ] d τ .</p><p>Theorem 2.1. Assume the Condition 2.1 holds and</p><p>s &gt; 2 p n 2 p − 1 ( 2 q + 1 p ) (2.13)</p><p>for p ∈ [ 1, ∞ ] and for a q ∈ [ 1,2 ] . Let 0 ≤ α &lt; 1 − 1 2 p . Then for φ ∈ E 0 p ∩ X 1 ( A α ) , ψ ∈ E 1 p ∩ X 1 ( A α − 1 2 ) , g ( ., t ) ∈ Y 1 s , p for t ∈ [ 0, T ] and g ( x ,. ) ∈ L 1 ( 0, T ; Y 1 s , p ) for x ∈ ℝ n problem (2.1)-(2.2) has a unique solution u ( x , t ) ∈ C 2 ( [ 0, T ] ; X ∞ ) . Moreover, the following estimate holds</p><p>‖ A α u ‖ X ∞ + ‖ A α u t ‖ X ∞ ≤ C 0 [ ‖ φ ‖ E 0 p + ‖ A α φ ‖ X 1 + ‖ ψ ‖ E 1 p + ‖ A α − 1 2 ψ ‖ X 1                                                             + ∫ 0 t ( ‖ g ( . , τ ) ‖ Y 1 s , p + ‖ g ( . , τ ) ‖ X 1 ) d τ ] , (2.14)</p><p>uniformly in t ∈ [ 0, T ] , where the constant C 0 &gt; 0 depends only on A, the space H and initial data.</p><p>Proof. By Lemma 2.1, the problem (2.1)-(2.2) has a solution u ( x , t ) ∈ C 2 ( [ 0, T ] ; Y s , p ( A ; H ) ) for φ ∈ E 0 p , ψ ∈ E 1 p and g ( ., t ) ∈ Y 1 s , p . Let N ∈ ℕ and</p><p>Π N = { ξ : ξ ∈ ℝ n , | ξ | ≤ N } , Π ′ N = { ξ : ξ ∈ ℝ n , | ξ | ≥ N } .</p><p>From (2.12) we deduced that</p><p>‖ A α u ‖ X ∞ ≲ ‖ F − 1 C ( ξ , t ) A α D 1 ( ξ ) D − 1 ( ξ ) ‖ L ∞ ( Π N )     + ‖ F − 1 S ( ξ , t ) A α D 2 ( ξ ) D − 1 ( ξ ) ‖ L ∞ ( Π N )     + ‖ F − 1 C ( ξ , t ) A α D 1 ( ξ ) D − 1 ( ξ ) ‖ L ∞ ( Π ′ N )     + ‖ F − 1 S ( ξ , t ) A α D 2 ( ξ ) D − 1 ( ξ ) ‖ L ∞ ( Π ′ N )     + 1 2 ‖ F − 1 A α Q ˜ ( ξ , t ) g ^ ( ξ , τ ) ‖ L ∞ ( Π N )     + 1 2 ‖ F − 1 A α Q ˜ ( ξ , t ) g ^ ( ξ , τ ) ‖ L ∞ ( Π ′ N ) . (2.15)</p><p>By virtue of Remakes 2.1, 2.2 and the properties of sectorial operators we get the following uniform estimate</p><p>‖ F − 1 A α Q ˜ ( ξ , t ) g ^ ( ξ , τ ) ‖ L ∞ ( Π N ) ≤ C ‖ g ‖ X 1 .</p><p>Hence, due to uniform boundedness of operator functions C ( ξ , t ) , S ( ξ , t ) , by (2.3), in view of (2.8)-(2.10) and by Minkowski’s inequality for integrals we get the uniform estimate</p><p>‖ F − 1 C ( ξ , t ) A α D 1 ( ξ ) D − 1 ( ξ ) ‖ L ∞ ( Π N ) + ‖ F − 1 S ( ξ , t ) A α D 2 ( ξ ) D − 1 ( ξ ) ‖ L ∞ ( Π N ) ≲ [ ‖ A α φ ‖ X 1 + ‖ A α ψ ‖ X 1 + ‖ g ‖ X 1 ] . (2.16)</p><p>Let</p><p>l = s ( 1 − 1 2 p ) − δ     for   a   δ &gt; 0.</p><p>Moreover, in a similar way, we deduced that</p><p>‖ F − 1 C ( ξ , t ) A α D 1 ( ξ ) D − 1 ( ξ ) ‖ L ∞ ( Π ′ N ) + ‖ F − 1 S ( ξ , t ) A α D 2 ( ξ ) D − 1 ( ξ ) ‖ L ∞ ≲ ‖ F − 1 C ( ξ , t ) A α D 1 ( ξ ) D − 1 ( ξ ) ‖ L ∞ + ‖ F − 1 S ( ξ , t ) A α D 2 ( ξ ) D − 1 ( ξ ) ‖ L ∞       + ‖ F − 1 S ( ξ , t ) A α Q ˜ ( ξ , t ) g ^ ( ξ , τ ) ‖ L ∞ ≲ ‖ F − 1 ( 1 + | ξ | 2 ) − l 2 C ( ξ , t ) ( 1 + | ξ | 2 ) l 2 A α φ ^ ( ξ ) ‖ L ∞       + ‖ F − 1 ( 1 + | ξ | 2 ) − l 2 S ( ξ , t ) ( 1 + | ξ | 2 ) l 2 A α ψ ^ ( ξ ) ‖ L ∞       + ‖ F − 1 ( 1 + | ξ | 2 ) − l 2 S ( ξ , t ) ( 1 + | ξ | 2 ) l 2 A α Q ˜ ( ξ , t ) g ^ ( ξ , τ ) ‖ L ∞ , (2.17)</p><p>here, the space L ∞ ( Ω ; H ) is denoted by L ∞ . Let</p><p>Φ 0 ( ξ ) = [ A 1 − 1 2 p − ε 0 + ( 1 + | ξ | 2 ) s ( 1 − 1 2 p ) − ε 0 ] − 1 , 0 &lt; ε 0 &lt; 1 − 1 2 p , (2.18)</p><p>Φ 1 ( ξ ) = [ A 1 2 − 1 2 p − ε + ( 1 + | ξ | 2 ) s ( 1 2 − 1 2 p ) − ε 1 ] − 1 , 0 &lt; ε 1 &lt; 1 2 − 1 2 p ,</p><p>Φ 01 ( ξ ) = 2 ξ k s ( 1 − 1 2 p − ε 0 ) [ ( 1 + | ξ | 2 ) s ( 1 − 1 2 p ) − ε 0 − 1 ]                           &#215; [ A 1 − 1 2 p − ε 0 + ( 1 + | ξ | 2 ) s ( 1 − 1 2 p ) − ε 0 ] − 2 ,</p><p>Φ 11 ( ξ ) = 2 ξ k s ( s ( 1 2 − 1 2 p ) − ε 1 ) [ ( 1 + | ξ | 2 ) s ( 1 2 − 1 2 p ) − ε 1 − 1 ]                           &#215; [ A 1 2 − 1 2 p − ε + ( 1 + | ξ | 2 ) s ( 1 2 − 1 2 p ) − ε 1 ] − 2 .