<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">JAMP</journal-id><journal-title-group><journal-title>Journal of Applied Mathematics and Physics</journal-title></journal-title-group><issn pub-type="epub">2327-4352</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/jamp.2021.91014</article-id><article-id pub-id-type="publisher-id">JAMP-106918</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  Ces&#224;ro Bounded Weighted Backward Shift
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Hui</surname><given-names>Gao</given-names></name><xref ref-type="aff" rid="aff1"><sub>1</sub></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib></contrib-group><aff id="aff1"><label>1</label><addr-line>Hebei University of Technology, Tianjin, China</addr-line></aff><pub-date pub-type="epub"><day>29</day><month>12</month><year>2020</year></pub-date><volume>09</volume><issue>01</issue><fpage>197</fpage><lpage>209</lpage><history><date date-type="received"><day>20,</day>	<month>December</month>	<year>2020</year></date><date date-type="rev-recd"><day>26,</day>	<month>January</month>	<year>2021</year>	</date><date date-type="accepted"><day>29,</day>	<month>January</month>	<year>2021</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p><html>
 <head></head>
 
  In this paper, we give a criterion of the absolutely Ces&#224;ro bounded weighted backward shift in spirit of the comparison method. Our approach is to construct the proper product of weight functions 
  <img src="Edit_7232e0dc-07ab-41c5-8657-a49f0463b47c.bmp" alt="" />by the fraction of two monomials of the indexes, then we apply proper scaling to give Ces&#224;ro boundedness. In particular, we present a new example of non Ces&#224;ro bounded weighted backward shift on 
  <img src="Edit_799dadb7-40ab-48f9-bae3-191378f96164.bmp" alt="" />.
 
</html></p></abstract><kwd-group><kwd>Ces&#224;ro Boundedness</kwd><kwd> Absolutely Ces&#224;ro Boundedness</kwd><kwd> Backward Weighted Shift</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>Let X be a complex Banach space and B ( X ) be the Banach algebra of all linear bounded operators on X. Given T ∈ B ( X ) , the Ces&#224;ro mean of T is the family of operators { M T ( n ) } n ∈ ℕ ⊂ B ( X ) which is defined by</p><p>M T ( n ) x : = 1 n + 1 ∑ j = 0 n     T j x</p><p>for x ∈ X . The operator T ∈ B ( X ) is called Ces&#224;ro bounded if { M T ( n ) } n ∈ ℕ is bounded in B ( X ) . That is sup n ‖ M T ( n ) ‖ &lt; ∞ . The operator T ∈ B ( X ) is called absolutely Ces&#224;ro bounded if there is C &gt; 0 such that</p><p>sup n ∈ ℕ 1 n + 1 ∑ j = 0 n ‖ T j x ‖ ≤ C ‖ x ‖ ,   ∀ x ∈ X .</p><p>It is clear that absolutely Ces&#224;ro bounded operators are Ces&#224;ro bounded. The concept of Ces&#224;ro boundness is highly connected with the dynamic of linear operators. It was firstly introduced by Hou and Luo in [<xref ref-type="bibr" rid="scirp.106918-ref1">1</xref>]. In their articles, they investigated that the unilateral weighted backward shift with weights</p><p>w k : = 2 k 2 k − 1 , ( k ∈ ℕ ) is absolutely Ces&#224;ro bounded. Then it attracts lots of attentions by several mathematicians. Interested readers can refer [<xref ref-type="bibr" rid="scirp.106918-ref2">2</xref>] for the theory of linear chaos and [<xref ref-type="bibr" rid="scirp.106918-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.106918-ref3">3</xref>] [<xref ref-type="bibr" rid="scirp.106918-ref4">4</xref>] for some results of Ces&#224;ro boundedness. It was proved in [<xref ref-type="bibr" rid="scirp.106918-ref5">5</xref>] that the unilateral weighted backward shift operator T with weights</p><p>w k : = ( k k − 1 ) α on the l p ( ℕ ) ( 1 ≤ p &lt; ∞ ) is absolutely Ces&#224;ro bounded for 0 &lt; α &lt; 1 p , and operator T with weights w k : = ( k k − 1 ) 1 / p is not Ces&#224;ro bounded. [<xref ref-type="bibr" rid="scirp.106918-ref6">6</xref>] generalized this work to the fractional case, constructed a weighted shift operator belonging to this class of operators, then they showed that the unilateral weighted backward shift operator T is absolutely ( C , α ) Ces&#224;ro bounded for 0 &lt; α ≤ 1 , and T is not ( C , α ) Ces&#224;ro bounded for any α . We can find more details about of the nth Ces&#224;ro mean of order α of the powers of T [<xref ref-type="bibr" rid="scirp.106918-ref7">7</xref>] [<xref ref-type="bibr" rid="scirp.106918-ref8">8</xref>] [<xref ref-type="bibr" rid="scirp.106918-ref9">9</xref>] [<xref ref-type="bibr" rid="scirp.106918-ref10">10</xref>]. Specially, when α = 1 , it is general Ces&#224;ro mean. The relation between ( C , α ) Ces&#224;ro mean and ( C , α ) strongly (weakly) ergodicity was given [<xref ref-type="bibr" rid="scirp.106918-ref11">11</xref>]. Example 5 in [<xref ref-type="bibr" rid="scirp.106918-ref12">12</xref>] proved that the unilateral weighted backward shift not have distributional unbounded orbit. [<xref ref-type="bibr" rid="scirp.106918-ref13">13</xref>] discussed that a distributionally unbounded orbit of the operator is not absolutely Ces&#224;ro bounded. Distributionally chaotic of</p><p>type D C 2 1 2 is not absolutely Ces&#224;ro bounded. [<xref ref-type="bibr" rid="scirp.106918-ref14">14</xref>] gave some equivalent characterizations of absolutely Ces&#224;ro bounded operators. In [<xref ref-type="bibr" rid="scirp.106918-ref13">13</xref>] [<xref ref-type="bibr" rid="scirp.106918-ref15">15</xref>], firstly they selected the sequence of weights v, then showed that the unilateral backward shift B on l p ( v ) ( 1 ≤ p &lt; ∞ ) is absolutely Ces&#224;ro bounded.</p><p>If 1 ≤ p &lt; ∞ , denote by l p ( ℕ ) the space of p-th summable sequences. Let { e n : n = 1,2, ⋯ } be the canonical basis of l p ( ℕ ) . Any vector x ∈ l p ( ℕ ) has</p><p>the unique representation x = ∑ j = 1 ∞     α j e j where { α j : j = 1, ⋯ } ⊂ ℂ . Let w = ( w 1 , w 2 , ⋯ ) be a weight sequence. We define the weighted backward shift operator B w on l p ( ℕ ) as B w e 1 = 0 and B w e k : = w k e k − 1 for integer k &gt; 1 . That is for x = ( α 1 , α 2 , ⋯ ) ∈ l p ( ℕ ) , B w ( α 1 , α 2 , ⋯ ) = ( w 2 α 2 , w 3 α 3 , ⋯ ) .