</p><p>By using the resolvent properties of sectorial operators, we have</p><p>‖ A α Φ i ( ξ ) ‖ B ( E ) ≲ | ξ | − ε , 0 &lt; ε &lt; 1 2 − 1 2 p , i = 1 , 2 , (2.19)</p><p>‖ A α C ( ξ , t ) Φ 0 ( ξ ) ‖ B ( E ) ≤ C ‖ A α A − ( 1 − 1 2 p − ε 0 ) ( ξ ) ‖ B ( E ) ≤ C 0 ,</p><p>‖ A α S ( ξ , t ) Φ 1 ( ξ ) ‖ B ( E ) ≤ ‖ A 1 2 η − 1 ( ξ ) ‖ B ( E ) ‖ A α A − 1 2 Φ 1 ( ξ ) ‖ B ( E ) ≤ C ‖ A α A − ( 1 − 1 2 p − ε 0 ) ( ξ ) ‖ B ( E ) ≤ C 1 .</p><p>Then by calculating ∂ ∂ ξ k Φ 0 ( ξ ) , ∂ ∂ ξ k Φ 1 ( ξ ) , we obtain</p><p>A α ∂ ∂ ξ k Φ 0 ( ξ ) ∈ B ( H ) , A α ∂ ∂ ξ k Φ 1 ( ξ ) ∈ B ( H ) .</p><p>Let we show that G i ( ., t ) ∈ B q ,1 n ( 1 q + 1 p ) ( ℝ n ; H ) for some q ∈ ( 1,2 ) and for all t ∈ [ 0, T ] , where</p><p>G i ( ξ , t ) = ( 1 + | ξ | 2 ) − l 2 A C ( ξ , t ) Φ i ( ξ ) , i = 0 , 1.</p><p>By embedding properties of Sobolev and Besov spaces it is sufficient to derive that G i ∈ W q n ( 1 q + 1 p ) + ε ( ℝ n ) for some ε &gt; 0 . Indeed by contraction, by Condition 2.2 and by (2.18) we get G i ∈ L q ( ℝ n ) . Let σ &gt; n ( 1 r + 1 p ) . For deriving the embedding relations G i ∈ W q σ + ε ( ℝ n ) , it sufficient to show</p><p>( 1 + | ξ | 2 ) σ 2 G i ( ., t ) ∈ L σ ( ℝ n )     for   al   t ∈ [ 0, T ] .</p><p>Indeed, in view of (2.18), ( 1 + | ξ | 2 ) σ 2 Φ i ( ξ ) are uniformly bounded for ξ ∈ ℝ n . By virtue of (2.3), (2.19), by Condition 2.2 for l &lt; s ( 1 − 1 2 p ) and ( l − σ ) q &gt; n we have</p><p>∫ ℝ n ( 1 + | ξ | 2 ) σ 2 q | G i ( ξ , t ) | q d ξ = ∫ ℝ n ( 1 + | ξ | 2 ) − l − σ 2 q ‖ C ( ξ , t ) ‖ q ‖ A α Φ i ( ξ ) ‖ B ( E ) q d ξ ≲ ∫ ℝ n ( 1 + | ξ | 2 ) σ − l + ε 2 q | ξ | − ε q d ξ ≲ ∫ ℝ n ( 1 + | ξ | 2 ) − ( l − σ 2 ) q d ξ &lt; ∞ .</p><p>Hence, by Fourier multiplier theorems (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref32">32</xref>], Theorem 4.3) we get that the functions G i ( ξ , t ) are Fourier multipliers from L p ( ℝ n ; H ) to L ∞ ( ℝ n ; H ) . In a similar way we obtain that</p><p>( 1 + | ξ | 2 ) − s 2 S ( ξ , t ) ( 1 + | ξ | 2 ) s 2 A α ψ ^ ( ξ ) ,</p><p>( 1 + | ξ | 2 ) − s 2 S ( ξ , t ) ( 1 + | ξ | 2 ) s 2 A α Q ˜ ( ξ , t ) g ^ ( ξ , τ )</p><p>are L p ( ℝ n ; H ) → L ∞ ( ℝ n ; H ) Fourier multipliers. Then by Minkowski’s inequality for integrals, from (2.3), (2.16)-(2.18) and by Remake 2.3 we have</p><p>‖ F − 1 C ( ξ , t ) A α φ ^ ( ξ ) ‖ L ∞ + ‖ F − 1 S ( ξ , t ) A α ψ ^ ( ξ ) ‖ L ∞ ≲ ‖ F − 1 C ( ξ , t ) η − 2 φ ^ ‖ L ∞ + ‖ F − 1 S ( ξ , t ) η − 1 ψ ^ ‖ L ∞ ≲ [ ‖ φ ‖ E 0 p + ‖ ψ ‖ E 1 p + ‖ g ‖ W s , p ] . (2.20)</p><p>Moreover, by virtue of Remakes 2.1 - 2.3 and by reasoning as the above, we have the following estimate</p><p>‖ F − 1 A α Q ˜ ( ξ , t ) ‖ X ∞ ≤ C 0 t ( ‖ g ( . , τ ) ‖ W s , p + ‖ g ( . , τ ) ‖ X 1 ) d τ (2.21)</p><p>uniformly in t ∈ [ 0, T ] . Thus, from (2.12), (2.20) and (2.21) we obtain</p><p>‖ A α u ‖ X ∞ ≤ C [ ‖ φ ‖ E 0 p + ‖ A α φ ‖ X 1 + ‖ ψ ‖ E 1 p + ‖ A α ψ ‖ X 1                                     + ∫ 0 t ( ‖ g ( . , τ ) ‖ Y s , p + ‖ g ( . , τ ) ‖ X 1 ) d τ ] . (2.22)</p><p>By differentiating (2.12) in a similar way, we get</p><p>‖ A α u t ‖ X ∞ ≤ C [ ‖ φ ‖ E 0 p + ‖ A α φ ‖ X 1 + ‖ A α ψ ‖ E 1 p + ‖ A α ψ ‖ X 1                                     + ∫ 0 t ( ‖ g ( . , τ ) ‖ Y s , p + ‖ g ( . , τ ) ‖ X 1 ) d τ ] . (2.23)</p><p>Then from (2.22) and (2.23) in view of Remarks 2.1, 2.2 we obtain the estimate (2.14).</p><p>Let now show that problem (2.1) has a unique solution u ∈ C ( 1 ) ( [ 0, T ] ; Y s , p ) . Let’s admit it is the opposite. So let’s assume that the problem (2.1) has two solutions u 1 , u 2 ∈ C ( 1 ) ( [ 0, T ] ; Y s , p ) . Then by linearity of (2.1), we get that υ = u 1 − u 2 is also a solution of the corresponding homogenous equation</p><p>u t t − a Δ u + A u = 0 , υ ( x , 0 ) = 0 , υ t ( x , 0 ) = 0 , x ∈ ℝ n , t ∈ ( 0 , T ) .</p><p>Moreover, by (2.7) we have the following estimate</p><p>‖ A α υ ‖ X ∞ ≤ 0.</p><p>Since N ( A ) = { 0 } , the above estimate implies that υ = 0 , i.e. u 1 = u 2 .</p><p>Theorem 2.2. Assume the Condition 2.1 and (2.13) is satisfied. Let 0 ≤ α &lt; 1 − 1 2 p . Then for φ ∈ E 0 p , ψ ∈ E 1 p , g ( ., t ) ∈ Y s , p for t ∈ [ 0, T ] and g ( x ,. ) ∈ L 1 ( 0, T ; Y s , p ) for x ∈ ℝ n problem (2.1)-(2.2) has a unique solution u ∈ C 2 ( [ 0, T ] ; Y s , p ) and the following estimate holds</p><p>( ‖ A α u ‖ Y s , p + ‖ A α u t ‖ Y s , p ) ≤ C 0 [ ‖ φ ‖ E 0 p + ‖ ψ ‖ E 1 p + ∫ 0 t ‖ g ( ., τ ) ‖ Y s , p d τ ] (2.24)</p><p>for all t ∈ [ 0, T ] .</p><p>Proof. From (2.11) and (2.17) we get the following uniform estimate</p><p>( ‖ F − 1 ( 1 + | ξ | 2 ) s 2 A α u ^ ‖ X p + ‖ F − 1 ( 1 + | ξ | 2 ) s 2 A α u ^ t ‖ X p ) ≤ C { ‖ F − 1 ( 1 + | ξ | 2 ) s 2 C ( ξ , t ) A α φ ^ ‖ X p + ‖ F − 1 ( 1 + | ξ | 2 ) s 2 A α S ( ξ , t ) ψ ^ ‖ X p         + ∫ 0 t ‖ ( 1 + | ξ | 2 ) s 2 A α Q ˜ ( ξ , t ) g ^ ( ξ , τ ) ‖ X p d τ } . (2.25)</p><p>By using the Fourier multiplier theorem ( [<xref ref-type="bibr" rid="scirp.116658-ref32">32</xref>], Theorem 4.3) and by reasoning as in Theorem 2.1 we get that ( 1 + | ξ | 2 ) − s 2 C ( ξ , t ) , ( 1 + | ξ | 2 ) − s 2 S ( ξ , t ) and ( 1 + | ξ | 2 ) − s 2 A α S ( ξ , t ) are Fourier multipliers in L p ( ℝ n ; H ) uniformly with respect to t ∈ [ 0, T ] . So, the estimate (2.25) by using the Minkowski’s inequality for integrals implies (2.24).</p><p>The uniquness of (2.1)-(2.2) is obtained by reasoning as in Theorem 2.1.</p></sec><sec id="s3"><title>3. Local Well Posedness of IVP for Nonlinear WE</title><p>In this section, we will show the local existence and uniqueness of solution of the nonlinear problem (1.1)-(1.2).</p><p>For this aim we need the following lemmas. By reasoning as in [<xref ref-type="bibr" rid="scirp.116658-ref7">7</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref18">18</xref>] [<xref ref-type="bibr" rid="scirp.116658-ref35">35</xref>], we show the following lemmas concerning the behaviour of the nonlinear term in E-valued space Y s , p . Here, let E be a Banach algebra.