</p><p>The boundedness of the weighted backward shifts is studied intensively for decades. Our motivation is to characterize the Ces&#224;ro bounded weighted backward shift and give a practical method to distinguish the Ces&#224;ro bounded backward shifts. Our results include those concrete examples in [<xref ref-type="bibr" rid="scirp.106918-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.106918-ref5">5</xref>] [<xref ref-type="bibr" rid="scirp.106918-ref6">6</xref>].</p></sec><sec id="s2"><title>2. A Criterion Based on the Comparison Principle</title><p>We first study the case when the weighted backward shift B w is not Ces&#224;ro bounded. Our method is to estimate the products of the weights ∏ i j     w n by the a fraction of two monomials of the indexes. In the sequel, to make the argument more compact, we set ∏ n = i j     a n = 1 whenever j &lt; i .</p><p>Theorem 1. For 1 ≤ p &lt; ∞ , let w be a weight sequence and B w the weighted backward shift on l p ( ℕ ) . Suppose ∏ n = i j     w n ≳ j s / p i t / p and the real pair ( t , s ) satisfies one of the following three conditions:</p><p>(1) t &gt; 1 and s &gt; 1 ;</p><p>(2) t = 1 and s ≥ 1 ;</p><p>(3) t &lt; 1 and t &lt; s .</p><p>Then B w is not Ces&#224;ro bounded on l p ( ℕ ) .</p><p>Proof. Let y N + 1 : = 1 ( N + 1 ) 1 / p ∑ n = 1 N + 1       e n , where N is an even integers. Therefore ‖ y N + 1 ‖ p = 1 . We compute directly that</p><p>‖ 1 N + 1 ∑ j = 0 N     T j y N + 1 ‖ p p = ‖ 1 ( N + 1 ) 1 + 1 / p ∑ k = 1 N + 1 ( ∑ j = k N + 1   ∏ n = k + 1 N − j + k + 1     w n ) e k ‖ p p = 1 ( N + 1 ) p + 1 ∑ k = 1 N + 1 ( ∑ j = k N + 1   ∏ n = k + 1 N − j + k + 1     w n ) p ≳ 1 ( N + 1 ) p + 1 ∑ k = 1 N + 1 ( ∑ j = k N + 1 ( N − j + k + 1 ) s / p k t / p ) p ≳ 1 ( N + 1 ) p + 1 ∑ k = 1 N / 2 + 1 1 k t ( ∑ j = N / 2 + 1 N + 1 ( N − j + k + 1 ) s / p ) p ≥ { 1 ( N + 1 ) p + 1 ( ∑ k = 1 N / 2 + 1 1 k t ) ( ∑ j = N / 2 + 1 N + 1 ( N − j + 2 ) s / p ) p ,   if     s &gt; 0 ; 1 ( N + 1 ) p + 1 ( ∑ k = 1 N / 2 + 1 1 k t ) ( ∑ j = N / 2 + 1 N + 1 ( 3 N 2 − j + 1 ) s / p ) p ,   if     s ≤ 0.</p><p>For short, we define</p><p>I = ∑ k = 1 N 2 + 1     k − t ,   I I = ∑ j = N 2 + 1 N + 1 ( N − j + 2 ) s p       and       I I I = ∑ j = N 2 + 1 N + 1 ( 3 N 2 − j + 1 ) s p .</p><p>If t &gt; 1 ,</p><p>I ≳ ∫ 1 N 2 + 2 1 x t d x = 1 t − 1 [ 1 − 1 ( N 2 + 2 ) t − 1 ] ≥ 2 t − 1 − 1 ( t − 1 ) 2 t − 1 ≃ 1.</p><p>Meanwhile s &gt; 1 implies</p><p>I I = ∑ j = 1 N 2 + 1     j s p ≥ ∫ 1 N 2 + 1     x s p d x = ( N 2 + 1 ) s p + 1 + s p s p + 1 ≃ N s p + 1 .</p><p>Then</p><p>I ⋅ I I p ( N + 1 ) p + 1 ≳ N s − 1 → ∞ ,       as     N → ∞ .</p><p>If t = 1 ,</p><p>I ≳ ∫ 1 N 2 + 2 1 x d x = log ( N 2 + 2 ) .</p><p>Meanwhile s ≥ 1 implies I I ≳ N s p + 1 . Then</p><p>I ⋅ I I p ( N + 1 ) p + 1 ≳ N s − 1 log N → ∞ ,       as     N → ∞ .