</p><p>Lemma 3.1. Let s ≥ 0 , f ∈ C [ s ] + 1 ( ℝ ; E ) with f ( 0 ) = 0 . Then for any u ∈ Y s , p ∩ L ∞ , we have f ( u ) ∈ Y s , p ∩ X ∞ . Moreover, there is some constant A ( M ) depending on M such that for all u ∈ Y s , p ∩ L ∞ with ‖ u ‖ X ∞ ≤ M ,</p><p>‖ f ( u ) ‖ Y s , p ≤ C ( M ) ‖ u ‖ Y s , p . (3.1)</p><p>Proof. For s = 0 in view of f ( 0 ) = 0 , we get</p><p>f ( u ) = ∫ 0 1 f ( 1 ) ( σ u ) d σ .</p><p>It follows that</p><p>‖ f ( u ) ‖ X p ≤ C ( M ) ‖ u ‖ X p .</p><p>If s is a positive integer, we have</p><p>‖ f ( u ) ‖ Y s , p ≤ C [ ‖ f ( u ) ‖ X p + ∑ k = 1 n ‖ ∂ s ∂ x k f ( u ) ‖ X p ] . (3.2)</p><p>By calculation of derivative and applying Holder inequality, we get</p><p>‖ ∂ s ∂ x i f ( u ) ‖ X p ≤ ∑ l = 1 s ∑ α ‖ f ( l ) ( u ) ∂ β 1 u ∂ x i ∂ β 2 u ∂ x i ⋯ ∂ β l u ∂ x i ‖ X p ≤ ∑ l = 1 s ∑ α ‖ f ( l ) ( u ) ‖ X ∞ ∏ k = 1 l ‖ ∂ β k u ∂ x i ‖ X p k , i = 1 , 2 , ⋯ , n , (3.3)</p><p>where</p><p>β = ( β 1 , β 2 , ⋯ , β l ) , β k ≥ 1 , β 1 + β 2 + ⋯ + β l = l , p k = p l β k .</p><p>Applying Gagliardo-Nirenberg’s inequality in E-valued X p spaces, we have</p><p>‖ ∂ β k u ∂ x i ‖ X p k ≤ C ‖ u ‖ X ∞ 1 − β k l ‖ ∂ s u ∂ x i s ‖ X p β k l . (3.4)</p><p>Hence, from (3.3) and (3.4) we get</p><p>‖ ∂ s ∂ x i f ( u ) ‖ X p ≤ C ( M ) ‖ ∂ s u ∂ x i s ‖ X p . (3.5)</p><p>Then combining (3.2), (3.3) and (3.5) we obtain (3.1).</p><p>Let s is not integer number and m = [ s ] . From the above proof, we have</p><p>‖ f ( u ) ‖ Y m , p ≤ C ( M ) ‖ u ‖ Y m , p , ‖ f ( u ) ‖ Y m + 1 , p ≤ C ( M ) ‖ u ‖ Y m + 1 , p .</p><p>Then using interpolation between W m + 1, p and W m , p yields (3.1) for all s ≥ 0 .</p><p>By using Lemma 3.1 and properties of convolution operators we obtain.</p><p>Corollary 3.1. Let s ≥ 0 , f ∈ C [ s ] + 1 ( ℝ ; H ) with f ( 0 ) = 0 . Moreover, assume Φ ∈ L ∞ ( ℝ n ; B ( H ) ) . Then for any u ∈ Y s , p ∩ L ∞ we have, f ( u ) ∈ Y s , p ∩ X ∞ . Moreover, there is some constant A ( M ) depending on M such that for all u ∈ Y s , p ∩ L ∞ with ‖ u ‖ X ∞ ≤ M ,</p><p>‖ Φ ∗ f ( u ) ‖ Y s , p ≤ C ( M ) ‖ u ‖ Y s , p .</p><p>Lemma 3.2. Let s ≥ 0 , f ∈ C [ s ] + 1 ( ℝ ; H ) . Then for any M there is some constant K ( M ) depending on M such that for all u, υ ∈ Y s , p ∩ X ∞ with ‖ u ‖ X ∞ ≤ M , ‖ υ ‖ X ∞ ≤ M , ‖ u ‖ Y s , p ≤ M , ‖ υ ‖ Y s , p ≤ M ,</p><p>‖ f ( u ) − f ( υ ) ‖ Y s , p ≤ K ( M ) ‖ u − υ ‖ Y s , p , ‖ f ( u ) − f ( υ ) ‖ X ∞ ≤ K ( M ) ‖ u − υ ‖ X ∞ .</p><p>Corollary 3.2. Let s &gt; n 2 , f ∈ C [ s ] + 1 ( ℝ ; H ) . Then for any positive M there is a constant K ( M ) depending on M such that for all u , υ ∈ Y s , p with ‖ u ‖ Y s , p ≤ M , ‖ υ ‖ Y s , p ≤ M ,</p><p>‖ f ( u ) − f ( υ ) ‖ Y s , p ≤ K ( M ) ‖ u − υ ‖ Y s , p .</p><p>Lemma 3.3. If s &gt; 0 , then Y ∞ s , p is an algebra. Moreover, for f , g ∈ Y ∞ s , p ,</p><p>‖ f g ‖ Y s , p ≤ C [ ‖ f ‖ X ∞ + ‖ g ‖ Y s , p + ‖ f ‖ Y s , p + ‖ g ‖ X ∞ ] .</p><p>By using, the Corollary 3.1 and Lemma 3.3 we obtain.