</p><p>If t &lt; 1 and s &gt; max { t ,0 } ,</p><p>I ≳ ∫ 1 N 2 + 2     x − t d x = ( N 2 + 2 ) 1 − t − 1 1 − t ≃ N 1 − t .</p><p>Meanwhile we have I I ≳ N s p + 1 . Then</p><p>I ⋅ I I p ( N + 1 ) p + 1 ≳ N s − t → ∞ ,       as     N → ∞ .</p><p>If t &lt; 0 and t &lt; s ≤ 0 , I ≥ ∫ 1 N 2 + 2   x − t d x ≃ N 1 − t . To estimate III, we have</p><p>I I I = ∑ j = N / 2 N     j s / p .</p><p>If t &lt; s ( ≠ − p ) ≤ 0 ,</p><p>I I I ≥ ∫ N 2 N     x s / p d x = N s / p + 1 − ( N / 2 ) s / p + 1 1 + s / p = N s / p + 1 ⋅ 1 − 2 − s / p − 1 1 + s / p .</p><p>Then</p><p>I ⋅ I I I p ( N + 1 ) p + 1 ≳ N s − t → ∞ ,       as     N → ∞ .</p><p>If t &lt; s = − p ,</p><p>I I I ≥ ∫ N 2 N     x − 1 d x = log N − log N / 2 = log 2.</p><p>Then</p><p>I ⋅ I I I p ( N + 1 ) p + 1 ≳ N − t − p → ∞ ,       as     N → ∞ .</p><p>We use the same strategy to consider the absolutely Ces&#224;ro bounded weighted backward shift.</p><p>Theorem 2. For 1 ≤ p &lt; ∞ , let w be a weight sequence and B w be the weighted backward shift on l p ( ℕ ) . Suppose ∏ m = i j | w m | ≲ j s / p i t / p and the real pair ( t , s ) satisfies one of the following three conditions:</p><p>(1) t &gt; 1 and s ≤ 1 ,</p><p>(2) t = 1 and s &lt; 1 ,</p><p>(3) t &lt; 1 and s ≤ t .</p><p>Then B w is absolutely Ces&#224;ro bounded on l p ( ℕ ) .</p><p>Proof. For every x ∈ l p ( ℕ ) , denote by x = ∑ j = 1 ∞     α j e j for some complex sequence { α j } . Let N be a positive integer, we have</p><p>∑ n = 0 N ‖ B w n x ‖ p p = ∑ n = 0 N ‖ ∑ j = n + 1 ∞     α j ∏ m = j + 1 − n j     w m e j − n ‖ p p = ∑ n = 0 N   ∑ j = n + 1 ∞   | α j | p ∏ m = j + 1 − n j | w m | p = ∑ j = 1 ∞ | α j | p ∑ n = 0 min { N , j − 1 } ∏ m = j + 1 − n j | w m | p ≲ ∑ j = 1 ∞ | α j | p ∑ n = 0 min { N , j − 1 } j s ( j − n ) t = ∑ j = 1 N | α j | p ∑ n = 0 j − 1 j s ( j − n ) t     + ∑ j = N + 1 2 N | α j | p ∑ n = 0 N j s ( j − n ) t + ∑ j = 2 N + 1 ∞ | α j | p ∑ n = 0 N j s ( j − n ) t : = S 1 + S 2 + S 3 .</p><p>In either case, we have s ≤ t . Whenever j ≥ 2 N + 1 and n ≤ N it is clear that ( j j − n ) t ≤ 1 for t ≤ 0 and ( j j − n ) t ≤ 2 t for t &gt; 0 . Then we get</p><p>S 3 ≤ ∑ j = 2 N + 1 ∞ | α j | p ∑ n = 0 N ( j j − n ) t ( 2 N + 1 ) s − t ≤ ( N + 1 ) ⋅ max { 2 t , 1 } ⋅ ∑ j = 2 N + 1 ∞ | α j | p ≲ N ∑ j = 2 N + 1 ∞ | α j | p .</p><p>If t &gt; 1 and s ≤ 1 , we estimate S 1 and S 2 . For j ≤ N we have</p><p>∑ n = 0 j − 1 j s ( j − n ) t = j s ∑ n = 1 j     n − t ≤ j s ( 1 + ∫ 1 j   x − t d x ) = j s t − 1 ( t − 1 j t − 1 ) ≲ N .</p><p>And for j ∈ [ N + 1,2 N ] ,</p><p>∑ n = 0 N j s ( j − n ) t ≤ j s ∑ n = 0 j − 1 1 ( j − n ) t ≲ ( 2 N ) s ≲ N .</p><p>Hence S 1 + S 2 ≲ N ∑ j = 1 2 N | α j | p .</p><p>Suppose t = 1 and s &lt; 1 . To estimate S 1 and S 2 , for j ≤ N we have</p><p>∑ n = 0 j − 1 j s j − n = j s ∑ n = 1 j 1 n ≤ j s ( 1 + ∫ 1 j 1 x d x ) = j s log j + j s ≲ N .</p><p>And for j ∈ [ N + 1,2 N ] ,</p><p>∑ n = 0 N j s j − n ≤ j s ∑ n = 0 j − 1 1 j − n ≲ j s log j ≲ N .</p><p>Hence S 1 + S 2 ≲ N ∑ j = 1 2 N | α j | p .