</p><p>Lemma 3.4. Let s ≥ 0 , f ∈ C [ s ] + 1 ( ℝ ; H ) and f ( u ) = O ( | u | γ + 1 ) for u → 0 , γ ≥ 1 be a positive integer. If u ∈ Y ∞ s , p and ‖ u ‖ X ∞ ≤ M , then</p><p>‖ f ( u ) ‖ Y s , p ≤ C ( M ) [ ‖ u ‖ Y s , p ‖ u ‖ X ∞ γ ] ,</p><p>‖ f ( u ) ‖ X 1 ≤ C ( M ) ‖ u ‖ X p p ‖ u ‖ X ∞ γ − 1 .</p><p>Corollary 3.3. Let s ≥ 0 , f ∈ C [ s ] + 1 ( ℝ ; H ) and f ( u ) = O ( | u | γ + 1 ) for u → 0 , γ ≥ 1 be a positive integer. Moreover, assume Φ ∈ L ∞ ( ℝ n ; B ( E ) ) . If u ∈ Y ∞ s , p and ‖ u ‖ X ∞ ≤ M , then</p><p>‖ Φ ∗ f ( u ) ‖ Y s , p ≤ C ( M ) [ ‖ u ‖ Y s , p ‖ u ‖ X ∞ γ ] ,</p><p>‖ Φ ∗ f ( u ) ‖ X 1 ≤ C ( M ) ‖ u ‖ X p p ‖ u ‖ X ∞ γ − 1 .</p><p>Lemma 3.5. Let s ≥ 0 , f ∈ C [ s ] + 1 ( ℝ ; H ) and f ( u ) = O ( | u | γ + 1 ) for u → 0 . Moreover, let γ ≥ 0 be a positive integer. If u , υ ∈ Y ∞ s , p , ‖ u ‖ Y s , p ≤ M , ‖ υ ‖ Y s , p ≤ M and ‖ u ‖ X ∞ ≤ M , ‖ υ ‖ X ∞ ≤ M , then</p><p>‖ f ( u ) − f ( υ ) ‖ Y s , p ≤ C ( M ) [ ( ‖ u ‖ X ∞ − ‖ υ ‖ X ∞ ) ( ‖ u ‖ Y s , p + ‖ υ ‖ Y s , p ) ( ‖ u ‖ X ∞ + ‖ υ ‖ X ∞ ) γ − 1 ,</p><p>‖ f ( u ) − f ( υ ) ‖ X 1 ≤ C ( M ) ( ‖ u ‖ X ∞ + ‖ υ ‖ X ∞ ) γ − 1 ( ‖ u ‖ X p + ‖ υ ‖ X p ) ‖ u − υ ‖ X p .</p><p>Let E 0 denotes the real interpolation space between Y s , p ( A , H ) and X p with θ = 1 2 p , i.e.</p><p>E 0 p = ( Y s , p ( A , H ) , X p ) 1 2 p , p .</p><p>Remark 3.1. By using J. Lions-J. Peetre result (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 1.8) we obtain that the map u → u ( t 0 ) , t 0 ∈ [ 0, T ] is continuous and surjective from Y 2, s , p ( A , H ) onto E 0 p and there is a constant C 1 such that</p><p>‖ u ( t 0 ) ‖ E 0 p ≤ C 1 ‖ u ‖ Y 2 , s , p ( A , E ) , 1 ≤ p ≤ ∞ . (3.6)</p><p>Let</p><p>C 2 ( Y 1 s , p ( A ) ) = C ( 2 ) ( [ 0 , T ] ; Y 1 s , p ( A , H ) ) , C 2 , s ( A , H ) = C ( 2 ) ( [ 0 , T ] ; Y s , p ( A , H ) ) .</p><p>Condition 3.1. Assume:</p><p>1) the Condition 2.1 holds for s &gt; 2 p n 2 p − 1 ( 2 q + 1 p ) , p ∈ [ 1, ∞ ] , for a q ∈ [ 1,2 ] and 0 ≤ α &lt; 1 − 1 2 p ;</p><p>2) the function u → f ( u ) : continuous from u ∈ E 0 p into H, f ∈ C k ( ℝ ; H ) with k an integer, k ≥ s &gt; n p and f ( u ) = O ( | u | γ + 1 ) for u → 0 , γ ≥ 1 be a positive integer.</p><p>Let</p><p>Y 1 s , p ( A α ; H ) = Y s , p ( A α ; H ) ∩ X 1 ( A α ) , Y s , p ( A α ; H ) = { u ∈ Y s , p ( A α ; H ) ,</p><p>‖ u ‖ Y s , p ( A α ; E ) = ‖ A α u ‖ X p + ‖ F − 1 ( 1 + | ξ | 2 ) s 2 u ^ ‖ X p &lt; ∞ } .</p><p>Main aim of this section is to prove the following results:</p><p>Theorem 3.1. Let the Condition 3.1 holds. Then there exists a constant δ &gt; 0 such that for any φ ∈ Y 0 ( A α ) and ψ ∈ Y 1 ( A α ) satisfying</p><p>‖ φ ‖ E 0 p + ‖ A α φ ‖ X 1 + ‖ ψ ‖ E 1 p + ‖ A α ψ ‖ X 1 ≤ δ , (3.7)</p><p>problem (1.1)-(1.2) has a unique local strange solution u ∈ C 2 ( Y 1 s , p ( A ) ) . Moreover,</p><p>sup t ∈ [ 0 , T ] ( ‖ u ( . , t ) ‖ Y ^ 1 s , p ( A α , H ) + ‖ u t ( . , t ) ‖ Y ^ 1 s , p ( A α ; H ) ) ≤ C δ , (3.8)</p><p>where the constant C depends only on A, E, g, f and initial values.</p><p>Proof. By (2.5), (2.6) the problem of finding a solution u of (1.1)-(1.2) is equivalent to finding a fixed point of the mapping</p><p>G ( u ) = C 1 ( t ) φ ( x ) + S 1 ( t ) ψ ( x ) + Q ( u ) , (3.9)</p><p>where C 1 ( t ) , S 1 ( t ) are defined by (2.6) and Q ( u ) is a map defined by</p><p>Q ( u ) = − ∫ 0 t F − 1 [ U ( ξ , t − τ ) f ^ ( u ) ( ξ , τ ) ] d τ .</p><p>We define the metric space</p><p>C ( T , A ) = C δ 2 ( Y 1 s , p ( A ) ) = { u ∈ C 2 , s ( A , E ) , ‖ u ‖ C 2 , s , p ( T , A ) ≤ 5 C 0 δ }</p><p>equipped with the norm defined by</p><p>‖ u ‖ C ( T , A ) = sup t ∈ [ 0 , T ] [ ‖ A α u ( . , t ) ‖ X ∞ + ‖ u ( . , t ) ‖ Y s , p + ‖ A α u t ( . , t ) ‖ X ∞ + ‖ u t ( . , t ) ‖ Y s , p ] ,</p><p>where δ &gt; 0 satisfies (3.7) and C 0 is a constant in Theorem 2.1 and 2.2. It is easy to prove that C ( T , A ) is a complete metric space. From imbedding in Sobolev-Lions space Y s , p ( A , E ) (see e.g. [<xref ref-type="bibr" rid="scirp.116658-ref27">27</xref>], Theorem 1) and trace result (3.6) we got that ‖ u ‖ X ∞ ≤ 1 if we take that δ is enough small. For φ ∈ Y 0 ( A α ) and ψ ∈ Y 1 ( A α ) , let</p><p>‖ φ ‖ E 0 p + ‖ A α φ ‖ X 1 + ‖ ψ ‖ E 1 p + ‖ A α ψ ‖ X 1 = δ .</p><p>So, we will find T and M so that G is a contraction in C 2, s , p ( T , A ) . By Theorems 2.1, 2.2 and Corollary 3.3 f ( u ) ∈ Y 1 s , p . So, problem (1.1)-(1.2) has a solution that satisfies the following</p><p>G ( u ) ( x , t ) = C 1 ( t ) φ + S 1 ( t ) ψ + Q ( u ) , (3.10)</p><p>where C 1 ( t ) , S 1 ( t ) are defined by (2.5) and (2.6). By assumptions, it is easy to see that the map G is well defined for f ∈ C [ s ] + 1 ( E 0 p ; H ) . First, let us prove that the map G has a unique fixed point in C ( T , A ) . For this aim, it is sufficient to show that the operator G maps C ( T , A ) into C ( T , A ) and G is strictly contractive if δ is suitable small. In fact, by (2.7) in Theorem 2.1, Corollary 3.3 and in view of (3.7), we have</p><p>‖ A α G ( u ) ‖ X ∞ + ‖ A α G t ( u ) ‖ X ∞ ≤ 2 C 0 [ ‖ φ ‖ Y 0 α ( A α ) + ‖ ψ ‖ Y 1 α ( A α ) + ∫ 0 t ( ‖ f ^ ( ( u ) ) ‖ Y s , p + ‖ f ^ ( ( u ) ) ‖ X 1 ) d τ ] ≤ 2 C 0 δ + C ∫ 0 t ( ‖ u ( τ ) ‖ Y s , p ‖ u ( τ ) ‖ X ∞ γ + ‖ u ( τ ) ‖ X p p ‖ u ( τ ) ‖ X ∞ γ − 1 ) d τ ≤ 2 C 0 δ + C ‖ u ‖ C 2 , s , p ( T , A ) γ + 1 . (3.11)</p><p>On the other hand, by (2.17), Corollary 3.3 and (3.7), we get</p><p>( ‖ A α G ( u ) ‖ Y s , p + ‖ A α G t ( u ) ‖ Y s , p ) ≤ 2 C 0 ( ‖ φ ‖ E 0 p + ‖ ψ ‖ E 1 p + ∫ 0 t ‖ f ^ ( ( u ) ) ‖ Y s , p d τ ) ≤ 2 C 0 δ + ∫ 0 t [ ‖ u ( τ ) ‖ Y s , p ‖ u ( τ ) ‖ X ∞ γ ] d τ ≤ 2 C 0 δ + C ‖ u ‖ C 2 , s , p ( T , A ) γ + 1 . (3.12)</p><p>Hence, combining (3.11) with (3.12) we obtain</p><p>‖ A α G ( u ) ‖ Y ∞ s , p + ‖ A α G t ( u ) ‖ Y ∞ s , p ≤ 4 C 0 δ + C ‖ u ‖ C 2 , s , p ( T , A ) γ + 1 . (3.13)</p><p>So, taking that δ is enough small such that C ( 5 C 8 δ ) γ &lt; 1 5 , by Theorems 2.1, 2.2 and (3.13), G maps C ( T , A ) into C ( T , A ) .</p><p>Now, we are going to prove that the map G is strictly contractive. Let u 1 , u 2 ∈ C ( T , A ) given. From (3.10) we get</p><p>G ( u 1 ) − G ( u 2 ) = ∫ 0 T [ S ( x , t − τ ) ( f ^ ( u 1 ) ( τ ) − f ^ ( u 2 ) ( τ ) ) ] d τ , t ∈ ( 0 , T ) .