</p><p>Now we suppose t &lt; 1 and s ≤ t . For j ≤ N ,</p><p>∑ n = 0 j − 1 j s ( j − n ) t = j s ∑ n = 1 j     n − t ≤ j s ( 1 + ∫ 1 j   x − t d x ) = j s j 1 − t − t 1 − t ≲ N .</p><p>For j ∈ [ N + 1,2 N ] , we have</p><p>∑ n = 0 N j s ( j − n ) t ≤ j s ∑ n = 0 j − 1 1 ( j − n ) t ≲ ( 2 N ) s − t + 1 ≲ N .</p><p>To complete the proof, we use all the inequalities above in each case, and use Jensen's inequality to get</p><p>( 1 N + 1 ∑ n = 0 N ‖ B w n x ‖ p ) p ≤ 1 N + 1 ∑ n = 0 N ‖ B w n x ‖ p p ≲ ‖ x ‖ p p .</p><p>That is B w is absolutely Ces&#224;ro bounded.</p><p>We summarize the theorems above and give the following corollary.</p><p>Corollary 1. Suppose 1 ≤ p &lt; ∞ . Let w be a weight sequence such that ∏ m = i j | w m | ≃ j s / p i t / p for a real pair ( t , s ) . The weighted backward shift B w on l p ( ℕ ) is absolutely Ces&#224;ro bounded if and only if the real pair ( t , s ) satisfies one of the following three conditions:</p><p>(1) t &gt; 1 and s ≤ 1 ,</p><p>(2) t = 1 and s &lt; 1 ,</p><p>(3) t &lt; 1 and s ≤ t .</p><p>To give a visualization, we have the following <xref ref-type="fig" rid="fig1">Figure 1</xref> to show the correspondence of the range of ( t , s ) ∈ ℝ 2 with the absolute Ces&#224;ro boundedness.</p></sec><sec id="s3"><title>3. A Criterion around the Critical Point</title><p>It is clear that our result include the cases in [<xref ref-type="bibr" rid="scirp.106918-ref5">5</xref>]. We call the point ( t , s ) = ( 1 , 1 ) in <xref ref-type="fig" rid="fig1">Figure 1</xref> the critical point. In this section, we will give a criterion around the critical point. In the following conditions, we can treat log j to be non zero, that is j ≠ 1 . Because otherwise it is trivial or invalid. We consider the non Ces&#224;ro boundedness firstly.</p><p>Theorem 3. For 1 ≤ p &lt; ∞ , let w be a weight sequence and B w the weighted backward shift on l p ( ℕ ) . Suppose ∏ n = i j   w n ≳ ( j i ⋅ log t i log s j ) 1 / p and the real pair ( t , s ) satisfies one of the following three conditions:</p><p>(1) t &gt; − 1 and s &lt; t + 1 ;</p><p>(2) t = − 1 and s ≤ 0 ;</p><p>(3) t &lt; − 1 and s &lt; 0 .</p><p>Then B w is not Ces&#224;ro bounded on l p ( ℕ ) .</p><p>Proof. Analogously to the proof of Theorem 1, let y N + 1 : = 1 ( N + 1 ) 1 / p ∑ n = 1 N + 1     e n , where N is a positive integer multiple of 4.</p><p>‖ 1 N + 1 ∑ j = 0 N     B w j y N + 1 ‖ p p ≳ 1 ( N + 1 ) p + 1 ∑ k = 1 N + 1 ( ∑ j = k N + 1 ( N − j + k + 1 ) 1 / p ( k + 1 ) 1 / p log t / p ( k + 1 ) log s / p ( N − j + k + 1 ) ) p ≥ 1 ( N + 1 ) p + 1 ∑ k = 1 N / 4 + 1 log t ( k + 1 ) k + 1 ( ∑ j = N / 4 + 1 3 N / 4 + 1 ( N − j + k + 1 ) 1 / p log s / p ( N − j + k + 1 ) ) p ≥ { 1 ( N + 1 ) p + 1 ( ∑ k = 1 N / 4 + 1 log t ( k + 1 ) k + 1 ) ( ∑ j = N / 4 + 1 3 N / 4 + 1 ( N − j + 2 ) 1 / p log s / p ( 5 N / 4 − j + 2 ) ) p , if     s &gt; 0 ; 1 ( N + 1 ) p + 1 ( ∑ k = 1 N / 4 + 1 log t ( k + 1 ) k + 1 ) ( ∑ j = N / 4 + 1 3 N / 4 + 1 ( N − j + 2 ) 1 / p log s / p ( N − j + 2 ) ) p , if     s ≤ 0.