</p><p>By (2.7) in Theorem 2.1 and Corollary 3.3, we have</p><p>‖ A α [ G ( u 1 ) − G ( u 2 ) ] ‖ X ∞ + ‖ A α [ G ( u 1 ) − G ( u 2 ) ] t ‖ X ∞ ≤ ∫ 0 t ( ‖ [ f ^ ( u 1 ) − f ^ ( u 2 ) ] ‖ Y s , p + ‖ [ f ^ ( u 1 ) − f ^ ( u 2 ) ] ‖ X 1 ) d τ ≤ ∫ 0 t { ‖ u 1 − u 2 ‖ X ∞ ( ‖ u 1 ‖ Y s , p + ‖ u 2 ‖ Y s , p ) ( ‖ u 1 ‖ X ∞ + ‖ u 2 ‖ X ∞ ) γ − 1     + ‖ u 1 − u 2 ‖ Y s , p ( ‖ u 1 ‖ X ∞ + ‖ u 2 ‖ X ∞ ) γ     + ( ‖ u 1 ‖ X ∞ + ‖ u 2 ‖ X ∞ ) γ − 1 ‖ u 1 + u 2 ‖ X p ‖ u 1 − u 2 ‖ X p } ≤ C ( ‖ u 1 ‖ C ( T , A ) + ‖ u 2 ‖ C ( T , A ) ) γ ‖ u 1 − u 2 ‖ C ( T , A ) . (3.14)</p><p>On the other hand, by (2.17) in Theorem 2.2, Corollary 3.3 and (3.7), we get</p><p>( ‖ A α [ G ( u 1 ) − G ( u 2 ) ] ‖ Y s , p + ‖ A α [ G ( u 1 ) − G ( u 2 ) ] t ‖ Y s , p ) ≤ C ∫ 0 t ‖ f ^ ( u 1 ) ( τ ) − f ^ ( u 2 ) ( τ ) ‖ Y s , p d τ ≤ C ∫ 0 t { ‖ u 1 − u 2 ‖ X ∞ ( ‖ u 1 ‖ Y s , p + ‖ u 2 ‖ Y s , p ) ( ‖ u 1 ‖ X ∞ + ‖ u 2 ‖ X ∞ ) γ − 1       + ‖ u 1 − u 2 ‖ Y s , p ( ‖ u 1 ‖ X ∞ + ‖ u 2 ‖ X ∞ ) γ } d τ ≤ C ( ‖ u 1 ‖ C ( T , A ) + ‖ u 2 ‖ C ( T , A ) ) γ ‖ u 1 − u 2 ‖ C ( T , A ) . (3.15)</p><p>Combining (3.14) with (3.15) yields</p><p>‖ G ( u 1 ) − G ( u 2 ) ‖ C ( T , A ) ≤ C ( ‖ u 1 ‖ C ( T , A ) + ‖ u 2 ‖ C ( T , A ) ) γ ‖ u 1 − u 2 ‖ C ( T , A ) . (3.16)</p><p>Taking δ is enough small, from (3.16) we obtain that G is strictly contractive in C ( T , A ) . Using the contraction mapping principle, we get that G ( u ) has a unique fixed point u ( x , t ) ∈ C ( T , A ) and u ( x , t ) is the solution of (1.1)-(1.2).</p><p>Let us show that this solution is a unique in C 2, s ( A , H ) . Let u 1 , u 2 ∈ C 2, s ( A , H ) are two solutions of (1.1)-(1.2). Then for u = u 1 − u 2 , we have</p><p>u t t − a Δ u + A u = [ f ( u 1 ) − f ( u 2 ) ] . (3.17)</p><p>Hence, by Minkowski’s inequality for integrals and by Theorem 2.2 from (3.17) we obtain</p><p>‖ u 1 − u 2 ‖ Y s , p ≤ C 2 ( T ) ∫ 0 t ‖ u 1 − u 2 ‖ Y s , p d τ . (3.18)</p><p>From (3.18) and Gronwall’s inequality, we have ‖ u 1 − u 2 ‖ Y s , p = 0 , i.e. problem (1.1)-(1.2) has a unique solution in C 2, s ( A , H ) .</p><p>Consider the problem (1.1)-(1.2), when φ ∈ E 0 p and ψ ∈ E 1 p . Let</p><p>C ( i ) ( Y s , 2 ) = C ( i ) ( [ 0 , ∞ ) ; Y s , 2 ( A , H ) ) , i = 0 , 1 , 2.</p></sec><sec id="s4"><title>4. Application</title><p>Consider the problem (1.4). Let</p><p>X p , 2 = L p ( ℝ n ; L 2 ( 0 , 1 ) ) , Y s , p , 2 = H s , p ( ℝ n ; L 2 ( 0 , 1 ) ) ,</p><p>Y q s , p , 2 = H s , p ( ℝ n ; L 2 ( 0 , 1 ) ) ∩ L q ( ℝ n ; L 2 ( 0 , 1 ) ) ,</p><p>Y s , p , 2 = H s , p ( ℝ n ; H 2 , 2 ( 0 , 1 ) , L 2 ( 0 , 1 ) ) , 1 ≤ p , q ≤ ∞ ,</p><p>E 0 p , 2 = ( Y s , p ( A , L 2 ( 0 , 1 ) ) ∩ X p .2 , X p , 2 ) 1 2 p , p ,</p><p>E 1 p , 2 = ( Y s , p ( A , L 2 ( 0 , 1 ) ) ∩ X p , p 1 , X p , 2 ) 1 + p 2 p , p .</p><p>Let ω 1 = ω 1 ( y ) , ω 2 = ω 2 ( y ) be roots of equation b 1 ( y ) ω 2 + 1 = 0 . Let</p><p>ν ( y ) = | ( − ω 1 ) m 1 α 1 β 1 ω 1 m 1 ( − ω 2 ) m 2 α 2 β 2 ω 2 m 2 | , η 1 ( ξ ) = [ a | ξ | 2 + A 1 ] 1 2 .</p><p>Here,</p><p>E i p ( L 2 ( 0 , 1 ) ) = W s ( 1 − θ i ) , p ( ℝ n ; L 2 ( 0 , 1 ) ) ∩ L p ( ℝ n ; H 2 ( 1 − θ i ) , 2 ( 0 , 1 ) ) ,</p><p>θ i = 1 + i p 2 p , i = 0 , 1 , p 1 ∈ ( 1 , ∞ ) .