</p><p>For short, we define M 1 = ∑ k = 1 N 4 + 1 log t ( k + 1 ) k + 1 , M 2 = ∑ j = N 4 + 1 3 N 4 + 1 ( N − j + 2 ) 1 / p log s / p ( 5 N / 4 − j + 2 ) , and M 3 = ∑ j = N 4 + 1 3 N 4 + 1 ( N − j + 2 ) 1 / p log s / p ( N − j + 2 ) .</p><p>If − 1 &lt; t ≤ 0 ,</p><p>M 1 = ∑ k = 2 N 4 + 2 log t k k ≥ ∫ 2 N 4 + 3 log t x x d x = log t + 1 ( N 4 + 3 ) − log t + 1 2 t + 1 ≳ log t + 1 N .</p><p>If t &gt; 0 ,</p><p>M 1 = ∑ k = 2 N 4 + 2 log t k k ≳ log t 2 2 + ∫ 2 N 4 + 2 log t x x d x ≳ log t + 1 ( N 4 + 2 ) − log t + 1 2 t + 1 ≳ log t + 1 N .</p><p>Meanwhile s &gt; 0 implies that</p><p>M 2 ≥ 1 log s / p ( N + 1 ) ∑ N 4 + 1 3 N 4 + 1 j 1 / p ≥ 1 log s / p ( N + 1 ) ∫ N 4 3 N 4 + 1 x 1 / p d x = ( 3 N 4 + 1 ) 1 / p + 1 − ( N 4 ) 1 / p + 1 ( log s / p ( N + 1 ) ) ( 1 p + 1 ) ≳ N 1 / p + 1 log s / p N .</p><p>Hence, t + 1 &gt; s implies</p><p>M 1 ⋅ M 2 p ( N + 1 ) p + 1 ≳ log t + 1 − s N → ∞ ,       as     N → ∞ .</p><p>When t &gt; − 1 , we have M 1 ≳ log t + 1 N . If s ≤ 0 , then</p><p>M 3 ≥ 1 log s / p ( N 4 + 1 ) ∑ j = N 4 + 1 3 N 4 + 1     j 1 / p ≥ 1 log s / p ( N 4 + 1 ) ∫ j = N 4 3 N 4 + 1     x 1 / p d x = ( 3 N 4 + 1 ) 1 / p + 1 − ( N 4 ) 1 / p + 1 log s / p ( N 4 + 1 ) ( 1 p + 1 ) ≳ N 1 / p + 1 log s / p N .</p><p>hence,</p><p>M 1 ⋅ M 3 p ( N + 1 ) p + 1 ≳ log t + 1 − s N → ∞ ,       as     N → ∞ ,</p><p>which proves the case (1).</p><p>If t = − 1 ,</p><p>M 1 = ∑ k = 2 N 4 + 2 1 k log k ≥ ∫ 2 N 4 + 3 1 x log x d x = log log ( N 4 + 3 ) − log log 2 ≳ log ( log N ) .</p><p>Meanwhile s ≤ 0 implies M 3 ≳ N 1 / p + 1 log s / p N . Hence,</p><p>M 1 ⋅ M 3 p ( N + 1 ) p + 1 ≳ log ( log N ) log s N</p><p>diverges when N goes to the infinity. That is the case (2).</p><p>If t &lt; − 1 ,</p><p>M 1 = ∑ k = 2 N 4 + 2 log t k k ≳ ∫ 2 N 4 + 3 log t x x d x = log t + 1 2 − log t + 1 ( N 4 + 3 ) − t − 1 ≳ 1.</p><p>Also s &lt; 0 implies M 3 ≳ N 1 / p + 1 log s / p N . Hence,</p><p>M 1 ⋅ M 3 p ( N + 1 ) p + 1 ≳ log − s N → ∞ ,       as     N → ∞ .</p><p>That is the case (3).</p><p>Theorem 4. For 1 ≤ p &lt; ∞ , let w be a weight sequence and B w the weighted backward shift on l p ( ℕ ) . Suppose ∏ n = i j | w n | ≲ ( j i ⋅ log t i log s j ) 1 / p and the real pair ( t , s ) satisfies one of the following three conditions:</p><p>(1) t &gt; − 1 and s ≥ t + 1 ;</p><p>(2) t = − 1 and s &gt; 0 ;</p><p>(3) t &lt; − 1 and s ≥ 0 .</p><p>Then B w is absolutely Ces&#224;ro bounded on l p ( ℕ ) . In the condition, we treat all log j to be positive. That is actually the case when j ≥ 3 . There are exceptions in our arguments. But the only cases are when j = 1 , 2 . We can concentrate to the cases when j large enough, because the exact values of w 1 and w 2 will not change the (absolute) Ces&#224;ro boundedness of the backward shift B w . From this point of view, we avoid to consider the trivial cases and abuse to treat all the log j to be positive.</p><p>Proof. Analogously to the proof of Theorem 2, for x = ∑ j = 1 ∞     α j e j , we have</p><p>∑ n = 0 N ‖ B w n x ‖ p p ≲ ∑ j = 1 N | α j | p ( ∑ n = 0 j − 1 j j − n ⋅ log t ( j − n ) log s j )     + ∑ j = N + 1 2 N | α j | p ( ∑ n = 0 N j j − n ⋅ log t ( j − n ) log s j )     + ∑ j = 2 N + 1 ∞ | α j | p ( ∑ n = 0 N j j − n ⋅ log t ( j − n ) log s j ) : = S 1 + S 2 + S 3 .</p><p>To estimate S 3 , we note that j ≥ 2 N + 1 , n ≤ N . Then</p><p>∑ n = 0 N j j − n ⋅ log t ( j − n ) log s j ≤ 2 ∑ n = 0 N log t ( j − n ) log s j ≲ { N log t j log s j , if     t &gt; 0 ; N log t ( j − N ) log s j , if     t ≤ 0.</p><p>Let L 1 = N log t j log s j and L 2 = N log t ( j − N ) log s j .</p><p>In either case (1), (2) and (3), we have t − s ≤ − 1 . If t &gt; 0 ,</p><p>L 1 = N log t − s j ≲ N log t − s N ≲ N .</p><p>If t ≤ 0 ,</p><p>L 2 ≲ N log t ( N + 1 ) log s j ≤ N log t ( N + 1 ) log s ( 2 N + 1 ) ≲ N log t − s N ≲ N .</p><p>Then, in either case (1), (2) and (3), we have</p><p>S 3 ≲ ∑ j = 2 N + 1 ∞ | α j | p ⋅ 2 N ≲ N ‖ x ‖ p p .</p><p>We split (1) into two cases, that is when − 1 &lt; t ≤ 0 or t &gt; 0 , to estimate S 1 and S 2 . If − 1 &lt; t ≤ 0 and s ≥ t + 1 . To estimate S 1 , we note that j ≤ N and</p><p>∑ n = 0 j − 1 j j − n ⋅ log t ( j − n ) log s j = j log s j ∑ n = 2 j log t n n ≤ j log s j ( log t 2 2 + ∫ 2 j log t x x d x ) = j log s j ( log t 2 2 + log t + 1 j − log t + 1 2 t + 1 ) ≲ N log t + 1 − s j ≲ N .</p><p>If t &gt; 0 and s ≥ t + 1 , we can estimate S 1 by the following computation</p><p>j log s j ∑ n = 2 j log t n n ≤ j log s j ∫ 2 j + 1 log t x x d x = j log s j ⋅ log t + 1 ( j + 1 ) − log t + 1 2 t + 1 ≲ N log t + 1 − s j ≲ N . (1)</p><p>Thus, in the case (1) we have S 1 ≲ N ∑ j = 1 N | α j | p ≲ N ‖ x ‖ p p .</p><p>The estimate for S 2 is similar. We note that j ≥ N + 1 and</p><p>S 2 ≤ ∑ j = N + 1 2 N | α j | p ( j log s j ∑ n = 2 j log t n n ) ≲ N ‖ x ‖ p p .</p><p>Now we consider the case (2), that is t = − 1 and s &gt; 0 . Since</p><p>j log s j ∑ n = 2 j 1 n log n ≤ j log s j ( 1 2 log 2 + ∫ 2 j 1 x log x d x ) ≲ N log log j log s j ≲ N log − s j ≲ N ,</p><p>we have</p><p>S 1 ≲ N ∑ j = 1 N | α j | p ≲ N ‖ x ‖ p p .</p><p>And similarly,</p><p>S 2 ≤ ∑ j = N + 1 2 N | α j | p ( j log s j ∑ n = 2 j 1 n log n ) ≲ N ‖ x ‖ p p .</p><p>We have the last case (3) to consider. That is t &lt; − 1 and s ≥ 0 . Similarly to (1), we can obtain S 1 ≲ N ‖ x ‖ p p and S 2 ≲ N ‖ x ‖ p p .</p><p>In the end of the proof, by the Jensen's inequality again, we have B w is absolutely Ces&#224;ro bounded on l p ( ℕ ) .</p><p>We summarize the above two theorem as a corollary.</p><p>Corollary 2. Suppose 1 ≤ p &lt; ∞ . Let w be a weight sequence such that</p><p>∏ m = i j | w m | ≃ ( j i ⋅ log t i log s j ) 1 / p for a real pair ( t , s ) . The weighted backward shift B w</p><p>on l p ( ℕ ) is absolutely Ces&#224;ro bounded if and only if the real pair ( t , s ) satisfies one of the following three conditions:</p><p>(1) t &gt; − 1 and s ≥ t + 1 ,</p><p>(2) t = − 1 and s &gt; 0 ,</p><p>(3) t &lt; 1 and s ≥ 0 .</p><p>We also give the following <xref ref-type="fig" rid="fig2">Figure 2</xref> to show our result around the critical point.