</p><p>From Theorem 3.1 we obtain the following result.</p><p>Theorem 4.1. Suppose the following conditions are satisfied:</p><p>1) a ∈ S ϕ 1 for 0 ≤ ϕ 1 &lt; π , 0 ≤ α &lt; 1 − 1 2 p , p ∈ [ 1, ∞ ] and ν ( y ) ≠ 0 for all y ∈ [ 0,1 ] ;</p><p>2) b 1 ∈ V M O ∩ L ∞ ( 0,1 ) , R e ω k ≠ 0 and λ ω k ∈ S ( ϕ 1 ) for a.e. x ∈ ( 0,1 ) , ϕ 1 ∈ [ 0 , π ) ; b 0 ∈ V M O ∩ L ∞ ( 0,1 ) , b 1 ( 0 ) = b 1 ( 1 ) , b 0 ( 0 ) = b 0 ( 1 ) .</p><p>3) φ ∈ Y 1 s , p ,2 , ψ ∈ Y 1 s − 1, p ,2 and f ( ., t ) ∈ Y 1 s , p ,2 for s &gt; 2 p n 2 p − 1 ( 2 r + 1 p ) for p ∈ [ 1, ∞ ] , r ∈ [ 1,2 ] and t ∈ [ 0, T ] .</p><p>4) The function u → F ( u ) is continuous in u ∈ E 02 for x , t ∈ ℝ n &#215; [ 0, T ] ; moreover F ( u ) ∈ C ( 1 ) ( E 02 ; L 2 ( 0,1 ) ) .</p><p>Then problem (1.9)-(1.10) has a unique local strange solution</p><p>u ∈ C ( 2 ) ( [ 0 , T 0 ) ; Y ∞ s , p ,2 ) ,</p><p>where T 0 is a maximal time interval that is appropriately small relative to M. Moreover, if</p><p>‖ φ ‖ E 0 p , p 1 + ‖ A α φ ‖ X 1 + ‖ ψ ‖ E 1 p , p 1 + ‖ A α ψ ‖ X 1 ≤ δ ,</p><p>then T 0 = ∞ .</p><p>Proof. By virtue of [<xref ref-type="bibr" rid="scirp.116658-ref30">30</xref>], L 2 ( 0,1 ) is a Fourier type space. By virtue of [<xref ref-type="bibr" rid="scirp.116658-ref30">30</xref>], the operator A 1 defined by (1.3) is sectorial in L 2 ( 0,1 ) . Moreover, by interpolation of Banach spaces ( [<xref ref-type="bibr" rid="scirp.116658-ref33">33</xref>], Section 1.3), we have</p><p>E 02 = ( W s , p ( ℝ n ; H 2 ( 0 , 1 ) , L 2 ( 0 , 1 ) ) , L p ( ℝ n ; L 2 ( 0 , 1 ) ) ) 1 2 p , p = B p , 2 s ( 1 − 1 2 p ) ( ℝ n ; H 2 l ( 1 − 1 2 p ) ( 0 , 1 ) , L 2 ( 0 , 1 ) ) .</p><p>Then, by using the properties of spaces Y s , p ,2 , Y ∞ s , p ,2 , E 02 we get that all conditions of Theorem 3.1 are hold, i.e., we obtain the conclusion.</p></sec><sec id="s5"><title>5. Conclusion</title><p>Here, assuming enough smoothness on the initial data in terms of interpolation spaces H ( A ) , H and the sectorial operators, the existence, uniqueness, regularity properties of solutions are established. By choosing the space H and A, the regularity properties of solutions of a wide class of wave equations in the field of physics are obtained.</p></sec><sec id="s6"><title>Data Availability</title><p>Data sharing is not applicable to this article as no datasets were generated or analysed during the current study.</p></sec><sec id="s7"><title>Conflicts of Interest</title><p>The authors declare no conflicts of interest regarding the publication of this paper.</p></sec><sec id="s8"><title>Cite this paper</title><p>Shakhmurov, V.B. and Shahmurov, R. (2022) The Quality Properties of Integral Type Problems for Wave Equations and Applications. Journal of Applied Mathematics and Physics, 10, 1217-1239. https://doi.org/10.4236/jamp.2022.104086</p></sec></body><back><ref-list><title>References</title><ref id="scirp.116658-ref1"><label>1</label><mixed-citation publication-type="other" xlink:type="simple">Linares, F. (1993) Global Existence of Small Solutions for a Generalized Boussinesq Equation. 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