</p></sec><sec id="s4"><title>4. Examples</title><p>According to our result, we can construct lots of absolutely Ces&#224;ro bounded weighted backward shift.</p><p>Example 1. If 0 &lt; s ≤ t &lt; 1 , let</p><p>w = ( w 1 , ⋯ , w n , ⋯ ) = ( ( 2 + log 2 ) s / p ( 1 + log 1 ) t / p , ⋯ , [ n + 1 + log ( n + 1 ) ] s / p ( n + log n ) t / p , ⋯ ) .</p><p>The operator B w is absolutely Ces&#224;ro bounded on l p ( ℕ ) . It follows from i + log i ≥ i and l i m j → ∞ j + log j j = 1 and hence</p><p>∏ n = i j | w n | p = [ j + 1 + log ( j + 1 ) ] s ( i + log i ) t ∏ n = i + 1 j ( n + log n ) s − t ≲ j s i t</p><p>for any j ≥ i ∈ ℕ .</p><p>Example 2. If 0 &lt; s &lt; t &lt; 1 , let</p><p>w = ( w 1 , ⋯ , w n , ⋯ ) = ( ( 2 log 3 ) s / p ( log 2 ) t / p , ⋯ , [ ( n + 1 ) log ( n + 2 ) ] s / p [ n log ( n + 1 ) ] t / p , ⋯ ) .</p><p>The operator B w is absolutely Ces&#224;ro bounded on l p ( ℕ ) . It follows from i log ( i + 1 ) ≳ i and log ( j + 1 ) ≲ j t − s 2 s and hence</p><p>∏ n = i j | w n | p = [ ( j + 1 ) log ( j + 2 ) ] s ( i log ( i + 1 ) ) t ∏ n = i + 1 j − 1 [ n log ( n + 1 ) ] s − t ≲ j s + t 2 i t</p><p>for any j ≥ i ∈ ℕ .</p><p>Example 3. If t ≥ 0 , let</p><p>w = ( w 1 , ⋯ , w m , ⋯ ) = ( 0, ⋯ , ( m + 1 ) 1 / p log t + 1 p ( m + 1 ) ⋅ log t p m m 1 / p , ⋯ ) .</p><p>The operator B w is absolutely Ces&#224;ro bounded on l p ( ℕ ) by Theorem 4. One can conduct the following computation that</p><p>∏ m = i j | w m | = ( j + 1 ) 1 p i 1 p ⋅ log t p i log t + 1 p ( j + 1 ) ⋅ ∏ k = i + 1 j 1 log 1 p k ≤ ( 2 log 2 ) 1 p ⋅ ( j i ⋅ log t i log t + 1 j ) 1 p .</p><p>We will also find a new example of non Ces&#224;ro bounded backward shift as follows.</p><p>Example 4. If t ∈ ℝ , let</p><p>w = ( w 1 , ⋯ , w m , ⋯ ) = ( 0 , ⋯ , ( m + 1 log t ( m + 1 ) ⋅ log t m m ) 1 / p , ⋯ ) .</p><p>The operator B w is not Ces&#224;ro bounded on l p ( ℕ ) by Theorem 3.</p></sec><sec id="s5"><title>5. Conclusion</title><p>In this paper, we proved Ces&#224;ro boundedness by constructing the proper product of weight functions ∏ a b     w n by the fraction of two monomials of the indexes. The method of proof is to obtain the characterization of absolutely Ces&#224;ro bounded and non Ces&#224;ro bounded by proper scaling and Jensen’s inequality. we give some examples after our results.</p></sec><sec id="s6"><title>Conflicts of Interest</title><p>The author declares no conflicts of interest regarding the publication of this paper.</p></sec><sec id="s7"><title>Cite this paper</title><p>Gao, H. (2021) Ces&#224;ro Bounded Weighted Backward Shift. Journal of Applied Mathematics and Physics, 9, 197-209. https://doi.org/10.4236/jamp.2021.91014</p></sec></body><back><ref-list><title>References</title><ref id="scirp.106918-ref1"><label>1</label><mixed-citation publication-type="other" xlink:type="simple">Hou, B. and Luo, L. (2015) Some Remarks on Distributional Chaos for Bounded Linear Operators. 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